Classical solutions and steady states of an attraction-repulsion chemotaxis in one dimension Jia Liu Department of Mathematics and Statistics University of West Florida Pensacola, FL 32514 jliu@uwf.edu Zhi-An Wang∗ Department of Applied Mathematics Hong Kong Polytechnic University Hung Hom, Kowloon, Hong Kong mawza@polyu.edu.hk Abstract: We establish the existence of global classical solutions and non-trivial steady states of an one-dimensional attraction-repulsion chemotaxis model subject to Neumann boundary conditions. The results are derived based on the method of energy estimates and the phase plane analysis. Key words: Chemotaxis, attraction-repulsion, classical solutions, steady states AMS subject classiο¬cation: 35K20, 35K40, 35K45, 92C17 1 Introduction Chemotaxis describes the directed migration of cells along the concentration gradient of the chemical which is produced by cells. It is a leading mechanism to account for the morphogenesis and self-organization of many biological system. The prototype of the population-based chemotaxis model, known as the Keller-Segel model, was ο¬rst proposed by Keller and Segel in the 1970s [5] to describe the aggregation of cellular slime molds Dictyostelium discoideum. The rudimental structure of the Keller-Segel model is a system of parabolic partial diο¬erential equations as follows π’π‘ = π·π’ Δπ’ − ∇(ππ’∇π£), π£π‘ = π·π£ Δπ£ + π (π’, π£), (1.1) where π’(π₯, π‘) denotes the cell density and π£(π₯, π‘) is the chemical concentration, π·π’ and π·π£ are positive diο¬usion coeο¬cients and π > 0 is called the chemotactic coeο¬cient measuring the strength of inο¬uence of the chemical on cells. The Keller-Segel model (1.1) describes the cell chemotactic movement toward a single chemical (i.e. chemoattractant) and has ∗ Corresponding author. Supported by the start-up funding from the Hong Kong Polytechnic University. 1 Classical Solutions and Steady States of an Attraction-repulsion Chemotaxis Model 2 been extensively studied in the past four decades from various perspectives ([8, 14, 15]). However in many biological processes, the cells may interact with a combination of repulsive and attractive signalling chemicals to produce various interesting biological patterns, such as the formation of nigrostriatal circuits during development [7], the chick primitive streak formation [3], and many others (e.g., see [4]). In this paper, we shall consider the following attraction-repulsion chemotaxis model π’π‘ = π·π’ Δπ’ − ∇(ππ£ π’∇π£) + ∇(ππ€ π’∇π€), π£π‘ = π·π£ Δπ£ + πΌπ’ − π½π£, (1.2) π€π‘ = π·π€ Δπ€ + πΎπ’ − πΏπ€, where π·π’ , π·π£ , π·π€ > 0 are diο¬usion coeο¬cients, ππ£ > 0, ππ€ > 0 are chemotactic coeο¬cients, πΌ, πΎ > 0 and π½, πΏ ≥ 0. The model (1.2) was proposed in [10] to describe the aggregation of microglia observed in Alzheimer’s disease and in [12] to describe the quorum eο¬ect in the chemotactic process. In their approaches, it is assumed that there exists a secondary chemical, denoted by π€, which behaves as a chemo-repellent to mediate the