ÆM⌃3–12.6 Cylinders and Quadric Surfaces ⇥˘ Mao-Pei Tsui ˙'xx˚ Feb. 15, 2022 Plan of the this lecture In this video, we study "Cylinders and Quadric Surfaces". We sketch the graph of I a plane I a sphere I quadric surfaces . We live in three dimensional space. We use the coordinate (x, y , z) to describe a point in the space R3 . Tv 34*41%1 . " " y string theory (344%7) We live : dimensions . 3 spare + B. KEY in 10 . ) Itm + 6 {Fab Epp Plane A plane in R3 is described by the equation ax + by + cy2- = d, that is P = {(x, y , z)|az + by + cz = d} represents a plane is R3 . For example: x y + 2z = 4 represents a plane that goes thru the following three points. (4, 0, 0), (0, 4, 0) and (0, 0, 2). t ✗ ÷☐ Yao , too *0,7=0 y ×= ye-4 *" + 2-o z A surface in 3D is defined by a 3-variable equation f (x, y , z) = 0. For example, we have seen that the above equation defines a plane in 3D when f (x, y , z) = ax + by + cz d. In this section, we attempt to sketch and visualize more interesting surfaces. - { CKY plane=/ .tl/fcxiYit1=o] represents in ix. T.nl axtbytcz D= - if surface a IRS . Sphere A sphere with radius R and center (x0 , y0 , z0 ) is described by the equation (x x0 )2 + (y y0 )2 + (z z0 )2 =Rt r 2. Example: The equation of a sphere with radius 2 and center i (1, 2, 3) is " " Its graph is the following. a kid 3) , ' a Here we investigate two other types of surfaces: cylinders and quadric surfaces. A cylinder is a surface that consists of all lines (called rulings) that are parallel to a given line and pass through a given plane curve. ¥-0.1 É¥÷÷ . . Example: Sketch the graph of the surface z = x 2 in R3 . fcxis.tl/z---xJ - - Solution: In x z plane, z = x 2 is a parabola in x z plane. Since the equation is independent of y , we still have z = x 2 for each y . So there is a parabola curve on each plane y = c where c is a constant. The graph z = x 2 is a surface, called a parabolic cylinder, made up of infinitely many shifted copies of the same parabola. Here the rulings of the cylinder are parallel to the y-axis. 2- z=XZ on X Z - plane "" 2- - plans ✗ In ✗ ← All the I i i I 1 1 * Sana 7=5 : ' y In previous example, the variable y is missing from the equation of the cylinder. This is typical of a surface whose rulings are parallel to one of the coordinate axes. If one of the variables x, y or z is missing from the equation of a surface, then the surface is a cylinder. EXample: Identify and sketch the following surfaces in R3 . (a) x 2 + y 2 = 1 (b) y 2 + z 2 = 1 y - z ¥04 , ✗ circle indepofz - with radius 1 . ✗ z ¥¥ I y t circle fizzy . 4×-3813 y ✗ y Quadric Surfaces A quadric surface is the graph of a second-degree equation in three variables x, y and z. The most general such equation is Ax 2 + By 2 + Cz 2 + Dxy + Eyz + Fxz + Gx + Hy + Iz + J = 0 where A, B, C, · · · , J are constants. Using translation and rotation, we can simplify it as one of the two standard forms Ax 2 + By 2 + Cz 2 + J = 0 or Ax 2 + By 2 + Iz = 0. ¥É÷**÷ £+4 y ' + zx¥ +2×+8 EE 5+2×+8 y e = = I ka ¢ YE - f 4 We can first use rotation to simplify it as Ax 2 + By 2 + Cz 2 + Dx + Ey + Fz + G = 0. it j-z-nx-xy-ba-8-ocx-ui-IY-a.fi - wie f Suppose A 6= 0, B 6= 0 