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Chapter-1-Difference-between-RCD-and-PCD

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SCE 104: Prestressed Concrete Design
Lesson 1: Difference between Prestressed and Reinforced Concrete
(Activity Research)
Submitted By:
Ignacio P. Siervo Jr.
BSCE – 4
193808
Submitted To:
Engr. Ric L. Gonzaga
Associate Professor
Overview
Introduction
Concrete is strong in compression, but weak in tension: its tensile strength
varies from 8 to 14 percent of its compressive strength. Due to such a low tensile
capacity, flexural cracks develop at early stages of loading. In order to reduce or
prevent such cracks from developing, a concentric or eccentric force is imposed in the
longitudinal direction of the structural element. This force prevents the cracks from
developing by eliminating or considerably reducing the tensile stresses at the critical
midspan and support sections at service load, thereby raising the bending, shear, and
torsional capacities of the sections. The sections are then able to behave elastically,
and almost the full capacity of the concrete in compression can be efficiently utilized
across the entire depth of the concrete sections when all loads act on the structure.
Such an imposed longitudinal force is called a prestressing force, i.e., a
compressive force that prestresses the sections along the span of the structural
element prior to the application of the transverse gravity dead and live loads or
transient horizontal live loads. The type of prestressing force involved, together with
its magnitude, are determined mainly on the basis of the type of system to be
constructed and the span length and slenderness desired. Since the prestressing force
is applied longitudinally along or parallel to the axis of the member, the prestressing
principle involved is commonly known as linear prestressing.
Circular prestressing, used in liquid containment tanks, pipes, and pressure
reactor vessels, essentially follows the same basic principles as does linear
prestressing. The circumferential hoop, or “hugging” stress on the cylindrical or
spherical structure, neutralizes the tensile stresses at the outer fibers of the curvilinear
surface caused by the internal contained pressure.
Figure 1.1 illustrates, in a basic fashion, the prestressing action in both types of
structural systems and the resulting stress response. In (a), the individual concrete
blocks act together as a beam due to the large compressive prestressing force P.
Although it might appear that the blocks will slip and vertically simulate shear slip
failure, in fact they will not because of the longitudinal force P. Similarly, the wooden
staves in (c)might appear to be capable of separating as a result of the high internal
radial pressure exerted on them. But again, because of the compressive prestress
imposed by the metal bands as a form of circular prestressing, they will remain in
place.
Comparison with Reinforced Concrete
It is plain that permanent stresses in the prestressed structural member are
created before the full dead and live loads are applied, in order to eliminate or
considerably reduce the net tensile stresses caused by these loads. With reinforced
concrete, it is assumed that the tensile strength of the concrete is negligible and
disregarded. This is because the tensile forces resulting from the bending moments
are resisted by the bond created in the reinforcement process. Cracking and deflection
are therefore essentially irrecoverable in reinforced concrete once the member has
reached its limit state at service load.
The reinforcement in the reinforced concrete member does not exert any force
of its own on the member, contrary to the action of prestressing steel. The steel
required to produce the prestressing force in the prestressed member actively
preloads the member, permitting a relatively high controlled recovery of cracking and
deflection. Once the flexural tensile strength of the concrete is exceeded, the
prestressed member starts to act like a reinforced concrete element.
By controlling the amount of prestress, a structural system can be made either
flexible or rigid without influencing its strength. In reinforced concrete, such a flexibility
in behavior is considerably more difficult to achieve if considerations of economy are
to be observed in the design. Flexible structures such as fender piles in wharves have
to be highly energy absorbent, and prestressed concrete can provide the required
resiliency. Structures designed to withstand heavy vibrations, such as machine
foundations, can easily be made rigid through the contribution of the prestressing force
to the reduction of their otherwise flexible deformation behavior.
Advantages and Disadvantages of Reinforced and Prestressed Concrete
Reinforced Concrete
Advantages
Disadvantages
1. Reinforced concrete has a high
1. The tensile strength of reinforced
compressive strength compared
concrete is about one-tenth of its
to other building materials.
compressive strength.
