# c11

```Exam
Name___________________________________
SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.
1) Cougar Telemarketing is considering establishing a call center. The initial cost will be
\$2,750,000 with a \$27,500 market value any time within a 13-year period. The fixed cost of
the center will be \$830,000 per year with an average variable cost of \$3.00 per call. Cougar
expects to generate revenue of \$5.25 per call with a capacity of 110,000 calls for the first
year. The company also expects to increase the capacity uniformly each year. At an
interest rate of 2% per year, determine the uniform amount the capacity must increase each
year so that the company can recover its investment in 3 years.
1)
Answer: Uniform amount of increase per year = 687,934 units
Explanation: Let G = uniform amount of increase per year
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AWRevenue = \$(5.25 - 3.00)[110,000 + G(A/G, 2%, 3)]
= \$247,500 + \$(2.22)G
AWCost = \$2,750,000(A/P, 2%, 3) + \$830,000 - \$27,500(A/F, 2%, 3)
= \$2,750,000(0.3468) + \$830,000 - \$27,500(0.3268)
= \$1,774,713.00
Th
Set Revenue = Cost:
G = [\$1,774,713.00 - \$247,500]/\$(2.22)
= 687,934 units
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2) Ginger has agreed to a lawsuit settlement of \$600,000 with a certain pharmaceutical
company. The company has offered options to pay her the awarded money. After
discussing the terms with the company, she expects that the company should be able to
pay her back within 3-5 years. Ginger has developed the following estimates. Which
option should she select, if her personal MARR is 13% per year?
Option
A
B - Pessimistic
C - Most likely
D - Optimistic
Delay period
5 years
4 years
3 years
2)
Cash Flow Estimates, \$
\$600,000 now
\$131,000 per year for every year the payment is delayed.
\$161,200 per year for every year the payment is delayed.
\$211,500 per year for every year the payment is delayed.
PWB(13%) = \$460,753.20
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PWC(13%) = \$479,489.40
PWD(13%) = \$499,393.80
PWA(13%) &gt; PWD(13%) &gt; PWC(13%) &gt; PWB(13%); therefore, Ginger should select
option A.
Explanation: Option A: PW(13%) = \$600,000
Option B: PW(13%) = \$(131,000)(P/A, 13%, 5)
= \$460,753.20
Option C: PW(13%) = \$(161,200)(P/A, 13%, 4)
= \$479,489.40
Option D: PW(13%) = \$(211,500)(P/A, 13%, 3)
= \$499,393.80
Th
PWA(13%) &gt; PWD(13%) &gt; PWC(13%) &gt; PWB(13%); therefore, Ginger should
select option A.
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3) Two processes are under consideration for a certain production. Process A requires
acquisition of a new machine that is estimated to have an initial cost of \$65,000 and a
salvage value of \$52,000 at the end of its useful life of 6 years. In addition, the process
requires a fixed cost of \$47,000 per year and a variable cost of \$250 per day. Alternatively,
Process B requires the use of human labor. The process will need 6 workers, each earning
\$200 per day and will have a fixed cost of \$36,000 per year and additional variable costs of
\$200 per day. Determine the minimum number of days per year required for the two
processes to break even at an interest rate of 2% per year.
3)
Explanation: Let X = number of breakeven days per year
AWA = -\$65,000(A/P, 2%, 6) - \$47,000 + \$52,000(A/F, 2%, 6) - \$250X
= -\$65,000(0.1785) - \$47,000 + \$52,000(0.1585) - \$250X
= -\$50,360.50 - \$250X
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AWB = -\$(6)(200)X - \$36,000 -\$200X
= -\$(1400)X -\$36,000
Set AWA= AWB:
-\$1400X - \$36,000X = -\$50,360.50 - \$250
-\$1150X = -\$14,360.50
X = -\$14,360.50/ -\$1150
= 12.49 days per year
4) Two machines are under consideration for a new production line. Machine X costs \$50,000
and is expected to have a salvage value of \$6500 at the end of its useful life of 5 years. It
will have a fixed cost of \$16,000 per year and a variable cost of \$55 per unit per year. On
the other hand, machine Y costs \$55,000 and is expected to have a salvage value of \$7000 at
the end of its useful life of 7 years. It will have a fixed cost of \$14,500 per year and a
variable cost of \$58 per unit per year. Determine the quantity that must be produced for
the two machines to break even at an interest rate of 3% per year.