and C 6= 0. Then we can use translation to rewrite it as Ax 2 + By 2 + Cz 2 + J = 0. A-tui.BY 0 If A or B or C is 0, we may assume C = 0, Then we have Ax 2 + By 2 + Dx + Ey + Fz + G = 0 and use translation to rewrite it as Ax 2 + By 2 + Fz + G = 0. É 2- + ¥) If F 6= 0 then we can do a translation to get Ax 2 + By 2 + Fz = 0. Ax 2 If F = 0 then we have + Ax 2 + By 2 + Cz 2 + J = 0. By 2 ¥ + G = 0 which is of the form - ¥ + g. To determine the graph of a quadratic surface, we first review quadratic curve. Up to an appropriate change of variables (e.g. translations), conics (=quadratic curves) can be classified as follows. These curves are called conics because they are sections on a double cone. conics ' 22*18 y a> 970.60 o ' ✗ ¥ §= - , (→ Y=&× ' 19,4 c-9,01 I ¥+¥=o←> ye - Lax After reviewing curves in 2D, we will investigate how to sketch quadratic surfaces in a three dimensional space. There are 6 different types The following software is useful in understanding 3D pictures. Geogebra 3D : https://www.geogebra.org/3d Also available on iOS and Android. Let’s start with the ellipsoid. Example: Sketch the quadric surface with equation y2 x2 z2 4 + 9 + 25 = 1. 2 v Zu 20 Solution: First, we notice that , |x| 2, |y | 3 and |z| 5. x2 4 1, I Fe 4 1 and I IYIE } ⑦ 1×182 y2 9 . z2 25 t 1-21 1, that is 5 , ¥+¥+ The surface intellect with the horizontal plane z = k is a curve y2 x2 k2 4 + 9 =1 25 . E- If k = 0, then it is a ellipse x2 4 + y2 9 →:÷É÷ = 1. 2 2 If k = 2 or k = 2 , then it is an ellipse x4 + y9 = 1 which is a smaller ellipse than the previous one. E- +8=1 E- 4 25 = 21 25 - If k = 5 or k = If |k | < 5, then 5 then it is reduced to a point (x, y ) = (0, 0). x2 4 + y2 9 =1 If |k | > 5, it is an empty set. k2 25 is an ellipse. ki z Keo kit Example: Let us sketch z 2 = x2 4 + y2 9 . ← Each cross section q is an ellipse , E- ¥ -1¥ ¥-1 ¥=o 2- =o z= . Cky )-40,0) ¥ -1%5=4 2- → 2- ¥+4 izz :* ±÷÷:* 2- = -1 or ⇐ 2- = -2 4 ellipse -1k same becomes ellipse . larger - ¥+Y¥=K ¥+8 - i ¥ ¥ . + . = I ⇐ 5+1%5=1 - Example: Let us sketch z = x2 4 + y2 9 . 2- = ☒ Fg When ¥-1¥ ¥ -1¥ 2- =K " 7- ° k=o Kou ellipse 2- zu ¥ -1¥ 20 =K ¥- ¥=o + IX. 9140,0) ¥+¥=kµ¥¥+¥=1 ①-÷ ¥.it#ri-t Example: Let us sketch the surface 4x 2 + 4y 2 z 2 = 1. 4×445=2-7-1 E- IK 4×445=1+14 is a x4j=¥=(¥fY circle -1-33 . From 4x 2 + 4y 2 z 2 = 1, we have 4x 2 + 4y 2 = 1 + z 2 , so if 2 z = k then 4x 2 + 4y 2 = 1 + k 2 , i.e. x 2 + y 2 = 1+k 4 . So it is a q 2 circle of radius 1+k 4 when z = k . If k = 0, then it is a circle of radius 12 . If k = 1 or k = 1, then it is a circle of radius q 1+1 4 = q 1 2. If |k | increases, then the radius of the circle also increases. 2--0 7=1 2- = 2 , Example: Let us sketch the surface z = x 2 + y 2. E- K z=k , ×7y ? 2- = - K> o " x4yIk ⇐ :* . - Koo *F- ,¥÷¥ x-t-KTK-v.es j☒ , - ~ y=o - " , Keyes ✗=3 ur ✗a - J . 2-= when x4y " - ✗ you z ✗ ✗ " ya ⇐ z= - y 2- E plan ¥¥ - 2- plan . " ; 1¥ fA × ⇐* Example: Let us sketch the surface x2 4 y2 9 → + z2 25 = 1. ¥+¥=¥ =ÉÉ5zo -1 - £-2520 12-125 ¥,+¥=¥¥z 2-2-2520 z=5orZ=¥ K> 5 z=K or Iz / 25 ¥ You + ¥-1 # ellipse = - as - cxiyklo.it ¥-7114 ¥ 2- = K . 1144 become > g- layer EKABBEh.t #at3F@tBg9iH khkH.k,,t 101