2. Due
to
the
provided
reinforcement,
2. The
main
steps
of
using
reinforced
reinforced concrete are mixing,
concrete can also withstand a
casting, and curing. All of this
good amount of tensile stress.
affect the final strength.
3. Fire and weather resistance of
reinforced concrete is fair.
3. The cost of the forms used for
casting is relatively higher.
4. The reinforced concrete building
4. For multi-storied building the RCC
system is more durable than any
column section for is larger than
other building system.
steel section as the compressive
5. Reinforced concrete, as a fluid
material, in the beginning, can be
economically molded into a nearly
limitless range of shapes.
6. The
maintenance
cost
of
reinforced concrete is very low.
7. In the structure like footings,
dams,
piers,
etc.,
reinforced
concrete is the most economical
construction material.
8. It acts like a rigid member with
minimum deflection.
9. As reinforced concrete can be
molded to any shape required, it
is widely used in precast structural
components.
It
yields
rigid
strength is lower in the case of;
5. Shrinkage
causes
crack
development and strength loss.
members with minimum apparent
deflection.
10. Compared to the use of steel in
structure,
reinforced
concrete
requires less skilled labor for the
erection of the structure.
Prestressed Concrete
Advantages
Disadvantages
1. Precast members like electric
1. Prestressed
concrete
sections
poles and railway sleepers are
are more brittle because of use of
produced in factories using simple
high-tension steel.
pre-stressing methods.
2. Prestressed
2. Prestressed concrete is used in
the
structures
where
tension
develops or the structure
is
concrete
requires
specialized tensioning equipment
and devices which are very costly.
3. Cost
of
materials
used
in
subjected to vibrations, impact
prestressed is very high (high
and shock like girders, bridges,
tensile steel is about three times
railway sleepers, electric poles,
costlier than mild steel).
gravity dams, etc.
3. Since the concrete does not crack
in prestressed concrete, rusting of
steel is minimized.
4. Since the concrete does not crack
in prestressed concrete, rusting of
steel is minimized.
5. Prestressed concrete members
show less deflection.
6. Long span bridges and flyovers
are made of prestressed concrete
because of lesser self-weight and
4. Prestressed
concrete
construction requires very good
quality.
thinner section. So, prestressed
concrete is used for heavily
loaded structures.
7. Thinner sections in prestressed
concrete results in less selfweight
and
hence
overall
economy.
8. In prestressed concrete, whole
concrete area is effective in
resisting loads, unlike RCC where
concrete below the neutral axis is
neglected.
9. Prestressed
concrete
sections
are thinner and lighter than RCC
sections,
since
high
strength
concrete and steel are used
prestressed concrete.
Sample Problems
1. Consider the prestressed concrete beam shown below, which is to be used in
an industrial building construction. The beam is only reinforced with
prestressing steel and no mild reinforcement is used. What is the maximum live
load that this beam can carry (in addition to the self-weight) considering only
the allowable section stresses at Midspan?
The Material properties and prestressing are as follow:
𝑓 ′ 𝑐 = 40π‘€π‘ƒπ‘Ž
𝑓 ′ 𝑐𝑖 = 35π‘€π‘ƒπ‘Ž
𝑓𝑝𝑒 = 1860π‘€π‘ƒπ‘Ž
𝑓 ′ 𝑝𝑖 = 1120π‘€π‘ƒπ‘Ž
βˆ†π‘“π‘π‘‡ = 140π‘€π‘ƒπ‘Ž (π‘‘π‘œπ‘‘π‘Žπ‘™ π‘™π‘œπ‘’π‘ π‘ π‘’π‘ )
𝐴𝑝𝑠 = 8πœ™π‘  13 = 8 × 99π‘šπ‘š2 /π‘ π‘‘π‘Ÿπ‘Žπ‘›π‘‘
𝑓𝑑 = 0.5√𝑓′𝑐 π‘Žπ‘›π‘‘ 𝑓𝑐 = 0.45𝑓′𝑐
2. Design for service load condition, a post-tensioned T-section to carry a total
service load of 15
π‘˜π‘
π‘š
(not including self-weight) on a 12π‘š simply supported
span. Design the section for zero-tension, for 𝑓𝑐𝑖 = 12.5π‘€π‘ƒπ‘Ž and 𝑓𝑐 = 11π‘€π‘ƒπ‘Ž
at transfer and service conditions, respectively. Assume that the sectional
properties are 𝑏𝑓 = 0.5β„Ž, β„Žπ‘“ = 0.2β„Ž, 𝑏𝑀 = 0.25β„Ž and use multiples of 50π‘šπ‘š for
β„Ž.
