Click the mouse button or press the Space Bar to display the answers. Objective Find the number of combinations of objects Vocabulary Combination An arrangement or listing in which order is not important C(a, b) = P(a, b) b! Math Symbols C(a, b) The number of combinations of a things taken b at a time Example 1 Use a Combination Example 2 Find a Combination Notation Example 3 Combinations and Permutations Example 4 Combinations and Permutations Find Write the combination statement A combination is another modified permutation and order is not important Write formula for combination using information in combination statement The numerator is a permutation of the statement The denominator is a factorial of the second number 1/4 P(8, 5) is a permutation that begins with 8 and multiply 5 descending numbers Find Write definition of 5! C(8, 5) = 87654 54321 C(8, 5) = 6,720 120 5! is a permutation that begins with 5 and multiply all descending numbers to 1 Follow Order of Operations P E MD AS Multiply in numerator Multiply in denominator 1/4 Find C(8, 5) = 87654 54321 Divide numerator by denominator C(8, 5) = 6,720 120 Answer: C(8, 5) = 56 1/4 Find Answer: C(6, 3) = 20 1/4 TOURNAMENTS Five teams are playing each other in a tournament. If each team plays every other team once, how many games are played? C(a, b) = P(a, b) b! Order does not matter so this is a combination C(5, Write the combination statement Write formula for combination “a” represents the number of choices Replace a with 5 2/4 TOURNAMENTS Five teams are playing each other in a tournament. If each team plays every other team once, how many games are played? C(a, b) = P(a, b) b! C(5, 2) = P(5, 2) 2! “b” represents the number wants to choose “each team plays every other team” refers to 2 teams playing each other at a time Replace b with 2 Complete the equation by replacing values for a and b 2/4 TOURNAMENTS Five teams are playing each other in a tournament. If each team plays every other team once, how many games are played? C(a, b) = P(a, b) b! P(5, 2) 2! C(5, 2) = 5 4 21 C(5, 2) = P(5, 2) is a permutation that begins with 5 and multiply only 2 numbers Write definition of 2! 2! is a permutation that begins with 2 and multiply all descending numbers to 1 2/4 TOURNAMENTS Five teams are playing each other in a tournament. If each team plays every other team once, how many games are played? C(a, b) = P(a, b) b! P(5, 2) 2! C(5, 2) = 5 4 21 C(5, 2) = 20 2 Answer: C(5, 2) = 10 games C(5, 2) = Follow Order of Operations P E MD AS Multiply in numerator Multiply in denominator Divide numerator by denominator Add dimensional analysis 2/4 TOURNAMENTS Six teams are playing each other in a tournament. If each team plays every other team once, how many games are played? Answer: C(6, 2) = 15 games 2/4 SCHOOL An eighth grade teacher needs to select 4 students from a class of 22 to help with sixth grade orientation. Does this represent a combination or a permutation? How many possible groups could be selected to help out the new students? Order does not matter so this is P(a, b) C(a, b) = a combination b! Write the combination statement C(22, Write formula for combination “a” represents the number of choices Replace a with 22 3/4 SCHOOL An eighth grade teacher needs to select 4 students from a class of 22 to help with sixth grade orientation. Does this represent a combination or a permutation? How many possible groups could be selected to help out the new students? C(a, b) = P(a, b) b! C(22, 4) = P(22, 4) 4! “b” represents the number wants to choose Replace b with 4 Complete the equation by replacing values for a and b 3/4 C(a, b) = P(a, b) b! C(22, 4) = P(22, 4) 4! P(22, 4) is a permutation that begins with 22 and multiply only 4 numbers Write definition of 4! Follow Order of Operations C(22, 4) = 22 21 20 19 4321 C(22, 4) = 175,560 24 P E MD AS Multiply in numerator Multiply in denominator Divide numerator by denominator C(22, 4) = 7,315 3/4 C(a, b) = P(a, b) b! C(22, 4) = P(22, 4) 4! Add dimensional analysis How many possible groups could be selected to help out the new students? C(22, 4) = 22 21 20 19 4321 C(22, 4) = 175,560 24 Answer: C(22, 4) = 7,315 groups 3/4 SCHOOL A teacher needs to select 5 students from a class of 26 to help with parent teacher conferences. Does this represent a combination or a permutation? How many possible groups could be selected to help? Answer: C(26, 5) = 65,780 groups 3/4 SCHOOL An eighth grade teacher needs to select 4 students from a class of 22 to help with sixth grade orientation. One eighth grade student will be assigned to sixth grade classes on the first floor, another student will be assigned to classes on the second floor, another student will be assigned to classes on the third floor, and still another student will be assigned to classes on the fourth floor. Does this represent a combination or a permutation? In how many possible ways can the eighth graders be assigned to help with the sixth grade orientation? Shows order is important P(a, b) = Write permutation formula 4/4 SCHOOL An eighth grade teacher needs to select 4 students from a class of 22 to help with sixth grade orientation. One eighth grade student will be assigned to sixth grade classes on the first floor, another student will be assigned to classes on the second floor, another student will be assigned to classes on the third floor, and still another student will be assigned to classes on the fourth floor. Does this represent a combination or a permutation? In how many possible ways can the eighth graders be assigned to help with the sixth grade orientation? “a” represents the number of P(a, b) = P(22, choices Replace a with 22 4/4 SCHOOL An eighth grade teacher needs to select 4 students from a class of 22 to help with sixth grade orientation. One eighth grade student will be assigned to sixth grade classes on the first floor, another student will be assigned to classes on the second floor, another student will be assigned to classes on the third floor, and still another student will be assigned to classes on the fourth floor. Does this represent a combination or a permutation? In how many possible ways can the eighth graders be assigned to help with the sixth grade orientation? “b” represents the number wants to choose P(a, b) = P(22, 4) = Replace b with 4 4/4 P(a, b) = P(22, 4) is a permutation that begins with 22 and multiply 4 numbers P(22, 4) = 22 21 20 19 Multiply Answer: P (22, 4) = 175,560 ways Add dimensional analysis In how many possible ways can the eighth graders be assigned to help with the sixth grade orientation? 4/4 * SCHOOL A teacher needs to select 5 students from a class of 26 to help with parent teacher conferences. One student will be assigned to fifth grade parents, another student will be assigned to sixth grade parents, another student will be assigned to seventh grade parents, another student will be assigned to eighth grade parents, and still another student will be assigned to ninth grade parents. Does this represent a combination or a permutation? In how many possible ways can the students be assigned to help with the parent teacher conferences? Answer: P(26, 5) = 7,893,600 ways 4/4 Assignment Lesson 8:4 Combinations 3 - 26 All