FUNDAMENTALS OF SURVEYING
(FIELD LABORATORY - F2F)
LEVELING SURVEY
Name:
LAURENTE, RACHIEL ANN I.
____________________________
Date:
Student No.:
22-1-02881
_____________________________
TCIE 2-6
Course/Section: ________
October 22, 2022
________________
Aim: To find the difference in elevation between two points.
Theory: Bench Mark - Types, Simple/ Differential Leveling
Instruments/ Accessories: Level, Leveling Rod, Tape Measure, Tripod, Pins or Marker
SURVEY PROCEDURE: GROUP WORK
1. Using student individual PACE FACTOR establish a straight line with a distance of
approximately 150 meters, consider the starting point as the Bench Mark 1 (BM1) and
the last point as Bench Mark 2 (BM2).
2. Divide the line into two approximately equal parts, the midpoint of the line considers as
the Turning Point (TP).
3. Set-up and level the instrument in the midway of the BM1 and TP.
4. Take the Backsight Rod Reading on BM1. Record the data.
5. Rotate the level, Take the Foresight Rod Reading on TP. Record the data.
6. Move the instrument and set-up and level again in the midway of TP and BM1.
7. Take the Backsight reading on the TP and take the Foresight reading on BM2. Record the
data.
8. Using Tape Measure, measure the distance between point BM1 to TP, TP to BM2.
9. Make sure all the data were recorded.
10. Check the instrument and return it properly.
Sample Table:
OUTPUT: INDIVIDUAL SUBMISSION
1. Individual Pace Factor used: ____________
2. The elevation (m) of BM1 is equal to 1+ last 2 digits of your student number. Sample: student
number SET22102230, BM1 = 130 m.
181
BM1 = ________________
INST INST
3. Sketch the level route from BM1 - TP and TP - BM2. Based on the survey data.
Sample:
4. Show the SOLUTION:
a. Computation of HI's and Elevation of Stations
➢ HI
181
+ 1.365
182.365
BM1
BS
➢ ELEVATION of BM2
182.365
- .545
181.82
HI
FS
b. Determining Backsight and Foresight Sums
∑ 𝐵𝑆 = 1.365
∑ 𝐹𝑆 = .545
5. Show the TABULATED SOLUTION:
STATION
BACKSIGHT
HI
BM1
1.365
182.365
BM2
FORE SIGHT
181
.545
6. Arithmetic Check
181
+ 1.365
182.365
- .545
181.82
ELEVATION
(Elevation of BM1)
(∑ BS)
(Sum)
(∑ FS)
(Check with Elevation of BM2)
181.82