Explanation: Let Q = number of breakeven units per year
AWX = -\$50,000(A/P, 3%, 5) - \$16,000 + \$6500(A/F, 3%, 5) - \$55Q
= -\$50,000(0.2184) - \$16,000 + \$6500(0.1884) - \$55Q
= -25,695.40 - \$55Q
Th
AWY = -\$55,000(A/P, 3%, 7) - \$14,500 + \$7000(A/F, 3%, 7) - \$58Q
= -\$55,000(0.1605) - \$14,500 + \$7000(0.1305) - \$58Q
= -\$22,414.00 - \$58Q
Set AWX = AWY:
\$(58- 55)Q = \$3281.40
Q = 1094 units per year
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4)
5) A distribution center wants to evaluate an alternative product tracking system. The system
has an initial cost of \$500,000 and a salvage value of \$80,000 at the end of its useful life of 7
years. The operating cost is estimated to be \$550 per metric ton of product moved per day.
The center can handle between 30 and 50 tons per day. Analyze the sensitivity of the PW
to changes in a 10-metric-ton increment of product moved. Use an interest rate of 3% per
year and 200 days of work per year.
5)
PW40(3%) = -\$27,848,272.00
PW50(3%) = -\$34,701,602.00
Explanation: PW30(3%) = -\$500,000 - \$(550)(30)(200)(P/A, 3%, 7) + \$80,000(P/F, 3%, 7)
= -\$500,000 - \$(3,300,000)(6.2303) + \$80,000(0.8131)
= -\$20,994,942.00
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PW40(3%) = -\$500,000 - \$(550)(40)(200)(P/A, 3%, 7) + \$80,000(P/F, 3%, 7)
= -\$500,000 - \$(4,400,000)(6.2303) + \$80,000(0.8131)
= -\$27,848,272.00
PW50(3%) = -\$500,000 - \$(550)(50)(200)(P/A, 3%, 7) + \$80,000(P/F, 3%, 7)
= -\$500,000 - \$(5,500,000)(6.2303) + \$80,000(0.8131)
= -\$34,701,602.00
6) The estimated cash flows of an investment project are shown below.
Item
Initial investment, \$
Annual revenue, \$
Annual expense, \$
Market value, \$
Project life, years
Estimated Cash Flows
55,000
7000
4500
1800
8
Sensitivity Range
&plusmn;5%
&plusmn;10%
&plusmn;10%
&plusmn;15%
&plusmn;5%
Using an interest rate of 2% per year, analyze the sensitivity of the PW to changes in initial
investment and annual revenue, and determine the breakeven percentage changes of these
two factors.
Th
Answer: Sensitivity to changes in initial investment:
+5%: PW(2%) = -\$37,899.95
-5%: PW(2%) = -\$32,399.95
Breakeven percent change = -64%
Sensitivity to changes in annual revenue:
+10%: PW(2%) = -\$30,022.10
-10%: PW(2%) = -\$40,277.80
Breakeven percent change = 68.55%
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6)
Explanation: PW(2%) = -\$55,000 + (\$7000 - \$4500)(P/A, 2%, 8) + \$1800(P/F, 2%, 8)
= -\$55,000 + (\$2500)(7.3255) + \$1800(0.8535)
= -\$35,149.95
Sensitivity to changes in initial investment:
+5%: PW(2%) = -\$55,000(1.05) + (\$7000 - \$4500)(P/A, 2%, 8) + \$1800(P/F, 2%, 8)
= -\$37,899.95
-5%: PW(2%) = -\$55,000(0.95) + (\$7000 - \$4500)(P/A, 2%, 8) + \$1800(P/F, 2%, 8)
= -\$32,399.95
Breakeven percent change:
PW(2%) = 0 = -\$55,000(1 + X%) + (\$7000 - \$4500)(P/A, 2%, 8) + \$1800(P/F, 2%, 8)
X = -0.64
or X = -64% change in initial investment
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Sensitivity to changes in annual revenue:
+10%: PW(2%) = -\$55,000 + [\$(7000)(1.1)- \$4500](P/A, 2%, 8) + \$1800(P/F, 2%,
8)
= -\$30,022.10
-10%: PW(2%) = -\$55,000 + [\$(7000)(0.9)- \$4500](P/A, 2%, 8) + \$1800(P/F, 2%,
8)
= -\$40,277.80
Th
Breakeven percent change:
PW(2%) = 0 = -\$55,000 + [\$(7000)(1 + X%) - \$4500](P/A, 2%, 8) + \$1800(P/F, 2%, 8)
X = [35,149.95]/[51,278.50]
= 0.6855
Or X = 68.55% change in annual revenue
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7) The estimated cash flows of an investment project are shown below.
Item
Initial investment, \$
Net annual revenue, \$/year
Market value, \$
Project life, years
Optimistic
745,000
81,500
39,500
7
Most likely
750,000
80,000
38,000
7
7)
Pessimistic
755,000
79,500
37,000
7
Using a MARR of 14% per year, determine the AW for each of the three estimation
conditions.
