Uploaded by T V Ananthakrishnan

Logarithms - Problems for challenge

advertisement
1.
2.
3. If 'x' and 'y' are real numbers such that, 2 log(2y – 3x) = log x + log y, find x/y .
4. Find the value of x satisfying log10 (2x + x – 41) = x (1 – log105).
5.
Positive numbers x, y and z satisfy xyz = 1081 and (log10x)(log10yz) + (log10y)(log10z) = 468. Find the
value of log10 x 2 log10 y2 log10 z 2
7.
8.
Download