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Bupropion HCl synthesis lab report.docx

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Aisha Green
Bupropion HCL Synthesis Lab Report
Abstract
Wellbutrin and Zyban are well known pharmaceuticals for the treatment of nicotine
addiction1. The drugs are comprised of bupropion hydrochloride salt. Bupropion hydrochloride
salt is created through the alpha bromination of m-chloropropiophenone, an SN2 reaction
adding t-butyl, and pronation from HCl. The salt was then analyzed through HNMR to verify the
structure of the compound that was formed. A yield of 65% was recovered from the reaction.
Overall, the experiment demonstrated the process of pharmaceutical synthesis and synthesis
efficiency.
Introduction
Bupropion hydrochloride salt an ingredient in medications such as Zyban and Wellbutrin
which are prescribed as antidepressants2. Zyban and Wellbutrin work to suppress the reuptake
of serotonin and norepinephrine, which can be used as a therapy of depression and smoking
cessation. The pharmaceutical can be used as a treatment for nicotine addiction 1. The synthesis
illustrates the ideas of pharmaceutical synthesis and synthesis efficiency. For a drug to be
produced it has to be synthesized without producing much waste.
In this experiment, a one-pot synthesis of m-chloropropiophenone into a bupropion
hydrochloride salt was performed as shown in Figure 1.
Figure 1: Synthesis of bupropion hydrochloride
The reaction mechanism is shown in Figure 2 depicting step 1 where the ketone undergoes
alpha bromination and is converted into a bromoketone. Then in step 2 there is a SN2
displacement of the bromine by the t-BuNH2. Finally, in step 3, there is conversion into
ammonium hydrochloride salt through a reaction with HCL. NMP is used as the solvent for
animation because generates a faster reaction.
Figure 2: Reaction mechanism of bupropion hydrochloride synthesis
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Results and Discussion
The bromine turned a lighter yellow color compared to the drops of bromine that was
added. There was a total of 8ml of distillate collected from the condensation reaction. The
solution turned the pH paper a dark pink/purple color. The crystals formed were a light-yellow
color instead of desired white crystals of bupropion hydrochloride. Figure 3 illustrates the
calculations for theoretical yield and 65% yield. The theoretical yield for the experiment is 1.63
grams of bupropion hydrochloride because the molecular weight of the product is multiplied by
the number of moles in the reagents. If there was only an actual yield of 65% then the yield for
the experiment would be around 1.06 grams of bupropion hydrochloride recovered.
Figure 3: Theoretical and 65% yield calculations
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Even though 100% recovery would be the desired outcome, that does not always
happen due to things like errors or the favorability of a reaction. Some things that may have
caused a yield of only 65% may be that the bromine did not reach a light-yellow color meaning
that the reaction did not go through to completion. Another source of error is not adding the
bromine in the solvent in drops because if too much bromine was added it may react with other
molecules or itself. Lastly, there was not 100% recovery because some of the salt was stuck in
the flask reducing the yield.
Some of the major plot points of the H NMR data is the singlet at 1.28ppm that is
integrating for 9 protons indicating the tertbutyl group. Another reading that stands out is the
doublet integrating 1 proton around 2.5ppm. There are also four very close readings that are
around 7-8ppm that integrate for 1 hydrogen each indicating a benzene ring.
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The major readings on the C NMR plot would be the large reading at 28.4ppm indicating
the tertbutyl group attached to the molecule. Another important reading is 193.1ppm indicating
a carbon attached to a very electronegative atom. Lastly there are the five readings that are
close together ranging from 126-183ppm indicating a benzene ring in the molecule.
Conclusion
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The experiment used many useful chemistry techniques such as distillation, running a
TLC plate, vacuum filtration, separation, and H NMR to create the product of bupropion
hydrochloride. The reaction worked by alpha bromination of a ketone, an SN2 reaction of tbutylamine, and protonation into a salt using HCL to get a more stable, longer lasting product.
The experiment had a yield of 1.06 grams meaning that there was a 65% yield, compared to the
1.63 grams that was expected. One reason the yield was decreased may have been due to not
letting the reaction heat long enough meaning that it did not go through to completion and not
yielding as much product. Overall, the experiment demonstrated the process of pharmaceutical
synthesis and synthesis efficiency.
Experimental
This experiment involved taking m-chloropropiophenone then converting it into
bupropion hydrochloride salt through a series of reactions. First one gram of mchloropropiophenone was dissolved in 5ml of CH2Cl2. Next, a few drops of 1M Br2 solution was
added to the CH2Cl2 in single drops allowing the color to fade. The reaction was heated slightly,
and 6 ml of bromine solution was added in drops. After all the bromine was added the reaction
mixed for 15 minutes. A TLC plate of 1:1 DCM:hexanes was made to monitor the rate of the
reaction. The CH2Cl2 was then removed by heating the reaction slightly. Next, 5ml of NMP was
added followed by 5ml of t-butylamine. Then, the flask was heated in a warm water bath
stirring for 15 min. The contents were then transferred into a separatory funnel adding 25ml of
water, then the mixture was extracted with 10ml of ether 3 times. The ether extracts were then
washed with 10ml of water, dried with anhydrous sodium sulfate, and chilled in an ice bath.
Finally, 5.93mmols of a 4M HCL solution was added and crystals will begin to form. Once the
crystals formed, they were collected, washed with ether and dried. Lastly, an H NMR reading
was obtained.
Post-lab questions
1. What would happen if you rinse the final crystals with water instead of Ether?
a. Nothing would happen if the crystals were rinsed with water versus ether. The
bupropion hydrochloride salt is not soluble in either solvent. The solvents will
dissolve the impurities that are formed within the crystals and not the crystals
themselves because the crystals are insoluble in those solvents.
2. What is the purpose of forming ammonium salts of organic compounds used as
medicine?
a. The purpose of forming ammonium salts in medicine is to reactivity because the
ammonium salt is less reactive thus masking the reactivity of the product. This is
done to allow the tablets to be stable for longer and not degrade.
3. Describe how your extraction would be different if you were using Ethyl acetate instead
of ether?
a. The extraction would not be different using ethyl acetate as the extraction
solvent instead of ether. Since ethyl acetate and ether both have a lower density
when compared to water. This means that the ether and acetate will be the top
layer of the extraction with the product and the aqueous layer will be on the
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bottom. But since the density of ethyl acetate is closer to water the compounds
may take longer/harder to separate when compared to ether.
References
1. Perrine, Daniel M.; Ross, Jason T.; Nervi, Stephen J.; Zimmerman, Richard H. A Short,
One-Pot Synthesis of Bupropion (Wellbutrin, Zyban). Journal of Chemical Education
2000, 77 (11), 1479, DOI: 10.1021/ed077p1479
2. National Library of Medicine. PubChem.
https://pubchem.ncbi.nlm.nih.gov/compound/Bupropion (accessed May 1, 2020)
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