Uploaded by JJ Daulo

2GEN-CHEM2 Q4-GIBBS-FREE-ENERGY

advertisement
SHS
GENERAL CHEMISTRY 2
Science Activity Sheet
Quarter 4
2 – MELC 2
Week 2
1B
Gibbs Free Energy
General Chemistry 2 Activity Sheet No. 2
Gibbs Free Energy
First Edition, 2020
Published in the Philippines
By the Department of Education
Region 6 – Western Visayas
Republic Act 8293, section 176 states that: No copyright shall subsist in any work
of the Government of the Philippines. However, prior approval of the government agency or
office wherein the work is created shall be necessary for exploitation of such work for profit.
Such agency or office may, among other things, impose as a condition the payment of
royalties.
This Learning Activity Sheet is developed by DepEd Schools Division of Iloilo.
ALL RIGHTS RESERVED. No part of this learning resource may be reproduced or
transmitted in any form or by any means electronic or mechanical without written permission
from the DepEd Schools Division of Iloilo.
Development Team of Activity Sheet
Writers: Ruth Grace Comodero
Illustrators: Ruth Grace Comodero
Editor: Zaldy M. Tondo
Layout Artist: Zaldy M. Tondo
Division Management Team:
Zaldy M. Tondo
Corazon C. Alarcon
Regional Management Team:
Roel F. Bermejo
Nordy D. Siason Jr., EdD.
Lilibeth T. Estoque, EdD.
Azucena T. Falales, PhD.
Introductory Message
Welcome!
The Learning Activity Sheet is a product of the Schools Division of
Iloilo through the Curriculum Implementation Division (CID).
This is
developed to guide the learning facilitators (teachers, parents and responsible
adults) in helping the learners meet the standards set by the K to 12 Basic
Education Curriculum.
The Learning Activity Sheet is a self-directed instructional material
aimed to guide the learners in accomplishing activities at their own pace and
time using the contextualized resources in the community. This will also
assist the learners in acquiring the lifelong learning skills, knowledge and
attitudes for productivity and employment.
For learning facilitator:
The Learning Activity Sheet will help you facilitate the leaching-learning
activities specified in each Most Essential Learning Competency (MELC) with
minimal or no face-to-face encounter between you and learner. This will be made
available to the learners with the references/links to ease the independent learning.
For the learner:
The Learning Activity Sheet is developed to help you continue learning
even if you are not in school. This learning material provides you with meaningful
and engaging activities for independent learning. Being an active learner, carefully
read and understand the instructions then perform the activities and answer the
assessments. This will be returned to your facilitator on the agreed schedule.
Name of Learner: _____________________________________________________
Grade& Section______________________________Date: ___________________
GENERAL CHEMISTRY 2 ACTIVITY SHEET NO. 2
Gibbs Free Energy
I. Learning Competency with Code
Use Gibbs’ free energy to determine the direction of a reaction
(STEM_GC11CT-IVa-b-143)
II. Background Information for Learners
The thermodynamic entity that takes into account both enthalpy and
entropy changes and is useful for determining whether a process is spontaneous
or not is called Gibbs free energy. The Gibbs free energy change (∆G) for reaction
carried out at constant temperature in Kelvin and pressure is given by
∆G = ∆H -T∆S
where both ∆H and ∆S refer to the system.
The Gibbs free energy change is equal to the maximum possible work (w)
that can be obtained from a process. Any process that occurs spontaneously can
be utilized to perform useful work. The Gibbs free energy of the system will
decrease (∆G<0) in a spontaneous process, and will increase (∆G >0) in a
nonspontaneous process. For example, the movement of water in waterfall is
spontaneous. Useful work, for example, in turning the wheels of a turbine, can
be derived from the process. On the other hand, a positive ∆G indicates that work
has to be done on the system for the process to take place. Such process is
nonspontaneous. The maintenance of life is nonspontaneous process; it requires
the sustained input of work or energy as maybe obtained from food. The free
energy criteria (at constant temperature and pressure) are summarized as follows:
If ∆G < 0, the forward reaction is spontaneous.
If ∆G = 0, the reaction is at equilibrium.
If ∆G < 0, the forward reaction is nonspontaneous. The reverse reaction
will have a negative ∆G and will be spontaneous.
The standard free-energy change of reaction (∆Gºrxn) is the free –energy
change for a reaction when it occurs under standard state conditions, when
reactants in their standard states are converted to products in their standard
states.
