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CE 214 Fundamentals of Surveying Lec
1st Semester, AY 2022-2023
Engr. Karen S. Galoso
Instructor
Civil Engineering Department
OUTLINE
β–ͺ Accuracy & Precision
β–ͺ Definition, Types and Sources of Errors
β–ͺ Theory of Errors & Adjustments
CE 214 FUNDAMENTALS OF SURVEYING LEC
Accuracy and Precision
ACCURACY
the degree of conformity of a given measurement with a standard value.
PRECISION
the extent to which a given set of measurements agree with their mean.
Precision without accuracy
Neither precision nor accuracy
CE 214 FUNDAMENTALS OF SURVEYING LEC
Precision and accuracy
Definition, Types and Sources of Errors
ERRORS
a difference between a measured or
observed value and the “true” value.
SOURCES
• NATURAL ERRORS
due to variations in the environment such
as magnetic declination, temperature,
humidity, wind etc.
• INSTRUMENTAL ERRORS
due to limitations in the instruments used
• PERSONAL ERRORS
due to the limitations of senses of sight,
touch and hearing.
MISTAKES
or gross error; the inaccuracies in measurements which
happen due to carelessness, inattention, poor judgment and
wrong execution.
TYPES
SYSTEMATIC ERRORS
repeated; errors for which
the magnitude and
algebraic sign can be
determined; also known as
cumulative errors
CE 214 FUNDAMENTALS OF SURVEYING LEC
ACCIDENTAL ERRORS
random; likely to be
positive or negative
Theory of Errors & Adjustments
MOST PROBABLE VALUE
ΰ΄₯=
𝑿
σ𝒙
𝒏
RESIDUAL
ΰ΄₯ −𝒙
𝒗= 𝑿
v – residual
𝑋ഀ – the most probable value
x – individual quantity (observation)
n – number of observation
ΰ΄₯=
𝑿
σ𝒙 βˆ™ π’˜
π’˜
For a single quantity multiple
measurement taken as π‘₯1 , π‘₯2 , π‘₯3 …
with weight 𝑀1 , 𝑀2 , 𝑀3 …
PROBABLE ERROR OF SINGLE OBSERVATION
𝑷𝑬𝒔 = 𝟎. πŸ”πŸ•πŸ’πŸ“
σ π’—πŸ
𝒏−𝟏
PROBABLE ERROR OF THE MEAN
σ π’—πŸ
π‘·π‘¬π’Ž = 𝟎. πŸ”πŸ•πŸ’πŸ“
𝒏(𝒏 − 𝟏)
CE 214 FUNDAMENTALS OF SURVEYING LEC
Percent Error
50%
0.6745
90%
1.645
95.5%
2.00
95%
1.96
99.9%
3.29
Theory of Errors & Adjustments
ERROR PROPAGATION
Case I. Sum of Errors
π‘¬π’”π’–π’Ž =
π‘¬πŸ 𝟐 + π‘¬πŸ 𝟐 + π‘¬πŸ‘ 𝟐 + β‹― + π‘¬πŸ 𝟐
Case II. Error in a product
𝑬𝒑𝒓𝒐𝒅𝒖𝒄𝒕 =
(π‘ΈπŸ βˆ™ π‘¬πŸ )𝟐 + (π‘ΈπŸ βˆ™ π‘¬πŸ )𝟐
CE 214 FUNDAMENTALS OF SURVEYING LEC
Theory of Errors & Adjustments
Sample Problem 1
A surveying instructor sent out seven groups of
students to measure a distance between two points
marked on the ground. The students came up with
the following measured values: 240.25 m, 240.15 m,
239.90 m, 241.04 m, 240.50m, 241.22m and 242m.
Find the most probable value of the measured
distance.
Sample Problem 2
The angles about a point Q have the
following observed values :
120˚15’20”, 152˚37’30” and 87˚07’40”.
Determine the most probable value
for each angle.
Solution
Solution
ΰ΄₯ = πŸπŸ’πŸŽ. πŸ•πŸ π’Ž
𝑿
Most probable values are:
𝜎1 = 120° 15′ 10′′
𝜎2 = 152° 37′ 20′′
𝜎3 = 87° 07′ 30′′
CE 214 FUNDAMENTALS OF SURVEYING LEC
σ1
σ3
σ2
Theory of Errors & Adjustments
Sample Problem 3
Given are the interior angles
of a triangle. Determine the
discrepancy for the given
observation and the most
probable value of each angle.
𝐴 = 33° 14′ 37′′
𝐡 = 98° 30′ 09′′
𝐢 = 48° 15′ 05′′
Solution
Most probable values are:
33° 14′ 40′′
𝐴=
𝐡 = 98° 30′ 12′′
𝐢 = 48° 15′ 08′′
Sample Problem 4
The following values were determined in a series of tape
measurements of a line: 1001.58 m, 1001.40 m, 1001.38
m, 1001.48 m, 1001.40 m, 1001.46 m. Determine the ff:
1) Most Probable Value
2) Probable Error of a single measurement
3) Probable Error of the mean
4) Final expression of the most probable length
Solution
ΰ΄₯ = 𝟏𝟎𝟎𝟏. πŸ’πŸ“ π’Ž
𝑿
𝑷𝑬𝒔 = ±πŸŽ. πŸŽπŸ“ π’Ž
π‘·π‘¬π’Ž = ±πŸŽ. 𝟎𝟐 π’Ž
𝑳 = 𝟏𝟎𝟎𝟏. πŸ’ ± 𝟎. 𝟎𝟐 π’Ž
CE 214 FUNDAMENTALS OF SURVEYING LEC
Theory of Errors & Adjustments
Sample Problem 5
Four measurements of a distance were recorded
as tabulated:
Measured Length
285.18 m
285.19 m
285.22 m
285.20 m
Weight
1
3
2
4
What is the most probable value of the
measurement?
Sample Problem 6
The three sides of a triangular
lot has the following sides and
corresponding probable errors.
Determine the probable error of
the sum and the most probable
value of the perimeter.
Solution
π‘·π‘¬π’”π’–π’Ž = ±πŸŽ. πŸŽπŸ• π’Ž
𝑷 = πŸ“πŸ—πŸ. πŸ’πŸ— ± 𝟎. πŸŽπŸ• π’Ž
Solution
ΰ΄₯ = πŸπŸ–πŸ“. πŸπŸ—πŸ— π’Ž
𝑿
CE 214 FUNDAMENTALS OF SURVEYING LEC
π‘Ž = 152.64 ± 0.03 π‘š
𝑏 = 253.25 ± 0.05 π‘š
𝑐 = 185.60 ± 0.04 π‘š
Theory of Errors & Adjustments
Sample Problem 7
The sides of a rectangular lot has the following
sides and corresponding probable error.
π‘Š = 564.75 ± 0.08 π‘š
𝐿 = 235.75 ± 0.06 π‘š
Determine the probable error of the product
and the most probable value of the area.
Solution
𝑷𝑬𝒑𝒓𝒐𝒅𝒖𝒄𝒕 = ±πŸ‘πŸ–. πŸ•πŸ– π’ŽπŸ
𝑨 = πŸπŸ‘πŸ‘, πŸπŸ‘πŸ—. πŸ–πŸ ± πŸ‘πŸ–. πŸ•πŸ“ π’ŽπŸ
CE 214 FUNDAMENTALS OF SURVEYING LEC
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