ElSanousi 1 Titration of Hydrochloric Acid with Sodium Hydroxide (Mostafa ElSanousi, 10/09/22, Chemistry HL) I. Introduction & Purpose Research Question What is the method to determine the concentration of NAOH through a titration experiment when NAOH is diluted into H2O and C20H14O4 (phenolphthalein or HPh) is mixed in. Introduction Titration experiments may seem niche and impractical to observe and utilize in real-world scenarios but that is simply not the case. I, for one, understood the importance of titration experiments in the automotive industry in order to produce the most efficient biodiesel fuel. In this case, pH level is determined to find how much of a base is needed for balance and achieving the correct pH level in the fuel. Therefore, titration experiments undoubtedly were brought to my attention as a possible IA topic. II. Background & Design Background Important Terms: Titration – Method of determining the concentration of a dissolved substance (in this case it is 0.1M of NAOH with a volume of 250cm^2) in terms of the smallest amount of a reagent required to bring about the end point of the reaction (e.g. color change). Titrant – A substance (the regent) that is used to bring about the end point of the reaction between it and the analyte + HPh. Indicator (C20H14O4) – C20H14O4, or phenolphthalein, is a colorless, weak acid, that is used in titrations in order to identify the end point of titration. Analyte – The analyte in a titration experiment is the unknown concentration (in this case it is the NAOH diluted into H2O). End Point – The point in a titration experiment when the indicator shows that the amount of reactant necessary for a complete reaction has been added. ElSanousi 2 Neutralization Reaction – Neutralization reactions are a type of reaction where an acid and a base react and result in an ionic compound or water sometimes. When the reaction is in water, the neutralization reaction depends on there being no excess of hydrogen or hydrogen ions in the solution. Important Concepts: Molarity: M = n/v where n is moles of solute and v is liters of solution. Molarity was used as this was the given concentration of NAOH in the beginning of the experiment that we used to find the amount of moles present in 0.1M concentration of NAOH if it has a volume of 250 cm^3. Dm^3 = Cm^3/1000 This is important as dm^3 is the standard unit used in titration experiments and using cm^3 would result in errors. C = n/v – > n = c*v According to the initial formula to determine concentration, moles are equal to the concentration multiplied by the volume. This formula is important as it allows us to determine the amount of moles in NAOH that has a concentration of 0.1M and has a volume of 250 cm^3 which is rewritten to 0.250 dm^3 as it has to be in terms of dm^3 in order for the formula to function. The connection to pH and the pH indicator: pH measures the acidity or basicity of an aqueous solution. In this case, the pH level changes according to the base in the titration experiment which is NAOH and since it is a base the pH indicator will have a pink hue as it is initially colorless in pH levels less than 8.5 but has a color in pH levels higher than 8.5. Calculating amount of moles using molarity: Molarity x volume = number of moles In this case, at the equivalence point – (MNaOH)(VNaOH) = (MHCl)(VHCl) Titration experiments are important to chemistry as they allow for an accurate determination of solution concentrations of the analyte. As discussed before, they also hold implications in real-life situations, and are, therefore, valuable to various industries (such as the automotive industry). Titration experiments are experiments where a volume of a solution of a known concentration is added to a volume of another solution in order to determine its concentration. Hypothesis I hypothesize that the concentration of NAOH + H2O will be less than the initial concentration of NAOH as dilution results in the decrease in concentration. ElSanousi 3 Furthermore, I believe that since the HPh will be dropped into the NAOH, the solution will become a pink color compared to if it was being dropped into HCl where it would retain its clear, transparent appearance. The reason for this is that HPh is colorless in solutions with a pH level lower than 8.5 and has a pink hue in pH levels above 9.0. Therefore, since the HPh is being dropped into a base (NAOH), although being diluted into H20, its pH level is approximately 9.0 and thus the solution will develop a pinkish hue and only lose it when it becomes transparent and has a pH level less than or equal to 8.5 which would mean that the end point has been reached (concentration of hydrogen and hydrogen ions in the solution are balanced and thus the color goes from pink to transparent again) and the concentration of the NAOH + H2O has been quantified. Design - Independent Variable: Volume of base (250cm^2/0.250dm^3 of NAOH) - Dependent Variable: The molarity of NAOH as identified through the final burette reading. - Controlled variables: Variable controlled Why it’s important to control Volume of Distilled Water Into the NaOH The volume of distilled water into the NaOH will affect the final concentration due to the amount of dilution that the NaOH will go through which will decide how much the initial concentration decreases due to dilution. Surface Area of Volumetric Flask The surface area of the volumetric flask that we used to dilute the NaOH with water accurately is important as it allowed for a specific concentration of diluted NaOH (50mL) that would become different if we used a different How this experiment will control or monitor the variable This will be monitored throughout the experiment through the use of a volumetric flask that is marked with a line that allows us to use the same amount of distilled water to dilute the NaOH each and every time. The surface area of the volumetric flask will be kept constant as we will be using the same exact flask. ElSanousi 4 volumetric flask with different proportions. Mass of NAOH diluted into H2O (1g) The mass of NaOH that we solved for (1g) using the given concentration (0.1M) and volume (250cm^3) needs to be kept constant as if it is different every time there will be a different concentration of diluted NaOH in the final burette reading. The concentration, and thus, the mass, of the NaOH was kept constant throughout the entirety of the experiment as we have had it measured out in the beginning using the mass scale to be 1 gram. Addition of HPh indicator (2 drops) It is important to keep the amount of HPh indicator used constant as having a different one every time will affect the pH as it is still an acid despite being a weak one. The same dropper used to add the HPh indicator into the solution will be reused to enforce similar results in the final burette reading. Room temperature (must remain constant) If the solution is at a higher or lower temperature because of the general room temperature then the volumetric flask readings may be incorrect as it will contract or expand meaning that the final burette reading will be wrong. The room temperature will be kept constant as the temperature system will not be tampered with or touched so as to keep the temperature constant. III. Procedure & Safety Materials Burette (1) 250mL Erlenmeyer Flask (3) 1 L of Distilled Water (1) pH Indicator (phenolphthalein) (1) ElSanousi 5 Dropper (1) Retort Stand and Clamp (1) 100mL Volumetric Flask (1) Wash Bottle (1) 50mL Beaker (1) Gloves Lab Coat Procedure 1. Wear safety equipment (e.g. gloves and lab coat). 2. Calculate amount of NaOH in grams that will be used in the titration experiment given volume (250cm^3) and molarity (0.1M). 3. Using a mass scale, weigh exactly 1 gram of NaOH that will be used in the experiment. 4. Remove the covering from the volumetric flask and fill approximately ¼ of the flask. 5. Add 1g of NaOH that you measured just before and begin to carefully move the volumetric flask in a circular motion to dilute the sodium hydroxide. 6. Proceed to fill the volumetric flask to the 50mL mark once the dilution of sodium hydroxide is complete. 7. Add the diluted substance equally to three erlenmeyer flasks at the indicated mark (25mL) provided in order to keep the amount constant. 8. Carefully add two drops of C20H14O4 (HPh) into each of the three erlenmeyer flasks. 9. Add HCl into the burette until it reaches the 0.00 mark in order to avoid mistakes in the final reading. 10. To begin the titration, place one of the three erlenmeyer flasks under the burette mechanism so as the tip of the burette is within the flask to avoid drippage outside the flask. 11. For the first trial, carefully calibrate the flask by turning the tap so as precise and orderly droplets are going into the flask. 12. Turn off the tap when the diluted NaOH (which turns pink due to the HPh) becomes a colorless liquid as that means it has reached the end point and the titration has been successful. 13. Check the amount of HCl that is left over and that is the experimental concentration of diluted NaOH. 14. Record your data. 15. Repeat the process two more times and record the data as well. ElSanousi 6 Diagram Safety/Ethical/Environmental Issues NaOH Dangers: Contact with NaOH may result in serious burns to the eyes, skin, and digestive system or lungs that can lead to serious injuries, or even death. HCl Dangers: HCl is extremely hazardous when it comes into contact with the skin or eyes or when it is inhaled or ingested and can cause permanent damage to your organs. HPh Dangers: HPh may cause eye irritation and skin irritation upon contact with skin and may be harmful if it is absorbed through the skin as well. Considerations: It is