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Design of Reinforced Concrete Superstructure of DALORA Hospital-Suysoklin Uth-Final Editon

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Reinforced Concrete Design of
Superstructure of DALORA Hospital
Bachelor’s Thesis
Suysoklin UTH
2023
Reinforced Concrete Design of
Superstructure of DALORA Hospital
A thesis submitted to the Department of Civil Engineering
by
Suysoklin UTH
Submitted to:
Sophy CHHANG, Ph.D.
Lida SORN
In Partial Fulfillment of the Requirements for
the Degree of Bachelor of Science in Civil Engineering
Date of submission: July 7th, 2023
THESIS APPROVAL
This thesis has been approved by the Thesis Committee in partial fulfillment of the
requirements for the Degree of Bachelor of Science in Civil Engineering
Entitled
“Reinforced Concrete Design of Superstructure of DALORA Hospital”
Written by
Suysoklin UTH
(ID: 17010201)
Dr. Sophy CHHANG
Supervisor
..................................
Date:
Mr. Lida SORN
First Reader
..................................
Date:
Presentation Date:
Mr. Mengleang LAY
Approved by the Dean of the Engineering
Faculty
July 1st, 2023
..................................
Disclaimer
I hereby declare that this Bachelor’s Thesis is my own original work and has not been
submitted before to any institution for assessment purposes.
Further, I have acknowledged all sources used and have cited these in the reference section.
……………………………..
Signature
……………………………
Date
Acknowledgements
Foremost, I would like to express special gratitude toward my beloved family for their effort, love,
and unconditional support to me. I am thankful for guiding me down the path to become the
better version of myself.
Besides, I would like to express my sincere gratitude to my supervisor, Dr. Sophy CHHANG, for
his helpful information, patience, insightful comments, practical advice, and unceasing ideas that
have pushed me tremendously at all times in my project. His profound experience, immense
knowledge, and professional expertise in structural design have enabled me to complete this thesis
successfully. Without his support and guidance, this endeavor would not be possible.
Last but not least, I would like to thank professors at Paragon International University for being
my judges. I am genuinely grateful and appreciative for their valuable time commenting on my
project and sharing good ideas for better improvement.
Abstract
Midrise reinforced concrete buildings are a fundamental part of the current urban environment,
and their structural implementation is no easy undertaking. The burden of duty falls decisively on
the shoulders of structural engineers, as the margin for error is impossible. As a result, the primary
objectives that guided the work done throughout this bachelor project were extreme precision and
attention to detail. The purpose of this thesis is to provide a detailed explanation of the numerous
processes carried out in relation to the two main elements of the project. The first of them was
the creation of structural design spreadsheets in MathCad Prime to act as manual calculations for
the primary structural members of midrise structures, such as columns, beams, and slabs. These
spreadsheets adhere to the ACI318-19 and ASCE7-16 codes' requirements and limit states. Also
included are the necessary validity checks to ensure the spreadsheets' proper functionality and
accuracy in obtaining results. The second aspect of the project, as thoroughly detailed in the thesis
contents, is the use of the finite element analysis software ETABS for structural modeling, analysis,
and design. ACI318-19 and ASCE7-16 are the two basic codes used for structural member design
in ETABS. This branch project's featured tasks include: creating a structural plan, performing
preliminary design of structural members, gathering required loads for the structural design,
performing precise structural analysis, identifying design demands, designing reinforced concrete
structural members, and preparing final structural drawings.
Keywords: Reinforced Concrete Structure, Structural Analysis, Wind Loads, Drift
Contents
List of Figures ................................................................................................................................................................ i
List of Tables ............................................................................................................................................................... iii
Chapter 1: Introduction .............................................................................................................................................. 1
1.1
Introduction................................................................................................................................................ 1
1.2
Project Description ................................................................................................................................... 1
1.3
Objective ..................................................................................................................................................... 2
1.4
Scope and Limitation ................................................................................................................................ 2
Chapter 2: Literature Review ..................................................................................................................................... 3
2.1
Reinforced Concrete ................................................................................................................................. 3
2.1.1
Advantages of Reinforced Concrete ............................................................................................. 3
2.1.2
Disadvantages of Reinforced Concrete ........................................................................................ 3
2.2
Design Loads .............................................................................................................................................. 4
2.2.1
Dead loads ......................................................................................................................................... 4
2.2.2
Live Loads ......................................................................................................................................... 4
2.2.3
Wind Loads ....................................................................................................................................... 5
2.2.4
Loads combination ......................................................................................................................... 13
2.3
Structural Analysis ................................................................................................................................... 13
2.3.1
Participation of Structural Analysis in Structural Engineering Projects. ............................... 14
2.3.2
Slenderness effects ......................................................................................................................... 15
2.3.3
Linear Elastic Frist-order Analysis............................................................................................... 17
2.3.4
Linear Elastic Second-order Analysis .......................................................................................... 19
Chapter 3: Methodology ........................................................................................................................................... 20
3.1
Preliminary Design of Structural Members ......................................................................................... 20
3.1.1
Pre-Dimensioning of Slabs ........................................................................................................... 20
3.1.2
Pre-Dimensioning of Beams ........................................................................................................ 20
3.1.3
Pre-Dimensioning of Columns .................................................................................................... 21
3.2
Load Assumption .................................................................................................................................... 22
3.2.1.
Dead Load ....................................................................................................................................... 22
3.2.2.
Live Loads ....................................................................................................................................... 22
3.2.3.
Wind Loads ..................................................................................................................................... 23
3.3
Rectangular Beam Design ...................................................................................................................... 24
3.3.1.
Flexural Design of Rectangular Beam ......................................................................................... 25
3.3.2.
Shear Design of Rectangular Beam ............................................................................................. 26
3.3.3.
Torsional Design of Rectangular Beam ...................................................................................... 27
3.3.4.
Deflection Check of Rectangular Beam ..................................................................................... 28
3.4
Column Design ........................................................................................................................................ 31
3.4.1.
Preliminary Design of Column Cross-section and Reinforcement ........................................ 31
3.4.2.
Checking for Sway or Non-sway Column .................................................................................. 32
3.4.3.
Checking Strength of Column by P-M Interaction Diagram .................................................. 34
3.4.4.
Shear Design for Rectangular Column ....................................................................................... 35
Chapter 4: Finding and Result ................................................................................................................................. 37
4.1.
Pre-Dimension of Structural Members ................................................................................................ 37
4.1.1.
Pre-Dimension of Slabs................................................................................................................. 37
4.1.2.
Pre-Dimension of Beams .............................................................................................................. 37
4.1.3.
Pre-Dimension of Columns.......................................................................................................... 38
4.2.
Load Assumption .................................................................................................................................... 39
4.2.1.
Dead Load ....................................................................................................................................... 39
4.2.2.
Live Loads ....................................................................................................................................... 40
4.2.3.
Wind Loads ..................................................................................................................................... 40
4.2.4.
Load Combinations ........................................................................................................................ 44
4.3.
Structural Modeling in ETABS ............................................................................................................. 44
4.3.1.
Defining Gridline and Stories....................................................................................................... 44
4.3.2.
Defining Material and Section Properties................................................................................... 46
4.3.3.
Modeling of Structural Members ................................................................................................. 48
4.3.4.
Stiffness Modifiers.......................................................................................................................... 49
4.3.5.
Checking for Sway or Non-sway ................................................................................................. 50
4.3.6.
Second-order Effects Consideration ........................................................................................... 52
4.3.7.
Checking Model and Running Analysis ...................................................................................... 53
4.4.
Slab Design ............................................................................................................................................... 54
4.4.1.
Flexural Design of Slab ................................................................................................................. 54
4.4.2.
Shear Design of Slab ...................................................................................................................... 56
4.4.3.
Checking Slab Deflection .............................................................................................................. 56
4.5.
Beam Design ............................................................................................................................................ 59
4.5.1.
Hand Calculation Design of Beam .............................................................................................. 59
4.5.2.
Beam Design in ETABS................................................................................................................ 67
4.5.3.
Beam B25x50 Discussion & Summary ....................................................................................... 69
4.6.
Column Design ........................................................................................................................................ 71
4.6.1.
Colum Design in ETABS.............................................................................................................. 71
4.6.2.
P-M Interaction Diagram .............................................................................................................. 71
4.6.3.
Determining of Column Lap Splice Length............................................................................... 79
4.6.4.
Colum Detailing.............................................................................................................................. 80
4.7.
Checking Building and Story Drift ....................................................................................................... 81
4.7.1.
Overall Building Drift .................................................................................................................... 81
4.7.2.
Inter-Story Drift ............................................................................................................................. 82
Chapter 5: Conclusion ............................................................................................................................................... 83
APPENDIX AARCHITECTURAL PLAN OF DALORA HOSPITAL ............................................... 84
APPENDIX BFLOW CHART OF THE DESIGN OF STRUCTURAL MEMBERS ....................... 91
APPENDIX CSTRUCTURAL DETAILING OF DALORA HOSPITAL......................................... 100
References............................................................................................................................................................. 133
List of Figures
Figure 1.1 Perspective view of DALORA Hospital ............................................................................................... 1
Figure 2.1 Concrete Composition ............................................................................................................................. 3
Figure 2.2 Exposure B Type 1 ................................................................................................................................... 7
Figure 2.3 Exposure B Type 2 ................................................................................................................................... 8
Figure 2. 4 Exposure B Type 3 .................................................................................................................................. 8
Figure 2.5 Exposure C Type 1 ................................................................................................................................... 8
Figure 2.6 Exposure C Type 2 ................................................................................................................................... 9
Figure 2.7 Exposure D ................................................................................................................................................ 9
Figure 2.8 Phases of a Typical Structural Engineering Project........................................................................... 14
Figure 2.9 Primary and secondary moment for beam-columns. ........................................................................ 15
Figure 2.10 Effective length factor k ...................................................................................................................... 16
Figure 2.11 Flowchart for determining column slenderness effects (ACI 318-19, Fig. R6.2.5.3). ............... 17
Figure 3.1 P-M Interaction diagram ........................................................................................................................ 34
Figure 4.1 Grid Line system data ............................................................................................................................ 45
Figure 4.2 Story data of the building ...................................................................................................................... 45
Figure 4.3 Defined grid line of DALORA Hospital project ............................................................................... 46
Figure 4.4 Defining material properties ................................................................................................................. 46
Figure 4.5 Defining section properties in ETABS ............................................................................................... 47
Figure 4.6 Structural modeling of DALORA Hospital ....................................................................................... 48
Figure 4.7 Ground floor plan of DALORA Hospital ......................................................................................... 49
Figure 4.8 Stiffness modifier in ETABS ................................................................................................................ 49
Figure 4.9 P-Delta option in ETABS ..................................................................................................................... 52
Figure 4.10 Column meshing in ETABS ............................................................................................................... 53
Figure 4.11 Analysis messages after running analysis in ETABS ....................................................................... 53
Figure 4.12 DALORA structural mode after running analysis ........................................................................... 54
Figure 4.13 Moment’s diagram from finite element analysis. ............................................................................. 54
Figure 4.14 Shear diagram from finite element analysis ...................................................................................... 56
Figure 4.15 Beam B25x50 on First Floor............................................................................................................... 59
Figure 4.16 M3 moment of B25x50 ........................................................................................................................ 60
Figure 4.17 Tension Reinforcement of Rectangular Beam B25x50 Cross-section ......................................... 61
Figure 4.18 Beam design in ETABS ....................................................................................................................... 68
Figure 4.19 Transverse reinforcement required area in ETABS ........................................................................ 69
Figure 4.20 Detailing of beams along gird line 4 .................................................................................................. 70
Figure 4.21 Interaction diagram for section C30x40............................................................................................ 73
i
Figure 4.22 P-M Interaction diagram in 2-axis direction of C3x40 for combo U7......................................... 75
Figure 4.23 P-M Interaction diagram in 3-axis direction of C3x40 for combo U7......................................... 75
Figure 4.24 P-M Interaction diagram in 2-axis direction of C3x40 for combo U11 ...................................... 77
Figure 4. 25 P-M Interaction diagram in 3-axis direction of C3x40 for combo U11 ..................................... 77
Figure 4.26 C2(300mmx400mm) column cross-section ...................................................................................... 80
Figure 4.27 Elevation detailing of C2(300mmx400mm) ..................................................................................... 80
Figure 4.28 Diagram of building drift..................................................................................................................... 81
Figure 4.29 Diagram of story drift .......................................................................................................................... 82
List of Tables
Table 2.1 Minimum Floor Live Loads for Buildings ............................................................................................. 5
Table 2.2 Risk Category of Buildings and Other Structures for Wind Loads .................................................... 6
Table 2.3 Basic wind speeds in Phnom Penh .......................................................................................................... 6
Table 2.4 Wind Directionality Factor ....................................................................................................................... 7
Table 2.5 Exposure Categories .................................................................................................................................. 7
Table 2.6 Internal Pressure Coefficient, GCpi, for Enclosed, Partially Enclosed, Partially Open, and Open
Buildings ...................................................................................................................................................................... 11
Table 2.7 Velocity Pressure Exposure Coefficient, Kh and Kz........................................................................... 12
Table 2.8 Wall Pressure Coefficient, Cp ................................................................................................................. 12
Table 3.1 Minimum thickness of solid non-prestressed slabs. ........................................................................... 20
Table 3.2 Minimum depth of non-prestressed beams ......................................................................................... 21
Table 3.3 Maximum permissible calculated deflections....................................................................................... 29
Table 3. 4 Modular ratio for normal-weight concrete.......................................................................................... 29
Table 3. 5 Time dependent factor for sustain loads ............................................................................................. 31
Table 4.1 Beam dimensions ..................................................................................................................................... 38
Table 4.2 Column cross-section dimensions ......................................................................................................... 39
Table 4.3 Super imposed dead load for floor ........................................................................................................ 39
Table 4.4 Super imposed dead load of brick walls and curtain wall .................................................................. 40
Table 4.5 Live loads for DALORA Hospital project........................................................................................... 40
Table 4.6 Velocity pressure coefficient................................................................................................................... 41
Table 4.7 Velocity pressure ...................................................................................................................................... 41
Table 4.8 Wind pressure on windward walls ......................................................................................................... 42
Table 4.9 Ultimate limit state wind load parameters for ETABS ...................................................................... 43
Table 4.10 Serviceability limit state wind load parameter for ETABS .............................................................. 43
Table 4.11 Stiffness modifier values ....................................................................................................................... 49
Table 4.12 Stability index in X-direction ................................................................................................................ 50
Table 4.13 Stability index in Y-direction ................................................................................................................ 50
Table 4.14 Upper column and beams dimension ................................................................................................. 51
Table 4.15 Lower column and beams dimension ................................................................................................. 51
Table 4.16 Beam B25x50 cross-section .................................................................................................................. 69
Table 4.17 Column cross-section and its provided reinforcement area ............................................................ 71
Table 4.18 P-M Interaction diagram of C2 in 2-axis direction ........................................................................... 72
Table 4.19 P-M Interaction diagram of C2 in 3-axis direction ........................................................................... 72
Table 4.20 Summary of factored loads and capacity ratio of C30x40 ............................................................... 73
iii
Table 4.21 Values of design axial force and moment in 2-axis direction.......................................................... 74
Table 4.22 Values of design axial force and moment in 3-axis direction.......................................................... 74
Table 4.23 Summary values of Pnx-2 and Pny-3 for combo U7 .............................................................................. 76
Table 4. 24 Summary values of Pnx-2 and Pny-3 for combo U11 ........................................................................... 78
Table 4.25 Story Response Values of building drift ............................................................................................. 81
Table 4.26 Story response values of story drifts ................................................................................................... 82
Chapter 1: Introduction
1.1
Introduction
The Kingdom of Cambodia is a developing nation in every aspect throughout the country. The
construction industry is one of those that has noticeable development recently. There are many buildings
was built in the last decade such as schools, hospital, commercial buildings, hotels, apartments, industrial
buildings, governmental buildings, residential buildings, etc. With the rapidly growth rate in economic
movement, increasing of population and urbanization, and many investors from abroad, it led to the raise
in price of land in Phnom Penh city. Due to the high price of land, all investors tend to invest more in midrise and high-rise buildings because such buildings required small area of land and produce more space for
users.
Nowadays, mid-rise building is a more widely utilized construction type in Cambodia. Mid-rise
buildings are those that have an elevation of 4 to 8 stories or a maximum height of 25 meters. Given their
established size, mid-rise structures offer a significant amount of room and are thus a practical solution to
many housing issues. They are used for a variety of purposes, including as residential apartments,
commercial buildings, offices, hotels, and even hospital facilities.
An appropriate construction material that could enable the mid-rise structure to stand stronger
for a long period of time and guarantee safety to the users was necessary for its development. Reinforced
concrete is the most typical material that is frequently utilized in many different structures around the world.
This highlights its importance to the field of structural engineering.
1.2 Project Description
My project is a hospital building drawn by architectural
design team of my company including me as well. The location of
the building is at Kilometer 6, 278H, Street 201R, Kroalkor Village,
Songkat Chrang Chomres 2, Khan Russey Keo, Phnom Penh. This
hospital has a width of 11.35m and length of 31.35m with total floor
area of 1586 m2. It is a 4 stories building with a total height of 19.9
m. The ground floor contains important functions such as
emergency room, lobby, pharmacy, scan room, x-ray room,
laboratory, doctor cabin, toilets, and storages. For the mezzanine
floor contains mostly the office functions such as manager room,
accounting room, meeting room, medical equipment storage,
medicine storage, canteen staff room, sweeper and toilets. More than
half of the area of the first floor is used as ward for patients and the
remaining space contains operation room, labor room, nurse station,
medical equipment storage, and toilets. The second floor is used for
wards with toilet separately in each ward. Lastly it is a terrace floor
on the top of the buildings. For more detailed about the layout plan
and elevation of the building can be found in Appendix A.
1
Figure 1.1 Perspective view of
DALORA Hospital
1.3 Objective
The purpose of this dissertation is to design reinforced concrete of superstructure of a hospital
building by following the ACI318-19 and ASCE7-16 code and that will ensure a practical design process
and methods that used in the design and analysis process. Also, this project aims to generate structural
detailing of each designed structural elements of the selected building.
1.4 Scope and Limitation
The scopes of this study are to design the superstructure elements of the building including slabs,
beams, columns. The design can be done by producing hand calculation of each structural elements and
adopting the use of finite element structural analysis software, ETABS. Then doing the comparison of hand
calculation and result from software to clarify that the design is acceptable. Furthermore, the construction
drawing will be generated by following the reinforcement detailing in ACI 318-19.
There are also some limitations to this particular project such as the design of foundation, MEP
system, cost estimation and project management which will not be included due to time restriction as well
as studies that are beyond our educational profile.
2
Chapter 2: Literature Review
2.1
Reinforced Concrete
In the modern construction industry, concrete is
the most fundamental construction material. Concrete is a
mixture of fine aggregate (sand), coarse aggregate (gravel,
crushed rock, or other aggregates) held together in a rock
like mass with a paste of cement and water. Admixtures
are sometimes used in the concrete mixing process to
produce additional chemical properties, such as
retardation and acceleration of setting time, reducing
shrinkage, and corrosion prevention.
Concrete is a construction material that produce
highly compressive strength, but with a very low tensile
strength with roughly about 8% of the available
compressive strength to resist tensile stress. As a result,
cracks appear if tensile stresses exceed the concrete’s
tensile strength due to loads, restricted shrinkage, or
temperature variations. To avoid such failure, steel
Figure 2.1 Concrete Composition
reinforcements must be used in the tension zones, referred
to as singly reinforced concrete, and sometimes in both
compression and tension zones, referred to as doubly reinforced concrete, to improve flexural and torsional
strength, increase ductility, reduce deflection, and even resist the more complex seismic loading during
earthquake, known as moment reverse, which is beyond the scope of the dissertation.
2.1.1 Advantages of Reinforced Concrete
Reinforced concrete may be the most essential construction material available. Almost all
structures, large and small buildings, bridges, pavements, dams, retaining walls, tunnels, drainage and
irrigation systems, tanks, and so on, utilize it in one form or another. When the multiple benefits of this
universal construction material are evaluated, it is easy to see why it has been such a huge success. The
following are some of the advantages of reinforced concrete:







High compressive strength per unit cost
Great resistance to fire and water
Provide rigidity for structure
Low-maintenance material
Long service life with proper design
The only economical material available for footing, floor slabs, basement walls, piers, and
similar application
Ability to be cast into an extraordinary variety of shapes
2.1.2 Disadvantages of Reinforced Concrete
To use concrete effectively, the engineer must be thoroughly conversant with both its strength and
weak characteristics. The following are some of its disadvantages:
3