chemotactic response to the chemoattractant π£ accordingly. To the best of our knowledge, there is rigorous result by now on the chemotaxis model with two opposite chemicals (i.e. chemo-attractant and chemo-repellent). The purpose of this paper is to establish the global existence of classical solutions and steady states of (1.2) in one dimension with Neumann boundary conditions. The results for higher dimensions still remains open. In one dimension, the system (1.2) reads π’π‘ = π·π’ π’π₯π₯ − (ππ£ π’π£π₯ )π₯ + (ππ€ π’π€π₯ )π₯ , π£π‘ = π·π£ π£π₯π₯ + πΌπ’ − π½π£, (1.3) π€π‘ = π·π€ π€π₯π₯ + πΎπ’ − πΏπ€. With the following scalings ππ£ ππ€ ππ£ πΎππ€ ˜ πΏ) ˜ = 1 (π·π£ , π·π€ , π½, πΏ), ˜ π£, π· ˜ π€ , π½, π‘˜ = π·π’ π‘, π£˜ = π£, π€ ˜= π€, π’ ˜ = 2 π’, πΎ˜ = , (π· π·π’ π·π’ π·π’ πΌππ£ π·π’ system (1.3) can be reduced to the following system π’π‘ = π’π₯π₯ − (π’π£π₯ )π₯ + (π’π€π₯ )π₯ , π£π‘ = π·π£ π£π₯π₯ + π’ − π½π£, (1.4) π€π‘ = π·π€ π€π₯π₯ + πΎπ’ − πΏπ€, where the tilde superscripts have been suppressed for readability. Letting Ω be a bounded open interval in β = (−∞, ∞), we prescribe the initial conditions π’(π₯, 0) = π’0 (π₯), π£(π₯, 0) = π£0 (π₯), π€(π₯, 0) = π€0 (π₯), (1.5) and Neumann boundary conditions ∂π’ ∂π£ ∂π€ = = = 0, π₯ ∈ ∂Ω, (1.6) ∂π ∂π ∂π where π denotes the unit outward normal vector to the boundary ∂Ω. In the present paper, we shall prove the existence of global classical solutions to the model (1.4), (1.5) and (1.6) based on Amann’s theory and the method of energy estimates. We also show the existence of non-trivial steady states of (1.4) subject to the Neumann boundary conditions (1.6) for the case π½π·π€ = πΏπ·π£ by the phase plane analysis. Classical Solutions and Steady States of an Attraction-repulsion Chemotaxis Model 3 Notations. Throughout the paper, Ω denotes a bounded open interval in β unless otherwise speciο¬ed and πΆ denotes a generic constant which can change from one line to another. πΏπ = πΏπ (Ω)(1 ≤ π ≤ ∞) denotes the usual Lebesgue space in a bounded open (∫ )1/π π ππ₯ interval Ω ⊂ β = (−∞, ∞) with norm β₯π β₯πΏπ = β£π (π₯)β£ for 1 ≤ π < ∞ and Ω β₯π β₯πΏ∞ = ess sup β£π (π₯)β£. When π = 2, we write β₯π β₯πΏ2 = β₯π β₯ for notational convenience. π» π π₯∈Ω (∑ )1/2 π π π β₯2 denotes the π-th order Sobolev space π π,2 with norm β₯π β₯π» π = β₯π β₯π = β₯∂ . π₯ π=0 For simplicity, β₯π (⋅, π‘)β₯πΏπ and β₯π (⋅, π‘)β₯π will be denoted by β₯π (π‘)β₯πΏπ and β₯π (π‘)β₯π , respectively. Moreover, we denote β₯(π, π)β₯πΏπ = β₯π β₯πΏπ + β₯πβ₯πΏπ for 1 ≤ π ≤ ∞ and β₯(π, π)β₯π» π = β₯π β₯π» π + β₯πβ₯π» π for π = 1, 2, 3, ⋅ ⋅ ⋅ . 