Manual of Physical chemistry/ 2nd stage/2015-2016
Exp. 4
Study the adsorption reaction between acetic acid and
Charcoal.
Theory:
Manual of Physical chemistry/ 2nd stage/2015-2016
1- Prepare 0.5M of acetic acid in 100ml of volumetric flask .
2- Transfer (5,10, 15, 20, 25) ml from acetic acid and complete the
volume to 50ml by D.W .
3- Take 5 conical flask and add each one 1 g from charcoal, and then
add solutions of acetic acid prepared in the previous step.
4- Shake the solutions at 30 min .
5- Filter the solutions (remove the 5 first drops) .
6- Take 10ml of each solution and add 2-3 drops of ph.ph indicator ,
and titrate with 0.2 NaOH.
Manual of Physical chemistry/ 2nd stage/2015-2016
1- Find the concentration of acetic acid solutions before adsorption (N1)
(𝑁 × 𝑉)𝐶𝑜𝑛𝑐 = (𝑁 × 𝑉)𝑑𝑖𝑙
(0.5 × 5) =( ? × 50)
10
15
20
25
2-
Find the concentration of acetic acid solutions after adsorption (N 2)
(𝑁 × 𝑉)𝑏𝑎𝑠𝑒
=
(𝑁 × 𝑉)𝑎𝑐𝑖𝑑
(0.2× The volume down from burette ) =( ? × 10)
3- Find the value
𝑎=
𝑋
𝑚
𝑋 𝑁1 − 𝑁2 𝑒𝑞. 𝑤𝑡(𝐶𝐻3 𝐶𝑂𝑂𝐻)
=
.
× 𝑊𝑡 𝑜𝑓 𝑎𝑏𝑠𝑜𝑟𝑏𝑒𝑛𝑡
𝑚
1000
𝑒𝑞. 𝑁𝑂
=
𝑁1 −𝑁2
1000
.
60.05𝑔𝑚⁄𝑚𝑜𝑙
𝑒𝑞 .𝑁𝑂=1
× 1𝑔𝑚
Manual of Physical chemistry/ 2nd stage/2015-2016
3-Calculate the n and k by plotting freundlich equation
Log(x/m)
1
𝑆𝑙𝑜𝑝𝑒 = 𝑛
Logk
LogN2
Questions for discussion:
1234-
Explain, what is the type of adsorption for this experiment?
Calculated the degree of freedom for this system?
What the difference between physical and chemical adsorption?
How can you to increase the efficiency of adsorption?