Concrete has very low tensile strength (required the use of tensile reinforcement)
Forms are required to hold the concrete in place until it hardens sufficiently. Formwork is
also quite costly.
Low strength per unit weight of concrete leads to heavy the members.
Larger structural members
Properties of concrete vary widely because of variation of its proportioning and mixing (quality control
problems).
2.2
Design Loads
Loads are commonly regarded as forces that result in stresses, deformations, or accelerations. A
structural engineer's objective is to design a structure that can endure all of the loads it is subjected to while
still performing its desired purpose throughout the duration of that structure's intended life. So, when
designing a structure, an engineer must take into account all the loads that can be reasonably anticipated to
act on the structure during the period of its intended life. Generally, the loads acting on typical civil
engineering structures can be divided into three categories: (1) dead loads deriving from the weight of the
structural system itself and any other material permanently attached to it; (2) live loads, which are movable
or moving loads resulting from the use of the structures; and (3) environment loads due to natural effects, such
as wind, snow, and earthquakes. An engineer must estimate the magnitudes of the design loads as well as
the potential that some of these loads could act on the structure at the same time. Thus, the structure is
designed to be capable of handling the worst load combinations that are likely to happen during the duration
of its lifespan.
The minimum design loads and the load combinations for which the structures must be designed
can be received from ASCE STANDARD Minimum Design Loads and Associated Criteria for Buildings and Other
Structures (ASCE/SEI 7-16) [5].
2.2.1 Dead loads
Dead loads are the initial vertical load to be taken into account in the structural design process.
They are constant magnitude and fixed position gravity loads that act on the structure permanently
throughout its lifetime. These loads include all of the weights of the equipment and materials that are
permanently connected to the structural system, as well as the weight of the structure system itself.
Typically, the dead loads of a building structure include the weight of all building components, such as
walls, floors, beams, columns, roofs, ceilings, stairways, built-in partitions, finished, cladding, framing and
bracing systems, heating and air-conditioning systems, plumbing, electrical systems, and so forth.
Additionally, fixed service equipment like cranes and material handling systems are included as well. Each
structure's dead loads are determined by multiplying the unit weight by the volume of each element [5].
2.2.2 Live Loads
Live loads are the dynamic forces resulting from building’s occupancy and intended use. They
represent the temporary forces that might pass through the building or exert pressure on a particular
structural component. The estimated weight of people, furniture, appliances, automobiles, movable
equipment, and the like is included in these loads. The magnitudes of design live loads are usually specified
in building codes. Each member of the structure must be designed for the location of the load that produces
the most stress on that member since the position of a live load may fluctuate. Different structural members
may experience their highest amounts of stress at different positions of the given load.
According to ASCE 7-16 code, live loads for buildings are typically specified as uniform distributed
surface loads in kilopascals. Table 2.1 below lists some minimum floor live loads for various common
building types [5].
4
Table 2.1 Minimum Floor Live Loads for Buildings
Occupancy or Use
Hospital patient rooms, residential dwellings, apartments, hotel guest rooms,
school classrooms
Library reading rooms, hospital operating rooms and laboratories
Live Load (kPa)
1.92
2.87
Dance halls and ballrooms, restaurants, gymnasiums
4.79
Light manufacturing, light storage warehouses, wholesale stores
6.00
Heavy manufacturing, heavy storage warehouses
11.97
2.2.3 Wind Loads
Wind loads are produced by the flow of wind around the structure. The magnitudes of wind loads
that may act on a structure depend on the geographical location of the structure, obstructions in its
surrounding terrain, such as nearby buildings, and the geometry and the vibrational characteristics of the
structure itself. The wind speed V to be used in the determination of the design loads on a structure depends
on its geographical location.
The step to determine the wind loads on the Main Wind Force Resisting System (MWFRS) using
directional procedure for enclosed, partially enclosed, and open buildings of all heights are provided below
(ASCE 7-16, section 27.2) [5]:
 Step 1: Determine Risk Category of building
 Step 2: Determine the basic wind speed, , for the applicable Risk Category
 Step 3: Determine the wind load parameters:
 Wind directionality factor,


Exposure category
Topographic factor,

Ground elevation factor,

Gust-effect factor,


Enclosure classification
Internal pressure coefficient,
or
 Step 4: Determine velocity pressure exposure coefficient,
 Step 5: Determine velocity pressure or
 Step 6: Determine external pressure coefficient,
or
or
 Step 7: Calculate wind pressure, , on each building surface
a) Risk Category of Building
Buildings and other structures shall be classified, based on the risk to human life, health, and
welfare associated with their damage or failure by nature of their occupancy or use, according to Table 2.2
for the purposes of applying food, wind, snow, earthquake, and ice provisions. Each building or other
structure shall be assigned to the highest applicable Risk Category or Categories [5].
5
Table 2.2 Risk Category of Buildings and Other Structures for Wind Loads
Occupancy or use of Buildings and Structures
Buildings and other structures that represent low risk to human life
in the event of failure
All buildings and other structures except those listed in Risk
Categories I, III, and IV
Buildings and other structures, the failure of which could pose a
substantial risk to human life
Importance Factor,
Category
Wind loads
0.87
for V45 m/s
I
0.77 for V>45 m/s
II
1.00
III
1.15
IV
1.15
Buildings and other structures, not included in Risk Category IV,
with potential to cause a substantial economic impact and/or mass
disruption of day-to-day civilian life in the event of failure
Buildings and other structures not included in Risk Category IV
(including, but not limited to, facilities that manufacture, process,
handle, store, use, or dispose of such substances as hazardous fuels,
hazardous chemicals, hazardous waste, or explosives) containing
toxic or explosive substances where the quantity of the material
exceeds a threshold quantity established by the Authority Having
Jurisdiction and is sufficient to pose a threat to the public if released
Buildings and other structures designated as essential facilities
Buildings and other structures, the failure of which could pose a
substantial hazard to the community Buildings and other structures
(including, but not limited to, facilities that manufacture, process,
handle, store, use, or dispose of such substances as hazardous fuels,
hazardous chemicals, or hazardous waste) containing sufficient
quantities of highly toxic substances where the quantity of the
material exceeds a threshold quantity established by the Authority
Having Jurisdiction and is sufficient to pose a threat to the public if
released
Buildings and other structures required to maintain the functionality
of other Risk Category IV structures
b) Basic wind speed
According to a case study related to basic wind speed analysis and serviceability evaluation of tall
reinforced concrete building in Phnom Penh [10], the basic wind speeds for various return periods are listed
in Table 2.3.
Table 2.3 Basic wind speeds in Phnom Penh
Return Period (Year)
10
20
50
100
200
500
700
1000
Basic Wind Speed (m/s)
30.16
32.45
35.42
37.65
39.87
42.80
43.87
45.01
6
c) Wind directionality factor,
The wind directionality factor,
indicated in Table 2.4.
, shall be determined based on the types of structure which is
Table 2.4 Wind Directionality Factor
Structure Type
Main Wind Force Resisting System
Buildings
Components and Cladding
Directionality Factor,
0.85
0.85
d) Exposure category
The upwind exposure for each wind direction considered shall be based on ground surface
roughness as determined by natural topography, vegetation, and constructed facilities. According to ASCE
7-16 (Section 26.7), the exposure category is categorized into 3 categories as shown in Table 2.5.
Table 2.5 Exposure Categories
Constants
Exposure
B
C
D
365.76
274.32
213.36
7.0
9.5
11.5
Exposure B(a): Suburban residential
area with mostly single-family dwellings. Lowrise building structures, less than 30 ft (9.1 m)
high.
Figure 2.2 Exposure B Type 1
7
Exposure B(b): Urban area with
numerous closely obstructions having the size
of single-dwellings or larger.
Figure 2.3 Exposure B Type 2
Exposure B(c): Structures in the
foreground are located in exposure B.
Structures in the center of the photograph
adjacent to the clearing to the left, which is
greater than approximately 656 ft (200 m).
Figure 2. 4 Exposure B Type 3
Exposure C(a): Flat open grassland
with scattered obstructions having heights
generally less than 30 ft (9.1 m).
Figure 2.5 Exposure C Type 1
8
Exposure C(b): Open terrain with
scattered obstructions having heights generally
less than 30 ft (9.1 m). for most wind directions,
all one-story structures with a mean roof height
less than 30 ft (9.1 m) in the photograph are less
than 1,500 ft (457 m) or 10 times the height of
the structure, whichever is greater, from an
open field that prevents the use of exposure B.
Figure 2.6 Exposure C Type 2
Exposure D: A building at the
shoreline (excluding shorelines in hurricaneprone regions) with wind flowing over open
water for a distance of at least one mile.
Figure 2.7 Exposure D
e) Topographic factor,
When the site conditions and the location of buildings and other structures meet all of the 5
conditions specified in ASCE 7-16, Section 26.8.1, wind speed-up effects at isolated hills, ridges, and
escarpments that represent sudden changes in the general topography and are located in any exposure
category shall be included in the determination of the wind loads. The wind speed-up effect shall be
included in the calculation of design wind loads by using the factor
:
Since the site conditions and locations of buildings in this project do not meet all those 5
conditions, then
.
f) Ground elevation factor,
The ground elevation factor to adjust for air density,
elevations.
9
, is permitted to take
for all
g) Gust-effect factor,
or
The determination of whether a building or other structure is rigid or flexible is the first procedure
for identifying the gust-effect factor, or
.
According to ASCE 7-16 Commentary C26.2:


If
If
, the building is rigid.
, the building is flexible.
The approximate lower bound natural frequency
buildings, is permitted to determine as follow:
, in hertz, of concrete or masonry shear wall
(ASCE 7-16, Eq. 26.11-5)
where
where
: mean roof height, (m)
: number of shear walls in the building effective in resisting lateral forces in the direction
under consideration.
: base area of the building, (m2)
: horizontal cross-sectional area of shear wall , (m2)
: length of shear wall , (m)
: height of shear wall , (m)
 For rigid buildings or other structures, the gust effect factor shall be taken as 0.85.
 For flexible or dynamically sensitive buildings or other structures, the gust effect factor shall be
calculated by
(ASCE 7-16, Eq. 26.11-10)
h) Enclosure classification
For the purpose of determining internal pressure coefficients, according to ASCE 7-16 section
26.12, all buildings shall be classified as enclosed, partially enclosed, partially open, or open.

Enclosed building: A building that has the total area of openings in each wall, that
receives positive external pressure, less than or equal to 4 sq ft (0.37 m2) or 1% of the area
of that wall, whichever is smaller. This condition is expressed for each wall by the
following equation:
, or 4 sq ft (0.37m2), whichever is smaller,

Partially enclosed building: A building that complies with both of the following
conditions:
- The total area of openings in a wall that receives positive external pressure exceeds
the sum of the areas of openings in the balance of the building envelope (walls and
roof) by more than 10%.
10
-


The total area of openings in a wall that receives positive external pressure exceeds 4
ft2 (0.37 m2) or 1% of the area of that wall, whichever is smaller, and the percentage
of openings in the balance of the building envelope does not exceed 20%.
Partially open building: A building that does not comply with the requirements for open,
partially enclosed, or enclosed buildings.
Open building: A building that has each wall at least 80% open. This condition is
expressed for each wall by the equation
.
where
: total area of openings in a wall that receives positive external pressure, in m2
: the gross area of that wall in which
is identified, in m2
: sum of the areas of opening in the building envelope (wall and roof) not
including , in m2
: sum of the gross surface areas of the building envelope not including
, in
m2
i)
Internal pressure coefficient,
Internal pressure coefficients, (
), shall be determined form Table 2.6 based on building
enclosure classifications, (ASCE 7-16, section 26.13).
Table 2.6 Internal Pressure Coefficient, GCpi, for Enclosed, Partially Enclosed, Partially Open,
and Open Buildings
Enclosure Classification
Criteria for Enclosure Classification
or 0.37 m2
Enclosed buildings
is less than the smaller of
and
Partially enclosed buildings
and
the lesser of
or 0.37
m2 and
A building that does not comply with Enclosed,
Partially Enclosed, or Open classifications
Each wall is at least 80% open
Partially open buildings
Open buildings
j)
Velocity pressure exposure coefficient,
Internal
Pressure
Internal
Pressure
Coefficient,
(
)
Moderate
+0.18
-0.18
High
+0.55
-0.55
Moderate
+0.18
-0.18
0.00
Negligible
or
According to ASCE 7-16 section 26.10.1, based on the exposure category, a velocity pressure
exposure coefficient,
or , as applicable shall be determined by the below equation or from Table 2.6.
The velocity pressure exposure coefficient may be determined from the following formula:

For
,
 For
,
 and are tabulated in Table 2.7.
11
Table 2.7 Velocity Pressure Exposure Coefficient, Kh and Kz
Height above Ground
Level, z (m)
0-4.6
6.1
7.6
9.1
12.2
15.2
18.0
21.3
24.4
27.4
30.5
Exposure
C
0.85
0.9
0.94
0.98
1.04
1.09
1.13
1.17
1.21
1.24
1.26
B
0.57
0.62
0.66
0.70
0.76
0.81
0.85
0.89
0.93
0.96
0.99
D
1.03
1.08
1.12
1.16
1.22
1.27
1.31
1.34
1.38
1.40
1.43
k) Velocity pressure,
Velocity pressure,
equation:
, evaluated at height z above ground shall be calculated by the following
(ASCE 7-16, Eq. 26.10-1.si)
l)
External pressure coefficient, C p
According to ASCE 7-16 (Fig. 27.3-1), the external pressure coefficient, C p can be determined
based on the wall surface the building as shown in Table 2.8.
Table 2.8 Wall Pressure Coefficient, Cp
Cp
L/B
All values
0-1
2
4
All values
Surface
Windward wall
Leeward wall
Sidewall
Use with
0.8
-0.5
-0.3
-0.2
-0.7
m) Wind pressure
Design wind pressures for the MWFRS of buildings of all heights in (N/m2), shall be determined
by the following equation, according to ASCE 7-16 (section 27.3.1):
(ASCE 7-16, Eq. 27.3-1)
where
: for windward walls evaluated at height above the ground.
: for leeward walls, sidewalls, and roofs elevated at height .
: for windward walls, sidewalls, leeward walls, and roof of enclosed buildings, and
for negative internal pressure elevation in partially enclosed buildings.
: for positive internal pressure evaluation in partially enclosed buildings where height
is defined as the level of the highest opening in the building that could affect the positive
internal pressure.
12
2.2.4 Loads combination
An engineer must take into account all loads that may occur simultaneously on a structure at a
given time after estimating the magnitudes of the design loads for the structure. In the end, the structure is
made to be able to endure the worst possible combination of loads that could happen throughout its
lifetime. Based on past experience and probability analysis, the ASCE 7-16 specifies various load
combinations to be considers when designing structures as shown below:
1.
2.
3.
4.
5.
6.
7.
where
: is dead load
: is live load
: is roof live load
: is snow load
: is rain load
: is wind load
: is earthquake-induced load
In addition to the aforementioned strength or safety requirements, a structure must also satisfy any
serviceability requirements related to its intended use. For example, a high-rise building may be perfectly
safe, yet unserviceable if it deflects or vibrates excessively due to wind. The unserviceability requirements
are specified in building codes for most common types of structures and usually concerned with deflections,
vibrations, cracking, corrosion, and fatigue.
Drifts (lateral deflections) of concern in serviceability checking arise primarily from the effects of
wind. Drift limits in common usage for building design are on the order of 1/600 to 1/400 of the building
or story height. Use of the nominal wind load in checking serviceability is excessively conservative. The
following combination can be used to check short-term effect:
D  0.5 L  Wa
Where Wa : is wind load based on serviceability wind speeds.
2.3
Structural Analysis
A structure can be described as an assortment of interconnected components known as elements
that allow for the transmission of forces. The forces are generated by loads on the structure, and the
elements are designed to transfer these forces to the foundations. Furthermore, a structure will have a
specific shape to enable it to perform useful functions such as providing an enclosed space. This is the
function of a building's structure in general.
As a structural engineer, several technical decisions about structural systems will have to be
considered thoroughly while working on the design of buildings. These decisions involve choosing a strong,
13
affordable, and visually appealing structural form; assessing its safety, that is, its stiffness and strength; and
organizing its erection under temporary construction loads.
Structural analysis is so significant for every structural designer that they should learn how to
conduct it properly. By definition, structural analysis is a mathematical algorithmic procedure used to
determine how a structure will react to specified loads and actions. The generated internal forces and
displacements or deformations across the entire structure are used to measure the response.
2.3.1 Participation of Structural Analysis in Structural Engineering
Projects.
Structural engineering is a process of planning, designing, and constructing structures that meet
their desired purposes. It is an art and science that comprehends the behavior of structural components
under specific loads and designs them to be cost-effective and dignified in order to provide a safe, useful,
and long-lasting framework. For structural engineers, structural analysis is a crucial phase because it allows
them to completely understand the specific load paths and the effects that various types of loads have on
their structural design. The process of structural design involves various phases as indicated in the flowchart
in Fig. 2.8.
Figure 2.8 Phases of a Typical Structural Engineering Project
1. Planning Phase: The planning phase typically includes consideration of the functional
requirements of the proposed structure, its layout plan and dimensions, as well as any
potentially practical structures types (e.g., rigid frames or trusses) and types of materials
(e.g., reinforced concrete of steel) that will be used. The primary consideration is the
function of the structure. Secondary considerations such as aesthetics, sociology, law,
economics and the environment impact may also be taken into account. In addition, there
are structural and constructional requirements and limitations, which may affect the type
14
2.
3.
4.
5.
6.
of structure to be designed. Typically, the result of this phase is a structural system that
satisfies the functional requirements and is anticipated to be the most cost-effective.
Preliminary Structural Design: Preliminary design is a quick, rough estimation, manual
method of designing a structure. The sizes of the various structural system members
chosen during the planning phase are estimated during the preliminary structural design
phase. The estimation is based on an approximation of the analysis, previous experience,
and code requirements. The chosen member sizes are then applied to the next step, which
involves estimating the structure's self-weight.
Estimation of Loads: Load estimation means the evaluation all of the loads that could
potentially affect the structure.
Structural Analysis: The loads' values are utilized in structural analysis to conduct the
analysis of the structure and find the stresses or stress results in the members, as well as
the deflection at various points of the structure.
Safety and Serviceability Checks: The analysis's results are used to verify whether or
not the structure complies with the design codes' standards for serviceability and safety.
The design drawings and construction specifications are generated, and the construction
phase starts, if these conditions are fulfilled.
Revised Structural Design: If the code specifications are not fulfilled, the member sizes
are revived, and phases 3 to 5 are repeated until all safety and serviceability requirements
are met.
2.3.2 Slenderness effects
The effect of slenderness ratio (ratio of unbraced length
to radius of gyration ) must be taken
into account in the design of compression members. Design moments may increase significantly as a result
of increased eccentricity of the axial compressive force due to lateral deflections in compression members
and, in some cases, the buckling may govern the axial compressive strength of the member. In addition,
slender members will deflect more under any primary bending moment, thus having a larger secondary
moment, which is the product of the axial compression and lateral deflection.
Figure 2.9 Primary and secondary moment for beam-columns.
Second-order effects in many structures are negligible. In some cases, it is unnecessary to consider
slenderness effects, so that compression members, such as columns, walls, or braces, can be designed based
on forces determined from first-order analyses. According to ACI 318-19, slenderness effects can be
neglected in both braced and unbraced systems if (a) or (b) equation is satisfied:
(a) For columns not braced (sway) against sidesway
15
(ACI 318-19, equation 6.2.5.1a)
(b) For column braced (non-sway) against sidesway
(ACI 318-19, equation 6.2.5.1b)
and
(ACI 318-19, equation 6.2.5.1c)
Where
: effective length factor
: actual unsupported length of column.
: radius of gyration;
(rectangular column)
: are numerically the smaller and larger first order bending moments, respectively,
at the end of the member; the ratio
is negative for single curvature and positive
for double curvature.
The effective length factor can be received from the diagram in Figure 2.10.
Figure 2.10 Effective length factor k
where
: ratio of
column
of all columns to
of beams in a plane at one end of a
: span length of beam measured center to center of joints
16
Neglect
Slenderness?
Yes
Only-1st-order
analysis required
No
No
Analyze columns
as non-sway?
Yes
Slenderness effects along at
column ends
Slenderness effects along
column length
Moment magnification method
– sway frames
Moment magnification method
– non-sway frames
Or
Or
2nd-order analysis
2nd-order analysis
Slenderness effects along
column length
Moment magnification
M2nd-order  1.4 M1st-order
No
Or
2nd-order analysis
Yes
Revise
structural
system
Design column
for 2nd-order
moment
Figure 2.11 Flowchart for determining column slenderness effects (ACI 318-19, Fig. R6.2.5.3).
2.3.3 Linear Elastic Frist-order Analysis
A first-order frame analysis is an elastic analysis that excludes the internal force effects resulting
from deflection. It satisfies the equilibrium equations using the structure's original undeformed geometry.
Slenderness effects are neglected when only first-order results are considered. Because of the significance
of these effects, the moment magnification method is used to calculate both individual member slenderness
17
effects
and sidesway effects
for the overall structure using first-order results. Moments
calculated using a first-order frame analysis are multiplied by a moment magnifier that is a function of the
factored axial load
and the critical buckling load
for the column.
In order to find moment magnification factor, verification if the stories are sway or non-sway is
needed. The method of determining if a frame is classified as non-sway or sway can be done by finding the
stability index for a story, (ACI 318-19, section 6.6.4.3).
(ACI 318-19, equation 6.6.4.4.1)
Where
: total vertical factored load in a story to be sway-resisted by the frame action
: relative lateral deflection between the top and bottom of the story in question due to
: factored shear in the story in question
: length of the compression member in question, measure from center to center of the
joints in the frame


The frame is non-sway if:
The frame is sway if:
a) Moment magnification method: non-sway frames
The factored moment used for design of columns and walls,
moment
amplified for the effects of member curvature.
, shall be the first-order factored
(ACI 318-19, Eq. 6.6.4.5.1)
which
is should be at least
Eq.6.6.4.5.4) about each axis separately.
Magnification factor
and
in mm (ACI 318-19,
shall be calculated by:
(ACI 318-19. Eq. 6.6.4.5.2)
Where the critical buckling load
If
,
shall be calculated by:
, else it can be computed based on (ACI 318-19, Eq. 6.6.4.5.3a):
for members with end moments only and
is negative for single
curvature
Cm  1 for the members with transverse loads (ACI 318-19, section 6.6.4.5.3)
18
b) Moment magnification method: Sway frames
Moments
and
at the ends of an individual column shall be calculated by (a) and (b).
(a)
(b)
(ACI 318-19, Eq. 6.6.4.6.1a)
(ACI 318-19, Eq. 6.6.4.6.1b)
The different methods are allowed for calculating the moment magnifier,
include the method, the sum of concept, and second-order elastic analysis.