Calculation of ∆Gºrxn.
The free energy change for a reaction can be calculated in two ways. When
both ∆H and ∆S are known, then ∆G = ∆H -T∆S will give the free energy change
at the temperature T. ∆Gºrxn can also be calculated from standard free energies of
formation in a manner analogous to the calculation of ∆Hº by using enthalpies of
formation of the reactants and products. The standard free energies of formation
(∆Gºf) of selected compounds are tabulated below (Table 2.1). Just as for the
1
standard enthalpies of formation, the free energies of formation of elements in
their standard states are equal to zero.
For a general reaction
aA + bB
cC + dD
The standard free energy change is given by
∆Gºrxn = [c∆Gºf (C) + d∆Gºf (D)] - [a∆Gºf (A) + b∆Gºf (B)]
In general:
∆Gºrxn = ∑n∆Gºf(products) - ∑m∆Gºf(reactants)
Where n and m are stoichiometric coeficients.
Table 2.1 Standard Gibbs free energy of formation of selected substances.
https://www.google.com/url?sa=i&url=http%3A%2F%2Fwiki.chemprime.cheme
ddl.org%2Farticles%2Fs%2Ft%2Fa%2FFile~Standard_Free_Energies_of_Formati
on.jpg_c314.html&psig=AOvVaw06AWRbEU4gWDgDtqBzRyc2&ust=161167685
1721000&source=images&cd=v
Sample Problem 1:
Calculate ∆Gºrxn at 25ºC for the following reaction given that:
∆Gºf (Fe2O3) = -741.0 kJ/mol
∆Gºf (Al2O3) = -1576.4 kJ/mol
2
2Al(s) + Fe2O3(s)
Method of Solution
Al2O3(s) + 2Fe(s)
∆Gºrxn = [∆Gºf (Al2O3) + 2∆Gºf (Fe)] - [2∆Gºf (Al) + ∆Gºf (Fe2O3)]
= [ 1mol (-1576.41 kJ/mol) + 0 ]-[ 0+ 1mol (741.0 kJ/mol))
∆Gºrxn = -1576.41 kJ + 741.0 kJ
= - 835.4 kJ
Temperature and the Free Energy Change
From the equation ∆G = ∆H - T∆S we can see that temperature too will
influence the spontaneity of reaction. If both ∆H and ∆S are positive then at low
temperature, as long as ∆H > T∆S, ∆G is positive and the process will be
nonspontaneous. However, as temperature increases, the T∆S term increases and
eventually ∆H = T∆S. At this point ∆G is zero. With further T increase, T∆S > ∆H,
making ∆G < 0, and the reaction becomes spontaneous. Table 2.1 summarizes
the four possible situtions affecting the ∆G of a reaction.
Table 2.2. Enthalpy and Entropy Factors that the signs of ∆Gºrxn
∆H
+
∆S
+
∆G
∆G is positive at low
temperatures and negative at
high temperature
Characteristic of Reaction
Nonspontaneous at lower
temperature
Spontaneous at higher
temperature
+
_
∆G is positive at all
tempratures
Nonspontaneous at any
temperature
-
+
∆G
is
negative
temperatures
-
-
∆G
is
negative
at
low Nonspontaneous at higher
temperatures and positive at temperature
high temperature
Spontaneous at lower
temperature
at
all Spontaneous at all
temperature
Brown, Le May and Bursten. Chemistry: The Central Science, 9th ed. 2004
Sample Problem 2:
The old camera flash bulb used Mg metal sealed in a bulb with oxygen. The
reaction is:
S° J/K mol:
ΔH°f kJ/mol:
Mg
32.7
0
+
½ O2
—>
205.0
0
3
MgO
26.9
-601.2
Calculating the ΔS°
ΔS° = ΣnS° (products) − ΣmS° (reactants)
= [(1) S° MgO] – [(1) S° Mg + (½) S° O2]
= [(1) (26.9)] – [(1)(32.7) + (½) (205.0)]
ΔS° = -108.3 J/K mol
Calculating the ΔH°
ΔH° = Σ nΔHf° (products) – Σ mΔHf° (reactants)
= [(1) ΔHf ° MgO] – [(1) ΔHf°Mg + (½) ΔHf°O2]
= [(1) (-601.2)] – [(1) (0) + (½) (0)]
ΔH° = -601.2k
Calculating the ΔG
ΔG = ΔH - TΔS
= 601.2kJ - (298K) (-108.3J/K) (1kJ/1000J)
= -601.2 + 32.3kJ
ΔG = -568.9kJ
Since ΔG is negative the reaction will form MgO amd it is spontaneous.
