MODULE FIVE: INVENTORY ANALYSIS Instructions 1. 2. Read the scenarios presented and answer the related questions. Submit your work as a pdf through the appropriate link in Blackboard. Scenario 1: I-Scream Parlor Daily demand for ice cream at the I-Scream parlor has a mean of 220 quarts per day. The owner has the ice cream supplied by a wholesaler who charges $5 per quart. The wholesaler charges a $50 delivery charge independent of order size. The opportunity cost of capital to I-Scream is estimated to be 20% per year, and the additional storage cost of keeping the ice cream frozen and in stock is another 5% per year. Assume 360 days in a year. 1. What is the optimal order size for quarts of ice cream? Formula: Daily demand of quarts (mean) = 220 Days in a year = 360 D = Annual demand = 220 x 360 = 79,200 S = Ordering cost = $50 H = Annual inventory holding cost = (20% + 5%) × $5 = $1.25 Optimal order size (EOQ) = ( 2 × D × S / H ) ½ = ( 2 × 79,200 × 50 / 1.25 ) ½ = ( 6,336,000) ½ = 2,517.14 units Problem Sets 2022 Page 1 of 5 Scenario 2: Parts-R-Us Parts-Are-Us is an auto parts supplier launched in 2015. Annual sales have increased by a factor of 10 over the last 5 years. After reviewing inventory levels, the president of the company finds that system wide inventories have increased by a factor of 5 over that period. The president views this as a signal that the company has been managing its inventories well. Assume that the company uses an Economic Order Quantity model to place orders and has no lead time or safety stock. Also assume that the setup cost and holding cost have not changed over this period – in other words, all that has changed is demand. 1. Do you agree with the company president’s view that the firm is managing its inventory well based on the information presented? Formula: EOQ = Economic order quantity D = Annual demand S = Cost per order H = Annual holding cost per unit Annual sales have increased by a factor of 10 EOQ = √2(10D)S / H = 3.16 √2DS/H Average inventory = EOQ/2 or 50% of EOQ Since the EOQ increased by 3.16, the inventory must also increase by the same factor, 3.16. However, the rise is 5 times instead of a 3.16 increment. Therefore, given all of the assumptions, if the company were managing the inventory well, the inventory would have increased by a factor of 3.16 (the square root of 10) and not by a factor of 5. Hence, we disagree with the President's view. Scenario 3: Parts-R-Us A supplier to Toyota stamps out parts using a press. Changing a part type requires the supplier to change a die on the press. This changeover currently takes two hours. The supplier estimates that each hour spent on the changeover costs $250. Demand for parts is 1,000 per month. Each part costs the supplier $100, and the supplier incurs an annual holding cost of 20%. 1. Determine the optimal production batch size for the supplier. This changeover currently takes = 2 hours Hour spent on the changeover costs = $250 Demand for parts = 1,000 per month Each part costs the supplier = $100 Supplier incurs an annual holding cost = 20%. Problem Sets 2022 Page 2 of 5 D = Annual demand = 1000 x 12 = 12,000 S = Fixed setup cost = 2 x $250 = $500 H = Annual holding cost = $100 x 20% = $20 per year EOQ = √2(D)S / H EOQ = √2(12,000 x 500) / 20 EOQ = 774.6 = 775 The optimal production batch size for the supplier is 775. 