Method:
Sum of
. These approaches
(ACI 318-19, Eq. 6.6.4.6.2a)
concept:
(ACI 318-19, Eq. 6.6.4.6.2b)
2.3.4 Linear Elastic Second-order Analysis
In linear elastic second order analysis, the deformed geometry of the structure is included
in the equations of equilibrium so that
effects are determined. The structure is assumed to
remain elastic, but the effects of cracking and creep are considered by using an effective stiffness
.
A linear elastic second-order analysis shall consider the influence of the axial loads,
presence of cracked regions along the length of the member, and effects of load duration. The
stiffnesses
used in an analysis for strength design should represent the stiffnesses of the
members immediately to prior to failure. This is particularly true for a second-order analysis that
should predict the lateral deflections at loads approaching ultimate. The values should not be
based solely on the moment-curvature relationship for the most highly loaded section along the
length of each member. Instead, they should correspond to the moment-end rotation relationship
for a complete member.
19
Chapter 3: Methodology
3.1
Preliminary Design of Structural Members
The preliminary sizing of structural components in the building is the most significant phase in the
structural design process. A solid understanding of preliminary sizing enables the structural designer to
become accustomed to identifying undersized structural elements and avoiding oversizing structural
elements. ACI318-19 specifies minimal structural member sizes so that designers can more precisely
forecast the sizing of structural elements.
3.1.1 Pre-Dimensioning of Slabs
The size of slab can be easily pre-determine by know the clear span, ln , of short and long span of
slab and yield strength of the selected rebar to be used in the slab. According to ACI 318-19 (Table 7.3.1.1),
minimum thickness of solid slab in accordance to different support conditions with f y other than 420 MPa
is indicated in Table 3.1.
Table 3.1 Minimum thickness of solid non-prestressed slabs.
Support condition
Minimum h
Simply supported
fy 
ln 
 0.4 

20 
700 
One end continuous
fy 
ln 
 0.4 

24 
700 
Both end continuous
fy 
ln 
 0.4 

28 
700 
Cantilever
fy 
ln 
 0.4 

10 
700 
The preliminary sizing of the slab thickness can be accomplished by investigating the clear spans
of the slabs, the support condition of the slabs, and the steel yield strength to be utilized in the slab design,
as described below:
-
Clear span in short direction:
lna
-
Clear span in long direction:
-
Yield strength of steel:
lnb
fy
-
Minimum slab thickness:
tmin (Selected from Table 3.1 based on support conditions)
-
Selected thickness:
minimum thickness)
t  tmin (Select the appropriate slab thickness that is bigger than
3.1.2 Pre-Dimensioning of Beams
Minimum depth of beam can be determined according to ACI 318M-19 (Table 9.3.1.1), shown in
Table 3.2 below:
20
Table 3.2 Minimum depth of non-prestressed beams
Minimum h
Support condition
f y  420 MPa
f y other than 420 MPa
Simply supported
l 16
fy 
ln 
 0.4 

16 
700 
One end continuous
l 18.5
fy 
ln 
 0.4 

18.5 
700 
Both end continuous
l 21
fy 
ln 
 0.4 

21 
700 
Cantilever
l 8
fy 
ln 
 0.4 

8
700 
Based on the span length, support conditions, and yield strength of reinforcement bar to be used
in the beam designed, the preliminary sizing of beam can be done as indicated below with respected to the
minimum h in Table 3.2.
-
Yield strength of steel:
fy
-
Dimension of column:
bc
hc
-
Beam center-to-center length:
L
-
Beam clear span:
ln  L   bc or hc 
-
Minimum beam depth:
hmin (Selected from Table 3.2 according to support conditions
of beam)
Practical dimension of beam:
l 
l
h n  n 
Beam height
 15 10 
h
Use
-
Beam width
Use
b   0.3h  0.6h 
b
3.1.3 Pre-Dimensioning of Columns
The initial stage in preliminary column sizing is to collect the ultimate loads acting on columns
using the tributary area approach. The gross area of the column cross-section may then be calculated using
the expected ultimate loads, and the column width and height can be determined using that gross area. For
further clarification of the pre-dimensioning of columns, the detailed procedure is shown below:
a)
-
Material properties of concrete
Known size of column:
Concrete compressive strength:
b
-
Steel yield strength:
fy
-
Concrete density:
-
Reinforcement percentage:
con
g
fc
21
b)
-
Load estimation
Width of tributary area:
Length of tributary area:
Tributary area:
W
L
Atrib  W  L
-
Number of floors:
nF
-
Length of beam:
lb  W  L
-
Length of column:
Thickness of slab:
lc
-
Average beam size:
hb
hs
bb
-
Average column size:
hc
bc
SW  hs  con 
bb  hb  lb  con  bc  hc  lc  c
W L
-
Self-weight:
-
LL
Live load:
SDL
Super-imposed dead load:
Ultimate load per square meter: Wu  1.2(SW  SDL)  1.6LL
-
Total ultimate load:
Pu  Wu  Atrib  nF
Pre-dimension of column cross-section

Strength reduction factor:
c)
-
Pu
0.8  
Ag 
0.85  f c  1   g   f y   g
-
Column gross area:
-
Square column:
hc  bc  Ag
-
Rectangular Column:
hc 
-
3.2
Ag
b
Then select column width and height:  bc , hc 
Load Assumption
3.2.1. Dead Load
Dead loads refer to the weight of the structural elements themselves including slabs, beams,
columns, stairs, roof, etc. The self-weight of the structure is automatically calculated by ETABS. Also, other
loads that are permanently attached on the structure including brick walls, partition, tiles, ceiling, MEP
systems and so on, are all need to be taken to account in the dead load consideration as well. Those nonstructural loads are called super imposed dead load. The super-imposed dead loads of floor can be input as
the area loads in ETABS.
For brick loads, the super-imposed dead loads are input as line load in ETABS. Values of line loads
resulting from brick walls can be determine by multiplying the area loads value with the height of the wall.
3.2.2. Live Loads
It is so significant to choose the live load correctly on the project as this value will have big impact
on design. If overestimated, it could lead to uneconomical design and higher risk for contractors. It is
assigned to each floor with varies value, depending on usage requirement. In this project, hospital building,
22
live loads are selected according to the function of each space in the building such as lobby & corridor,
hospital operation room, hospital patient room, roof and stair.
3.2.3. Wind Loads
Wind loads are divided into two such as wind loads for ultimate limit state (ULS) design, W, and
wind loads for serviceability limit state (SLS) design, Wa. The only difference between the two wind loads
is the basic wind speed corresponding to different returning periods. The procedure to determine wind
load pressure on the building is shown below:
a)
Horizontal dimension of building measured normal to wind direction: B
Horizontal dimension of building measured parallel to wind direction: L
Mean height of the building: h
Step1: Determine Risk Category of Building
The risk category of building is chosen according to the functions and risk to human life of the
building.
b)
Step2: Determine the basic wind speed V for the applicable Risk Category
The basic wind speed can be chosen from Table 2.3 (Chapter 2) with corresponding to the
different returning period for the ultimate limit state and serviceability limit state design.
c)
Step3: Determine the Wind Load Parameter
Kd
 Wind directionality factor:


Exposure category: is based on the location of the building.
K zt
Topographic factor:

Ground elevation factor:
Ke

Gust effect factor:
o Natural frequency:
75 ft
na 
h
o If na  1 , thus the building is Rigid! Gust effect factor value can be taken as 0.85.
o Else, the building is flexible! Gust effect factor needed to be calculated.
 Enclosure classification:
 Internal pressure coefficient: the internal pressure coefficient value that corresponding to
enclosure classification of the building.
d) Step4: Determine velocity pressure coefficient, Kz or Kh
Due to the building is in exposure category, the value of  , and zg can be determine:
Velocity pressure coefficient:
2
o
 4.6 
If z  4.6 m  K z  2.01
 zg 


o
 z
4.6 m  z  zg  K z  2.01
 zg

2



23
For the value of K h , it can be found by using the z  h (height of building).
e)
Step5: Determine velocity pressure qz or qh
Velocity pressure: qz  0.613  K z  K zt  K d  Ke  V 2
The values of q z , is calculated at different height from the ground of each building story.
f)
Step6: Determine external pressure coefficient, Cp or Cn
 Wall pressure coefficient:
L

o Aspect ratio:
B
o External pressure coefficient for windward wall:
o External pressure coefficient for sidewall:
C p , windward
C p,sidewall
o External pressure coefficient for leeward wall:
According to ASCE7-16 (Figure 27.3-1), the external pressure coefficient for leeward wall
can be get doing linear interpolation that corresponding to the value of  .
C p,leeward
 Roof pressure coefficient (flat roof):
h
o Ratio:
L
 0
o Roof angle:
h
A  B
2
o Reduction factor: RF , the reduction factor for roof pressure coefficient can be found by
doing linear interpolation between value indicated in ASCE7-16 (Figure 27.3-1).
h
o From 0  , Roof pressure coefficient: C p,windwardroof 1
2
h
o Form  h , Roof pressure coefficient: C p, windwardroof 2
2
o C p, windwardroof 2
g)
Step7: Calculate wind pressure, p, on each building surface
 Wind pressure on windward walls:
Pz  qz  G  C p, windward  qi  GC pi
 Wind pressure on leeward walls:
Pz  qh  G  C p,leeward  qh  GC pi
 Wind pressure on side walls:
Pz  qh  G  C p, sidewall  qh  GC pi
3.3
Rectangular Beam Design
Flexure and shear are the two main forces that affect reinforced concrete beams. If any, axial forces
are typically negligible. A reinforced concrete beam ought to be capable of experiencing substantial, obvious
deformations before failing, giving occupants plenty of advance notice of the risk of a potential failure if it
is appropriately designed. Thus, it is crucial to have a solid understanding of beam behavior and the variables
affecting their flexural response.
24
3.3.1. Flexural Design of Rectangular Beam
Rectangular beam can be designed to resist bending moment by following step:
1) Define materials properties of beam:
bc
- Beam dimensions:
hc
-
Concrete compressive strength: f c
-
Concrete elastic modulus: Ec
Steel yield strength: f y
-
Steel elastic modulus: Es
-
Deform bar diameters: DB
Concrete cover for beam: c
2) Determine Bending moment resulting from external forces.
With the help of ETABS, external bending moments, Mu , can be easily taken from the software
after precisely modeled the structure.
3) Verification of beam to be singly-reinforced or doubly-reinforced beam.

f'
4M u
- Reinforcement ratio:   0.85  c  1  1 

'
2
f y 
1.7 f c bd 
-

f ' 1.4 

Minimum reinforcement ratio:  min  max  0.25  c ,

fy fy 


-
Maximum reinforcement ratio:  max  0.85  1 
f c '   cu

f y   cu   y



 0.05  f c '  28  

Where: 1  0.85  


7


 cu : crushing strain of concrete
 y : strain in steel reinforcement
-
If   min and min    max , beam will be designed as singly -reinforced beam.
-
If   max , beam will be designed as doubly-reinforced beam.
4) Calculate required area of steel reinforcement in beam (for singly-reinforced beam)
- Required reinforcement area: As.req  max   bd , min bd 
  DB 2
-
Steel area: As 
-
Amount of rebars: n 
4
As , req
As
5) Verify strength of beam to be able to resist external bending moment:
  DB 2
- Provided reinforcement area: As. pro  n 
4
25
-
Depth of equivalent compression stress block:
As . pro f y
a
0.85 f c 'b
-
Distance from extreme compression fiber to neutral axis:
a
c
1
-
Tensile strain in tension reinforcement:
t 
dt  c
  cu
c
fy
-
Strain in steel reinforcement:  y 
-
If  t   y , compression-controlled section,   0.65
-
If  y   t  0.005 , transition-controlled section,   0.65  0.25 
Es

t
y 
 0.005   
y
6)
-
If  t  0.005 , tension-controlled section,   0.9
a

Design moment:  M n   As. pro f y  d  
2

If  M n  M u , the design is SAFE, else the design needs to be revised.
Determine the rebar spacing in beam:
b  2cov er  2d stirrup  n  DB
Rebar spacing: s 
n 1
4


Minimum spacing: smin  max  DB, 25mm, d agg 
3


If found that s  smin , minimum spacing need to be used in the construction drawing.
3.3.2. Shear Design of Rectangular Beam
Rectangular beam can be designed to resist external shear force by following step:
1) Define materials properties of beam:
- Concrete compressive strength: f c
-
Concrete elastic modulus: Ec
Stirrup yield strength: f yt
-
Steel elastic modulus: Es
Stirrup diameters: d stirrup
-
Concrete cover for beam: c
Amount of stirrup leg: nleg
2) Taking factored shear force, Vu , from finite element analysis in ETABS.
3) Design of shear reinforcement:
- Shear strength attributable to concrete
Vc  0.17 
f c '  bw d
26
-
If Vu , d  0.5 Vc , no shear reinforcement required! But minimum shear reinforcement is
-
used.
If 0.5 Vc  Vu ,d  Vc , Minimum shear reinforcement required!
-
If Vu ,d   Vc , shear reinforcement required!
2
 d stirrup
-
Area of stirrup: Av , s  nleg
-
Minimum stirrup area: Av ,min s  max  0.062 f c '
4


-
b
b 
, 0.35

f yt
f yt 
If Av,s  Av,min s  OK!
4) Find spacing of stirrup:
- Shear strength attributable to shear reinforcement:
V  Vc
Vs  ud

-
Stirrup spacing: sstirrup 
Av , s f yt d
Vs

d

min  2 ,600mm  , if Vs  0.33 f cbw d




min  d ,300mm  , if V  0.33 f b d
s
c w



4

-
Maximum spacing: smax
-
Taken stirrup spacing as: sstirrup  min  sstirrup , smax 
3.3.3. Torsional Design of Rectangular Beam
Rectangular beam can be designed to resist external torsion by following step:
1. Checking whether torsion can be neglected or not:
-
Threshold torsion: Tth  0.083 f
'
c
Acp2
pcp
Where Acp : area enclosed by outside perimeter of concrete cross section
Acp  x0  y0
pcp : outside perimeter of the concrete cross section
pcp  2  x0  y0 
-
If Tu  Tth , torsion can be neglected!
-
If Tu  Tth , design the beam to resist torsion!
2. Checking limitations on cross-sectional dimensions, if torsion needs to be taken into account in
beam design:
2
 Vu   Tu ph 
 Vc





0.66
f

 


 , the section has adequate size.
c
2
 bw d   1.7 Aoh 
 bw d

-
If
-
Else, revise beam cross-section.
3. Determine transvers reinforcement for combined shear and torsion:
27
-
Stirrup reinforcement required for shear:
Av Vu  Vc

s
 df yt
-
Transvers torsional reinforcement requirement:
At
T /
 u
tan 
s 2 Ao f yt
Where Ao  0.85 Aoh
-
Aoh : is the area enclosed by the closed stirrups, measured to the centerline of the
outermost hoops.
 : permits to be taken as 45o for non-prestressed members
Transvers reinforcement for combined shear and torsion.
Av 2 At

s
s
-
Minimum reinforcement:
-

b
b 
s  max  0.062 f c w , 0.35 w 

f yt
f yt 

Transvers reinforcement should not be less than  Av  2 At min s
-
Spacing of reinforcement:
 Av  2 At min
s
-
nleg d stirrup
 Av  2 At 
s
Maximum spacing of reinforcement:
p

smax  min  h ,300mm 
 8

Where ph : is the perimeter enclosed by the closed stirrups, measured to the centerline
of the outermost hoops.
-
Spacing of reinforcement stirrup can be taken as: sstirrup  min  s, smax 
4. Determine longitudinal torsional reinforcement:
Al 
-
2 A0 f y
Check minimum longitudinal reinforcement:
Al ,min
-
Tu   ph cot 
 0.42 f c Acp  A 
f yt
  t  ph

fy
fy
 s 

 min 
f yt
 0.42 f c Acp  0.175bw 

p



 f
 h f
fy
yt
y




Then Al  max Al , Al ,min

3.3.4. Deflection Check of Rectangular Beam
Deflection is determined by the structure's serviceability requirements, such as the amount of
deformation that the structure's interacting components can tolerate. Excessive member deflection may
not be harmful in and of itself, but the influence on nonstructural (and structural) components supported
28
by the deflecting member typically dictates the allowable degree of deflection. The maximum allowable
deflection of flexural members is shown in Table 3.3.
Table 3.3 Maximum permissible calculated deflections
Member
Condition
Not supporting or attached to nonstructural
elements likely to be damaged by large
deflections
Immediate deflection due to L
Flat roofs
Floors
Roof or
floors
Supporting or attached
to nonstructural
elements
Likely to be
damaged by large
deflections
Not likely to be
damaged by large
deflections
Deflection to be considered
Immediate deflection due to
maximum of Lr, S, and R
Deflection
Limitation
l 180
l 360
That part of the total deflection
occurring after attachment of
nonstructural elements, which is the
sum of the time-dependent
deflection due to all sustained loads
and the immediate deflection due to
any additional live load
l 480
l 240
According to ACI 318M-19, deflection checks are divided between two deflection types:
Immediate deflections and long-term deflections which are resulting from creep and shrinkage of flexural
members. ACI-Table 24.2.2 provide maximum permissible calculated deflections as shown in Table above:
1. Checking for instantaneous deflection:
The procedure of checking for instantaneous deflection can be done as the following:
- Determine M DL , M LL , M DL LL , (Taken output from software)
-
Es
Ec
The values of modular ratio n for normal-weight concrete can also get from Table 3.4:
Calculate values for modular ratio: n 
Table 3. 4 Modular ratio for normal-weight concrete
-
f c  MPa 
n
20
25
30
35
40
9
8
7.5
7
6.5
Find I e,left of DL for section at left support:
Gross moment of inertia: I g 
bh3
12
Cracking moment of inertia: I cr
Modulus of concrete: f r  7.5
Cracking moment: M cr 
-
fc '
fr I g
yt
3
  M 3 
M 
 I e ,left   cr  I g  1   cr   I cr
  M DL  
 M DL 
Find I e, mid of DL for section at left support:
29
Gross moment of inertia: I g 
bh3
12
Cracking moment of inertia: I cr
Modulus of concrete: f r  7.5
Cracking moment: M cr 
fc '
fr I g
yt
3
-
  M 3 
 M cr 
cr
 I e , mid  
 I g  1  
  I cr
M
M
  DL  
 DL 
Find I e , right of DL for section at left support:
Gross moment of inertia: I g 
bh3
12
Cracking moment of inertia: I cr
Modulus of concrete: f r  7.5
Cracking moment: M cr 
fc'
fr I g
yt
3
-
  M 3 
 M cr 
cr
 I e ,right  
 I g  1  
  I cr
M
M
  DL  
 DL 
Calculate I e, DL using weighted average approach:
Average I e , DL  0.7 I e , mid  0.15  I e ,left  I e , right  for span with both ends continuous.
Average I e , DL  0.85 I e , mid  0.15  I e ,left or I e , right  for span with one end continuous.
-
-
-
Determine instantaneous deflection for DL:
 M L2 
 i , DL   a  DL 
E I

 c e , DL 
The procedure of determining of instantaneous deflection for DL+LL will be the same as
instantaneous deflection for DL. Just replace M DL with M DL LL
M
L2 
 i , DL  LL   a  DL  LL 
E I

 c e , DL  LL 
Determine instantaneous deflection for LL:
i , LL  i , DL  LL  i , DL
-
If i , LL  allow , the design is SAFE
-
Else, revise design.
Instantaneous deflection flow chart can be found in Appendix B for a better understanding.
2. Checking long term deflection:
Shrinkage and creep cause time-dependent deflections in addition to the elastic deflections that
occur when loads are first placed on the structure. Such deflections are influenced by temperature,
humidity, curing conditions, age at time of loading, amount of compression reinforcement, and
magnitude of the sustained load. Additional time-dependent deflection resulting from creep and
shrinkage of flexural members shall be calculated as the product of the immediate deflection caused
by sustained load and the factor  .
30
 

(ACI 318M-19, Eq 24.2.4.1.1)
1  50 
Where  : is time dependent factor for sustain loads
  : is ratio of compression steel
-
Value of time dependent factor for sustain loads,  , shall be in accordance with Table
3.5:
Table 3. 5 Time dependent factor for sustain loads
Sustained load duration, months
3
6
12
60 or more
-
Time-dependent factor 
1.0
1.2
1.4
2.0
Determine long term deflection due to creep and shrinkage:
cp  sh   i , D Sus
where
i , D  Sus : is immediate deflection of dead load plus the sustained life load, if part
of the lived load were considered as sustained (in certain types of
equipment whose placement or installation is not expected to change for
a period of 5 years or more).
Under ACI code, an additional effective moment of inertia Ie would be computed using
Mcr Mmax , where M max is due to dead load plus sustained live load.
-
Total long-term deflection:
total  i , L  cp sh
-
3.4
If total  allow , the beam design is SAFE.
Else, revise the design.
Column Design
3.4.1. Preliminary Design of Column Cross-section and Reinforcement
Column cross-section and its reinforcement can be determined as follow:
1) Define materials properties for the design of column:
- Concrete compressive strength: f c
-
Concrete elastic modulus: Ec
Steel yield strength: f y
-
Steel elastic modulus: Es
- Deform bar diameters: DB
- Concrete cover for column: c
2) Estimate column cross-section:
-
Find gross area of concrete: Ag ,est 
Pu
0.4 f c
31
where ultimate axial force Pu , can be get from software
-
Ag
h
 1.5  b 
b

Height of beam h  1.5b
Find provided gross area: Ag  b  h
Assume  
3) Find steel reinforcement to be used in column:
- Required reinforcement area:
Pu
 0.85 f cAg
K
As , req 
f y  0.85 f c
Strength reduction factor  , is 0.65 for tied column. The value of K , is 0.8 for tied column.
  DB 2
-
Area of steel to be used in column: As 
-
Amount to rebar: n 
-
Area of provided reinforcement: As , pro  n 
-
Steel reinforcement ratio:  g 
-
If 1%   g  8% , the design is acceptable!
-
Else, revise design!
4
As , req
As
  DB 2
4
As , pro
Ag
3.4.2. Checking for Sway or Non-sway Column
It can be assumed (ACI 318M-19, Section 6.6.4.4.1) that a story within a structure is non-sway if:
Q
Where
P
u
P 
u
Vus lc
0
 0.05
and Vus are the story total factored vertical load and horizontal story shear in the
story being evaluated, respectively, and  0 is the first-order relative lateral deflection between the top and
bottom of the story due to . The length lc is that of the compression member in a frame, measured from
center to center of the joints in the frame.
3.4.2.1. Magnified Moments in Non-sway Frames
The effect of the slenderness ratio klu r in a compression member of a braced frame may be
ignored if:
klu
 34  12  M 1 M 2 
r
(ACI 318M-19, equation 6.2.5.1b)
klu
 40
r
(ACI 318M-19, equation 6.2.5.1c)
And
32
If klu r  34  12  M1 M 2  , then the slenderness must be considered. The procedure for
determining the magnification factor  ns in non-sway frames can be summarized as follows (ACI
318M-19, Section 6.6.4):
1. Determine if the frame is braced against sidesway and find the unsupported length, lu , and the
effective length factor, k ( k may be assumed to be 1.0).
2. Calculate the effective member stiffness,  EI eff , using the simplified approximated equation:
 EI eff