III. Activity Proper
Activity 1. Gibbs Free Energy
For the reaction to be spontaneous, the sign of ∆G (Gibbs free energy) must be
negative. The mathematical formula for this value is:
∆G = ∆H -T∆S
Where:
∆H – change in enthalpy
T- temperature in Kelvin
∆S – change in entropy
Complete the table for the sign of
∆G: -, + or undetermined. When
conditions
allow
for
an
undetermined
sign
of
∆G,
temperature
will
decide
spontaneously.
4
∆H
+
∆S
-
+
+
-
+
_
_
∆G
Answer the following below:
1. The conditions in which ∆G is always negative is when ∆H is ____________
and ∆S is ____________.
2. The conditions in ∆G is always positive is when ∆H is ____________ and ∆S
is __________.
3. Under what conditions will a reaction with a decreasing entropy be
spontaneous or thermodynamically favorable?
4. Under what conditions will an endothermic reaction be spontaneous or
thermodynamically favorable?
5. An exothermic reaction is nonspontaneous or thermodynamically
unfavorable under what conditions of temperature and entropy change?
6. When the situation is indeterminate, a low temperature favors the
(entropy /enthalpy) factor, and a high temperature favors the (entropy/
enthalpy) factor.
7. Use complete sentences to explain how changes in enthalpy, temperature,
and entropy would create each type of reaction.
a. A reaction that is always favorable
b. A reaction that is always unfavorable
c. A reaction that is sometime favorable
Activity 2. Is It Favorable or Not?
Much like enthalpy and entropy, Gibbs free energy is a state function
because they describe quantitatively an equilibrium state of a thermodynamic
system, irrespective of how the system arrived in that state. Additionally, like
enthalpy and entropy, Gibbs free energy can be calculated independently using
the equation below.
∆Grxn˚ = ∑Gf˚ products - ∑Gf˚ reactants
1. What is the standard free energy change, ∆G˚, in kJ, for the following
reaction at 298K? Is the reaction spontaneous?
C2H5OH(l) + 3O2(g) —> 2CO2(g) + 3H2O(g)
Compound
C2H5OH(l)
O2(g)
CO2(g)
H2O(g)
∆Gf˚ kJ/mol
- 175
0
-394
-229
5
2. Calculate the ∆Gº for the reaction of graphite and predict whether the
reaction is spontaneous or not:
2C(graphite) + H2(g) —> C2H2(g)
3. Copper (I) sulfide reacts with sulfur to produce copper (II) sulfide at
25°C. The process is exothermic (ΔH˚ = -26.7 kJ/mol) with a decrease in
disorder (ΔS˚ = -19.7 J/(mol•K)).
Determine the thermodynamic favorablity of the reaction by calculating
ΔG˚.
Cu2S(s) + S(s) → 2 CuS(s)
4. Is the reaction spontaneous at 298K and 1atm?
CO(NH2)2 aq +
H2O(l)
—> CO2 (g) + 2NH3 (g)
∆Hº = 119kJ
∆Sº = 354.8 J/K
T
= 25ºC = 298K
IV. Reflection
Complete the statements below.
I understand _________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
I don’t understand ___________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
I need more information about _______________________________________________
______________________________________________________________________________
______________________________________________________________________________
6
V. Answer Key
VI. References
Barrameda, M.C.B., Jusayan, S.R., Macale, A.M, Sabularse, V.S. (2016).
Teaching Guide for Senior High School in General Chemistry 2.Commision on
Higher Education. pp. 413-440.
Brown, Le May and Bursten. Chemistry: The Central Science, 9th ed. 2004
Chang, R. (2007) Chemistry, 9th Ed. McGraw-Hill, Inc., USA.
Whitten, K.W., et al (2007) Chemistry, 8th Ed. Thomson-Brooks/Cole, USA.
https://www.google.com/url?sa=i&url=http%3A%2F%2Fwiki.chemprime.cheme
ddl.org%2Farticles%2Fs%2Ft%2Fa%2FFile~Standard_Free_Energies_of_Formati
on.jpg_c314.html&psig=AOvVaw06AWRbEU4gWDgDtqBzRyc2&ust=161167685
1721000&source=images&cd=v
7
8
Download