Section 12.1 - Double Integrals over rectangles We want to find the volume of the space bounded by the graph of fx, y ≥ 0 and the xy-plane over the rectangular region R a, b c, d x, y | a ≤ x ≤ b, c ≤ y ≤ d We first subdivide R into subrectangles by dividing the interval a, b into m subintervals x i−1 , x i of equal width Δx b−a m and dividing the interval c, d into n subintervals y j−1 , y j of equal width d−c Δy n . This creates mn subrectangles of area ΔA ΔxΔy. For an arbitrary subrectangle R ij x i−1 , x i y j−1 , y j x, y | x i−1 ≤ x ≤ x i , y j−1 ≤ y ≤ y j we choose a sample point x ∗ij , y ∗ij . Then we can approximate the volume of space below f over the region R ij by the rectangular box (or "column") with base R ij and height fx ∗ij , y ∗ij . The volume of such a box is ΔV ij fx ∗ij , y ∗ij ΔA If we follow this procedure for all the subrectangles and add the corresponding volumes, we get an estimate for the desired volume m V≈ n m n ∑ ∑ ΔV ij ∑ ∑ fx ∗ij , y ∗ij ΔA i1 j1 i1 j1 If we take the limit as m, n → we get the desired volume m V m,n→ lim n ∑ ∑ fx ∗ij , y ∗ij ΔA i1 j1 The double integral of fx, y over the rectangular area R is m n lim ∑ ∑ fx ∗ij , y ∗ij ΔA R fx, y dA m,n→ i1 j1 It can be shown that the limits above exist if f is continuos on R (they also exists for some functions that are not continuous on R). If fx, y ≥ 0 on R, then the double integral represents the volume of the space bounded by the graph of f and the xy-plane over R. For estimating we can choose the sample points x ∗ij , y ∗ij to be any point in the subrectangle R ij . Common choices are the upper right corner, lower right corner, upper left corner, lower left corner, or midpoint of rectangle R ij . If we choose the upper right corner then we have x ∗ij , y ∗ij x i , y j . Examples: 1. Estimate the volume of the surface that lies below the graph of fx, y x 2 y 2 2 over the rectangular region x, y | 0 ≤ x ≤ 4, 0 ≤ y ≤ 2 with m 4 and n 2. Do it using the upper right corner of each subrectangle for the sample point. 1 2. Estimate the value of fx, y dA if the contour plot of f is as shown below and R R −3, 3 −4, 4. Use Midpoints of the subrectangles with m n 2. 5 4 3 2 1 -5 -4 -3 -2 1 -1 -1 1 2 2 3 3 -2 4 5 4 5 -3 -4 6 -5 3. Find the exact value of |x − 2| dA if R x, y | 0 ≤ x ≤ 2, 0 ≤ y ≤ 3 R Homework: Page 847 #’s 3, 9 (for part (b) see page 844 for a discussion of average value), 11, 12, 13 More practice. Turn the below problems in for a grade. Due by Thursday March 23. Show all work on separate paper. Worth 6 points. 1. Estimate the value of fx, y dA in each case: R a. fx, y x 2y 3, R x, y | 0 ≤ x ≤ 3, −1 ≤ y ≤ 1, with m 3 & n 4 using the upper right corners of subrectangles for sample points. b. fx, y x 2y 3, R x, y | 0 ≤ x ≤ 3, −1 ≤ y ≤ 1, with m 3 & n 4 using the lower left corners of subrectangles for sample points. c. fx, y x 2y 3, R x, y | 0 ≤ x ≤ 3, −1 ≤ y ≤ 1, with m 3 & n 2 using the midpoints of subrectangles for sample points. 2. Find the exact value of the double integral by identifying it as the volume of a solid: a. b. c. R 4 − y 2 dA if R x, y | 0 ≤ x ≤ 2, − 2 ≤ y ≤ 2 R 4 − y 2 dA if R x, y | 0 ≤ x ≤ 2, 0 ≤ y ≤ 2 R −|x| 2 dA if R x, y | − 2 ≤ x ≤ 2, 0 ≤ y ≤ 3 2