0.4 Ec I g
1   dns
3. Determine the buckling load, Pc :
Pc 
 2 EI
(ACI 318M-19, Eq. 6.6.4.4.2)
2
 klu 
Use the values of  EI eff ,
k , and lu as calculated from step 1 and step 2.
4. Calculate the value of the factor Cm to be used in the equation of the moment-magnifier factor.
For braced members without transverse loads,
Cm  0.6 
0.4 M 1
M2
(ACI 318M-19, Eq. 6.6.4.5.3a)
5. Calculate the moment magnifier factor  ns :
 ns 
Cm
 1.0
Pu
1
0.75Pc
(ACI 318M-19. Eq. 6.6.4.5.2)
where Pu is the applied factored load Pc and Cm are as calculated previously.
6. Design the compression member using the axial factored load, Pu , from the conventional frame
analysis and a magnified moment, M c , computed as follows:
Mc  ns M 2
(ACI 318M-19, Eq. 6.6.4.5.1)
where M 2 is the larger factored end moment due to loads that result in no sidesway and should
be M 2  M 2,min  Pu 15  0.03h  .
3.4.2.2. Magnified Moments in Sway Frames
The effect of slenderness may be ignored in sway (unbraced) frames when klu r  22 . The
procedure for determining the magnification factor,  s , in sway (unbraced) frames may be summarized as
follows (ACI 318M-19, Section 6.6.4.6):
1. Determine if the frame is unbraced against sidesway and fine the unsupported length lu and k ,
which can be obtained from the alignment charts (Fig.2.1.2.2).
2. Calculate  EI eff , Pc , and Cm by the same procedure from step 2-4 in section 3.2.2.1. Note that
the term  ds is used instead of  dns to calculate  EI eff and is defined as the ratio of maximum
factored sustained shear within a story to the total factored shear in that story.
3. Calculate the moment-magnifier factor,  s using one of the following methods:
a. Q-method:
33
1
1
1 Q
b. Sum of P method:
1
s 
1
 Pu
1
0.75  Pc
s 
(ACI 318M-19, Eq. 6.6.4.6.2a)
(ACI 318M-19, Eq. 6.6.4.6.2b)
4. Calculate the magnifier end moments M 1 and M 2 at the ends of an individual compression
members, as follows:
M1  M1ns   s M1s
(ACI 318M-19, Eq. 6.6.4.6.1a)
M 2  M 2ns   s M 2s
(ACI 318M-19, Eq. 6.6.4.6.1b)
Where M1ns and M 2ns are the moments obtained from the non-sway condition, whereas M1s
and M2s at the moments obtained from the sway condition. The design magnified moment M c
is the larger between M 1 and M 2 .
3.4.3. Checking Strength of Column by P-M Interaction Diagram
The P-M interaction diagram is a graphical representation of the interaction between axial force
(P) and bending moment (M) in a structural member. It is used to design reinforced concrete members that
have both axial force and bending moment acting on them at the same time. The P-M interaction curve
shows how much P and M reinforced concrete can withstand.
Figure 3.1 P-M Interaction diagram
For combined axial force and bi-axial bending moment, the final design Pn can be determined using
Reciprocal Load Method as indicated below:
-
Concrete compressive strength:
fc
-
Steel yield strength:
fy
-
Column dimension:
b
34
-
Gross area of column cross section:
h
Ag  b  h
-
Rebar diameter:
Amount of rebar:
DB
n
-
Area of reinforcement bar:
Ast  n 
-
Strength reduction factor:
  0.65
Strength of concentrically load:
P0  0.85  f c   Ag  Ast   f y  Ast
-
Since Pu  0.1   fc  Ag , use Reciprocal Load Method!
-
Design strength Pn:
Pn 
-
  DB 2
4
1
1
1
1


Pnx 2 Pny 3 P0
Capacity Ratio:
D C
Pu
 Pn
3.4.4. Shear Design for Rectangular Column
Rectangular column can be designed to resist external shear force by following step:
1. Define materials properties of column:
- Concrete compressive strength: f c
-
Concrete elastic modulus: Ec
Stirrup yield strength: f yt
-
Steel elastic modulus: Es
Stirrup diameters: d stirrup
-
Concrete cover for column: c
Amount of stirrup leg: nleg
2. Ultimate shear force Vu , from external horizontal force can be get from software.
3. Design of shear reinforcement:
- Shear strength attributable to concrete

N 
Vc  0.17 1  u  f c '  bw d
 14 A 
g 

 0.5 Vc , no shear reinforcement required! But minimum shear reinforcement is
-
If Vu , d
-
used.
If Vu ,d  0.5 Vc , shear reinforcement required!
4. Find spacing of stirrup:
- Shear strength attributable to shear reinforcement:
V  Vc
Vs  u
 0.66 f cbw d

35

d

min  2 ,600mm  , if Vs  0.33 f cbw d




min  d ,300mm  , if V  0.33 f b d
s
c w



4

-
Maximum spacing: smax
-
Used spacing as: s   smin  smax 
5. Find required shear area:
Vs s
f yt d
-
Required shear area: Av, s 
-
Minimum shear area: Av ,min  max  0.062 f c '


-
bw s
b s
, 0.35 w 
f yt
f yt 
Take required shear area as: Av , s  max  Av , s , Av ,min 
6. Select appropriate steel for stirrups:
2
 d stirrup
Av , pro  nleg 
4
 Av , s
36
Chapter 4: Finding and Result
The determination and results of the structural design of each element in this project may be
proceeded more conveniently and precisely by implementing the flow of structural design procedure
outlined in Chapter 3. The design process is summarized as follows: preliminary design of structural
members, load assumptions, and design of each member such as slabs, beams, and columns.
4.1. Pre-Dimension of Structural Members
4.1.1. Pre-Dimension of Slabs
Thickness of slab can be estimated by the following procedure:
-
Clear span in short direction:
lna  3.3 mm
-
Clear span in long direction:
lnb  4 mm
-
Yield strength of steel:
f y  390 MPa
-
Clear span ratio:

-
Minimum slab thickness:
-
Selected thickness:
lnb 4

 1.21
lna 3.3

fy  


 0.8 

1400  


tmin  max 90 mm, lnb
 91.97 mm

36  9 




t  120 mm
4.1.2. Pre-Dimension of Beams
-
Yield strength of steel:
f y  390 MPa
-
Dimension of column:
bc  300 mm
-
Beam center-to-center length:
hc  300 mm
L  6.05 m
-
Beam clear span:
Minimum beam depth (ACI 318-19):
For both ends continuous:
-
hmiin 
ln  L  bc  6.05  0.3  5.75 m
f y  5.75 
ln 
390 
 0.4 

 0.4 
  262.075 mm
21 
700  21 
700 
Practical dimension of beam:
l   3.75
3.75 
l
h n  n 

Beam height
   383.33 mm  575 mm 
10 
 15 10   15
Use
h  500 mm
Beam width
Use
b   0.3h  0.6h    0.3  500  0.6  500  150  300 mm
b  250 mm
37
As a result, following pre-dimensioning, beam 250mm x 500mm will be used for modeling in
ETABS. Two beam cross-section dimensions are chosen with varying span lengths, as illustrated in Table
4.1.
Table 4.1 Beam dimensions
Span Length
Beam Cross-section (mm)
6.05 m
250x500
7m
250x500
4.2 m
250x300
3.5 m
250x300
4.1.3. Pre-Dimension of Columns
a)
-
Material properties of concrete
Known size of column:
b  350 mm
-
Concrete compressive strength:
fc  30 MPa
-
Steel yield strength:
f y  390 MPa
-
Concrete density:
-
Reinforcement percentage:
con  25 kN m3
g  0.02
b)
-
Load estimation
Width of tributary area:
Length of tributary area:
W  3.4 m
L  4.775 m
-
Tributary area:
Atrib  W  L  3.4  4.775  16.235 m2
-
Number of floors:
nF 5
-
Length of beam:
lb  W  L  3.4  4.775  8.175 m
-
Length of column:
Thickness of slab:
lc  4.2 m
-
Average beam size:
hb  0.4 m
hs  0.12 m
bb  0.25 m
-
Average column size:
hc  0.35 m
bc  0.35 m
bb  hb  lb  con  bc  hc  lc  c
W L
2
SW  5.051kN m
-
Self-weight:
SW  hs  con 
-
Live load:
LL  2.9 kN m2
-
Super-imposed dead load:
SDL  5 kN m2
c)
-
Ultimate load per square meter: Wu  1.2(SW  SDL)  1.6LL  16.701 kN m2
Total ultimate load:
Pu  Wu  Atrib  nF  1355.732 kN
Pre-dimension of column cross-section
  0.65
Strength reduction factor:
-
Column gross area:
-
Square column:
Pu
0.8  
Ag 
 79511.343 mm2
0.85  f c  1   g   f y   g
hc  Ag  281.978 mm  300 mm
38
2.6 m
250x300
bc  300 mm
-
Rectangular Column:
hc 
Ag
b

79511.343
 257.143 mm
350
Due to the wind effect dimension of column will be used a bit larger than the pre-dimension,
which is 300mm x 400 mm.
Following pre-dimensioning of all columns based on column position and span of beam and slab
connected to columns, three types of column cross-sections are selected, as shown in Table 4.2.
Table 4.2 Column cross-section dimensions
Column Cross-section (mm)
300x300
300x400
300x500
4.2. Load Assumption
4.2.1. Dead Load
According to section 3.2.1 in Chapter 3, the procedure to gathering dead loads is by input in
ETABS the assumption of super imposed dead loads, SDL, for floors are shown in Table 4.3.
Table 4.3 Super imposed dead load for floor
Story
Roof
terrace
second floor
First floor
Mezzanine floor
Ground Floor
SDL (kN/m2)
Floor finishes (Ceramic+tiles+mortar)
Ceiling
MEP
Floor finishes (Ceramic+tiles+mortar)
Ceiling
MEP
Floor finishes (Ceramic+tiles+mortar)
Ceiling
MEP
Minimum floor partition
Floor finishes (Ceramic+tiles+mortar)
Ceiling
MEP
Minimum floor partition
Floor finishes (Ceramic+tiles+mortar)
Ceiling
MEP
Minimum floor partition
Floor finishes (Ceramic+tiles+mortar)
Minimum floor partition
Total SDL (kN/m2)
1.1
0.3
0.1
1.1
0.3
0.1
1.1
0.3
0.1
1
1.1
0.3
0.1
1
1.1
0.3
0.1
1
1.1
1
1.5
1.5
2.5
2.5
2.5
2.1
For brick loads, there are two type of wall thickness using on in this building such as 20cm thickness
wall and 10cm thickness wall. The weights of each brick wall are shown as area loads, which indicated in
Table 4.4. Value of line loads resulting from brick walls can be determine by multiplying the area loads
value with the height of the wall.
39
Table 4.4 Super imposed dead load of brick walls and curtain wall
Wall types
10 cm thickness wall with both sides plastering
20 cm thickness wall with both sides plastering
Curtain Wall
Weight (kN/m2)
1.8
3.2
0.5
4.2.2. Live Loads
In this project, hospital building, the selected values of live load according ASCE7-16 (Table 4.31) are indicated in Table 4.5.
Table 4.5 Live loads for DALORA Hospital project
Live load
Lobby &
Corridor
Hospital
Operation Room
Hospital Patient
Room
Roof
Stair
kN/m2
4.8
2.9
2
1
4.8
4.2.3. Wind Loads
4.2.3.1. Wind Loads in Ultimate Limit State
-
Horizontal dimension of building measured normal to wind direction: B  31.35 m
-
Horizontal dimension of building measured parallel to wind direction: L  11.35 m
a)
Mean height of the building: h  19.4 m
Step1: Determine Risk Category of Building
In this project, it is the hospital building that corresponding to the risk category III.
b)
Step2: Determine the basic wind speed V for the applicable Risk Category
For ultimate limit state design, the basic wind speed is chosen corresponding to the returning
period of 700 years. The basic wind speed value is: V  43.87 m s .
c)
Step3: Determine the Wind Load Parameter
Kd  0.85
 Wind directionality factor:


Exposure category:
Topographic factor:
Exposure B
Kzt  1

Ground elevation factor:
Ke  1

Gust effect factor:
o Natural frequency:
75 ft 22.86 m
na 

 1.178 Hz
h
19.4 m

o Since na  1.178  1 , thus the building is Rigid!
o So, the gust effect factor value is: G  0.85
Enclosure classification is partially enclosed building
40

d)
Internal pressure coefficient: the internal pressure coefficient value that corresponding to
partially enclosed building is GC pi  0.55
Step4: Determine velocity pressure coefficient, Kz or Kh
Due to the building is in exposure category B, the value of  , and zg can be taken as:
o
o
 7
zg  365.76 m
Velocity pressure coefficient:
2
o
 4.6 
If z  4.6 m  K z  2.01
 zg 


o
 z
4.6 m  z  zg  K z  2.01
 zg

2



Thus, by following the equation above corresponding to different values of z according to
building level and with the assist from MathCad Prime, the value of velocity pressure coefficient,
K z , are determined as shown in the Table 4.6.
Table 4.6 Velocity pressure coefficient
z (m)
19.4
15.4
11.4
7.4
4.2
Kz
0.869
0.813
0.746
0.659
0.576
For the value of K h , it can be found by using the z  19.4 m (height of building), which is
K h  0.869
e)
Step5: Determine velocity pressure qz or qh
Velocity pressure: qz  0.613  K z  K zt  K d  Ke  V 2
Table 4.7 Velocity pressure
z (m)
19.4
15.4
11.4
7.4
4.2
Kz
0.869
0.813
0.746
0.659
0.576
41
qz (kN/m2)
0.871
0.815
0.748
0.661
0.577
The values of q z , at different height from the ground of each building story can be calculated
using the equation above and are indicated in Table 4.7.
f)
Step6: Determine external pressure coefficient, Cp or Cn
 Wall pressure coefficient:
L 11.35
 
 0.362
o Aspect ratio:
B 31.35
o External pressure coefficient for windward wall:
o External pressure coefficient for sidewall:
C p,windward  0.8
C p, sidewall  0.7
o External pressure coefficient for leeward wall:
According to ASCE7-16 (Figure 27.3-1), the external pressure coefficient for leeward wall
can be get doing linear interpolation that corresponding to the value of  .
Cp,leeward  0.5
 Roof pressure coefficient (flat roof):
h 19.4

 1.709
o Ratio:
L 11.35
o Roof angle:
 0
h
19.4
A  B   31.35 
 304.095 m 2
2
2
o Reduction factor: RF  8 , the reduction factor for roof pressure coefficient can be found
by doing linear interpolation between value indicated in ASCE7-16 (Figure 27.3-1).
h
 1.3  RF   1.04 
o From 0  , Roof pressure coefficient: C p , windwardroof 1  


2
 0.18   0.18
h
 0.7 
o Form  h , Roof pressure coefficient: C p , windwardroof 2  

2
 0.18
o C p, windwardroof 2  0
g)
Step7: Calculate wind pressure, p, on each building surface
 Wind pressure on windward walls:
Pz  qz  G  C p, windward  qi  GC pi
 0.871  0.85  0.8  0.871   0.55  
Pz  max 

0.871  0.85  0.8  0.871   0.55  
 0.113
2
Pz  max 
  1.071 kN m
1.071


Table 4.8 Wind pressure on windward walls
z (m)
19.4
15.4
11.4
7.4
4.2
Kz
0.869
0.813
0.746
0.659
0.576
qz (kN/m2)
0.871
0.815
0.748
0.661
0.577
pz (kN/m2)
1.071
1.034
0.988
0.929
0.872
With the same procedure and different value of z, Kz, and qz, wind pressure on windward wall can
be calculated as shown in Table 4.8.
42
 Wind pressure on leeward walls:
Pz  qh  G  C p,leeward  qh  GC pi
 0.871  0.85  (0.5)  0.871   0.55  
Pz  min 

0.871  0.85  (0.5)  0.871   0.55  
 0.849 
Pz  min 
 0.849 kN m 2

 0.109 
 Wind pressure on side walls:
Pz  qh  G  C p, sidewall  qh  GC pi
 0.871  0.85  (0.7)  0.871   0.55  
Pz  min 

0.871  0.85  (0.7)  0.871   0.55  
 0.997 
2
Pz  min 
  0.997 kN m

0.039


4.2.3.2. Wind Loads in Ultimate Limit State (Input in ETABS)
Wind loads can be calculated automatically and quickly in ETABS with the help of diaphragm
function. Just some wind load parameters as indicated in Table 4.9, that needed to insert in the wind load
pattern tab in ETABS.
Table 4.9 Ultimate limit state wind load parameters for ETABS
Wind Parameter for ETABS in ULS (W)
Wind speed, V
43.87 m/s
Exposure type
B
Ground elevation factor, Ke
1
Topographical factor, Kzt
1
Gust factor, G
0.85
Directional factor, Kd
0.85
4.2.3.3. Wind Loads in Serviceability Limit State (Input in ETABS)
The same procedure is applied for wind loads in serviceability limit state design. Parameters for
inputting in ETABS are almost the same as ultimate limit state design, just a change for the value of basic
wind speed V. For the serviceability limit state design basic wind speed is chosen at the returning period of
20 years, which shown in Table 4.10 with other wind load parameters.
Table 4.10 Serviceability limit state wind load parameter for ETABS
Wind Parameter for ETABS in SLS (Wa)
Wind speed, V
32.45 m/s
Exposure type
B
Ground elevation factor, Ke
1
Topographical factor, Kzt
1
Gust factor, G
0.85
Directional factor, Kd
0.85
43
4.2.4. Load Combinations
4.2.4.1. Load Combinations for Ultimate Limit State Design
In ultimate limit state design, the load combination resulting from dead loads, live loads, roof live
loads, and wind loads can be generated as twelve combinations as indicated below:
o
o
o
o
o
o
o
o
o
o
o
o
U1:
U2:
U3:
U4:
U5:
U6:
U7:
U8:
U9:
U10:
U11:
U12:
1.4D
1.2D+1.6L
1.2D+1.6L+0.5Lr
1.2D+L+1.6Lr
1.2D+L+W
1.2D+L-W
1.2D+L+0.5Lr+W
1.2D+L+0.5Lr-W
1.2D+1.6Lr+0.5W
1.2D+1.6Lr-0.5W
0.9D+W
0.9D-W
The combination that produced highest factored loads will be taken to design of structural
members.
4.2.4.2. Load Combinations for Serviceability Limit State Design
In serviceability limit state design, the load combinations are used for checking the drift of the
building due to the effect of wind loads. According to ASCE7-16, the combinations for serviceability limit
state are generated into two which is:
o
o
Drift1: D+0.5L+Wa
Drift2: D+0.5L-Wa
4.3. Structural Modeling in ETABS
4.3.1. Defining Gridline and Stories
To begin generating the model in ETABS, the user must first define the initial unit, preferences,
properties, and definitions. The fundamental code chosen for use in the design is ACI 318-19, and the SI
unit is the general unit used in Cambodia.
The grid line is then required to be created for the convenience of precisely modeling each
structural element according to the specified architectural plan. Grid lines can be created by entering each
grid line spacing dimension into the grid data system in ETABS, as shown in Figure 4.1. After carefully
studying the building's layout, the grid line is formed in accordance with the architectural plan's grid line.
In addition, a reference plane named "Cored Grid" is generated for modeling elevator columns. The story
data, as illustrated in Figure 4.2, is then required to be appropriately created in accordance with the elevation
of the building as shown in the architectural plan. Figure 4.3 depicts the final outcome of the DALORA
Hospital project's grid line and story data.
44
Figure 4.1 Grid Line system data
Figure 4.2 Story data of the building
45
Figure 4.3 Defined grid line of DALORA Hospital project
4.3.2. Defining Material and Section Properties
Choosing the appropriate materials for the project is crucial to producing a model that is ready for
study. A designer should be attentive while choosing the materials because accuracy is essential to producing
the best design. If we design the structure irresponsibly, it may have an impact on other people and cost
the designer a lot of money. Material characteristics can be defined based on the materials selected during
structural member pre-dimensioning. These materials are illustrated below:
Figure 4.4 Defining material properties
46
o
o
o
C30: Concrete compressive strength of 30MPa.
SD390: Steel yield strength of 390 MPa (for main reinforcement bars).
SD295: Steel yield strength of 295 MPa (for confinement bars).
The method for defining material in ETABS can be done by go to Define menu > Material
Properties and then add new materials, modify parameters and requirement needed for each material as
shown in Figure 4.4.
After carefully defining material properties, section properties can be generated by selecting the
proper materials that those sections required. Figure 4.5 is an example of defining section properties in
ETABS.
Figure 4.5 Defining section properties in ETABS
47
4.3.3. Modeling of Structural Members
After carefully establishing material properties and section properties based on the selected crosssections in structural member pre-dimensioning, structural member modeling may be simply generated on
the specified gird line and story data. Figure 4.6 and Figure 4.7 display the end result of 3D view and floor
plan of DALORA Hospital’s structural modeling.
Figure 4.6 Structural modeling of DALORA Hospital
48
Figure 4.7 Ground floor plan of DALORA Hospital
4.3.4. Stiffness Modifiers
Stiffness modifiers in ETABS are parameters that reduce some cross-sectional properties such as
area, inertia, torsional constant, and so on. They are typically used to decrease the rigidity of concrete
sections in order to simulate cracked concrete behavior. Two models with various stiffness modifiers are
produced in the practical design of a structural system. The first model is the ultimate limit state cracked
model (ULS cracked model), and the second is the serviceability limit state cracked model (SLS cracked
model). Table 4.11 specifies the stiffness modifier for the ULS and SLS cracked models.
Table 4.11 Stiffness modifier values
Members
Slab
Beam
Column
SLS
0.35Ig
0.5Ig
Ig
Figure 4.8 Stiffness modifier in ETABS
49
ULS
0.25Ig
0.35Ig
0.7Ig
4.3.5. Checking for Sway or Non-sway
Model checking begins once the model has been completely modeled in accordance with the
defined grid line and story data, pre-determined members, all the loading requirements, and the stiffness
modifier of each element of this project. After reviewing the model to ensure no errors or warnings, the
model may be run as a linear first-order analysis to obtain the necessary data for determining whether the
frame is sway or non-sway. By following the procedure of checking sway or non-sway of the frame stated
in section 3.4.2 (Chapter 3), the results in summary in Table 4.12 and Table 4.13.
Table 4.12 Stability index in X-direction
Story
height lc
(m)
4
4
4
3.2
4.2
1.5
Pu (kN)
Vus, X
(kN)
 0 -X
(mm)
QX
Sway or Non-Sway
376.98
4041.47
9882.88
15793.53
20759.07
26502.98
-9.05
-46.57
-82.05
-111.80
-140.20
-156.15
0.94
0.95
1.55
1.32
2.34
0.80
0.010
0.021
0.047
0.058
0.082
0.090
Non-Sway
Non-Sway
Non-Sway
Sway
Sway
Sway
Table 4.13 Stability index in Y-direction
Story
height (m)
Pu (kN)
Vus, Y
(kN)
 0 -Y
(mm)
QY
Sway or Non-Sway
4
4
4
3.2
4.2
1.5
376.983
4036.749
9873.43
15779.36
20740.17
26479.36
-14.55
-114.58
-209.62
-289.78
-376.77
-425.69
2.73
3.06
4.96
4.57
8.02
2.61
0.018
0.027
0.058
0.078
0.105
0.108
Non-Sway
Non-Sway
Sway
Sway
Sway
Sway
According to Table 4.12 and Table 4.13, the result show that this has sway columns from ground
floor to first floor. So, slenderness effect for sway case will be checked to verify the need of linear second
order analysis due to P-Delta effects. The procedure of checking slenderness effect of a selected column,
C30x40, on the ground floor is indicated as the following:
b  0.4 m
h  0.3 m
-
Width of column:
Depth of column:
-
Length of column measured center-to-center of the joints: Lc  4.2 m
Unsupported length of column: Lu  Lc  0.3 m  3.9 m
-
Unbraced length ratio of column:
-
Upper column and beams dimension show in Table 4.14:
Lu
 0.929
Lc
50
Table 4.14 Upper column and beams dimension
-
Width
Depth
Center-to-center length
Upper column
bc ,up  0.4 m
hc ,up  0.3 m
Lc ,up  3.2 m
Left beam
bb ,up ,l  0.2 m
hb ,up ,l  0.3 m
Lb ,up ,l  2.6 m
Right beam
bb ,up , r  0.2 m
hb ,up , r  0.3 m
Lb ,up , r  4.2 m
Lower columns and beams dimension show in Table 4.15:
Table 4.15 Lower column and beams dimension
Upper column
Width
bc ,low  0.4 m
Depth
hc ,low  0.3 m
Center-to-center length
Lc ,low  1.5 m
Left beam
bb,low,l  0.2 m
hb,low,l  0.3 m
Lb,low,l  2.6 m
Right beam
bb ,low,r  0.2 m
hb,low,r  0.3 m
Lb,low,r  4.2 m
-
Concrete compressive strength:
-
Radius of gyration:
-
f c  30 MPa
h
 0.087 m
12
Concrete modulus of elasticity: Ec  25742.96 MPa
Relative stiffness of column and beam:
b  h3
EI c  Ec  0.70 
 16218.06 kN.m 2
o Designed column:
12
bc ,up  hc3,up
o Upper column:
EI c ,up  Ec  0.70 
 16218.06 kN.m 2
12
bc ,low  hc3,low
o Lower column:
EI c ,low  Ec  0.70 
 16218.06 kN.m 2
12
bb ,up ,l  hb3,up ,l
EI b ,up ,l  Ec  0.35 
 4054.51 kN.m 2
o Upper left beam:
12
bb ,up , r  hb3,up , r
EI b ,up ,r  Ec  0.35 
 4054.51 kN.m 2
o Upper right beam:
12
b
 h3
o Lower left beam:
EI b ,low,l  Ec  0.35  b ,low,l b ,low,l  4054.51 kN.m 2
12
b
 h3
o Lower right beam:
EI b ,low, r  Ec  0.35  b ,low, r b ,low, r  4054.51 kN.m 2
12
EI c ,up
EI
 8929.58 kN.m
o  ic ,up  c 
Lc
Lc ,up
o
 ic ,low 
o
 ib ,up 
o
 ib ,low 
r
EI c EI c ,low