Assume the self-weight of the beam is 6.0
π‘˜π‘
π‘š
and the following prestressing
data.
𝑓 ′ 𝑐 = 35π‘€π‘ƒπ‘Ž
𝑓 ′ 𝑐𝑖 = 30π‘€π‘ƒπ‘Ž
𝑓𝑝𝑒 = 1860π‘€π‘ƒπ‘Ž
𝑓 ′ 𝑝𝑖 = 1300π‘€π‘ƒπ‘Ž
βˆ†π‘“π‘π‘‡ = 250π‘€π‘ƒπ‘Ž
𝐴𝑝𝑠 = 1πœ™π‘  13 = 99π‘šπ‘š2 /π‘ π‘‘π‘Ÿπ‘Žπ‘›π‘‘
3. A 300π‘šπ‘š × 400π‘šπ‘š concrete beam has a span of 6π‘š. A posttension force of
640 π‘˜π‘ was applied at a point 70 π‘šπ‘š above the bottom of the beam. Assume
concrete wont crack in tension. 𝑓′𝑐 = 20.7 π‘€π‘ƒπ‘Ž. Unit weight of concrete is
23.5 π‘˜π‘/π‘š3.
a. Compute the deflection due to pre-stressing force of 240 π‘˜π‘.
b. Compute the net deflection of the beam immediately after transfer.
c. Computer the safe uniform live load that maybe imposed on the
beam so that there will be a net deflection upward of 5 π‘šπ‘š.
Solution:
a. Deflection due to prestressing force of 240 π‘˜π‘.
𝑒 = 200 − 70 = 130 π‘šπ‘š
𝑀 = 𝑃𝑒
𝑀 = (640)(1.3) = 83.2 π‘˜π‘ ⋅ π‘š
𝐼=
(300)(400)2
12
= 1600 × 106
𝐸 = 4700√𝑓′𝑐
𝐸 = 4700√20.7 = 21384 π‘€π‘ƒπ‘Ž
𝛿1 =
𝑀𝐿2
8𝐸𝐼
83.2×106 (6000)2
𝛿1 = 8(21384)(1600)106
𝜹𝟏 = 𝟏𝟎. πŸ—πŸ’ π’Žπ’Ž (π’–π’‘π’˜π’‚π’“π’…)
b. Net deflection of the beam immediately after transfer.
π‘Š = (0.3)(0.4)(23.5)(6) = 2.82
5π‘ŠπΏ2
𝛿2 = 384𝐸𝐼
5(2820)(6)(6000)2
𝛿2 = 384(21384)(1600)106
𝛿2 = 1.39 π‘šπ‘š
Net Deflection
𝛿 = 𝛿1 − 𝛿2
𝛿 = 10.94 − 1.39
𝜹 = πŸ—. πŸ“πŸ“ π’Žπ’Ž (π’–π’‘π’˜π’‚π’“π’…)
π‘˜π‘
π‘š
c. Safe uniform live load that maybe imposed on the beam so that there will be a
net deflection upward of 5 π‘šπ‘š.
9.55 − 𝛿4 = 5 π‘šπ‘š
𝛿4 = 4.55 π‘šπ‘š
5π‘ŠπΏ2
𝛿4 = 384𝐸𝐼
5π‘Š(1000)(6)(6000)2
4.55 = 384(21384)(1600)106
𝑾 = πŸ—. πŸπŸ‘
π’Œπ‘΅
π’Ž
4. A post-tensioned bonded concrete beam has a prestress of 1560 kN in the steel
immediately after prestressing which eventually reduces to 1330 kN. The beam
carries two live loads of 45 kN each in addition to itw own weight of 4.40 kN/m.
compute the extreme fiber stresses at mid-span:
a. Under the initial condition with full prestress and no live load
b. Under final condition after all the losses have taken place and with full live
load.