2 Preliminaries In this section, we present some inequalities which will be used to derive the required estimates. First we recall the Gagliardo-Nirenberg inequality for functions that do not vanish at the boundary of Ω (see Theorem 1 in [11]). Lemma 2.1. Let Ω be a open bounded domain in βπ with smooth boundary. Then for any π ≥ 1, there exists a positive constant πΆπ , which depends on π, π, Ω, such that for all π ∈ π 1,2 (Ω), β₯π β₯πΏπ ≤ πΆπ (β₯∇π β₯π2 β₯π β₯1−π + β₯π β₯πΏ1 ) (2.1) πΏ1 where π = (1 − 1π )/( π1 + 21 ) and 0 ≤ π < 1. Letting π = 1, π = 4, πΌ = 1/2 in (2.1) and using the inequality (π + π)2 ≤ 2(π2 + π2 ) for any π, π ∈ β, we obtain the following inequality β₯π β₯2πΏ4 ≤ πΆ(β₯ππ₯ β₯β₯π β₯πΏ1 + β₯π β₯2πΏ1 ). (2.2) The following Gronwall’s type inequality [16] will be used later. Proposition 2.2. Let π(⋅) be a nonnegative diο¬erentiable function on [0, ∞) satisfying the diο¬erential inequality π ′ (π‘) + ππ(π‘) ≤ π(π‘), where π is a constant and π(π‘) is a nonnegative continuous functions on [0, ∞). Then ( ) ∫ π‘ ππ π(π‘) ≤ π(0) + π π(π )ππ π−ππ‘ . (2.3) 0 Alternatively, if for π‘ ≥ 0, π(π‘) ∫ π‘ ≥ 0 and π(π‘) ≥ 0 are continuous function such that the inequality π(π‘) ≤ πΆ exp(ππ‘) + πΏ 0 π(π )π(π )ππ holds on π‘ ≥ 0 with πΆ and πΏ positive constants, then ( ∫ ) π(π‘) ≤ πΆ exp(ππ‘) exp πΏ 3 π‘ 0 π(π )ππ . (2.4) Global existence of classical solutions In this section, we shall establish the global existence of classical solutions of the system (1.4), (1.5) and (1.6). The main result is the following: Classical Solutions and Steady States of an Attraction-repulsion Chemotaxis Model 4 Theorem 3.1. Let (π’0 , π£0 , π€0 ) ∈ π» 2 (Ω). Then there exists a unique global solution (π’, π£, π€) to the system (1.4), (1.5) and (1.6) such that (π’, π£, π€) ∈ [πΆ 0 (Ω × [0, ∞); β3 )]3 ∩ [πΆ 2,1 (Ω × (0, ∞); β3 )]3 . Moreover π’, π£, π€ ≥ 0 if π’0 , π£0 , π€0 ≥ 0. Remark 3.1. Theorem 3.1 does not exclude the possibility that the solution may blow up at inο¬nity time. Theorem 3.1 will be proved by the local existence and the a priori estimates as given below. 3.1 Local existence In this section, we shall apply Amann’s theory [1] to establish the local existence of solutions. Theorem 3.2. (local existence). Let Ω be a bounded open interval in β. Then (i) For any initial data (π’0 , π£0 , π€0 ) ∈ [π» 1 (Ω)]3 , there exists a maximal existence time constant π0 ∈ (0, ∞] depending on the initial data (π’0 , π£0 , π€0 ), such that the problem (1.4), (1.5) and (1.6) has a unique maximal solution (π’, π£, π€) deο¬ned on Ω × [0, π0 ) satisfying (π’, π£, π€) ∈ [πΆ 0 (Ω × [0, π0 ); β3 )]3 ∩ [πΆ 2,1 (Ω × (0, π0 ); β3 )]3 . (ii) If sup 0<π‘<π0 ∩π β₯(π’, π£, π€)(⋅, π‘)β₯πΏ∞ < ∞ for each π > 0, then π0 = ∞, namely, (π’, π£, π€) is a global classical solution of the system (1.4), (1.5) and (1.6). Moreover π’ ≥ 0, π£ ≥ 0, π€ ≥ 0 if π’0 ≥ 0, π£0 ≥ 0, π€0 ≥ 0. Proof. Deο¬ne π = (π’, π£, π€) ∈ β3 . Then the system (1.4) with (1.5) and (1.6) can be rewritten as ππ‘ − ∇ ⋅ (π(π)∇π) = β±(π), in Ω × [0, +∞), ∂π (3.1) = 0, on ∂Ω × [0, +∞), ∂π π(⋅, 0) = (π’0 , π£0 , π€0 ), in Ω, where β β β β 1 −π’ π’ 0 π(π) = β 0 π·π£ 0 β , β±(π) = β π’ − π½π£ β . 0 0 π·π€ πΎπ’ − πΏπ€ It is clear that the eigenvalues of π(π) are all positive and hence system (1.4) is normally elliptic. Then the local existence result of assertion (π) follows from [1, Theorem 14.6], and (ππ) is a consequence of [1, Theorem 15.3]. Finally the positivity of solutions follows from [1, Theorem 15.1]. 