 14673.48 kN.m
Lc
Lc ,low
EI b ,up ,l
Lb ,up ,l

EI b ,low,l
Lb ,low,l
EI b ,up ,r

Lb ,up , r
 2524.79 kN.m
EI b ,low, r
Lb ,low,r
 2524.79 kN.m
51
 ic ,low
-
A:
 low 
-
B:
 up 
-
Base on the k factor alignment chart for sway frame as shown in Table 4.16:
k  2.56
klu
 115.28  22
Slenderness ratio:
r
-
 ib ,low
 ic ,up
 ib ,up
 5.81
 3.53
The column is Slender according to the estimated slenderness ratio. Thus, the P-Delta option in
ETABS, as well as column meshing, are necessary in order to obtain the magnified moments for the final
column design.
4.3.6. Second-order Effects Consideration
Second-order effects in ETABS can be easily calculated by enable the P-Delta options, iterativebased on loads. The iterative P-Delta load case input in ETABS is 1.2D+0.5L as shown in Figure 4.9.
Furthermore, in order to get p-small delta effects, columns can be meshing to several segments as illustrated
in Figure 4.10.
Figure 4.9 P-Delta option in ETABS
52
Figure 4.10 Column meshing in ETABS
4.3.7. Checking Model and Running Analysis
After the modeling of all members and input all the requirements mention above, checking model
is needed in order to make sure that the model has no any warnings or errors as shown in Figure 4.11. Then
the model can be running the analysis and the required results from the analysis can be used for further
design of structural members. The final analysis model is shown is Figure 4.12.
Figure 4.11 Analysis messages after running analysis in ETABS
53
Figure 4.12 DALORA structural mode after running analysis
4.4. Slab Design
4.4.1. Flexural Design of Slab
Slab can be design to resist flexure by taken the biggest positive and negative moment from finite
element analysis from ETABS. Moment’s diagram is shown in Figure 4.13.
Figure 4.13 Moment’s diagram from finite element analysis.
-
Concrete compressive strength:
fc  30 MPa
-
Steel yield strength:
f y  390 MPa
-
Concrete elastic modulus:
Ec  25742.96 MPa
54
-
Steel elastic modulus:
Es  200000 MPa
-
Bottom rebar diameter:
DBb  10 mm
-
Top rebar diameter:
DBt  10 mm
-
Clear cover:
-
Thickness of slab:
cc  20 mm
t  120 mm
-
Design bending moments per 1m width: M neg  10 kN.m m
M pos  9 kN.m m
  0.9
- Strength reduction factor:
a) Top reinforcements:
b  1m
- Design width of slab:
-
 0.05  f c '  28  
 0.05  30  28  
  0.85  
1  0.85  
  0.836


7
7




Maximum strain at the extreme concrete compression fiber:  cu  0.003
Maximum reinforcement ratio:

f '
 cu
30 
0.003

 max  0.85  1  c 
  0.85  0.836 

  0.02
f y   cu  0.005 
390  0.003  0.005 
-
Shrinkage reinforcement ratio:
 shrinkage  0.0018
-
Effective depth: d  t  (cc 
-
DB
)  95 mm
2
Factored moment: Mu  M neg  b  10 kN.m
-
Reinforcement ratio:   0.85 
-
Required reinforcement area: As.req  max   bd ,  shrinkage bd   307.507 mm 2
-
Maximum spacing: smax  min  2t , 450 mm   240 mm
-
Used rebar area: As.DB 
-
Number of rebar per 1m length: nt 
fc ' 
4M u
 1  1 
fy 
1.7 f c 'bd 2
  DBt2
4

  0.0032

 78.54 mm 2
As.req
As .DB
 3.915  4


b
,10 mm   240 mm
Required top rebar spacing: st ,used  max  smax ,
nt  1


- Used top rebar spacing: DB10@200mm
b) Bottom reinforcements:
- Factored moment: M u  M pos  b  10 kN.m
-
fc ' 
4M u
 1  1 
fy 
1.7 f c 'bd 2

  0.0029

-
Reinforcement ratio:   0.85 
-
Required reinforcement area: As.req  max   bd ,  shrinkage bd   276.039 mm 2
-
Maximum spacing: smax  min  2t , 450 mm   240 mm
55
  DBt2
 78.54 mm 2
-
Used rebar area: As.DB 
-
Number of rebar per 1m length: nt 
-
4
As.req
As . DB
 3.515  4


b
,10 mm   240 mm
Required rebar spacing: st ,used  max  smax ,
nt  1


Used rebar spacing: DB10@200mm
4.4.2. Shear Design of Slab
Factored shear force, Vu , can be taken from the result of finite element analysis in ETABS as
shown in Figure 4.14.
Figure 4.14 Shear diagram from finite element analysis
-
Factored shear force: Vu  20 kN
-
Effective depth for shear design: d  t  (cc  DBb 
-
DBb
)  95 mm
2
d  dl
d shear  s
 90 mm
2
Strength reduction factor for shear design:   0.75
-
Concrete shear strength: Vc  0.17  f c '  bw d  83.802 kN
DBb
)  85 mm
2
d  t  (cc 
Vc  75.421 kN
-
Maximum allowable shear demand: Vmax  Vc  0.66 f c '  b  d shear  409.149 kN
-
Since Vu  Vc , shear reinforcement is not required!
4.4.3. Checking Slab Deflection
a) Instantaneous Deflection
- Moment due to dead loads:
- Moment due to live loads:
-
M D  5.7 kN.m
M L  5.7 kN.m
Moment due to dead+live loads: M D  L  7.08 kN.m
Portion of sustained live load:
  30%
56
-
Elastic deflection (Taken from ETABS):  e , D  5.52 mm
 e , L  1.76 mm
 e , D  L  7.28 mm
 e , sus   e , D     e , L  6.048 mm
-
Beam slab dimension:
b 1m
t  120 mm
L  4.2 m
-
Clear cover:
Deformed bar diameter:
cc  20 mm
-
Effective depth:
-
Number of tension rebar:
Number of compression rebar:
DB 

d  t   cc 
  95 mm
2 

DB
d   cc 
 95 mm
2
nts  5
nc  5
-
Area of tension rebar:
As  nts 
-
Area of compression rebar:
-
Strength reduction factor:
  0.9
-
Modular ratio:
nmr 
-
Gross moment of inertia: I g 
-
Modulus of rupture: f r  0.62 f c '  3.396 MPa
-
Distance form centroidal axis of concrete section: Yt 
-
Cracking moment: M cr 
-
Distance to neutral axis: B 
b
 327.77 m
nmr  As
r
 nmr  1  As  0.871
-
DB  10 mm
  DB 2
 392.699 mm 2
4
  DB 2
As  nc 
 392.699 mm 2
4
fr I g
yt
Es
 7.769
Ec
bt 3
 14400 cm 4
12
 8.15 kN.m
nmr  As
r  d 
2

2  d  B  1 
  1  r   1  r 
d


C
 0.022 m
B
Moment of inertia of cracked transformed section:
b  C3
2
2
 nmr  As   d  C    nmr  1  As   C  d    1982.699 cm4
3
Effective moment of inertia due to dead loads at mid span:
 M 3

  M 3 
4
cr
cr


I e,mid , D  min 
I

1

I
,
I
 g

 cr g   14400 cm
M
M
  D  
 D 

I cr 
-
t
 60 mm
2
57
-
-
Effective moment of inertia due to dead+live loads at mid span:
 M 3

  M 3 
4
cr
cr


I e, mid , D  L  min 
I

1

I
,
I
 g

 cr g   14400 cm
M
M
  D  L  
 D  L 

Effective moment of inertia due to dead loads (using mid span value):
Ie, D  Ie,mid , D  14400 cm4
-
Effective moment of inertia due to dead+live loads (using mid span value):
Ie, D L  I e,mid , D L  14400 cm4
-
-
-
-
Immediate deflection due to dead loads:
 Ig 
i , D   e, D 
 5.52 mm
 I 
 e, D 
Immediate deflection due to dead+live loads:
 Ig 
i , D  L   e, D  L 
  7.28 mm
I
 e, D  L 
Immediate deflection due to live loads:
i , L  e, D  L  e, D  1.76 mm
Since i , L  1.76 mm 
L
 11.667 mm , instantaneous deflection is Acceptable!
360
b) Long-term Deflection
- Bending moment due to sustained load:
M sus  M D    M L  6.114 kN.m
- Effective bending moment of inertia due to dead load at mid span:
 M 3

  M 3 
I e, sus  min  cr  I g  1   cr   I cr , I g   14400 cm 4
M
  M sus  
 sus 

-
-
Immediate deflection due to sustained load:
 Ig 
 i , sus   e , sus 
  6.048 mm
I
 e , sus 
Time dependent factor for 5 years or more:   2
A
Compression reinforcement ratio:    s  0.004
bd
Factor:  

 1.657
1  50  
Long-term deflection due to creep and shrinkage:
 longterm  D   i , sus  10.024 mm
-
Total long-term deflection:
 total longterm   longterm  0.7   L  11.256 mm
-
Since total longterm  11.256 
L
 17.5 mm , long-term deflection is Acceptable!
240
58
4.5. Beam Design
4.5.1. Hand Calculation Design of Beam
Beam B25x50 is chosen as a sample of hand calculation procedure. It is the side beam which
locates on first floor as shown in Figure 4.15.
Figure 4.15 Beam B25x50 on First Floor
4.5.2.1. Flexural Design of B25x50
a)
Material Properties
The material properties for beam design are specified as follow:
-
Beam width:
Beam height:
b  250 mm
h  500 mm
-
Concrete compressive strength:
fc  30 MPa
-
Steel yield strength:
f y  390 MPa
-
Concrete elastic modulus:
Ec  25742.96 MPa
-
Steel elastic modulus:
-
Deformed bar diameter:
Es  200000 MPa
DB  16 mm
-
Stirrup dimeter:
dstirrup  10 mm
-
Stirrup yield strength
f yt  295 MPa
-
Aggregate diameter:
dagg  20 mm
-
Concrete clear cover for beam:
cc  40 mm
-
Minimum rebar spacing:
-
Assume tension-controlled section:
sh  30 mm
  0.9
-
Effective depth:
d  h  (cc  dstirrup  DB  20)  414 mm
59
dt  d
b)
Factored bending moment taken from ETABS
The factored bending moment used for the design of beam B25x50 is taken from the load
combination U 8  1.2D  L  0.5Lr  W , as shown in Figure 4.16 which has the maximum value about:
Mu  101.60 kN.m
Figure 4.16 M3 moment of B25x50
c)
-
Verification of Beam to be Singly-Reinforced or Doubly-reinforced Beam

f '
4M u
Reinforcement ratio:
  0.85  c 1  1 
'
2 
fy 
1.7 f c bd 
  0.85 
30 
4  101.60
 1  1 
390 
1.7  0.9  30  0.25  0.4142

  0.0071

-
Minimum reinforcement ratio:
-

f c ' 1.4 
30 1.4 
,   max  0.25 
,
  0.004

fy fy 
390 390 



'
 0.05  f c  28 
 0.05  30  28  
  0.85  
1  0.85  
  0.836


7
7




Maximum strain at the extreme concrete compression fiber:  cu  0.003
-
Strain in steel reinforcement:
-
Maximum reinforcement ratio:

f '
 cu
30 
0.003

 max  0.85  1  c 
  0.85  0.836 

  0.02
f y   cu  0.005 
390  0.003  0.005 
Since min  0.004    0.007  max  0.02 , thus beam will be designed as singly-reinforced
beam!

 min  max  0.25 
-
d)
-
y 
fy
Es

390
 0.002
2 105
Singly-Reinforced Rectangular Beam Design
Required reinforcement area:
As.req  max  bd , min bd 
As.req  max  0.0071 0.25  0.414,0.004  0.25  0.414  739.59 mm2
-
Used rebar area:
As. DB 
  DB 2
4
60

3.14  162
 201.062 mm 2
4
-
Amount of rebars needed:
n
As , req

As
739.59
 3.678  5
201.062
So, the amount of rebar used in tension zone is: 5 DB16 !
e)
Verification of Design Strength of Beam
-
3.14  162
 1005.31 mm 2
4
4
As . pro f y
1005.31  390
Depth of equivalent compression stress block: a 

 61.501 mm
0.85 f c 'b 0.85  30  0.25
Provided reinforcement area:
As. pro  n 
  DB 2
 4
Distance from extreme compression fiber to neutral axis: c 
a
1

61.501
 73.591 mm
0.836
Figure 4.17 Tension Reinforcement of Rectangular Beam B25x50 Cross-section
dt  c
414  73.591
  cu 
 0.003  0.014
c
61.501
f
390
y  y 
 0.002
Es 2 105
-
Tensile strain in tension reinforcement:  t 
-
Strain in steel reinforcement:
-
Since  t  0.014  0.005 , the beam is tension-controlled section!    0.9
-
a

Design moment:  M n   As. pro f y  d  
2



 M n  0.9  1005.31  30  0.414 
-
-
61.501 
  135.235 kN.m
2 
Since  M n  135.235 kN.m  M u  101.60 kN.m , thus the design is SAFE!
Minimum rebar spacing:
4
4


smin  max  DB, 25 mm, d agg   max(16 mm, 25 mm,  20 mm  26.667 mm
3
3


Rebar spacing for the first layer with 3 rebar:
61
s
b  2cc  2d stirrup  n  DB
n 1
250  2  40  2  10  3  16
s
 51 mm
3 1
Since s  smin , the spacing of rebar is acceptable that allow the aggregate go through while concrete
pouring in the construction site.
4.5.2.2. Shear Design of B25x50
a)
-
Material Properties
Concrete compressive strength:
fc  30 MPa
-
Concrete elastic modulus:
Ec  25742.96 MPa
-
Stirrup yield strength:
f yt  295 MPa
-
Steel elastic modulus:
Stirrup diameters:
Es  200000 MPa
-
Concrete cover for beam:
Amount of stirrup leg:
-
Strength reduction factor:
  0.75
Design for shear reinforcement
Factored shear force from ETABS: Vu  109.70 kN
Shear strength attribute to concrete:
b)
-
Vc  0.17 
-
-
-
d stirrup  10 mm
cc  40 mm
nleg  2
f c '  bw d  0.17  1  30  0.25  0.414  96.372 kN
Since Vu  96.372 kN   Vc  72.276 kN , thus shear reinforcement is required!
Shear strength attribute to shear reinforcement:
V  Vc 109.70  72.276
Vs  u

 49.895 kN

0.75
Required shear area per meter length:
A
Vs
49.895
Av .s  v 

 408.539 mm 2 m
s
f yt  d 295  0.414
Provided stirrup area:
Av , pro  nleg 
2
  d stirrup
4
 2
3.14  102
 157.08 mm 2
4
-
Required spacing:
Av , pro
157.08
sreq 

 380 mm
Av , s
408.539
-
Since Vs  49.895 kN  0.33 f cbw d  0.33  30  0.25  0.4142  187.075 kN
-
Thus, the maximum stirrup spacing is:
d

 414

smax  min  ,600 mm   min 
,600 mm   207 mm
2

 2

-
Take stirrup spacing as: sstirrup  min  sreq , smax   min(380 mm, 207 mm)  207 mm
s stirrup  200 mm
62
4.5.2.3. Design for Combined Shear & Torsion
a)
-
Check whether torsion can be neglect or not
Factored Torsional Force:
Tu  10.88 kN.m
Area enclosed by outside perimeter of concrete cross section:
Acp  b  h  250  500  125000 mm 2
-
Outside perimeter of the concrete cross section:
pcp  2  b  h   2(250  500)  1500 mm
-
Threshold torsion:
Tth  0.083 f c'
b)
-
Acp2
pcp
 0.083  1  30 
1250002
 4.736 kN.m
1500
Since Tu  10.88 kN.m   Tth  0.75  4.736  3.552 kN.m , torsional reinforcement is required!
Check limitation on cross sectional dimension:
Aoh   b  2cc  d stirrup    h  2cc  d stirrup    250  2  40  10    500  2  40  10 
Aoh  65600 mm2
-
ph  2  b  2cc  d stirrup    h  2cc  d stirrup    2  250  2  40  10    500  2  40  10  
ph  65600 mm2
2
-
 Vu   Tu ph

 
2
 bw d   1.7 Aoh
2
 Vc

 96.372

 0.66 f c   0.75 
 0.66  30   3.41 MPa
 0.25  0.414

 bw d


2
c)
-
-
2

 109.70   10.88  65600 
 1.999 MPa
 
 
2 
 250  414   1.7  65600 

2
 V   T p 
 V

Since  u    u h2     c  0.66 f c  , thus beam section has Adequate size!
 bw d   1.7 Aoh 
 bw d

Design for combined shear & torsion (stirrup)
Stirrup area required for shear per meter length:
A
Vs
49.895
Av.s  v 

 408.539 mm 2 m
s
f yt  d 295  0.414
Permitted   45o for non-prestressed members
Transvers torsional reinforcement requirement area per meter length:
A
T /
At , s  t  u
tan 
s 2 Ao f yt
Where Ao  0.85 Aoh  0.85  65600  55760 mm2
10.88 kN.m
At
Tu / 
0.75
 At , s 

tan  
 tan(45o )  440.954 mm 2 m
s 2 Ao f yt
2  0.056  295
-
Transverse reinforcement for combined shear and torsion:
 Av  2 At 
-
s  408.539  2  440.954  1290.446 mm2 m
Minimum reinforcement:
63

b
b 
s  max  0.062 f c w , 0.35 w 

f yt
f yt 

0.25
0.25 
2
, 0.35 
 Av  2 At min s  max  0.062 30c 
  296.61 mm m
295
295 

Required area of stirrup:
 Av  2 At min
-
 Av  2 At req
-
Provided stirrup area:
Av , pro  nleg 
-
-
d)
-
-
s  max   Av  2 At  s ,  Av  2 At min s   1290.446 mm 2 m
2
  d stirrup
 2
3.14  102
 157.08 mm 2
4
4
Required spacing of stirrups:
Av , pro
157.08
s

 121.725 mm  120 mm
 Av  2 At req s 1290.446
Maximum spacing:
p

 1140

smax  min  h ,300 mm   min 
,300 mm   142.5 mm
 8

 8

smax  140 mm
Used stirrup spacing for combined shear & torsion: DB10@100 mm
Determine transverse reinforcement
Required longitudinal torsional reinforcement:
T   ph cot   10.88 0.75  1.14 cot 45o  380.238 mm2
Al ,req  u
 
