1-1
1-2
1-3
1-4
1-5
1-6
From the stress-strain diagram Fig. a, the modulus of elasticity for the steel alloy is
𝐸
1
=
290𝑀𝑝𝑎−0
0.001−0
;
E = 290(103 )𝑀𝑝𝑎
When the specimen is unloaded, its normal strain recovered along line AB, Fig. a,
Which has a gradient of E. Thus
500
500𝑀𝑝𝑎
Elastic Recovery =
=
= 0.001724 𝑚𝑚/𝑚𝑚
𝐸
290(103 )𝑀𝑝𝑎
Thus, the permanent set is
∈𝑝 = 0.08 − 0.001724 = 0.07828 𝑚𝑚/𝑚𝑚
Then, the increase in gauge length is
∆L = ∈𝑝 𝐿 = 0.07828(50) = 3.914𝑚𝑚
1-7
1-8
1-9
0
