Answers to end-of-chapter questions Chapter 3 11 a weight = mass × g 1 A force can make an object change direction, = 80 × 10 = 800 N decelerate, or accelerate. 2 resultant force [1] [1] [1] 3 weight b the same [1] 4 a force = mass × acceleration c less [1] 12 a the two 5000 N forces b, c Quantity Unit Scalar or vector? mass kg scalar acceleration m/s2 vector force N vector They are equal in size but act in opposite directions. [1] [1] [1] c The lorry will speed up (accelerate). [1] = 20 × 5 = 100 N 6 a weight downwards, air resistance upwards c The resultant force on it is zero, so it does not accelerate. force mass 1 400 000 = 800 000 d terminal velocity = 1.75 m/s2 14 acceleration = b zero 7 a impulse of force = change of momentum b F = force, t = time, m = mass, v = final velocity, u = initial velocity 15 acceleration = = c Momentum is a vector quantity. 8 a kilogram (kg) or gram (g) [1] b newton (N) [1] c metre per second per second (m/s2) [1] direction (like an arrow). b Mass is not a vector quantity (it is a scalar), so it does not have direction. 10 the bigger force acting on the smaller mass, that is, the 10 N force acting on the 5 kg mass © Cambridge University Press 2014 IGCSE Physics [1] [1] [1] [1] [1] [1] [1] [1] [1] [1] change in speed time [1] (20 – 12) 6.4 [1] = 1.25 m/s2 force = mass × acceleration = 1200 × 1.25 = 1500 N 16 weight = mass × g 9 a Force is a vector quantity, that is, it has [1] b resultant force = 1300 – 1200 = 100 N forwards (to the left) 13 force = mass × acceleration 5 90° [1] [1] [1] [1] [1] [1] [1] [1] = 50 × 1.6 = 80 N 17 a resultant force = 680 – 600 = 80 N upwards b He will accelerate upwards. Answers to end-of-chapter questions: Chapter 3 [1] [1] [1] [1] 1 18 a i (engine) thrust and (air) friction ii force shown vertically upwards, anywhere on plane b i speed = distance in any form time [1] [1] [1] = 2200 2 75 [1] = 800 (km/h) [1] ii idea of headwind on outward journey or tailwind on return journey or routes of different lengths or less friction or less weight © Cambridge University Press 2014 IGCSE Physics 19 a i (v − u) or v or 8 3 t t = 2.7 m/s2 ii F = ma or 42 × 8/3 = 112 N iii distance in first 3 s = 12 m so distance in last 11.2 s = 88 m so final speed = 88 = 7.9 m/s 11.2 b Any two from: lower top speed, longer total time, less steep slope at first, etc. [1] [1] [1] [1] [1] [1] [1] [2] [1] Answers to end-of-chapter questions: Chapter 3 2