I can divide fractions by whole numbers
Workings out
1.
a.
2
3
b.
3
5
c.
2.
a.
a.
1
5
3
1
1
3
5
1
÷3=6×
𝟑
𝟏𝟎
3
10
𝟒
𝟏𝟓
4
15
=
3
=
1
=
3
𝟐
𝟏𝟓
2
15
𝟑
𝟖
8
𝟏
𝟔
6
𝟓
𝟏𝟖
5
18
= 3 ÷ 4 = 0.75
4
5
8
4
5
6
c.
9
÷6 =
6
6
0
5
2
0
2
5
0
4
0.625
0.3
0.4
1
3
4
5
0.8
0
0.25
= 0.4;
10 =
0.75
0
0.5
9
=
2
×
10
= 0.333;
1
÷2=5×
10
8
4
= 5 ÷ 8 = 0.625
÷
0
0
0
5
5
b.
3
8
2
5
5
2
4
5.
4
7
3
5
1
4
1
2
2
5
3
10
a.
0
= 4 ÷ 5 = 0.8
4.
6.
2
÷3=2×
5
c.
=
3
÷2=4×
3
=
2
4
4
b.
1
3
6
3.
3
1
1
=
5
÷3=5×
5
2
c.
1
÷2=5×
4
4
b.
2
÷5=3×
Answers
1
10
×
1
6
4
10
=
3
8
5
5
= 60 =
Smallest:
0.28
0.3
1
3
3
8
2
5
𝟐
𝟓
2
= 60 =
9
= 0.375… =
1
12
3
20
𝟏
𝟏𝟐
𝟑
𝟐𝟎
Largest
7.
a.
7
= 7 ÷ 8 = 0.875
8
b.
1
= 1 ÷ 6 = 0.166…
6
c.
1
1 4 = 1 + 1 ÷ 4 = 1.25
8.
1
6
of 5 =
5
6
= 0.833…
8
6
4
6
0
8
7
5
7
7
6
4
0
1
6
6
1
1
4
4
0
2
5
1
1
2
0
8
3
3
5
5
2
2
0
0
0
0
0
0
0
0
0.1666...
1.25
0
0
0.875
0
0.833…rounds to 0.83
= 83p . Yes.
Challenge
3
4
3
÷6=4×
1
6
=
3
24
=
1
8
= 0.125; 0.125m = 0.125 ×100 cm = 12.5 cm
Challenge 2
So... Andy walks away with 14 marbles, 2/3 of what was recovered.
His friend walks away with 1/3 of what was recovered. 14 is 2/3 so to
find out 1/3 I then half 14, getting 7. Sam had 7 and Andy had 14. A
total rescued of 14 + 7 = 21
21 is half (1/2) of what was lying around on the ground, the other half
having been taken by the children. To find how many were on the
ground nearby I have to double 21. I now have an answer of 42.
42 must be doubled to get the final answer, as 1/3 and 1/6 went down
drains or hills (1/3 + 1/6 = 1/6 + 2/6 =1/2).
This gives me a final answer of 84 marbles in the bag.
To find out what fraction of the marbles Andy had given away or lost
you have to find the fraction of marbles he was left with. He was left
with 14 out of 84 marbles (14/84). You then work out the fraction in
its lowest form. Firstly divide 14 and 84 by 2 to get 7/42 then divide
them by 7 to get an answer of 1/6. However 1/6 is what he is left with
so he must have lost or given away 5/6 of his marbles!