Cancer Trials Reading instructions • • • • • • • 6.1: 6.2: 6.3: 6.4: 6.5: 6.6: 6.7: Introduction General Considerations Single stage phase I designs Two stage phase I designs Continual reassessment Optimal/flexible multi stage designs Randomized phase III designs What is so special about cancer? The disease •Many cancers are life-threatening. •Many cancers neither curable or controlable. •Malignant disease implies limited life expectancy. The drugs •Narrow therapeutic window. •Many drug severely toxic even at low doses. •Serious or fatal adverse drug reactions at high doses. •Difficulty to get acceptance for randomization Ethics Some ways to do it •No healty volunteers. •Terminal cancer patients with short life expectancy. •Minimize exposure to experimental drug. •Efficient selection of acceptable drug. The cancer programme Phase I: Find the Maximum Tolerable Dose (MTD) The dose with probability of dose limiting toxicity less than p0 max d : Pd DLT p0 d D Doses di , i 1,, I Phase II: DLT=Dose Limiting Toxicity p0 often between 0.1 and 0.4 Investigate anti tumour actividy at MTD using e.g. tumour shrinkage as outcome. Sufficient anti tumour activity Phase III: Investigate effect on survival Phase I cancer trials Objective: Find the Maximum Tolerable Dose (MTD) max d : Pd DLT p0 d D PDLT p p x ln 1 p Use maximum likelihood to estimate and p0 ˆ ln 1 p 0 xm ˆ Phase I cancer trials Design A If di is the highest dose then d i 1 is the estimated MTD •Only escalation possible. •Start at the lowest dose. •Many patients on too low dose. Start with a group of 3 patients at the initial dose level No toxicity Yes Next group of 3 patients at the next higher dose level No Next group of 3 patients at the same dose level Toxicity in at most one patient No Trial stops Yes Next group of 3 patients at the next higher dose level Phase I cancer trials Start with a single patient at the initial dose level Design B •Escalation and deescaltion possible. •No need to start with the lowest dose. p0 ln 1 p ˆ 0 MTD: xm ˆ Yes No Next patient at the next lower dose level No Toxicity in two consequtive patients No Next patient at the next lower dose level Next patient at the same dose level No toxicity Yes Toxicity in two consequtive patients No Trial stops Yes Next patient at the next higher dose level Phase I cancer trials Design D •Escalation and deescaltion possible. •No need to start with the lowest dose. p0 ln 1 p ˆ 0 MTD: xm ˆ Start with a group of 3 patients at the initial dose level Toxicity in more than one patient Yes Next group of 3 patients at the next lower dose level No Toxicity in one patient No Next group of 3 patients at the next higher dose level Repeat the process until exhaustion of all dose levels or max sample size reached Yes Next group of 3 patients at the same dose level Phase I cancer trials Design BD Run design B until it stops. DLT in last patient Run design D starting at same dose level. Run design D starting at the next lower dose level. Phase I cancer trials Continual reassessment designs p0 Acceptable probability of DLT MTD d 0 max d : Pd DLT p0 d D Dose response model: logitPxi , xi Assume fixed. Let g be the prior distribution for the slope parameter. Phase I cancer trials Once the response, DLT or no DLT, is available from the current patient at dose xi 1 the estimated slope is update as: i E | i 1 f | i 1 d where f | i 1 where qi1 g q z g z dz i 1 i 1 qi1 Px j , j 1 Px j , j 1 y i 1 x1 , y1 ,, xi 1 , yi 1 1 y j is the likelihood function, and is the cumulative data up to the i-1 patient. Phase I cancer trials The next dose level is given by minimizing Pxi , i p0 MTD is estimated as the dose xm for the hypothetical n+1 patient. The probability of DLT can be estimated as Pxm , m •CRM is slower than designs A, B, D and BD. •Estimates updated for each patient. •CRM can be improved by increasing cohort size Phase II cancer trials Objective: Investigate effect on tumor of MTD. Response: Sufficient tumour shrinkage. Progression free survival. Two important things: •Stop developing ineffective drug quickly. •Identify promising drug quickly. Phase II cancer trials Optimal 2 stage designs. First stage: n1 patients: Second stage: n2 patients: Unacceptable response rate: Acceptable response rate: Test: p0 p1 Stop and reject the drug if