16005030

advertisement
N Acetylation: The Acetylation of Aniline
Introduction
In an earlier experiment, we saw that the oxygen atom in an alcohol or
phenol could be acetylated with acetic anhydride or acetyl chloride. These are
examples of acylation reactions that produce acetate esters. If we substitute
nitrogen plus an H (to account for the trivalent N), for oxygen in an alcohol we get
an amine. For example, ethanol would become ethylamine. Likewise, the
substitution of NH for O in phenol makes aniline, a primary aromatic amine.
Figure 1 shows the structural relationships among these compounds. In these
structures, nitrogen requires two hydrogen atoms to satisfy its trivalence.
CH3CH2OH
CH3CH2NH2
ethanol
ethyl alcohol
OH
phenol
ethanamine
ethylamine
NH2
aniline
Figure 1. Alcohols and amines.
Though the compounds in Figure 1 differ in some properties (e.g., ethanol is
a neutral compound, phenol is a weak acid, and ethylamine and aniline are weak
bases), they can all serve as nucleophiles because of the pair of non-bonding
electrons on the heteroatom. Thus, all of these compounds react similarly with
acetic anhydride or acetyl chloride. As we have seen before, acetic anhydride is
formed by heating (i.e., pyrolysis) of acetic acid. Two molecules of acetic acid lose
one molecule of water to form one molecule of the anhydride. When two
molecules join by the loss of a small molecule such as water, the reaction is called
a condensation reaction. Acetic anhydride is formed by a condensation reaction
between two acetic acid molecules as shown in Figure 2.
Lab 10
1
O
2 CH3COH

O O
CH3COCCH3 + H2O
acetic anhydride
acetic acid
Figure 2. Preparation of acetic anhydride.
Mechanism of Acetylation of Aniline
Figure 3 shows the mechanism of N acylation, using acetic anhydride as the
acylating agent and aniline as the substrate.
O O
CH3COCCH3
NH2
+
O- O
CH3C O CCH3
NH2
acetic anhydride
aniline
transfer
of H+
OH
O
CH3C O CCH3
NH
di-ion
O H
CH3C
NH
O
-O CCH3
+
O
N CCH3
H
acetanilide
acetate
+
O
HOCCH3
acetic acid
Figure 3. Mechanism of N acylation.
The product of an acetylation of an amine is an acetamide, which is an
analog of an acetate ester. When the amine is aniline, the acetamide is called
Lab 10
2
acetanilide. Thus, amides contain a nitrogen atom next to a carbonyl group.
Compounds that contain a heteroatom next to a carbonyl group are acids or acid
derivatives. Amides are acid derivatives. Acid derivatives are composed of an acid
part and a second part, which depends on the heteroatom and overall structure. For
example, esters are a combination of an acid and an alcohol, and amides are a
combination of an acid and an amine. Both esters and amides are acid derivatives
because they both contain an acid part. The acidic hydrolysis of acid derivatives
produce the acid and the other part. Basic hydrolysis produces the acid salt and the
other part. The salt must be acidified to produce the acid. Thus, amides, esters, acyl
halides, and anhydrides are all acid derivatives because hydrolysis of them yields
an acid.
Figure 4 shows the acid hydrolysis of four derivatives of acetic acid, acetamide,
ethyl acetate, acetyl chloride and acetic anhydride. Acetic acid is a product in each
case, because acetic acid is the acid part of each starting compound. The second
part depends on the starting material. For example, acetamide yields ammonia,
ethyl acetate yields ethanol, acetyl chloride yields hydrogen chloride, and acetic
anhydride yields acetic acid.
Lab 10
3
O
CH3CNH2
O
HOH
H+
acetamide
an amide
O
CH3COCH2CH3
O
HOH
ethyl acetate
an ester
CH3CCl
acetic anhydride
CH3COH + HOCH2CH3
ethanol
an alcohol
acetic acid
O
HOH
H+
acetyl chloride
an acyl chloride
or acid chloride
O O
CH3COCCH3
ammonia
acetic acid
H+
O
CH3COH + NH3
CH3COH
acetic acid
O
HOH
H+
CH3COH
acetic acid
+
HCl
hydrochloric acid
O
+ CH COH
3
acetic acid
Figure 4. Hydrolysis of acid derivatives.
Lab 10
4
Procedure
1. Tare a 25-mL Erlenmeyer flask on a microanalytic balance.
2. Carefully transfer 0.46-g aniline to the Erlenmeyer flask.
3. Take the Erlenmeyer flask to your bench; add 10 drops of concentrated
hydrochloric acid, HCl, to the flask.
4. Add 10-mL distilled water to the Erlenmeyer flask and mix the contents.
5. Prepare a solution of sodium acetate (NaOAc) by dissolving 0.5-g anhydrous
sodium acetate in 3-mL distilled water in a small beaker.
6. Add, in quick succession, 15 drops of acetic anhydride and the solution from
Step 5 to the 25-mL Erlenmeyer flask.
7. Swirl the Erlenmeyer flask to mix the contents and place it in an ice-water bath.
8. Acetanilide will crystallize from the solution. When the crystallization is
complete, filter the crystals on a Büchner funnel.
9. Weigh the dry crystals and then show them to the instructor.
10. Clean and return all glassware to the storages areas. Check the balance area.
Return any chemicals to their original locations and turn off all balances.
Lab 10
5
Questions N Acetylation
Stu No___ Sec___ Last name____________________________, First _____________________
1. Draw structures of isopropylamine, acetamide, sec-butyl alcohol, and methyl
acetate.
________________ _________________ ______________ _____________
isopropylamine
acetamide
sec-butyl alcohol methyl acetate
Write complete chemical equations for the reactions indicated below.
2. The pyrolysis (strong heating) of acetic acid.
3. The preparation of propanoyl chloride, starting with propanoic acid.
4. 2-Nitrophenol plus acetic anhydride at room temperature.
5. Phenol plus acetyl chloride, heated in the presence of aluminum chloride.
6. Aniline plus acetic anhydride at room temperature.
7. Ethanol plus propanoyl chloride at room temperature.
Lab 10
6
8. Acetic anhydride plus water in an acidic medium.
9. Aniline plus acetyl chloride, when heated in the presence of aluminum chloride.
10. What family is produced by the reaction indicated in problem 6?
__A. amine
__B. amide
__C. lactam
__D. imide
Lab 10
7
Download