EEET2336 Power System Protection Tutorial Problem Sheet 1 Problem 1 For the radial power system shown in Fig. 1.1, design simple overcurrent protection using IDMT relays with the characteristics given in Fig. 1.2. Assume that the relay of the circuit breaker B3 is set for the fastest operation available, and the coordination time is in the commonly used range. The maximum fault level in MVA-s on each busbar is given in Table 1.1. The available pick-up current settings for the relays are 1 A to 12 A, in steps of 1 A. The available Time Dial Settings for the relays are 0.4 to 10, in steps of 0.2. The available ratios of current transformers to be used are given in Table 1.2. Determine the CT ratio and the settings for each relay. Show that the time grading computed for the maximum fault levels results in protection selectivity at lower fault currents too. What is the condition for the above to be fulfilled automatically? Busbar No. Max. Fault MVA 1 2 3 4 130 90 60 40 Table 1.1 Busbar Fault Levels CT No. Ratio 1 2 3 4 150/5 200/5 300/5 400/5 5 6 500/5 7 600/5 8 700/5 9 800/5 1000/5 Table 1.2 Available CT Ratios 1 3 2 C/B B1 B2 4 B3 11 kV 5 MVA Load 6 MVA Load 5 MVA Load Fig: 1.1 Radial 11-kV distribution feeder Page:1 RMIT University © School of Engineering 0.4 Fig. 1.2 Page:2 RMIT University © School of Engineering Problem 2 The minimum current at which an overcurrent relay operates is 10 A. The relay is connected to a CT with a CT ratio of 200: 5. The data for the CT is included in Fig. Q4 and Table 1. Determine the minimum primary fault current that will cause the relay to operate, if the CT burden is (a) 1.0 Ω, (b) 4.0 Ω and (c) 5.0 Ω. Calculate the CT error for each case. Table 1 CT ratio 50:5 100:5 150:5 200:5 250:5 300:5 400:5 450:5 500:5 600:5 Secondary impedance [Ω} 0.061 0.082 0.104 0.125 0.146 0.168 0.211 0.230 0.242 0.296 Secondary magnetizing voltage [V] Secondary magnetizing current [A] Page:3