Department of Computer and IT Engineering University of Kurdistan Operating systems Disk Management By: Dr. Alireza Abdollahpouri Hard Disk Drives Read/Write Head Side View Western Digital Drive http://www.storagereview.com/guide/ Mechanics of Disks Platters circular platters covered with magnetic material to provide nonvolatile storage of bits Spindle of which the platters rotate around Tracks concentric circles on a single platter Disk heads Sectors segment of the track circle – usually each contains 512 bytes – separated by non-magnetic gaps. The gaps are often used to identify beginning of a sector read or alter the magnetism (bits) passing under it. The heads are attached to an arm enabling it to move across the platter surface Cylinders corresponding tracks on the different platters are said to form a cylinder Hard Disk Drives Disk Access Time Disk platter Disk access time = Disk head Seek time + Rotational delay Disk arm + Transfer time + Other delays Measure Disk Performance • Transfer rate is rate at which data flows between drive and computer • Positioning time (random-access time) is time – The time to move disk arm to desired cylinder (seek time) – and the time for desired sector to rotate under the disk head (rotational latency) Magnetic Disks Platters range from .85” to 14” (historically) Commonly 3.5”, 2.5”, and 1.8” Range from 30GB to 3TB per drive Performance Transfer Rate – theoretical – 6 Gb/sec Effective Transfer Rate – real – 1Gb/sec Seek time from 3ms to 12ms – 9ms common for desktop drives Average seek time measured or calculated based on 1/3 of tracks Latency based on spindle speed 1/(RPM * 60) Average latency = ½ latency (From Wikipedia) Magnetic Disk Performance Access Latency = Average access time = average seek time + average latency For fastest disk 3ms + 2ms = 5ms For slow disk 9ms + 5.56ms = 14.56ms Average I/O time = average access time + (amount to transfer / transfer rate) + controller overhead For example to transfer a 4KB block on a 7200 RPM disk with a 5ms average seek time, 1Gb/sec transfer rate with a .1ms controller overhead = 5ms + 4.17ms + 4KB / 1Gb/sec + 0.1ms = 9.27ms + 4 / 131072 sec = 9.27ms + .12ms = 9.39ms Disk Structure Disk drives are addressed as large 1-dimensional arrays of logical blocks, where the logical block is the smallest unit of transfer The 1-dimensional array of logical blocks is mapped into the sectors of the disk sequentially Sector 0 is the first sector of the first track on the outermost cylinder Mapping proceeds in order through that track, then the rest of the tracks in that cylinder, and then through the rest of the cylinders from outermost to innermost Logical to physical address should be easy Except for bad sectors Non-constant # of sectors per track via constant angular velocity Disk Scheduling Disk can do only one request at a time; What order do you choose to do queued requests? 3 2 10 7 5 2 User Requests Head cylinder # of requested block Seek time seek distance Several algorithms exist to schedule the servicing of disk I/O requests Disk Scheduling (Cont.) There are many sources of disk I/O request OS System processes Users processes I/O request includes input or output mode, disk address, memory address, number of sectors to transfer OS maintains queue of requests, per disk or device Idle disk can immediately work on I/O request, busy disk means work must queue Optimization algorithms only make sense when a queue exists Note that drive controllers have small buffers and can manage a queue of I/O requests (of varying “depth”) Several algorithms exist to schedule the servicing of disk I/O requests The analysis is true for one or many platters We illustrate scheduling algorithms with a request queue (0-199) 98, 183, 37, 122, 14, 124, 65, 67 Head pointer 53 Disk Scheduling: FCFS Fair among requesters, but order of arrival may be to random spots on the disk Very long seeks Example در اين روش سيلندرهاي متقاض ي به ترتيب درخواستشان سرويسدهي ميشوند .بعبارتي هر درخواست در صف اجرا قرار ميگيرد .