5. The flooring of a warehouse is made up of double tee joists (DT). The joists are
simply supported on a span of 7.5 m and are pre-tensioned with one tendon in
each stem with an initial force of 745 kN each, located at 75 mm above the
bottom fiber, loss of stress service load is 18%.
πΏπ‘œπ‘Žπ‘‘ π‘–π‘šπ‘π‘œπ‘ π‘’π‘‘ π‘œπ‘› π‘‘β„Žπ‘’ π‘—π‘œπ‘–π‘ π‘‘π‘ :
π‘ƒπ‘Ÿπ‘œπ‘π‘’π‘Ÿπ‘‘π‘–π‘’π‘  π‘œπ‘“ 𝐷𝑇:
π·π‘’π‘Žπ‘‘ π‘™π‘œπ‘Žπ‘‘ = 2.3 π‘˜π‘ƒπ‘Ž
𝐴 = 200,000π‘šπ‘š2
𝐿𝑖𝑣𝑒 π‘™π‘œπ‘Žπ‘‘ = 6.0 π‘˜π‘ƒπ‘Ž
𝐼 = 1880 × 106 π‘šπ‘š4
π‘Ž = 2.4 π‘š
𝑦𝑑 = 88 π‘šπ‘š
𝑦𝑏 = 267 π‘šπ‘š
a. Compute the stress at the bottom fibers of the DT at mid-span due to the
initial prestressing force alone.
b. Compute the resulting stress at the bottom fibers of the DT at mid-span due
to the service loads and prestress force.
c. What additional super imposed load can DT carry such that the resulting
stress at the bottom fiber at mid-span is zero.
6. A concrete beam with cross-section area of 32 × 103 π‘šπ‘š2 and the radius of
gyration is 72 mm is prestressed by a parabolic cable carrying an effective
stress of 1000N/mm2. The span of the beam is 8 m, the cable composed of 6
wires of 7 mm diameter has an eccentricity of 50 mm at the center and zero at
the supports. Neglecting all losses, find the central deflection of the beam as
follows:
a. Self-weight + prestress
b. Self-weight + prestress + live load of 2kN/m
7. A prestressed concrete beam, 100 mm wide and 300 mm deep, is prestressed
by straight, wires carrying an initial force of 150 kN at an eccentricity of 50 mm.
the modulus of elasticity of steel and concrete are 210 and 35 kN/mm2
respectively. Estimate the percentage loss of stress in steel due to elastic
deformation of concrete if the area of steel wires is 188 mm 2.
8. A Single-T prestressed concrete beam shown below is simply supported having
a span of 10 m. It carries a superimposed live load of 15.08kN/m in addition to
the weight of beam. It is prestressed with 700 mm 2 of steel to an initial stress
of 1034 N/mm2 located 400 mm from the topmost fiber of the beam section.
Immediately after transfer, the stress reduced by 12%. Determine the stresses
at L/4 from the support due to losses in prestress and final service loads. Use
concrete weight equals to 24kN/m3
9. A beam with width b = 300mm and depth d = 600mm is to be prestressed.
Considering a 15% prestress loss, compute the value of initial prestressing
force P and eccentricity e.
a. If the compressive stress is 21 MPa.
b. If the compressive stress at the bottom fiber is 12 MPa and a tensile stress
at the fiber is 2 MPa.
c. If he compressive stress at the top is 16 MPa
10. A beam with width b = 250 mm and depth d = 450 mm is prestressed by an
initial force of 600 kN. Total loss of prestress at service load is 15%.
1. Calculate the resulting final compressive stress if the prestressing force is
applied the centroid of the beam section.
2. Calculate the final compressive stress if the prestressing force is applied at
an eccentricity of 100 mm below the centroid of the beam section.
3. Calculate the eccentricity at which the prestressing force can be applied so
that the resulting tensile stress at the top fiber of the beam is zero.
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