Dense atomic packing for crystal structures of metals High degree of shielding (of ion cores) provided Crystal structures for metals simpler than by free electron cloud structures for ceramics and polymers. Centers of atoms located at the eight corners of a cube number of nearest-neighbor or touching atoms a π a a a a a a a a π a a Atoms located at 8 cube corners and at the centers of the 6 faces a a a π a a a a A sketch of one-third of an HCP unit cell is shown below. JH = JM = JK = 2R = a (JM) 2 = ( JH) 2 ( MH) 2 a 2 c 2 a2 c2 a = + = + 3 2 3 4 2 c 2 2 2 a = ( JH ) + a 3 2 a /2 cos 30 = = JH 3 2 c = a 8 = 1.633 3 a 4 R 3 3 VS = 6 = 8 R 3 2R 3 BC = 2R cos (30) = 2 VC = (AREA)(c) = 6 R2c 3 = (6 R2 3) (2)(1.633 )R = 12 3 (1.633) R3 2 R 3 2 AREA = (3)(CD)(BC) = (3)(2 R) = 6R 3 2 and since c = 1.633a = 2R(1.633) APF = VS VC = 8 R3 12 3 (1.633 ) R3 = 0.74 Stacking Sequence Referenced to an FCC Unit Cell. Close-Packed Plane (nA / N A ) VC a a a a VC ρ Atomic Bonding in Ceramics • Bonding: -- Can be ionic and/or covalent in character. -- % ionic character increases with difference in electronegativity of atoms. • Degree of ionic character may be large or small: CaF2: large SiC: small Factors that Determine Crystal Structure 1. Relative sizes of ions – Formation of stable structures: --maximize the # of oppositely charged ion neighbors. - + - - + - unstable 2. Maintenance of Charge Neutrality : - stable --Net charge in ceramic should be zero. --Reflected in chemical formula: CaF 2 : - + - stable Ca 2+ + cation A m Xp m, p values to achieve charge neutrality Fanions F- Coordination Number and Ionic Radii r cation • Coordination Number increases with r anion To form a stable structure, how many anions can surround around a cation? r cation r anion < 0.155 Coord. Number linear 2 triangular 0.155 - 0.225 3 0.225 - 0.414 4 tetrahedral 0.414 - 0.732 6 octahedral 0.732 - 1.0 8 cubic ZnS (zinc blende) NaCl (sodium chloride) CsCl (cesium chloride) Computation of Minimum Cation-Anion Radius Ratio • Determine minimum rcation/ranion for an octahedral site (C.N. = 6) 2ranion + 2rcation = 2a a = 2ranion 2ranion + 2rcation = 2 2ranion ranion + rcation = 2ranion rcation = ( 2 - 1)ranion rcation = 2 - 1 = 0.414 ranion Ionic Radii for Several Cations and Anions for a Coordination Number of 6 Example Problem: Predicting the Crystal Structure of FeO • On the basis of ionic radii, what crystal structure would you predict for FeO? Cation Ionic radius (nm) Al 3+ 0.053 Fe 2+ 0.077 Fe 3+ 0.069 Ca 2+ 0.100 Anion O2Cl F- 0.140 0.181 0.133 • Answer: rcation 0.077 = ranion 0.140 = 0.550 based on this ratio, -- coord # = 6 because 0.414 < 0.550 < 0.732 -- crystal structure is NaCl based on Octahedral structure FeO and MgO FeO and MgO also have the NaCl structure O2- rO = 0.140 nm Mg2+ rMg = 0.072 nm rMg/rO = 0.514 cations prefer octahedral sites So each Mg2+ (or Fe2+) has 6 neighbor oxygen atoms AX Crystal Structures AX–Type Crystal Structures include NaCl, CsCl, and zinc blende Cesium Chloride structure: rCs + rCl - = 0.170 = 0.939 0.181 Since 0.732 < 0.939 < 1.0, cubic sites preferred So each Cs+ has 8 neighbor Cl- AX2 Crystal Structures Fluorite structure • Calcium Fluorite (CaF2) • Cations in cubic sites • UO2, ThO2, ZrO2, CeO2 • Antifluorite structure – positions of cations and anions reversed AX2 Crystal Structures Fluorite structure Question: the ionic radii for K+ and O2- as 0.138 and 0.140 nm, respectively. (a) What is the coordination number for each O2- ion? (b) Briefly describe the resulting crystal structure for K2O. (c) Explain why this is called the antifluorite structure. r + K = 0.138 nm = 0.986 r 2- 0.140 nm O (a) The coordination number for oxygen is eight. (b) For a coordination number of eight for both cations and anions, the crystal structure should be cesium chloride. However, there are twice as many K+ as O2- ions. Therefore, the centers of the K+ ions are positioned at the corners of cubic unit cells, while half of the cube centers are occupied by O2- ions. (c) This structure is called the antifluorite crystal structure because anions and cations are interchanged with one another from the fluorite structure. ABX3 Crystal Structures • Perovskite structure Ex: complex oxide BaTiO3 Density Computations for Ceramics Number of formula units/unit cell n¢(SAC + SAA ) r= VC N A Avogadro’s number Volume of unit cell SAC = sum of atomic weights of all cations in formula unit SAA= sum of atomic weights of all anions in formula unit Atomic Bonding in Ceramics ρ ρ ρ ρ ’ single crystal for turbine blade are composed of many small, single crystals (i.e., are polycrystalline). Temperature β T ° δ ° γ ° — E(edge) ≠ E(diagonal) Unit cell of BCC iron μ a, b, and c unit cell edge lengths a a a, b, and c) and remove commas a Example Problem I a a 1. Point coordinates of tail and head a a 2 & 3. Subtract and normalize 4 & 5. Multiply by 2 to eliminate the fraction, then place in square brackets (no commas) Family of directions – all directions that are crystallographically equivalent (have the same atomic spacing) – indicated by indices in angle brackets z Algorithm a2 - a3 a1 1. Vector repositioned (if necessary) to pass through origin. 2. Read off projections in terms of unit cell dimensions a1, a2, a3, or c 3. Adjust to smallest integer values 4. Enclose in square brackets, no commas [uvtw] a 2 -a3 a2 2 ex: ½, ½, -1, 0 => [ 1120 ] a3 dashed red lines indicate projections onto a1 and a2 axes a1 2 a1 z a2 - a3 a1 a a a a aa a a a aa a a · a aa a · · Family of planes – all planes that are crystallographically equivalent (have the same atomic packing) – indicated by indices in braces a a l a a a 1a aa a a a a a l a a There are 2 half atoms and 1 full atom = 2 atoms centered on vector a a = = a = - There are 4 quarter atoms = 1 atom centered on plane a= = a= = = a = a a a • Ceramic crystal structures are based on: -- maintaining charge neutrality -- cation-anion radii ratios. • Crystallographic points, directions and planes are specified in terms of indexing schemes. Crystallographic directions and planes are related to atomic linear densities and planar densities. For most single crystals, properties vary with crystallographic orientation (i.e., are anisotropic) For polycrystalline materials having randomly oriented grains, properties are independent of crystallographic orientation (i.e., they are isotropic)