سادهترين روش است اما كارآيي چنداني ندارد. Disk Scheduling: SSTF در اين روش ،هر لحظه سيلندر متقاض ي كه به محل هد در آن لحظه نزديكتر باشد مورد پردازش قرار ميگيرد. Disk Scheduling: SCAN • The disk arm starts at one end of the disk, and moves toward the other end, servicing requests until it gets to the other end of the disk, where the head movement is reversed and servicing continues. Sometimes called the elevator algorithm Disk Scheduling: C-SCAN The head moves from one end of the disk to the other, servicing requests as it goes. When it reaches the other end, however, it immediately returns to the beginning of the disk, without servicing any requests on the return trip Treats the cylinders as a circular list that wraps around from the last cylinder to the first one C-LOOK Arm only goes as far as the last request in each direction, then reverses direction immediately, without first going all the way to the end of the disk Total number of cylinders? مثال فرض کنید یک دیسک 200شیار داشته و صف درخواست دیسک درخواستهای Randomرا در خود دارد .شیار )(trackهای در خواست شده به ترتیب دریافت عبارتند از : 55, 58, 39,18,90,160,38,184در هر یک از حاالت زیر: اگر زمان حرکت از شیار به شیار دیگر 4میلی ثانیه طول بکشد ،و بازوی دیسک در ابتدا در روی شیار 100قرار داشته باشد : ترتیب سرویس دهی به در خواستها و طول متوسط Seekچقدر است ؟ کل زمان جستجو چقدر خواهد بود ؟ الف ) از روش FIFOاستفاده کنید . ب ) از الگوریتم SSTFاستفاده شود . ج ) از الگوریتم آسانسور استفاده شود. د ) از الگوریتم C-SCANاستفاده شود . فرض کنید در روش scanو c-scanجهت اولیه حرکت به سمت افزایش شماره شیار می باشد. FIFO order of service request in queue 0 100 0 1 55 45 2 58 3 3 39 19 4 18 21 5 90 72 6 160 70 7 150 10 8 38 112 9 184 146 Average Seek Length 55.3 های پیموده شدهtrack تعداد های پیمودهtrack = تعداد498 FIFO FIFO ترتیب serviceدهی 8 9 7 5 6 3 4 1 2 0 0 18 38 20 39 40 90 80 100 100 120 150 184 شماره track 58 55 60 140 160 160 180 200 = زمان جستجو کل 498 * 4 (ms) =1992 msec = 498تعداد trackهای پیموده SSTF تعدادtrack های پیموده شده order of service request serviced 0 100 1 90 10 2 58 32 3 55 3 4 39 16 5 38 1 6 18 20 7 150 132 8 160 10 9 184 24 Average Seek Length 27.5 های پیمودهtrack = تعداد248 = زمان جستجو کل 248 * 4 (ms) = 299 msec SSTF تعدادtrack های پیموده شده order of service request serviced 0 100 1 90 10 0 2 58 32 20 3 55 3 40 4 39 16 60 5 38 1 80 6 18 20 7 150 132 8 160 10 140 9 184 24 160 SSTF دهیservice ترتیب شماره شیار 0 1 2 3 4 5 6 7 8 9 18 39 58 38 55 90 100 100 120 150 180 200 160 184 SCAN or ELEVATOR ))آسانسور تعدادtrack های پیموده شده request in queue order of service 100 0 55 1 58 2 39 3 18 4 90 5 160 6 150 7 38 8 160 184 90 58 55 39 38 184 9 18 های پیمودهtrack = تعداد250 = زمان جستجو کل request serviced 100 150 Average Seek Length 250 * 4 (ms) = 1000 msec 50 10 24 94 32 3 16 1 20 27.8 SCAN or ELEVATOR ))آسانسور order of service SCAN request serviced دهیservice ترتیب 0 100 1 150 0 2 160 20 3 184 40 0 1 2 3 4 5 5 58 6 55 7 39 140 8 38 160 9 18 شماره شیار 90 58 90 100 120 150 180 200 8 39 80 100 7 9 18 60 4 6 160 184 55 38 C-SCAN تعدادtrack های پیموده شده order of service request serviced 0 100 1 150 50 2 160 10 3 184 24 4 18 166 5 38 20 6 39 1 7 55 16 8 58 3 9 90 32 Average Seek Length های پیمودهtrack = تعداد322 = زمان جستجو کل 322 * 4 (ms) = 1288 msec 35.8 C-SCAN order of service request serviced 0 100 تعدادtrack های پیموده شده C_SCAN دهیs e rvice ترتیب 0 1 150 50 0 2 160 10 20 3 184 1 2 3 4 38 18 7 8 9 39 55 60 4 6 18 40 24 5 58 166 5 38 20 شماره شیار 80 90 100 6 39 1 7 55 16 140 8 58 3 160 9 90 32 180 100 120 150 200 160 184 SSTF FIFO ترتیب se rv iceده ی 9 8 7 5 6 3 4 1 2 ترتیب serviceدهی 0 0 18 8 9 6 7 4 5 2 3 0 1 20 38 39 0 18 40 55 58 38 60 20 39 40 90 100 100 120 شماره شیار 80 80 90 100 100 120 140 140 150 150 160 160 184 160 160 180 184 180 شماره track 58 55 60 200 200 C_SCAN SCAN ترتیب s e r viceدهی 9 8 7 6 5 4 3 2 1 0 ترتیب serviceدهی 0 9 18 39 58 8 6 7 4 5 3 2 1 20 38 18 40 55 20 38 60 39 40 55 شماره شیار 90 100 58 60 80 90 100 120 120 140 140 150 160 184 100 150 160 160 180 200 184 160 180 200 شماره شیار 80 100 0 0 Questions 28