2. Toyota wants the supplier to reduce its batch size by a factor of 4; that is, if the supplier currently produces Q parts per batch, Toyota would like them to produce Q/4 parts per batch. What should the supplier do in order to achieve this result? In other words, what setup time (in minutes) creates a scenario in which the optimal batch size drops to ¼ of its current level? Target batch size = Q/4 = 775/4 = 194 In the equation of EOQ, the Batch size (Q) is directly proportional to the square root of the setup cost. Therefore, if Q is reduced by a factor of 4, then the setup cost should decrease by a factor of 16 Target setup cost = 500/16 = $31.25 Each hour of setup costs $ 250 Therefore, target setup time = 31.25/250 = 0.125 hours or 7.5 minutes The supplier should achieve a setup time of 7.5 minutes so that the optimal batch size drops to 1/4 of its current level. Problem Sets 2022 Page 3 of 5 Scenario 4: Dresses-We-Sell Dresses-We-Sell offers a line of upscale evening dresses in a boutique. The store charges $500 per dress and sales average 20 units per week. Currently, they order 80 dresses at a time from the manufacturer and pay $200 per dress. Lead-time is 2 weeks. The store estimates the administrative cost of placing each order to be $200. Adding the cost of capital and related costs the store manager believes that each dollar’s worth of idle inventory cost $0.30 per year. 1. Compute the total annual cost of ordering and carrying inventory. Wd = Average weekly demand = 20 units Annual demand = 20 units x 52 weeks = 1040 units Cost of dress = 200 per unit Administrative cost of placing each order = 200 Order size = 80 units Annual carrying cost = 0.30 per dollar 0.3 x 200 = 60 = (1040/80) x 200 + (80/2) x 60 = $5000 The total annual cost of ordering and carrying inventory is $5000 2. If they wish to minimize cost, when and how much should the store order in each batch? (Assume that the store will order enough units to cover demand for some number of weeks – n, so the question is to find the value of the integer n yielding the lowest total cost.) EOQ = √2(D)S / H EOQ = √2 (1040 x 200) / 60 = 83 units Q/wd = 83/20 = 4.15 = 4 weeks Optimal order = #weeks x demand per week = 4 x 20 = 80 units Leadtime = 2 weeks Weekly demand = 20 units Re order point = leadtime x weekly demand Re order point = 2 x 20 = 40 units The store will order 80 units when the inventory level is 40 units. 3. Find the number of inventory turns per year given the old and the new policy. The old and the optimal policy has the order size Q=80 In both cases, the weeks of supply will be = 4. Therefore, Number of weeks/weeks of supply = 52/ 4 = 13 turns per year Problem Sets 2022 Page 4 of 5 Scenario 5: Dresses-We-Make (Supplier to Dresses-We-Sell) The supplier from Scenario 4 offers Dresses-We-Sell a volume based discount. The supplier will drop the price to $195 per dress, but for only order sizes above 200. The store is also considering an alternate supplier that has an electronic ordering system. Because of the nature of the software, ordering from this supplier drops the administrative cost to $100 per order and the store can select any order size up to (but not more than) 200 units per order. 1. Which deal should the store accept? (Assume they must accept one of these deals.) Volume discount deal Order quantity, Q = 200 units Item cost, C = $195 per unit Order cost = 200 Annual demand = 52 x 20 = 1040 Unit carrying cost, h = 0.3 of 195 = $58.5 per annum Total annual ordering cost = (annual demand/quantity ordered ) x order cost = (1040/200) x 200 = 1040 Annual carrying cost = (order quantity/ 2) x 58.5 = (200/2) x 58.5 = 5850 Total cost of the item = (annual demand x cost per item) = 1040 x 195 = 202,800 Total annual Ordering cost + total annual carrying cost + total cost of the item = 1040 + 5850 + 202,800 = $209,690 The deal of alternate supplier with electronic ordering Order cost, K = $100 per order Item cost, C = $200 per unit Unit carrying cost, h = $60 per annum EOQ = (2.D.K / h)1/2 = (2 * 1040 * 100 / 60)^0.5 = 59 units Total annual ordering cost = (1040/59) * 100 = 1762.71 Total annual carrying cost = (EOQ/2) * annual carrying cost = (59/2)* 60 = 1770 Total cost of the item = Annual demand * cost of the item = 1040 * 200 = 208,000 1763 +1770 + 208,000 = 211,533 The volume-discount deal is the best as it offers the least annual total cost of $209,690 among all the possible alternatives. Problem Sets 2022 Page 5 of 5