AWm = -\$91,358.40
AWp = -\$93,117.60
Explanation: AW(optimistic) = -\$745,000(A/P, 14%, 7) + \$81,500 + \$39,500(A/F, 14%, 7)
= -\$745,000(0.2332) + \$81,500 + \$39,500(0.0932)
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= -\$88,552.60
AW(most likely) = -\$750,000(A/P, 14%, 7) + \$80,000 + \$38,000(A/F, 14%, 7)
= -\$750,000(0.2332) + \$80,000 + \$38,000(0.0932)
= -\$91,358.40
AW(pessimistic) = -\$755,000(A/P, 14%, 7) + \$79,500 + \$37,000(A/F, 14%, 7)
= -\$755,000(0.2332) + \$79,500 + \$37,000(0.0932)
= -\$93,117.60
8) A manufacturer of an inspecting and profiling web controller has a fixed cost of \$83,000
per year and variable costs of \$60 per unit produced. If the product is sold at \$90 per unit,
determine the breakeven quantity per year for the company.
Th
Explanation: Q = \$83,000/ (\$90 - \$60) = 2767 units
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8)
9) Wolfpack, Inc., a textile manufacturing company, is considering opening a production and
shipping facility to keep up with demand for its pillows. The facility is expected to require
an initial investment of \$190,000 and will have a \$36,000 salvage value after 5 years. Net
annual revenue is estimated to be \$100,000. Determine how sensitive the decision to invest
in the new facility is to the estimates of initial cost and net annual revenue. Use a MARR of
4% per year and a 5-year study period.
9)
Answer: If the change in initial cost is greater than 150%, the investment in the new facility
would no longer be acceptable.
If the change in net annual revenue is lower than -64.00%, the investment in the
new facility would no longer be acceptable.
Explanation: PW(4%) = -\$190,000 + \$100,000(P/A, 4%, 5) + \$36,000(P/F, 4%, 5)
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Let X = change in initial cost that would reverse decision
PW(4%) = 0 = -\$190,000(1+ X%) + \$100,000(P/A, 4%, 5) + \$36,000(P/F, 4%, 5)
X = 1.50
If the change in initial cost is greater than 150%, the investment in the new
facility would no longer be acceptable.
Let Y = change in net annual revenue that would reverse decision
PW(4%) = 0 = -\$190,000 + \$100,000(1 + Y%)(P/A, 4%, 5) + \$36,000(P/F, 4%, 5)
Y = -0.64
If the change in net annual revenue drops by -64.00%, the investment in the
new facility would no longer be acceptable.
10) Two different machines are under consideration for a reengineering project. Machine X is
expected to have an initial cost of \$74,000 and an expected life of 7 years. It will have a
fixed cost of \$10,000 per year and a variable cost of \$60 per unit per year. Process Y is
expected to have a useful life of 9 years. It will have a fixed cost of \$8500 per year and a
variable cost of \$57 per unit per year. Determine the amount the company can spend on
Machine Y so the two machines will break even at an interest rate of 11% per year.
Assume the current process capacity of 150 units per year is used for the analysis.
Answer: Initial cost of machine Y = \$97,745.29
Explanation: Let P = initial cost of machine Y
AWX = -\$74,000(A/P, 11%, 7) - \$10,000 - \$(60)(150)
= -\$74,000(0.2122) - \$10,000 - \$9000
= -\$34,702.80
Th
AWY = -\$P(A/P, 11%, 9) - \$8500 - \$(57)(150)
= -\$P(0.1806) - \$17,050
Set AWX = AWY:
P = [-\$34,702.80 + \$17,050]/ (-0.1806)
= \$97,745.29
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10)
Testname: C11
1) Uniform amount of increase per year = 687,934 units
2) PWA(13%) = \$600,000
PWB(13%) = \$460,753.20
PWC(13%) = \$479,489.40
PWD(13%) = \$499,393.80
PWA(13%) &gt; PWD(13%) &gt; PWC(13%) &gt; PWB(13%); therefore, Ginger should select option A.
3) 12.49 days per year
4) 1094 units per year
5) PW30(3%) = -\$20,994,942.00
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PW40(3%) = -\$27,848,272.00
PW50(3%) = -\$34,701,602.00
6) Sensitivity to changes in initial investment:
+5%: PW(2%) = -\$37,899.95
-5%: PW(2%) = -\$32,399.95
Breakeven percent change = -64%
Sensitivity to changes in annual revenue:
+10%: PW(2%) = -\$30,022.10
-10%: PW(2%) = -\$40,277.80
Breakeven percent change = 68.55%
7) AWo = -\$88,552.60
AWm = -\$91,358.40
AWp = -\$93,117.60
8) Q = 2767 units
9) If the change in initial cost is greater than 150%, the investment in the new facility would no longer be acceptable.
Th
If the change in net annual revenue is lower than -64.00%, the investment in the new facility would no longer be
acceptable.
10) Initial cost of machine Y = \$97,745.29
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