at most r1 successes Stop and reject the drug if at most r successes p0 p1 H0 : p p0 vs. H1 : p p0 PT ypeI error PT ypeII error Phase II cancer trials How to select n1 and n2 ? Minimize expected sample size under H0: EN n1 1 PETp0 n2 n1 where PETp0 p0 1 p0 Br1; n1 , p0 is the i 1 i r1 probability of early termination. Pp0 (reject drug) Br1; n1 , p0 min(n1 , r1 ) bx; n , p Br x; n , p x r1 1 1 0 1 1 0 Given p0, p1, and , select n1, n2, r1 and r such that EN n1 1 PETn2 is minimized. Nice discrete problem. Phase II cancer trials Assume specific values of p0, p1, and For each value of the total sample size n, n1[1,n-1] and r1[0,n1] Find the largest value of r that gives the correct PT ypeII error Check if the combination: n1, n2, r1 and r satisfies PT ypeI error If it does, compare E[N] for this design with previous feasible designs. Start the search at p1 p0 p1 p2 z1 z1 1 2 2 p1 p0 !: not unimodal 2 Phase II cancer trials Optimal 2 stage designs with: PT ypeI error 0.05 PT ypeII error 0.20 Efficacy hypotheses p0 p1 0.05 0.25 0.30 0.50 0.70 0.90 r1/n1 0/9 5/15 4/6 Reject drug if r/n 2/17 18/46 22/27 E[N] 12.0 23.6 14.8 PET 0.63 0.72 0.58 Corresponding designs with minimal maximal sample size Efficacy hypotheses p0 p1 0.05 0.25 0.30 0.50 0.70 0.90 Reject drug if r1/n1 r/n 0/12 2/16 6/19 16/39 19/23 21/26 E[N] 13.8 25.7 23.2 PET 0.54 0.48 0.95 Phase II cancer trials Optimal flexible 2 stage designs. In practise it might be difficult to get the sample sizes n1 and n2 exactly at their prespecified values. Solution: let N1{n1, …n1+k} with P(N1=n1j)=1/k, j=1,…k and N2{n2, …n2+k} with P(N2=n2j)=1/k , j=1,…k. N1 and N2 independent, n1+k< n2. P(N1=n1j ,N2=n2j)=1/k2 , j=1,…k. Total samplesize N=N1+N2 Phase II cancer trials For a given combination of n1 +i and n2 +j: EN n1 i 1 PETp0 n2 j n1 i p0 1 p0 Br1; n1 i, p0 i i 1 where PETp 0 r1 Minimize the average E[N] (Average over all possisble stopping points) Phase II cancer trials Flexible designs with 8 consucutive values of n1 and n2. PT ypeI error 0.05 PT ypeII error 0.20 Efficacy hypotheses p0 p1 0.05 0.25 0.30 0.50 0.70 0.90 Reject drug if r1/n1 r/n 0/5-10, 1/11-12 2/17-21, 3/23-24 3/11, 4/12-14 16/40-41, 17/42-44 5/15-16, 6/17-18 18/45-46, 19/47 4/6, 5/7, 6/8, 7/9, 22/27, 23/28-29, 8/10-11, 9/12, 10/13 24/30, 25/31, 26/32-33, 27/34 E[N] 11.8 24.0 PET 0.73 0.68 15.2 0.74 Phase II cancer trials Optimal three stage designs The optimal 2 stage design does not stop it there is a ”long” initial sequence of consecutive failures. First stage: n1 patients: Stop and reject the drug if no successes Second stage: n2 patients: Stop and reject the drug if at most r2 successes Third stage: n3 patients: Stop and reject the drug if at most r3 successes For each n1 such that: 1 p1 n 1 Preject Ha | p1 Determine n2, r2, n3, r3 that minimizes the expected sample size. More? Phase II cancer trials Example: Optimal 3 stage design with n1 at least 5 and PT ypeI error 0.05 PT ypeII error 0.20 Efficacy hypotheses p0 p1 0.05 0.25 0.30 0.50 0.70 0.90 Reject drug if at least r1/n1 0/7 0/5 0/5 r2/n2 1/15 5/15 4/6 r3/n3 3/26 19/49 22/27 E[N] 10.9 22.5 14.8 Stage 1 Overall PET 0.70 0.17 0.00 PET 0.87 0.73 0.58 Phase II cancer trials Multiple-arm phase II designs Say that we have 2 treatments with P(tumour response)=p1 and p2 Select treatment i for further development if pˆ i pˆ j Ambiguous if pˆ i pˆ j Assume p2>p1. The probability of correct secection is PCorr P pˆ 2 pˆ 2 | p1, p2 n n x n x n y I x y n p2 1 p2 p1y 1 p1 x 0 y 0 x y n n Phase II cancer trials The probability of ambiguity is Ambiguous if pˆ i pˆ j PAmb P pˆ 2 pˆ 2 | p1, p2 n n n n x n x n y y I x y n p2 1 p2 p1 1 p1 x 0 y 0 x y Phase II cancer trials Select n such that: PCorr PAmb Probability of outcomes for different sample sizes (=0.05) n 50 50 75 75 100 100 P1 0.25 0.20 0.25 0.20 0.25 0.20 P2 0.35 0.35 0.35 0.35 0.35 0.35 PCorr 0.71 0.87 0.76 0.92 0.76 0.94 PAmb 0.24 0.12 0.21 0.07 0.23 0.06 PCorr+0.5PAmb 0.83 0.93 0.87 0.96 0.87 0.97 Phase II cancer trials Sample size can be calculated approximately by using PCorr P Z Where Z ~ N 0,1 The power of the test of PAmb P Z P Z p2 p1 1 p1 1 p1 p2 1 p2 n H0 : p1 p2 vs. H1 : p1 p2 is given by p2 p1 p2 p1 1 1 Z / 2 Z / 2 Z / 2 is the upper /2 quantile of the standard normal distribution Phase II cancer trials