Archimides

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
1. To observe the buoyant force acting on 
an object immersed in a liquid.
2. To prove that the amount of water 
displaced is equal to the buoyant force.

Tools:
- Beaker- ball –cube -dynamometerVernier Calliper- cube- ball
water
Theory:
Archimedes’ principle states that a body
immersed in a liquid is acted upon by a
buoyant force F, the magnitude of which
is equal to the weight G of the displaced
liquid.
:Laboratory results
1. Buoyant force = (the weight of the
body in the air - the weight of the
body in the liquid)
2. weight of water displaced = volume
of the body × density of water×
gravitational acceleration
The Volume of the cube=L3
The Volume of the ball = π ×4/3 ×r 3
Steps:
1.Susbend a cube in the dynamometer and read its
This is w1.
2.Submerge the cube in the water by raising the
beaker and read its weight . This is w2
3. Repeat stes 1 and 2 using the metal ball
.
4.Find the dimensions of the body using Vernier
caliper and concluded the Volume.
5-Calculate Buoyant force and the weight of
displaced water and then compare them
Data. 
Table1 
Fb= w3 
Objects
W1(air)
W2(water)
w3(airwater)
1.cube
2.ball
Buoyant
force
Table2
W(H2Odisplaced ) =v . ρ . g
Objects
1.cube
2.ball
Volume(m3)
ρ (kg /m3)
g(kg .m/s2) Weight of
water
displaced
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