2 A0 f y
2  0.056  390
Minimum longitudinal reinforcement:
 0.42 f c Acp  A 
f yt
  t  ph

fy
fy
 s 

Al ,min  min 
f yt
 0.42 f c Acp  0.175bw 

ph


 f

fy
fy
yt



Al ,min
 0.42  30  0.125
295
  440.954   1.14 
 357.081 mm 2

390
390

 min 
 0.42  30  0.125   0.175  0.25   1.14  295  609.434 mm 2



390
295
390


Al ,min  357.081 mm2
-
Used longitudinal torsional reinforcement area:
Al  max  Al , req , Al ,min   max  380.238,357.081  380.238 mm 2
4.5.2.4. Instantaneous Deflection of B25x50
a)
-
Material properties
The values of moment are taken from serviceability limit state (SLS Crack Model).
Moment due to dead loads:
M D  63.52 kN.m
Moment due to live loads:
M L  10.53 kN.m
Moments due to dead+live loads: M D  L  63.52  10.53  74.05 kN.m
b  250 mm
Beam dimension:
64
h  500 mm
L  6.05 m
-
Clear cover:
-
Half spacing from 1st to 2nd layer: shf  20 mm
-
Deformed bar diameter:
DB  16 mm
-
Stirrup diameter:
dstirrup  10 mm
-
-
Effective depth from extreme compression fiber of tension steel: d  414 mm
Effective depth from extreme compression fiber of compression steel:
DB
d '  cc  d stirrup 
 58 mm
2
Number of tension rebar:
nt  5
Number of compression rebar: nc  3
-
Area of tension rebar:
-
Area of compression rebar:
-
Strength reduction factor:
-
Net tensile strain:
-
Modular ratio:
-
b)
-
-
cc  40 mm
-
-
  DB 2
 5
 t  0.014
E
200000
nmr  s 
 7.769
Ec 25742.96
Instantaneous deflection
Gross moment of inertia:
bh3 250  5003
Ig 

 2603416.667 cm 4
12
12
Modulus of rupture:
f r  0.62
-
3.14  162
 1005.31 mm 2
4
4
  DB 2
3.14  162
As  nc 
 3
 603.186 mm 2
4
4
  0.9
As  nt 
f c '  0.62  1  30  3.396 MPa
Distance from centroidal axis of concrete section:
h
Yt   250 mm
2
Cracking moment:
f r I g 3.396  2603416.667
M cr 

 35.374 kN.m
yt
250
Distance to neutral axis:
b
250
B

 32.009 m
nmr  As 7.769  1005.31
r
C
C
 nmr  1  As   7.769  1  603.186  0.523
nmr  As
7.769  1005.31
r  d 
2

2  d  B  1 
  1  r   1  r 
d


B
2
 0.523  0.058 
2  0.414  32.009   1 
  1  0.058   1  0.058 
0.414


32.009
65
-
C  0.126 m
Moment of inertia of cracked transformed section:
b  C3
2
2
I cr 
 nmr  As   d  C    nmr  1  As   C  d 
3
I cr 
0.25   0.126 
3
3
  0.126  0.058
-
2
 7.769 1005.31  0.414  0.126   7.769  1  603.186
2
I cr  83339.715 cm 4
Effective moment of inertia due to dead loads at mid span:
 M 3

  M 3 
cr
cr
I e,mid , D  min 
 I g  1  
  I cr , I g 
M
  M D  
 D 

 35.37 3

  35.37 3 
I e, mid , D  min 

2603416.66

1  

   83339.71, 2603416.66 
  63.52  
 63.52 

Ie,mid , D  113922.274 cm4
-
Effective moment of inertia due to dead+live loads at mid span:
 M 3

  M 3 
cr
cr
I e, mid , D  L  min 
 I g  1  
  I cr , I g 
M
  M D  L  
 D  L 

 35.37 3

  35.37 3 
I e ,mid , D  L  min 

2603416.66

1  

   83339.71, 2603416.66 
  74.05  
 74.05 

Ie,mid , D L  102642.95 cm4
-
Using the mid span value:
Effective moment of inertia due to dead loads:
Ie, D  Ie,mid , D  113922.274 cm4
-
Effective moment of inertia due to dead+live loads:
I e, D L  Ie,mid , D L  102642.95 cm4
1
16
-
Coefficient for fixed support beam:  a 
-
Immediate deflection due to dead loads:
 M L2  1 

63.52  6.052
i,D   a  D    

 E I  16
 25742.96  113922.27 
 c e, D 
i , D  4.955 mm
-
Immediate deflection due to dead+live loads:
 M L2  1 

74.05  6.052
i,D L  a  D L    

E I
 16
 25742.96  102642.95 
 c e, D  L 
i , D  L  6.411 mm
-
Immediate deflection due to live loads:
i , L  i , D  L  i , D  6.411  4.955  1.456 mm
66
-
L
6.05

 16.806 mm
360 360
Thus, the instantaneous deflection is Acceptable!
Since i , L  1.456 mm   allow 
4.5.2.5. Long-term Deflection of B25x50
-
Portion of sustained live load:
  30%
Bending moment due to sustained load:
M sus  M D    M L  63.52  0.3  10.53  66.679 kN.m
Effective moment of inertia due to dead load at mid span:
 M 3

  M 3 
cr
cr
I e, sus  min 
 I g  1  
  I cr , I g 
  M sus  
 M sus 

I e , sus


  35.37 3 
3
 min  66.67   2603416.66  1  
   83339.71, 2603416.66 
  66.67  


I e, sus  109778.291cm4
-
-
Immediate deflection due to sustained load:
 M L2  1 

66.67  6.052
 i , sus   a  sus    
  5.398 mm
E I
 16
 25742.96  109778.291 
 c e , sus 
Time dependent factor for 5 years or more:   2
A
603.186
 0.006
Compression reinforcement ratio:    s 
b  d 250  414

2

 1.549
Factor:  
1  50   1  50  0.006
Long-term deflection due to creep and shrinkage:
longterm   i , sus  1.549  5.398 mm  8.359 mm
-
Total long-term deflection:
 total   longterm  1     i , L  8.359  1  0.3  1.456  9.379 mm
-
Since total  9.379 mm  allow 
L
6.05

 12.604 mm , long-term deflection of the beam is
480 480
Acceptable!
4.5.2. Beam Design in ETABS
4.5.2.1. Flexural Design of Beam B25x50
ETABS has the strong ability to design the beam automatically and faster. As a results from the
design in ETABS, the required area for longitudinal reinforcement is As , req  724 mm2 , as illustrated in
Figure 4.18.
The value of As , req , from ETABS is then input in beam design spreadsheet in MathCad Prime in
order to find the required amount of rebar. The procedure is shown as following:
-
Required rebar area:
As , req  724 mm2
-
Diameter of rebar:
DB  16 mm
67
Figure 4.18 Beam design in ETABS
  DB 2
 201.062 mm 2
-
Area of rebar:
As .DB 
-
Number of rebar:
n
-
Provided rebar area:
As . pro  n 
-
Gross area of beam:
 804.248 mm 2
4
Ag  b  h  0.15 m 2
-
Rebar percentage:

As , req
As
As , pro
Ag
4
 3.377  5
  DB 2
 0.536%
4.5.2.2. Combined shear and Torsion Design of Beam B25x50
The transverse reinforcement required area for combined shear & torsion is Av s  1640 mm2 m
, as shown in Figure 4.19.
Since ETABS does not differentiate the required area of combined shear & torsion and longitudinal
reinforcement area, using the result of transverse reinforcement from ETABS will not receive the accurate
results. Thus, finding stirrup spacing can use the hand calculation method.
68
Figure 4.19 Transverse reinforcement required area in ETABS
4.5.3. Beam B25x50 Discussion & Summary
According to the design of beam B25x50 by hand calculation and ETABS, we can conclude that
ETABS and hand calculation give similar result which is acceptable for further detailing of the beam. Table
4.16 show the beam B25x50 cross-section with determined reinforcement. Detailing of beams along gird
line G are illustrated in Figure 4.20.
Table 4.16 Beam B25x50 cross-section
Support
Cross-section
Top Bars
Side Bars
Bottom Bars
Stirrup
Mid Span
250x500
5DB16
2DB12
3DB16
DB10@100
Cross-section
Top Bars
Side Bars
Bottom Bars
Stirrup
69
250x500
3DB16
2DB12
5DB16
DB10@200
Figure 4.20 Detailing of beams along gird line 4
70
4.6. Column Design
4.6.1. Colum Design in ETABS
It is desirable to use as few column sizes as possible for the same story as it ensures consistency
and provide appreciable savings in formwork and labor costs. So, in this project there are only 3 different
sizes of column due to the location of the columns whether they are side columns or middle columns and
because of the span between columns. Those three sizes of column are C30x30 (300mm x 300mm), C30x40
(300mm x 400mm), C30x50 (300mm x 500 mm). Also, for economical perspective, column size is changing
to all C30x30 from first floor due to lesser of floor levels which result in less amounts of axial forces acting
on columns. From this regard, the construction will be easier and faster because only one size of column is
using and also reducing some amounts of loads acting on the foundation. The cross-section and steel
reinforcements distribution in columns will be shown in Table 4.17.
Table 4.17 Column cross-section and its provided reinforcement area
Colum Size
(mm)
Reinforcement
Area (mm2)
Provided Reinforcement
Ratio (%)
C1(300x300)
1609
1.79
C2(300x400)
1609
1.34
C3(300x500)
2011
1.34
Column Cross-section
4.6.2. P-M Interaction Diagram
For a given reinforced column cross section, a large collection of pairs of axial loads and bending
moments are calculated using different value of, c , which is the depth of the neutral axis and corresponds
to different combined loading conditions of axial force and bending moment. The resulting pairs of axial
loading capacity, Pn , and bending moment capacity, M n , from assuming different values of depth of
neutral axis, c, are plotted to generate a P-M interaction diagram. The generated P-M interaction diagrams
71
are modified with three factors to account for accidental moment, tie or spiral column, and failure in brittle
or ductile manner. Three P-M interaction diagrams will be generated for the three reinforced column cross
sections, then the most critical combination of loadings of each column type will be checked with their
corresponding P-M diagrams.
4.6.2.1. P-M Interaction Diagram in ETABS of C2 (300x400)
The P-M interaction diagram of column, C1 (300x400), generated by ETABS for both 2-axis and
3-axis directions are shown below in Table 4.18 and Table 4.19, respectively. The selected column is the
critical 300x400 side-column which located on the ground floor to mezzanine floor.
Table 4.18 P-M Interaction diagram of C2 in 2-axis direction
C2(300x400)
Point
1
2
3
4
5
6
7
8
9
10
11
Pn
Mn2
Mn3
(kN) (kN.m) (kN.m)
1896.13
0
0.00
1896.13
0
55.24
1763.66
0
87.57
1485.43
0
112.40
1185.50
0
129.15
853.37
0
139.59
746.14
0
152.84
528.79
0
158.43
206.19
0
120.63
-245.40
0
55.02
-564.69
0
0.00
P-M3 Interaction Diagram
Table 4.19 P-M Interaction diagram of C2 in 3-axis direction
C2(300x400)
Point
1
2
3
4
5
6
7
8
9
10
11
Pn
Mn2
Mn3
(kN) (kN.m) (kN.m)
1896.13
0.00
0
1896.13 -40.11
0
1752.82 -64.55
0
1463.01 -82.46
0
1148.87 -93.55
0
785.06
-98.24
0
648.66 -103.82
0
416.65 -104.66
0
99.01
-76.12
0
-340.55 -30.88
0
-564.69
0.00
0
P-M2 Interaction Diagram
The shown P-M interaction diagrams are generated from combined axial force and bending
moment that included design strength reduction factor,  . The blue dots inside each P-M interaction
diagram are the sets of imposed combined axial force and bending moment from different factored load
combinations. The blue dots that lie close to the boundary of the diagram are the result from the huge
factored axial load and bending moment from the critical load combination. If the blue dots fall outside
72
the diagram boundary, it means the column fail to support such load and it must revise the design. The
selected column is the most critical one of its types, located on lower story of the structure, therefore highcapacity ratio is expected and should be of no concern. Meanwhile, other columns area experiencing lower
capacity ration meaning they are functioning more conservatively.
Figure 4.21 Interaction diagram for section C30x40
The most critical load combination acting on the selected column, C2 (300x400), is the
combination U7=1.2D+L+0.5Lr+W as shown in Figure 4.21. The details of its factored load and
capacity ratio can be found in Table 4.20.
Table 4.20 Summary of factored loads and capacity ratio of C30x40
Combo
U7: 1.2D+L+0.5Lr+W
C1 (300x400)
Pu (kN)
Mu2 (kN.m)
908.55
-29.06
Mu3 (kN.m)
-50.04
D/C Ratio
0.623
4.6.2.2. P-M Interaction Diagram by Hand Calculation
For verification of the consistency and correctness of ETABS, P-M interaction diagram is also
plotted by hand calculation using MathCad Prime. The process of plotting the diagram is by using the pure
axial forces and bending without the consideration of strength reduction factored,  . Few load
combinations are selected for the interaction diagram plotting, including the most critical combination. The
values of the design axial load and bending moments for both 2-axis and 3-axis direction are shown in
Table 4.21 and Table 4.22. The critical load combination and another load combination for the verification
of P-M interaction diagram are:

The critical load combination for this column is U7: 1.2D+L+0.5Lr+W, which has the value of
factored axial force and bending moment as following:
o Pu  908.75 kN
o M u 2  29.06 kN.m
o M u 3  50.03 kN.m

Another selected load combination for P-M diagram plotting is U11: 0.9D+W, which has the value
of factored axial force and bending moment as indicated below:
o Pu  546.71 kN
73
o
o
M u 2  21.66 kN.m
M u 3  33.71 kN.m
Table 4.21 Values of design axial force and moment in 2-axis direction
Point
Pn-2 (kN)
Mn-2 (kN.m)
Mn-3 (kN.m)
1
2
3
4
5
6
7
8
9
10
11
2917.13
2917.13
2696.64
2250.78
1767.49
1207.79
861.28
462.94
110.01
-378.39
-627.43
0.00
-61.70
-99.30
-126.86
-143.93
-151.13
-137.85
-116.29
-84.57
-34.32
-0.00
0
0
0
0
0
0
0
0
0
0
0
Table 4.22 Values of design axial force and moment in 3-axis direction
Point
Pn-3 (kN)
Mn-2 (kN.m)
Mn-3 (kN.m)
1
2
3
4
5
6
7
8
9
10
11
2917.126
2917.126
2713.321
2285.281
1823.851
1312.874
990.707
587.5442
229.0963
-272.6704
-627.432
0
0
0
0
0
0
0
0
0
0
0
0
84.9818
134.7296
172.9259
198.6997
214.7496
202.9432
176.0374
134.0306
61.132
0
The procedure of plotting P-M interaction diagram is conducted by putting all values of Pn2, Mn2,
Pn3 and Mn3, separately as matrix function in MathCad Prime. After that there is a function “Insert Plot” in
MathCad Prime that can use to produce the interaction diagram automatically by just setting the parameter
Pn2 as Y-axis and Mn2 as X-axis. And so on, the same procedure is applied to Pn3 and Mn3 diagram. After
getting the P-M interaction diagram of (Pn2, Mn2) and (Pn3, Mn3), the values of (Pu, Mu2) and (Pu, Mu3) from
different load combinations are inserted as point into the diagram of (Pn2, Mn2) and (Pn3, Mn3), respectively.
The P-M interaction diagrams for the combination U7: 1.2D+L+0.5Lr+W are shown in Figure
4.22 and Figure 4.23.
74
Figure 4.22 P-M Interaction diagram in 2-axis direction of C3x40 for combo U7
Figure 4.23 P-M Interaction diagram in 3-axis direction of C3x40 for combo U7
75
The cyan lines are the line that connect from point (0, 0) to point (Pu, Mu2) and extended further
more until it reaches the outer surface of diagram (Pn2, Mn2). Then, the projection line drew from the
intersection point of cyan line and outer surface of the P-M diagram parallelly to Mn2-axis and reach the
Pn2-axis. The value from the projection line on the Pn2 axis is the value of design axial force Pnx-2 due to the
factored axial load Pu. The same procedure is applied on the (Pn3, Mn3) interaction diagram in order to get
the value of design axial force Pny-3 due to the factored load Pu. The summary of the values of Pnx-2 and Pny3 are shown in the Table 4.23.
Table 4.23 Summary values of Pnx-2 and Pny-3 for combo U7
U7: 1.2D+L+0.5Lr+W
Pnx2 (kN)
2816
Pu (kN)
908.75
Pny3 (kN)
2620
The mathematic calculation below is the procedure using the Reciprocal Load Method in order
to find the design axial force Pn resulting from the combined axial force and biaxial bending moments.
-
Concrete compressive strength:
fc  30 MPa
-
Steel yield strength:
f y  390 MPa
-
Column dimension:
b  300 mm
h  400 mm
-
Gross area of column cross section:
Ag  b  h  300  400  120000 mm 2
-
Rebar diameter:
Amount of rebar:
-
Area of reinforcement bar:
-
DB  16 mm
n8
  DB 2
Ast  n 
 1608.495 mm 2
4
  0.65
Strength reduction factor:
Strength of concentrically load:
P0  0.85  f c   Ag  Ast   f y  Ast  3646.297 kN
-
Since Pu  908.75 kN  0.1   fc  Ag  234 kN , use Reciprocal Load Method!
-
Design strength Pn:
Pn 
-
1
1

 2161.965 kN
1
1
1
1
1
1




Pnx 2 Pny 3 P0 2816 2620 3646.29
Capacity Ratio:
D C
-
Comparing the capacity ratio result with ETABS:
o ETABS result: D C ETABS  0.623
o
-
Pu
908.75

 0.647
 Pn 0.65  2161.965
My result:
D C Hand  0.647
Calculation of error:
D C Hand  D C ETABS 0.647  0.623

 0.037  3.7 %
D C Hand
0.647
The P-M interaction diagrams for the combination U11: 0.9D+W are shown in Figure 4.24 and
Figure 4.25.
76
Figure 4.24 P-M Interaction diagram in 2-axis direction of C3x40 for combo U11
Figure 4. 25 P-M Interaction diagram in 3-axis direction of C3x40 for combo U11
77
By following the same projection line procedure as applied with the load combination U7, the
values of Pnx2 and Pnx3 resulting from the combination U11 can be received as indicated in the Table
4.23.
Table 4. 24 Summary values of Pnx-2 and Pny-3 for combo U11
U11: 0.9D+W
Pnx2 (kN)
2761
Pu (kN)
546.71
Pny3 (kN)
2489
Then, by applying the same mathematic calculation procedure using Reciprocal Load Method,
the design axial force Pn resulting from the combined axial force and biaxial bending moments for U11
can be found as following:
-
Strength of concentrically load:
P0  0.85  f c   Ag  Ast   f y  Ast  3646.297 kN
-
Since Pu  546.71kN  0.1   fc  Ag  234 kN , use Reciprocal Load Method!
-
Design strength Pn:
Pn 
-
1
1

 2042.048 kN
1
1
1
1
1
1




Pnx 2 Pny 3 P0 2761 2489 3646.29
Capacity Ratio:
D C
-
Comparing the capacity ratio result with ETABS:
o ETABS result: D C ETABS  0.413
o
-
Pu
546.71

 0.412
 Pn 0.65  2042.048
D C Hand  0.412
My result:
Calculation of error:
D C ETABS  D C Hand 0.413  0.412

 0.0024  0.24 %
D C ETABS
0.413
The summary result of column, C2 (300x400), from ETABS are shown in the Table below.
ETABS Concrete Frame Design
ACI 318-19 Column Section Design
Level
Mezzanine Floor
Unique
Element
Name
C22
457
Column Element Details (Summary)
Station
Section ID
Combo ID
Length (mm)
Loc
C30X40 8DB16
U7 1.2D+L+0.5Lr+W
78
0
4200
LLRF
Type
0.528
Sway Special
Section Properties
b (mm)
h (mm)
dc (mm)
Cover (Torsion) (mm)
300
400
58
27.3
Material Properties
Ec (MPa)
f'c (MPa)
Lt.Wt Factor (Unitless)
fy (MPa)
fys (MPa)
25743
30
1
390
235
Design Code Parameters
ϕT
ϕCTied
ϕCSpiral
ϕVns
ϕVs
ϕVjoint
Ω0
0.9
0.65
0.75
0.75
0.6
0.85
2
Axial Force and Biaxial Moment Design For Pu , Mu2 , Mu3
Design Pu
kN
Design Mu2
kN-m
Design Mu3
kN-m
Minimum M2
kN-m
Minimum M3
kN-m
Rebar %
%
Capacity Ratio
Unitless
908.5586
-29.063
50.0421
22.0235
24.7491
1.34
0.623
Axial Force and Biaxial Moment Factors
Cm Factor
Unitless
δns Factor
Unitless
δs Factor
Unitless
K Factor
Unitless
Effective Length
mm
Major Bend(M3)
0.330473
1
1
1
3700
Minor Bend(M2)
0.269047
1
1
1
3700
Shear Design for Vu2 , Vu3
Shear Vu
kN
Shear ϕVc
kN
Shear ϕVs
kN
Shear ϕVp
kN
Rebar Av /s
mm²/m
Major, Vu2
22.6138
148.7952
0
0
0
Minor, Vu3
12.8303
145.117
0
0
0
4.6.3. Determining of Column Lap Splice Length
ACI318-19 (Section 25.5.2.1) provides the method for calculating the lap splice length as the
following procedure:
-
Concrete compressive strength:
fc  30 MPa
-
Steel yield strength:
f y  390 MPa
-
Normal weight concrete:
e 1
t 1
 1
-
 g 1
-
Development length:
 f y  t  e  g 

ld  max 
 DB, 300 mm   542.50 mm (ACI 318-19, Section 25.4.2.1)
 2.1    f c 

Lap splice length:
lst  max 1.3  ld , 300 mm   705.25 mm
(ACI 318-19, Section 25.2.2.1)
-
Selected lap splice length: 750 mm
79
4.6.4. Colum Detailing
The cross-section and elevation detailing of column C2(300mmx400mm) area shown in Figure
4.26 and 4.27. More detailing of other columns can be found in Appendix C.
Figure 4.26 C2(300mmx400mm) column cross-section
Figure 4.27 Elevation detailing of C2(300mmx400mm)
80
4.7. Checking Building and Story Drift
4.7.1. Overall Building Drift
Drift (lateral deflection) of concern in serviceability checking arise primary form the effects of
wind. According to ASCE7-16 (Appendix CC.2.2), drift limits in common usage for building design are on
the order of 1/600 to 1/400 of the building or story height. In this project, the drift limit of 1/400 is chosen
for the story drift checking. The overall building drift can be generated automatically in ETABS. Those
values are shown in Fig.4.28 and Table 4.25.
Table 4.25 Story Response Values of building drift
Story
Roof
Terrace
Second Floor
First Floor
Mezzanine Floor
Ground Floor
Base
Elevation
m
19.4
15.4
11.4
7.4
4.2
0
-1.5
Location
Top
Top
Top
Top
Top
Top
Top
X-Dir
mm
5.034
5.748
4.975
3.678
2.872
0.622
0
Figure 4.28 Diagram of building drift
Overall building drift:  overall  14.28 mm
Allowable overall building drift:  allow 
H 19.4  1000