important to wash your hands with a large volume of water if you come into contact with any of the mentioned substances during the replication of this titration experiment. ElSanousi 7 IV. Data Processing Data Tables (give them meaningful titles) DATA COLLECTION (RAW) Amount of Distilled Water (mL) Volume of HCl (mL) Trials Initial Burette Reading Final Burette Reading 50 1st Trial 0.00 44.5 50 2nd Trial 0.00 44.2 50 3rd Trial 0.00 44.3 Calculations Average of the three trials: 44.5 + 44.5 + 44.3 divided by 3 = 44.33mL of HCl Concentration of NaOH: At the equivalence point – (MNaOH)(VNaOH)=(MHCl)(VHCl) Average volume of HCl used = 44.33mL - 0.00 of HCl = 44.33mL of HCl (MNaOH) = (MHCl)(VHCl)/(VNaOH) (MNaOH) = (0.1)(44.33mL)/25mL (MNaOH) = 0.17732 M ElSanousi 8 Graphs: Example of Strong Base-Strong Acid Graph and its general logarithmic trend at the equivalence point: ElSanousi 9 V. Conclusion Consequently, based on my titration experiment results seen in the above graph and how they do not represent a properly logarithmic function, it is safe to say that there may have been some issues in the reporting or conduction aspect of the experiment. Based on the data I worked out, the final concentration of NaOH that the titration experiment was meant for, turned out to be 0.177M while the initial concentration was 0.1M. Therefore, this cannot be true as the dilution that the NaOH went through (NaOH(aq) + HCl(aq) → NaCl(aq)+H2O(I); 1:1 molar ratio) means that the concentration should be less than 0.1M as concentration decreases when becoming diluted. The experiment could have gone better if some more measures were taken for greater precision and accuracy, as well as some considerations into the actual measurements and measuring devices being used as they have tampered with the final results eventually at the end as well. Furthermore, titration experiments are faulted in their nature as their main limitation is that the end point of the titration does not necessarily equal the equivalence point. All in all, it was an informative experience that facilitated the conceptual understanding of a titration, its property and construct, and its product. VI. Analysis Sources of Error and Improvements Source of Error Mass Scale How it could skew (increase or decrease the final result) Suggested Procedural Improvement The mass scale could result in an excess or lack of NaOH needed for the titration to be accurate, therefore, it could skew the final results so that it increases as the concentration of NaOH in the water would be higher. In order to ensure that the mass scale does not malfunction or to check that it is giving precise or accurate measurements, it may be better to have two available to have a few attempts instead of using one and taking it for what it is worth. ElSanousi 10 HPh dropper The HPh dropper was not entirely precise and sometimes leaked for more than two drops. This will skew the final results as the volume of HCl needed in mL would be higher in order to perform the neutralization reaction and complete the titration successfully; therefore, the final concentration of NaOH would also be higher as well as it would take more to balance the pH level. In order to procedurally improve this aspect of the experiment, it is best to ensure that the dropper is working using it and comparing it to other droppers to see if they are secreting the same amount of liquid to avoid having a malfunctioning dropper that may be leaking more than it is supposed to. Reaction Time Reaction time is an important factor in a titration experiment as in order for the exact volume of the titrant needed to perform a neutralization reaction, you must have a faster reaction time so as the result is as accurate as physically possible for a human. If it is overestimated due to a poor reaction time, then the volume of HCl will be higher, and thus the volume of NaOH will also be higher as well. In order to improve upon this procedural issue, it is possible to perform more than 3 trials as that will minimize the presence of the systematic errors that are present due to a person’s natural reaction time while also giving a clear insight into what the actual results may be. Unequal distribution of substance (NAOH + If there is an unequal distribution of substance This procedural issue could be fixed through ensuring ElSanousi 11 H2O) in conical flasks in the conical flasks, there will be less or more of the volume of diluted NaOH, and thus this could lead to the final concentration either skewing upwards or downwards based upon if there is more NaOH in the flask or less. that there is an equal distribution in the conical flasks through precisely measuring the amount of substance in the flasks and equating them to the other flasks instead of basing it off of your eyes which can have issues for a number of reasons (e.g. parallax error).