Letting PCorr PAmb it can be showed that: 1 Z / 2 Sample size can be calulated for a given value of . P1 0.05 0.10 0.15 0.20 0.25 0.30 0.35 0.40 P2 0.20 0.25 0.30 0.35 0.40 0.45 0.50 0.55 =0 =0.90 32 38 53 57 71 73 75 76 =0.80 13 15 17 19 31 32 32 33 =0.5 =0.90 16 27 31 34 36 38 46 47 Phase II cancer trials Many phase II cancer trials not randomized Treatment effect can not be estimated due to variations in: •Patient selection •Response criteria •Inter observer variability •Protocol complience •Reporting procedure???? •Sample size (?) Phase III cancer trial It’s all about survival! Diagnosis •Progression free survival •Cause specific survival •All cause survival Treatment Progression Death from the cancer Death from other causes The competing risks model D (t ) Death cused by D Diagnosed with D D (t ) Death from other cause tot (t ) D (t ) D (t ) The aim is to estimate the cause specific survival function S D (t ) for death caused by D. The usual way The cause specific survival, S D (t ), is usually estimated using the cause of death information and standard methods such as Kaplan-Meier or life tables, censoring for causes of death other than D. Problem: The actual cause of death is not always equal to the registered cause of death. The model : tot (t ) D (t ) D (t ) can be formulated using the corresponding survival functions as: Stot (t ) S D (t ) * S D (t ) using t S. (t ) exp . (u )du 0 Estimate: SˆD (t ) Sˆtot (t ) / SˆD (t ) Estimation Stot (t ) can be estimated directly from data. SD (t ) relating to deaths from causes other than D can be estimated using data from a population registry if: D is a ‘rare’ cause of death in the population. The study population has the same risk of dying from other causes as the background population. SD (t ) : the “expected” survival given age, sex and calender year The intuitive way (no formulas) • We have the annual survival probability given age, sex and calender year. • Multiply to get the probability of surviving k years for each individual • Average to get the expected survival. Converting intuition into formulas Individuals i=1 …n, time intervals j=1 to k For each individual we have the “expected” probability Pi (t j ) of surviving time interval j. j 1 I ˆ S D (t j ) Pi (th ) n i 1 h1 n Now is called the Ederer I estimate of the expected survial Problemo age at risk at tj 91 95 88 82 85 77 74 72 72 73 70 66 63 tj t tj+1 All inividuals contributes to I ˆ S D (t j ) Only individuals at risk at tj contributes to Sˆtot (t j ) Solution: Let only individuals at risk contribute to the expected survival. n 1 II ˆ S D (t j ) 1{iI (th )} Pi (th ) h 1 n(t h ) i 1 j where n(t ) is then number of individuals at risk at time t. and I (t ) is the index set of individuals at risk at time t The Ederer II estimate Expected survival for a group pf patients diagnosed with prostate cancer 1992 Ederer I and Ederer II expected survival Expected survival 1 0.9 0.8 0.7 0.6 0.5 0.4 0.3 Ederer I 0.2 0.1 Ederer II 0 0 1 2 3 4 5 6 Time from diagnosis (years) 7 8 9 10 Estimated cause specific survival of patients diagnosed with prostate cancer 1992 1 0.9 cause specific survival 0.8 0.7 0.6 0.5 0.4 0.3 Ederer II 0.2 Life table 0.1 0 0 1 2 3 4 5 Time from diagnosis (years) 6 7 8 Continuous time, expected hazard *i (t ) : ‘expected’ morality (hazard) from the population for individual i. Yi (t ) : at risk indicator for individual i at time t. Y (t ) Yi (t ) : number of individuals at risk i The expected integrated hazard is now given by t n Yi (u ) A (t ) (u ) du Y (u ) 0 i 1 * * i Cont. time relative survival Rewriting the model: tot (t ) D (t ) D (t ) t using integrated hazards we can estimate D (u ) du using 0 =event times X , X ,... D 1 2 i Aˆ D (t ) A* (t ) where Di = # events at time X i X i t Y ( X i ) Now the continuous time relative survival is given by: ˆ (t ) S tot SˆD (t ) exp Aˆ D (t ) Illustrated 1* (t ) *2 (t ) * 3 (t ) * 4 (t ) * 1 (t ) t Illustrated (t ) * 1 (t ) * *2 (t ) * 3 (t ) * 4 (t ) * 1 (t ) t Example Example Population based trials In many countries there are cancer registers where data on all cases of cancer diagnoses are collected. Many countries also have a cause of death registry Intervension Incidence Death Incidence Intervension Death Often observational studies i.e. no randomization.