 48.5 mm
400
400
81
Y-Dir
mm
9.472
14.279
12.725
9.818
7.785
1.98
0
Since  overall   allow  OK !
4.7.2. Inter-Story Drift
Story drift is the lateral displacement of one level relative to the level above or below. Story drift
ratio is the story drift divided by the story height. According to ASCE7-16 (Appendix CC.2.2), drift limits
in common usage for building design are on the order of 1/600 to 1/400 of the building or story height.
In this project, the drift limit of 1/400 is chosen for the story drift checking. Values of story drift taken
from ETABS are shown in Table 4.26 and Figure 4.29.
Table 4.26 Story response values of story drifts
Story
Roof
Terrace
Second Floor
First Floor
Mezzanine Floor
Ground Floor
Base
Elevation (m) Location
19.4
15.4
11.4
7.4
4.2
0
-1.5
Top
Top
Top
Top
Top
Top
Top
X-Dir
Y-Dir
0.000163
0.000197
0.000325
0.000376
0.000582
0.000415
0
0.000405
0.000389
0.00073
0.000929
0.001382
0.00132
0
Figure 4.29 Diagram of story drift
82
Allowable
Story Drift
(1/400)
0.0025
0.0025
0.0025
0.0025
0.0025
0.0025
0.0025
Status
OK
OK
OK
OK
OK
OK
OK
Chapter 5: Conclusion
In conclusion, as the project comes to an end, it can be assumed that all the project deliverables
have been successfully completed and presented satisfactorily. As the aim of this project was to design
reinforced concrete structure of DALORA hospital with an objective to design only superstructure of the
building including slabs, beams, and columns, and also provide construction drawing of each structural
member. The design and calculation are mainly based on ACI318-19 and ASCE 7-16 with the help of
structural analysis software ETABS, hand calculation using MathCad Prime, and also using RCM ACI
Builder to confirm the consistency of hand calculation. The original restriction of this project was the
limitation on structural analysis software, which only employed ETABS as the major analysis program,
whereas two or more software should be used in a design to compare the results in order to produce a safe
and accurate design. However, each structural members have been designed accurately to meet the strength
and serviceability requirements, and properly in accordance with the architectural plan. Some members
required smaller cross-section and reinforcements, but for the convenience in real life construction only
few typical cross-sections and reinforcements are used the design. Furthermore, all of the required detailed
drawings of each structural component were successfully prepared in accordance with the code
requirements and may be used in real-life construction. Furthermore, in order to apply this design project
to real-world construction, a few other structural components, such as stairs, footings, and foundations,
must be constructed by simply taking the reaction force at the pin support of each stump column to produce
the design in ETABS or any specific analysis software specialized in those respective structural members.
On a personal level, an immeasurable amount of knowledge and experience was obtained during
the duration of the project. For instance, in order to create the design spreadsheets, I undertook extensive
research on the design of various structural components in all of their potential configurations, which was
really beneficial to me academically. Furthermore, the practical experience of finishing a structural design
project from start to finish, traveling through all of its phases and challenges, has tremendously increased
my insights as a future engineer. Another significant benefit I received from this project was the ability to
use structural design software such as ETABS, RCM ACI Builder, and MathCad Prime. All of these aspects
have given me a sense of accomplishment and self-confidence in implementing any kind of structural design
I may confront in the future. Among the many advantages, the most pleasant part of this project for me
was the experience of working through an independent cycle of work. I created my design tools from
scratch and then used them to develop an actual end product. This was motivating to me because it
indicated that every step I took during the project, resulting in the final structural drawings, was a result of
my original efforts. To summarize, I cannot emphasize how beneficial this experience has been for me
enough. I will be eternally grateful for the opportunity to work on such a project and with my professional
supervisor, Dr. Sophy Chhang, whose incomparable guidance has unquestionably broadened my horizons
as a structural engineer to far greater extents.
83
APPENDIX AARCHITECTURAL PLAN OF DALORA
HOSPITAL
84
85
86
87
88
89
90
APPENDIX BFLOW CHART OF THE DESIGN OF
STRUCTURAL MEMBERS
FLEXURAL DESIGN OF RECTANGULAR BEAM
f c, f y , DB, d stirrup
b, h, d , M u
  0.85 
fc' 
4M u
1  1 
f y 
1.7 f c 'bd 2



 0.05  f c '  28  

1  0.85  


7


 max  0.85  1 
f c '   cu

f y   cu   y

 min  max  0.25 


f c ' 1.4 

,
fy fy 

   min
 min     max
  max
Singly
Reinforced Beam
Doubly
Reinforced Beam
As.req  max   bd ,  min bd 
As 



  DB 2
n
4
91
As , req
As
FLEXURAL DESIGN OF RECTANGULAR BEAM
f c ' , f y , Ec , Es , DB, d stirrup
b, h, d , d t , M u , n
As. pro  n 
a
y 
fy
Es
  DB 2
As. pro f y
0.85 f c 'b
, s 
4
,c
a
1
d c
d c
  cu ,  t  t
  cu
c
c
t   y
 y   t  0.005
 t  0.005
 (Compression Controlled )
 (Transition Controlled )
 (Tension Controlled )

   0.65
   0.65  0.25 
t
  t  0.005
y 
 0.005   
y


a
 M n   As. pro f y  d  
2
SAFE
Yes
4


smin  max  DB, 25mm, d agg 
3


b  2cov er  2d stirrup  n  DB
s
n 1

Mn  Mu
s  max  s, smin 
92
No
Revise design
SHEAR DESIGN OF RECTANGULAR BEAM
f c ' , f yt , d stirrup
b, h, d , Vu ,   1
L' 
Vu1  L
Vu1  Vu 2
Vu , d 
( L ' d )  Vu1
L'
Vc  0.17 f c '  bd
Vu , d   Vc
Vu , d  0.5 Vc
0.5 Vc  Vu ,d   Vc
Shear
reinforcement
required
No shear
reinforcement
required
Minimum shear
reinforcement required

b
b 
Av ,min s  max  0.062 f c '
, 0.35


f yt
f yt 

2
 d stirrup
Av , s  nleg
4
Av , s  max  Av , s , Av ,min s 

b
b 
Av , s  Av ,min s  max  0.062 f c '
, 0.35


f
f
yt
yt 

Vs 
Vud  Vc
sstirrup 

Av , s f yt d
Vs
Vs  0.33 f c' bd
Vs  0.33 f c' bd
d

 smax  min  ,300mm 
4

d

 smax  min  , 600mm 
2

sstirrup  min  sstirrup , smax 
93
TORSIONAL DESIGN OF RECTANGULAR BEAM
f c ' , f yt , d stirrup
b, h, d , Tu ,Vu ,Vc
Acp  x0  y0
pcp  2  x0  y0 
Tth  0.083 f c'
No
Acp2
pcp
Yes
Tu  Tth
Neglect Torsion
2
 Vu   Tu ph 
 V

   c  0.66 f c 

 
2 
 bw d   1.7 Aoh 
 bw d

No
Yes
-
Transvers reinforcement for combined
shear and torsion.
Longitudinal torsional reinforcement.
94
Revise beam
cross-section
COMBINED SHEAR & TORSION DESIGN OF RECTANGULAR BEAM
Av Vu  Vc

s
 df yt
At
T /
 u
tan 
s 2 Ao f yt
Av 2 At

s
s
 Av  2 At min

b
b 
s  max  0.062 f c w , 0.35 w 

f yt
f yt 

Av  2 At
 A  2 At

 max  v
,  Av  2 At min s 
s
s


s
nleg d stirrup
 Av  2 At 
s
p

smax  min  h ,300mm 
 8

sstirrup  min  s, smax 
95
CHECKING INSTANTANEOUS DEFLECTION FOR RECTANGULAR BEAM
f c ' , f yt , Ec , Es , DB, b, h
d , M DL , M LL , M DL  LL
n
Es
Ec
Section at left support
Midspan
Section at right support
Find Ie for DL and DL+LL
Find Ie for DL and DL+LL
Find Ie for DL and DL+LL
I g , I cr
I g , I cr
I g , I cr
f r  7.5 f c '
f r  7.5 f c '
f r  7.5 f c '
M cr 
fr I g
M cr 
yt
fr I g
yt
I e,left
I e , mid
 M L2
 i , DL   a  DL
E I
 c e, DL
Midspan value
or
Simple Average
or
Weighted average



M
L2
 i , DL  LL   a  DL  LL
E I
 c e, DL  LL
M cr 
Revise design
 i , LL   allow
Yes
SAFE
No
96
yt
I e,right



 i , LL   i , DL  LL   i , DL
fr I g
CHECKING LONG-TERM DEFLECTION FOR RECTANGULAR BEAM
 i , DL  LL ,  i , DL ,  ', 


1  50  '
 total   i , DL  LL   i , DL
total   allow
No
Revise design
Yes
SAFE
COLUMN DESIGN PROCEDURE
f c, f y , Ec , Es , DB, d stirrup
b, h, Ag , Pu , , K
As , req
As 
Pu
 0.85 f cAg
K

f y  0.85 f c
  DB 2
4
n
As , req
As
As , pro  n 
g 
  DB 2
As , pro
Ag
97
4
1%   g  8%
Yes
No
Acceptable
sx 
sy 
b  2c  2d stirrup  n  DB
n 1
h  2c  2d stirrup  n  DB
n 1
smin
Revise design
 X  Direction 
Y  Direction 

1.5 DB

 max  cc
4
 d agg
3
SHEAR DESIGN OF COLUMN
f c ' , f yt , d stirrup
b, h, d , Vu ,   1

N
Vc  0.17 1  u
 14 Ag

Vu  0.5 Vc
Shear reinforcement required
Vs 
Vu


'
 f c  bw d

Vu  0.5 Vc
No shear reinforcement required
 Vc  0.66 f cbw d
d

Vs  0.33 f cbw d  smax  min  , 600mm 
2

d

Vs  0.33 f cbw d  smax  min  ,300mm 
4

98
smin  max  48d stirrup ,16 DB, bw 
s   smin  smax 
Av , s 
s   smin  smax 
Vs s
f yt d stirrup

b s
b s
Av ,min  max  0.062 f c ' w , 0.35 w 

f yt
f yt 


b s
b s
Av ,min  max  0.062 f c ' w , 0.35 w 

f yt
f yt 

Av , s  max  Av , s , Av ,min 
Av , pro  nleg 
99
2
 d stirrup
4
 Av , s
100
99
No.
Date
1a
A
B
C2
C1
Revision
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar): fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
C1
C2
C1
C1
C1
3500
B
C1
3500
1. CONCRETE COVER FOR COLUMN : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
1800
C1
C2
C2
Company
C
C2
C2
C2
C1
C
6050
2450
6050
D
C2
C2
C2
C1
30550
30550
3500
3500
E
E
1:120
C1
C2
C2
C1
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
STUMP COLUMN LAYOUT PLAN
Drawn by:
C2
C2
C2
1800
D
Paragon International Designed by:
University
3500
3500
F
F
C1
C2
C2
C1
Signature
3500
3500
3500
3500
Date
G
C1
C2
C1
C3
G
C1
H
SECTION
300x300
300x400
300x500
C2
C3
C1
C1
C1
I
I
COLUMN
STUMP COLUMN LAYOUT
Plan name:
3500
3500
LEGEND :
C1
C2
C3
H
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
1:120
Scale
Owner:
4200
4
A
1
Sheet
33
Sheet No.
Paragon International University
Architectural Engineering
APPENDIX C
STRUCTURAL DETAILING OF DALORA
HOSPITAL
101
No.
Date
1a
A
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar): fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
Revision
B
C2
C1
C1
C2
C1
C1
C1
3500
B
C1
3500
1. CONCRETE COVER FOR COLUMN : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
1800
Company
C
C2
C2
C2
C1
C
C1
C2
C2
C2
C1
30550
30550
3500
3500
E
E
C1
C2
C2
C1
1:120
3500
3500
SCALE
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Signature
GROUND FLOOR COLUMN LAYOUT PLAN
D
C2
C2
C2
D
Name and position
C2
C2
1800
Drawn by:
6050
2450
6050
Paragon International Designed by:
University
3500
3500
F
F
C1
C2
C2
C1
Date
3500
3500
G
3500
3500
C1
H
3500
3500
SECTION
300x300
300x400
300x500
C2
C3
C1
C1
C1
I
I
COLUMN
LEGEND :
C1
C2
C3
H
GROUND FLOOR COLUMN LAYOUT
Plan name:
Site Location:
C1
C2
C3
G
4200
2600
11000
1:120
Scale
Owner:
4200
4
A
1
2
3
4
2
Sheet
33
Sheet No.
Paragon International University
Architectural Engineering
102
No.
Date
1a
A
B
C2
C1
Revision
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar): fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
C1
C2
C1
C1
C1
3500
B
C1
3500
1. CONCRETE COVER FOR COLUMN : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
3500
3500
1800
C1
C1
C1
6050
2450
6050
C1
C2
C2
C2
30550
30550
3500
3500
E
E
C1
C2
C2
C1
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
1:120
F
F
C1
C2
C2
C1
Signature
MEZZANINE FLOOR COLUMN LAYOUT PLAN
D
Drawn by:
C2
C1
C1
1800
D
Paragon International Designed by:
University
Company
C
C2
C2
C2
C1
C
3500
3500
Date
G
C1
C2
C3
G
C1
H
SECTION
300x300
300x400
300x500
C1
C2
C3
C1
C1
COLUMN
I
I
MEZZANINE FLOOR COLUMN LAYOUT
Plan name:
3500
3500
LEGEND :
C1
C2
C3
H
Site Location:
3500
3500
4200
2600
4200
4
A
11000
Sheet
3
Scale
1:120
Owner:
1
2
3
4
33
Sheet No.
Paragon International University
Architectural Engineering
103
No.
Date
1a
A
B
C1
C1
Revision
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar): fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
C1
C1
C1
C1
C1
3500
B
C1
3500
1. CONCRETE COVER FOR COLUMN : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
1800
Company
C
C1
C1
C1
C1
C
C1
C1
C1
6050
2450
6050
D
C1
C1
C1
C1
30550
30550
3500
3500
E
E
C1
C1
C1
C1
1:120
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
Signature
FIRST FLOOR COLUMN LAYOUT PLAN
Drawn by:
C2
C1
C1
1800
D
Paragon International Designed by:
University
3500
3500
C1
C1
C1
C1
Date
3500
3500
G
C1
C1
C1
G
H
H
SECTION
300x300
300x400
300x500
C2
C3
C1
C1
C1
I
I
COLUMN
FIRST FLOOR COLUMN LAYOUT
Plan name:
3500
3500
LEGEND :
C1
C1
C1
C1
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
Sheet
4
Scale
1:120
Owner:
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
104
No.
Date
1a
A
B
C1
C1
Revision
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar): fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
C1
C1
C1
C1
C1
3500
B
C1
3500
1. CONCRETE COVER FOR COLUMN : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
1800
C1
C1
C1
Company
C
C1
C1
C1
C1
C
6050
2450
6050
D
C1
C1
C1
C1
30550
30550
3500
3500
E
E
C1
C1
C1
C1
1:120
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
C1
C1
C1
C1
Signature
SECOND FLOOR COLUMN LAYOUT PLAN
Drawn by:
C2
C1
C1
1800
D
Paragon International Designed by:
University
3500
3500
Date
3500
3500
G
C1
C1
C1
G
H
H
SECTION
300x300
300x400
300x500
C1
C2
C3
C1
C1
COLUMN
I
I
SECOND FLOOR COLUMN LAYOUT
Plan name:
3500
3500
LEGEND :
C1
C1
C1
C1
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
Sheet
5
Scale
1:120
Owner:
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
105
No.
Date
1a
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar): fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR COLUMN : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
C1
C1
C1
Company
C
C1
C1
C
6050
2450
6050
D
C1
C1
30550
30550
3500
3500
E
E
1:120
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
Signature
TERRACE FLOOR COLUMN LAYOUT PLAN
Drawn by:
C2
C1
C1
1800
D
Paragon International Designed by:
University
3500
3500
3500
3500
Date
G
G
H
H
SECTION
300x300
300x400
300x500
COLUMN
C1
C2
C3
I
I
TERRACE FLOOR COLUMN LAYOUT
Plan name:
3500
3500
LEGEND :
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
Sheet
6
Scale
1:120
Owner:
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
No.
Date
3
106
1a
A
Revision
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar) : fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
C1
Company
C
1800
B-02
B25X50
2450
6050
B-01
B25X30
B-02
B25X50
6050
B-02
B25X50
B-01
B25X30
D
30550
30550
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
E
E
1:120
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
Signature
GROUND FLOOR BEAM LAYOUT PLAN
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
B
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
C
B-01
B25X30
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B
B-01
B25X30
3500
1. CONCRETE COVER FOR BEAM : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
2550
B-01
B25X30
1650
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
Date
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
G
G
H
H
SECTION
200x400
300x500
B-01
B-02
I
I
BEAM
B-01
B25X30
GROUND FLOOR BEAM LAYOUT
Plan name:
3500
B-01
B25X30
B-01
B25X30
3500
LEGEND :
Site Location:
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
4200
2600
11000
1
2
3
4
1:120
Scale
Owner:
4200
4
A
7
Sheet
33
Sheet No.
Paragon International University
Architectural Engineering
No.
Date
3
107
1a
A
Revision
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar) : fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
C1
Company
C
1800
B-02
B25X50
2450
6050
B-01
B25X30
B-02
B25X50
6050
B-02
B25X50
B-01
B25X30
D
30550
30550
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
E
E
1:120
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
Signature
MEZZANINE FLOOR BEAM LAYOUT PLAN
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
B
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
C
B-01
B25X30
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B
B-03
B25X45
3500
1. CONCRETE COVER FOR BEAM : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
2550
B-01
B25X30
1650
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
Date
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
G
G
H
H
SECTION
200x400
300x500
B-01
B-02
I
I
BEAM
LEGEND :
3500
B-04
B25X55
B-04
B25X35
3500
B-01
B25X30
MEZZANINE FLOOR BEAM LAYOUT
Plan name:
Site Location:
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
4200
2600
11000
1
2
3
4
1:120
Scale
Owner:
4200
4
A
8
Sheet
33
Sheet No.
Paragon International University
Architectural Engineering
No.
Date
3
108
1a
A
Revision
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar) : fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
Company
C
1800
B-02
B25X50
2450
6050
C1
B-01
B25X30
B-02
B25X50
6050
C2
D
30550
30550
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
E
E
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
3500
F
F
Signature
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
1:120
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
FIRST FLOOR BEAM LAYOUT PLAN
Drawn by:
B-02
B25X50
B-01
B25X30
1800
D
Paragon International Designed by:
University
3500
3500
B
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
C
B-01
B25X30
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B
B-03
B25X45
3500
1. CONCRETE COVER FOR BEAM : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
2550
B-01
B25X30
1650
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
Date
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
G
G
H
H
3500
3500
I
I
SECTION
200x400
300x500
BEAM
B-01
B-02
LEGEND :
FIRST FLOOR BEAM LAYOUT
Plan name:
Site Location:
3500
B-01
B25X30
B-01
B25X30
B-02
B25X50
B-01
B25X30
3500
B-01
B25X30
11000
1
2
3
4
Sheet
9
Scale
1:120
Owner:
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
4200
2600
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
No.
Date
3
109
1a
A
Revision
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar) : fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
C1
Company
C
1800
B-02
B25X50
2450
6050
B-01
B25X30
B-02
B25X50
6050
B-02
B25X50
B-01
B25X30
D
30550
30550
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
E
E
1:120
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
Signature
SECOND FLOOR BEAM LAYOUT PLAN
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
B
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
C
B-03
B25X45
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B
B-01
B25X30
3500
1. CONCRETE COVER FOR BEAM : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
2550
B-01
B25X30
1650
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
Date
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
G
G
H
H
3500
3500
I
I
SECTION
200x400
300x500
BEAM
B-01
B-02
LEGEND :
SECOND FLOOR BEAM LAYOUT
Plan name:
Site Location:
3500
B-01
B25X30
B-01
B25X30
B-02
B25X50
B-01
B25X30
3500
B-01
B25X30
11000
1
2
3
4
Sheet
10
Scale
1:120
Owner:
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
4200
2600
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
No.
Date
3
110
1a
A
Revision
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar) : fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
C1
Company
C
1800
B-02
B25X50
2450
6050
B-01
B25X30
B-02
B25X50
6050
B-02
B25X50
B-01
B25X30
D
30550
30550
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
E
E
1:120
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
Signature
TERRACE FLOOR BEAM LAYOUT PLAN
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
B
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
C
B-01
B25X30
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B
B-03
B25X45
3500
1. CONCRETE COVER FOR BEAM : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
2550
B-01
B25X30
1650
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
Date
3500
B-01
B25X30
B-01
B25X30
B-01
B25X30
3500
G
G
H
H
3500
3500
I
I
200x400
300x500
B-01
B-02
TERRACE FLOOR BEAM LAYOUT
Plan name:
SECTION
BEAM
LEGEND :
Site Location:
3500
B-01
B25X30
B-01
B25X30
B-02
B25X50
B-01
B25X30
3500
B-01
B25X30
11000
1
2
3
4
Sheet
11
Scale
1:120
Owner:
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
B-01
B25X30
4200
2600
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
111
No.
Date
1a
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF DEFORMED
BAR (Confinement bar) : fy = 295MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR BEAM : C = 40mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
C
B25X30
C1
Company
C
1800
B25X30
6050
B25X50
B25X30
B25X30
2450
6050
B25X30
D
30550
30550
3500
3500
E
E
1:120
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
ROOF BEAM LAYOUT PLAN
Drawn by:
C2
1800
D
B25X30
Paragon International Designed by:
University
3500
3500
F
F
Signature
3500
3500
3500
3500
Date
G
G
H
H
SECTION
200x400
300x500
B-01
B-02
I
I
BEAM
ROOF BEAM LAYOUT
Plan name:
3500
3500
LEGEND :
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
Sheet
12
Scale
1:120
Owner:
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
112
No.
Date
1a
DB10@200
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
C1
Company
C
C
6050
2450
6050
D
30550
30550
3500
3500
E
E
1:120
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
Signature
GROUND FLOOR SLAB TOP REBAR DETAIL
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
Date
3500
3500
G
G
H
DB10@200
DB10@200
H
3500
DB10@200
3500
I
I
GROUND FLOOR SLAB TOP REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
Sheet
13
Scale
1:120
Owner:
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
113
No.
Date
1a
DB10@200
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
C1
Company
C
C
6050
2450
6050
D
30550
30550
3500
3500
E
E
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
1:120
F
F
Signature
GROUND FLOOR SLAB BOTTOM REBAR DETAIL
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
3500
3500
Date
G
G
H
DB10@200
DB10@200
H
3500
DB10@200
3500
I
I
GROUND FLOOR SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
Scale
Owner:
4200
4
A
14
Sheet
33
Sheet No.
Paragon International University
Architectural Engineering
114
No.
Date
1a
DB10@200
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
C1
Company
C
C
6050
2450
6050
D
30550
30550
3500
3500
E
E
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
1:120
F
F
Signature
MEZZANINE FLOOR SLAB TOP REBAR DETAIL
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
Date
3500
3500
G
G
H
DB10@200
H
3500
3500
I
I
MEZZANINE SLAB TOP REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
Sheet
15
Scale
1:120
Owner:
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
115
No.
Date
1a
DB10@200
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
Company
C
C
C1
6050
2450
6050
D
30550
30550
3500
3500
E
E
3500
3500
F
F
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
Signature
1:120
MEZZANINE FLOOR SLAB BOTTOM REBAR DETAIL
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
Date
3500
3500
G
G
H
DB10@200
H
3500
3500
I
I
MEZZANINE SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
Sheet
16
Scale
1:120
Owner:
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
116
No.
Date
1a
DB10@200
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
Company
C
C
C1
6050
2450
6050
D
D
30550
30550
3500
3500
E
E
1:120
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
Signature
FIRST FLOOR SLAB TOP REBAR DETAIL
Drawn by:
C2
1800
Paragon International Designed by:
University
3500
3500
Date
3500
3500
G
G
H
DB10@200
DB10@200
H
3500
DB10@200
3500
I
I
FIRST FLOOR SLAB TOP REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
Sheet
17
Scale
1
2
3
4
1:120
Owner:
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
117
No.
Date
1a
DB10@200
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
C1
Company
C
C
6050
2450
6050
D
30550
30550
3500
3500
E
E
1:120
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
Signature
FIRST FLOOR SLAB BOTTOM REBAR DETAIL
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
Date
3500
3500
G
G
H
DB10@200
DB10@200
H
3500
DB10@200
3500
I
I
FIRST FLOOR SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
Sheet
18
Scale
1:120
Owner:
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
118
No.
Date
1a
DB10@200
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
Company
C
C
C1
C2
D
D
30550
30550
3500
3500
E
E
1:120
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
Signature
SECOND FLOOR SLAB TOP REBAR DETAIL
1800
Drawn by:
6050
2450
6050
Paragon International Designed by:
University
3500
3500
F
F
Date
3500
3500
G
G
H
DB10@200
DB10@200
H
3500
DB10@200
3500
I
I
SECOND FLOOR SLAB TOP REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
1:120
Scale
Owner:
4200
4
A
1
2
3
4
19
Sheet
33
Sheet No.
Paragon International University
Architectural Engineering
119
No.
Date
1a
DB10@200
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
C1
Company
C
C
6050
2450
6050
D
30550
30550
3500
3500
E
E
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
1:120
F
F
Signature
SECOND FLOOR SLAB BOTTOM REBAR DETAIL
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
3500
3500
Date
G
G
H
DB10@200
DB10@200
H
3500
DB10@200
3500
I
I
SECOND FLOOR SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
1:120
Scale
Owner:
4200
4
A
20
Sheet
33
Sheet No.
Paragon International University
Architectural Engineering
120
No.
Date
1a
DB10@200
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
C1
Company
C
C
6050
2450
6050
D
30550
30550
3500
3500
E
E
Studied by:
Approved by:
Checked by:
1:120
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
TERRACE SLAB TOP REBAR DETAIL
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
F
F
Signature
3500
3500
Date
3500
3500
G
G
H
DB10@200
DB10@200
H
3500
DB10@200
3500
I
I
TERRACE SLAB TOP REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
1:120
Scale
Owner:
4200
4
A
21
Sheet
33
Sheet No.
Paragon International University
Architectural Engineering
121
No.
Date
1a
DB10@200
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
C1
Company
C
C
6050
2450
6050
D
30550
30550
3500
3500
E
E
1:120
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
Signature
TERRACE SLAB BOTTOM REBAR DETAIL
Drawn by:
C2
1800
D
Paragon International Designed by:
University
3500
3500
3500
3500
Date
G
G
H
DB10@200
DB10@200
H
3500
DB10@200
3500
I
I
TERRACE SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
Sheet
22
Scale
1:120
Owner:
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
122
No.
Date
1a
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
C1
Company
C
C
6050
B25X50
2450
6050
D
30550
30550
3500
DB10@100
3500
E
E
Studied by:
Approved by:
Checked by:
1:120
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
TERRACE SLAB TOP REBAR DETAIL
Drawn by:
C2
DB10@100
1800
D
Paragon International Designed by:
University
3500
3500
F
F
Signature
3500
3500
Date
3500
3500
G
G
H
H
3500
3500
I
I
ROOF SLAB TOP REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
1:120
Scale
Owner:
4200
4
A
23
Sheet
33
Sheet No.
Paragon International University
Architectural Engineering
123
No.
Date
1a
A
3500
3500
Revision
4. STEEL YIELD STRENGTH OF ROUND
BAR : fy = 235MPa
3. STEEL YIELD STRENGTH OF DEFORMED
BAR : fy = 390MPa
2. CONCRETE CYLINDER COMPRESSION
STRENGTH : f'c = 35MPa (Cylinder)
1. CONCRETE COVER FOR SLAB : C = 20mm
NOTES :
1
2
11000
4200
2600
4200
3
2550
1650
B
B
1800
C1
Company
C
C
6050
2450
6050
D
30550
30550
3500
DB10@100
3500
E
E
1:120
3500
3500
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
F
F
Signature
TERRACE SLAB BOTTOM REBAR DETAIL
Drawn by:
C2
DB10@100
1800
D
Paragon International Designed by:
University
3500
3500
Date
3500
3500
G
G
H
H
3500
3500
I
I
ROOF SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
3500
3500
4200
2600
11000
1
2
3
4
Sheet
24
Scale
1:120
Owner:
4200
4
A
33
Sheet No.
Paragon International University
Architectural Engineering
No.
Date
8DB16
8DB16
Revision
DB10@150
CENTER
DB10@250
CENTER
Studied by:
Drawn by:
Approved by:
Checked by:
Dr. Sophy Chhang
Signature
40mm
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
CLEAR COVER
30MPa
DB10@250
8DB16
40 220 40
300
TOP & BOT
MAIN BARS
CONCRETE STRENGTH, f`c
TIE
-0.05m to +4.15m
COLUMN2
GROUND COLUMN (H=4.2m)
LEVEL
40mm
FLOOR
CLEAR COVER
30MPa
DB10@150
8DB16
40 220 40
300
TOP & BOT
MAIN BARS
CONCRETE STRENGTH, f`c
TIE
LEVEL
COLUMN2
STUMP (H=1.5m)
-1.55m to -0.05m
FLOOR
Paragon International Designed by:
University
Company
40mm
CLEAR COVER
DB10@250
DB10@250
30MPa
CENTER
TOP & BOT
MAIN BARS
40 220 40
300
CONCRETE STRENGTH, f`c
TIE
-0.05m to +4.15m
LEVEL
COLUMN1
GROUND COLUMN (H=4.2m)
FLOOR
GROUND COLUMN SCHEDULE
40mm
CLEAR COVER
DB10@150
DB10@150
30MPa
CENTER
TOP & BOT
MAIN BARS
40 220 40
300
CONCRETE STRENGTH, f`c
TIE
LEVEL
COLUMN1
STUMP (H=1.5m)
-1.55m to -0.05m
FLOOR
STUMP COLUMN SCHEDULE
40 220 40
300
40 220 40
300
40
320
400
40
40
320
400
40
CENTER
TOP & BOT
MAIN BARS
CENTER
TOP & BOT
MAIN BARS
Date
40mm
30MPa
DB10@250
DB10@250
10DB16
40 220 40
300
ROOF SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
CLEAR COVER
CONCRETE STRENGTH, f`c
TIE
-0.05m to +4.15m
COLUMN3
GROUND COLUMN (H=4.2m)
LEVEL
40mm
30MPa
DB10@150
DB10@150
10DB16
40 220 40
300
FLOOR
CLEAR COVER
CONCRETE STRENGTH, f`c
TIE
LEVEL
COLUMN3
STUMP (H=1.5m)
-1.55m to -0.05m
FLOOR
40
420
500
40
40
420
500
124
40
SCHEDULE OF COLUMN RE-BARS
1:20
Scale
Owner:
25
Sheet
33
Sheet No.
Paragon International University
Architectural Engineering
No.
Date
8DB16
TIE
Revision
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Signature
40mm
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
Drawn by:
Paragon International Designed by:
University
Company
CLEAR COVER
40mm
CLEAR COVER
30MPa
DB10@250
CONCRETE STRENGTH, f`c
DB10@250
CENTER
8DB16
DB10@250
TOP & BOT
MAIN BARS
8DB16
DB10@250
40 220 40
300
30MPa
CENTER
TOP & BOT
MAIN BARS
+11.35m to +15.35m
SECOND COLUMN (H=4m)
40mm
30MPa
DB10@250
DB10@250
8DB16
40 220 40
300
40 220 40
300
COLUMN1
LEVEL
+7.35m to +11.35m
COLUMN1
FLOOR
FIRST COLUMN (H=4m)
LEVEL
SECOND COLUMN SCHEDULE
CLEAR COVER
CONCRETE STRENGTH, f`c
TIE
CENTER
TOP & BOT
MAIN BARS
CONCRETE STRENGTH, f`c
TIE
+4.15m to +7.35m
LEVEL
COLUMN2
MEZZANINE COLUMN (H=3.2m)
FLOOR
FLOOR
FIRST COLUMN SCHEDULE
40mm
CLEAR COVER
DB10@250
DB10@250
30MPa
CENTER
TOP & BOT
MAIN BARS
40 220 40
300
CONCRETE STRENGTH, f`c
TIE
+4.15m to +7.35m
COLUMN1
MEZZANINE COLUMN (H=3.2m)
LEVEL
40
FLOOR
40 220 40
300
40 220 40
300
CENTER
TOP & BOT
MAIN BARS
CENTER
Date
+15.35m to +19.35m
40mm
30MPa
DB10@250
DB10@250
8DB16
40 220 40
300
ROOF SLAB BOTTOM REBAR DETAIL
Plan name:
40mm
30MPa
DB10@250
DB10@250
10DB16
40 220 40
300
TERRACE COLUMN (H=4m)
Site Location:
CLEAR COVER
CONCRETE STRENGTH, f`c
TIE
TOP & BOT
MAIN BARS
COLUMN1
LEVEL
FLOOR
TERRACE COLUMN SCHEDULE
CLEAR COVER
CONCRETE STRENGTH, f`c
TIE
+4.15m to +7.35m
LEVEL
COLUMN3
MEZZANINE COLUMN (H=3.2m)
FLOOR
40
420
500
40
320
400
40
40 220 40
300
125
40 220 40
300
MEZZANINE COLUMN SCHEDULE
Sheet
26
Scale
1:20
Owner:
33
Sheet No.
Paragon International University
Architectural Engineering
No.
Date
CLEAR COVER
B-01-(250X300)
DB10@120
-
2DB16
DB10@90
-
BOTTOM BAR
STIRRUP
Revision
BEAM SCHEDULE FOR FF
CLEAR COVER
CONCRETE STRENGTH, f`c
LINK REBAR
4DB16
-
40
40
Approved by:
Checked by:
Paragon International Designed by:
University
Studied by:
Drawn by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
Signature
Date
40
40
40
40
-
DB10@200
5DB16
2DB12
3DB16
250
MIDDLE
-
DB10@200
5DB16
2DB12
3DB16
250
MIDDLE
ROOF SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
40MM
CLEAR COVER
40MM
Company
30MPA
-
DB10@100
3DB16
2DB12
5DB16
250
B-02-(300X500)
CONCRETE STRENGTH, f`c
LINK REBAR
STIRRUP
BOTTOM BAR
SIDE BAR
TOP BAR
SECTION
SUPPORT
30MPA
-
4DB16
2DB16
250
40
SECTION LOCATION
BEAM MARK
40MM
-
DB10@100
3DB16
2DB12
CLEAR COVER
40
40
5DB16
250
40MM
TOP BAR
250
40
40
B-02-(300X500)
30MPA
LINK REBAR
STIRRUP
BOTTOM BAR
SIDE BAR
TOP BAR
SECTION
SUPPORT
CONCRETE STRENGTH, f`c
MIDDLE
BEAM MARK
SECTION LOCATION
30MPA
SIDE BAR
SECTION
SECTION LOCATION
BEAM MARK
BEAM SCHEDULE FOR MF
40
-
CONCRETE STRENGTH, f`c
SUPPORT
-
DB10@90
STIRRUP
4DB16
40 220 40
300
LINK REBAR
DB10@120
2DB16
BOTTOM BAR
-
2DB16
250
40
-
40
4DB16
250
40
MIDDLE
TOP BAR
40
B-01-(250X300)
SIDE BAR
SECTION
SUPPORT
40 220 40
300
BEAM MARK
40 220 40
300
SECTION LOCATION
40
420
500
40
BEAM SCHEDULE FOR GF
40
420
500
40
40
420
500
40
126
40 220 40
300
40
420
500
40
SCHEDULE OF BEAM RE-BARS
Sheet
27
Scale
1:20
Owner:
33
Sheet No.
Paragon International University
Architectural Engineering
No.
Date
BEAM MARK
CLEAR COVER
127
B-01-(250X300)
40
CLEAR COVER
Revision
BEAM SCHEDULE FOR TERRACE
Studied by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
Drawn by:
Paragon International Designed by:
University
Company
Signature
CLEAR COVER
LINK REBAR
40MM
-
-
CONCRETE STRENGTH, f`c
STIRRUP
CONCRETE STRENGTH, f`c
DB10@120
DB10@90
STIRRUP
BOTTOM BAR
SIDE BAR
TOP BAR
SECTION
30MPA
4DB16
2DB16
BOTTOM BAR
LINK REBAR
-
2DB16
-
250
40
SECTION LOCATION
BEAM MARK
40
40
Date
30MPA
B-02-(300X500)
40MM
40
40
40
250
40
MIDDLE
-
DB10@200
5DB16
2DB12
3DB16
250
MIDDLE
-
DB10@200
5DB16
2DB12
3DB16
ROOF SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
DB10@100
3DB16
2DB12
5DB16
250
SUPPORT
40MM
-
DB10@100
3DB16
2DB12
CLEAR COVER
4DB16
250
40
40
5DB16
250
40MM
TOP BAR
40
40
B-02-(300X500)
30MPA
LINK REBAR
STIRRUP
BOTTOM BAR
SIDE BAR
TOP BAR
SECTION
SUPPORT
CONCRETE STRENGTH, f`c
SIDE BAR
SECTION
SECTION LOCATION
BEAM MARK
BEAM SCHEDULE FOR SF
BEAM MARK
SECTION LOCATION
30MPA
MIDDLE
-
-
CONCRETE STRENGTH, f`c
SUPPORT
DB10@120
DB10@90
STIRRUP
LINK REBAR
4DB16
2DB16
BOTTOM BAR
40
2DB16
250
-
40
-
40
4DB16
250
MIDDLE
TOP BAR
40
B-01-(250X300)
SIDE BAR
SECTION
SUPPORT
40 220 40
300
40 220 40
300
40
420
500
40
40
420
500
40
SECTION LOCATION
40 220 40
300
40 220 40
300
40
420
500
40
40
420
500
40
BEAM SCHEDULE FOR FF
1:20
Scale
Owner:
28
Sheet
33
Sheet No.
Paragon International University
Architectural Engineering
128
No.
Date
-
DB10@90
-
STIRRUP
Studied by:
Drawn by:
Approved by:
Checked by:
BEAM MARK
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Signature
CLEAR COVER
CONCRETE STRENGTH, f`c
LINK REBAR
STIRRUP
BOTTOM BAR
SIDE BAR
TOP BAR
SECTION
SECTION LOCATION
Name and position
4DB16
Paragon International Designed by:
University
Company
40MM
CLEAR COVER
Revision
30MPA
CONCRETE STRENGTH, f`c
LINK REBAR
DB10@120
2DB16
BOTTOM BAR
-
2DB16
250
40
-
40
4DB16
250
40
TOP BAR
40
MIDDLE
SIDE BAR
SECTION
B-01-(250X300)
40 220 40
300
SUPPORT
40 220 40
300
BEAM MARK
40
-
DB10@100
3DB16
2DB12
5DB16
250
Date
40
SUPPORT
30MPA
B-02-(300X500)
40
-
DB10@200
5DB16
2DB12
ROOF SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
40MM
40
3DB16
250
MIDDLE
40
420
500
40
SECTION LOCATION
40
420
500
40
BEAM SCHEDULE FOR RF
Sheet
29
Scale
1:20
Owner:
33
Sheet No.
Paragon International University
Architectural Engineering
No.
Date
4
D
129
Revision
1100
3500
11DB10@120
3500
2DB16
Company
10DB10@90
2DB16
10DB10@90
1100
F
10DB10@90
2000
700
1:100
10DB10@90
Studied by:
Drawn by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
SCALE
3DB16
Signature
3500
11DB10@120
14DB10@100
2DB16
BEAM DETAIL GRID 4
3500
11DB10@120
3500
11DB10@120
2DB16
Paragon International Designed by:
University
10DB10@90
E
2DB16
10DB10@90
2DB16
2DB16
10DB10@90
C
2DB16
11DB10@120
B
2DB16
2DB16
2DB16
Date
10DB10@90
G
6050
4350
2DB16
3500
10DB10@90
D
ROOF SLAB BOTTOM REBAR DETAIL
Plan name:
700
14DB10@100
2000
3DB16
11DB10@120
2DB16
Site Location:
10DB10@90
13DB10@200
1750
2DB16
2DB16
10DB10@90
3DB16
10DB10@90
A
H
Sheet
30
Scale
1:100
Owner:
4
33
Sheet No.
Paragon International University
Architectural Engineering
130
No.
Date
Revision
4200
500
750
100
Company
300
16DB10@250mm
4200
500
1:40
Studied by:
Drawn by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
Signature
COLUMN C1 DETAIL
SCALE
3DB16
2DB16
Paragon International Designed by:
University
750
750
100
750
16DB10@250mm
3DB16
300
Date
3DB16
2DB16
3DB16
ROOF SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
Sheet
31
Scale
1:40
Owner:
33
Sheet No.
Paragon International University
Architectural Engineering
131
No.
Date
Revision
4200
500
750
100
Company
300
16DB10@250mm
4200
500
1:40
Studied by:
Drawn by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
Signature
COLUMN C2 DETAIL
SCALE
3DB16
2DB16
Paragon International Designed by:
University
750
750
100
750
16DB10@250mm
3DB16
Date
400
3DB16
2DB16
3DB16
ROOF SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
Sheet
32
Scale
1:40
Owner:
33
Sheet No.
Paragon International University
Architectural Engineering
No.
Date
Revision
4200
500
SCALE
16DB10@250mm
1:40
Studied by:
Drawn by:
Approved by:
Checked by:
Dr. Sophy Chhang
Dr. Sophy Chhang
Suysoklin Uth
Amara Team
Name and position
Signature
COLUMN C3 DETAIL
Paragon International Designed by:
University
Company
300
3DB16
2DB16
4200
500
16DB10@250mm
3DB16
750
100
750
750
100
750
132
500
Date
3DB16
2DB16
3DB16
ROOF SLAB BOTTOM REBAR DETAIL
Plan name:
Site Location:
1:40
Scale
Owner:
33
Sheet
33
Sheet No.
References
[1]. ACI Committee 318, & American Concrete Institute. (2019). Building Code Requirements for Structural
Concrete (ACI 318-19): an ACI standard: Commentary on Building Code Requirements for Structural
Concrete (ACI 318R-19). American Concrete Institute.
[2]. Chu-Kia Wang, Salmon, C. G., Pincheira, J. A., & Parra-Montesinos, G. (2018). Reinforced Concrete
Design. Oxford University Press.
[3]. Aslam Kassimali. (2009). Structural Analysis. Cengage Learning.
[4]. Kenneth Marvin Leet, Chia-Ming Uang, & Gilbert, A. M. (2011). Fundamentals of structural analysis.
Mcgraw-Hill.
[5]. American. (2017). Minimum design loads and associated criteria for buildings and other structures:
ASCE/SEI 7-16. Reston, Virginia American Society of Civil Engineers.
[6]. P-Delta effect - Technical Knowledge Base - Computers and Structures, Inc. - Technical Knowledge Base.
(n.d.). Wiki.csiamerica.com. https://wiki.csiamerica.com/display/kb/P-Delta+effect
[7]. Sway and Non-sway Frames: What is the Difference Between the Two? (2021, April 1). The Constructor.
https://theconstructor.org/structural-engg/sway-non-sway-frames/506250/
[8]. https://evagenix.com. (2021, July 20). Importance of Structural Analysis in Construction Industry.
Imaginationeering Design Solution. https://www.imaginationeering.com/importance-of-structuralanalysis-in-construction/
[9]. M Nadim Hassoun, & Al-Manaseer, A. A. (2020). Structural concrete: theory and design. John Wiley &
Sons.
[10]. Siden Vong, Rattana Chhin, Piseth Doung. (2020). Basic Wind Speed Analysis and Serviceability
Evaluation of Tell Reinforced Concrete Building Subjected to Wind and Earthquake: A Case Study in
Phnom Penh.
[11]. American Concrete Institute. (2020). ACI Detailing Manual.
[12]. American Concrete Institute. (2015). The Reinforced Concrete Design Handbook: A Companion to ACI
318-14.
[13]. James G. Macgregor. (1997). Reinforced Concrete Mechanics and Design, 3rd Edition.
[14]. Sophy Chhang. (2022). Basic Understanding & Modeling of Reinforced Concrete and Steel Structures
using ETABS.
[15]. Sophy Chhang. (2022). Introduction to Reinforcement Concrete according to ACI318-19.
133
134
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