3.2 A priori estimates In this section, we are devoted to deriving the a priori estimates of solutions obtained in Theorem 3.1 to establish the global existence of solutions. First of all, we notice that the ο¬rst equation of (1.4) is a conservation equation. If we denote ∫ π’0 (π₯)ππ₯ =: π (3.1) Ω Classical Solutions and Steady States of an Attraction-repulsion Chemotaxis Model 5 then by integrating the ο¬rst equation of (1.4) and using the Neumann boundary conditions (1.6), we have ∫ β₯π’(π‘)β₯πΏ1 = π’(π₯, π‘)ππ₯ = π. (3.2) Ω Lemma 3.3. Let (π£0 , π€0 ) ∈ [πΏ2 (Ω)]2 and (1.6) hold. Let (π’, π£, π€) be a solution of the problem (1.4)-(1.6). Then for any π > 0, there is a constant πΆ such that the following inequality holds for any 0 < π‘ < π ∫ π‘ ∫ π‘ (3.3) β₯(π£, π€)(π‘)β₯2 ≤ πΆ, β₯(π£, π€)(π )β₯2 ππ + β₯(π£π₯ , π€π₯ )(π )β₯2 ππ ≤ πΆ(1 + π‘). 0 0 Proof. Multiplying the second equation of (1.4) by π£ and integrating the resulting equation with respect to π₯ over Ω gives rise to ∫ ∫ ∫ ∫ 1 π 2 2 2 π£π₯ ππ₯ = π’π£ππ₯ ≤ πβ₯π£β₯πΏ∞ . π£ ππ₯ + π½ π£ ππ₯ + π·π£ 2 ππ‘ Ω Ω Ω Ω Applying the Sobolev embedding π» 1 ,→ πΏ∞ , one has that ∫ ∫ ∫ 1π π½ π·π£ 2 2 β₯π£π₯ β₯2 + β₯π£β₯2 + πΆ, π£ ππ₯ + π½ π£ ππ₯ + π·π£ π£π₯2 ππ₯ ≤ πΆπ(β₯π£β₯ + β₯π£π₯ β₯) ≤ 2 ππ‘ Ω 2 2 Ω Ω where the Young inequality has been used. Then it follows that π β₯π£β₯2 + π½β₯π£β₯2 + π·π£ β₯π£π₯ β₯2 ≤ πΆ. ππ‘ (3.4) Applying Gronwall’s inequality (2.3) to (3.4) yields that ( ) ∫ π‘ 2 π½π 2 β₯π£β₯ ≤ β₯π£0 β₯ + πΆ π ππ π−π½π‘ 0 ≤ (β₯π£0 β₯2 − πΆ/π½)π−π½π‘ + πΆ/π½ ≤ πΆ. Furthermore the integration of (3.4) with respect to π‘ over [0, π‘] gives ∫ π‘ 0 2 β₯π£(π )β₯ ππ + ∫ 0 π‘ β₯π£π₯ (π )β₯2 ππ ≤ πΆ(1 + π‘). (3.5) Applying the same procedure to π€, we ο¬nish the proof. Lemma 3.4. Let π’0 ∈ πΏ2 (Ω), (π£0 , π€0 ) ∈ [π» 1 (Ω)]2 and (π’, π£, π€) be a solution of the problem (1.4)-(1.6). Then for any π > 0, there is a positive constant πΆ such that for any 0 < π‘ < π it follows that ∫ π‘ ∫ π‘ ( ) β₯π’(π‘)β₯2 + β₯π’π₯ (π )β₯2 ππ + β₯(π£, π€)(π‘)β₯21 + β₯(π£, π€)(π )β₯22 ππ ≤ πΆ 1 + ππΆπ‘ . (3.6) 0 0 Classical Solutions and Steady States of an Attraction-repulsion Chemotaxis Model 6 Proof. We multiply the ο¬rst equation of (1.4) by π’ and integrate the resulting equation by parts. Then by (2.2), the HoΜlder inequality and the Young inequality, we derive that ∫ ∫ ∫ ∫ 1π 1 1 π’2 ππ₯ + π’2π₯ ππ₯ = − π’2 π£π₯π₯ ππ₯ + π’2 π€π₯π₯ ππ₯ 2 ππ‘ Ω 2 2 Ω Ω Ω 1 ≤ β₯π’β₯2πΏ4 (β₯π£π₯π₯ β₯ + β₯π€π₯π₯ β₯) 2 ≤ πΆ(πβ₯π’π₯ β₯ + π2 )(β₯π£π₯π₯ β₯ + β₯π€π₯π₯ β₯) 1 ≤ β₯π’π₯ β₯2 + πΆ(β₯π£π₯π₯ β₯ + β₯π€π₯π₯ β₯ + β₯π£π₯π₯ β₯2 + β₯π€π₯π₯ β₯2 ), 2 where the Young inequality has been used. Using the Cauchy-Schwarz inequality to derive πΆ(β₯π£π₯π₯ β₯ + β₯π€π₯π₯ β₯) ≤ 2πΆ 2 + β₯π£π₯π₯ β₯2 + β₯π€π₯π₯ β₯2 , we have ∫ ∫ π π’2 ππ₯ + π’2π₯ ππ₯ ≤ πΆ(1 + β₯π£π₯π₯ β₯2 + β₯π€π₯π₯ β₯2 ). (3.7) ππ‘ Ω Ω Next we estimate the right hand side of (3.7). To this end, we multiply the second equation of (1.4) by −π£π₯π₯ and integrate the resulting equation to obtain that ∫ ∫ ∫ ∫ π 2 2 2 π£ ππ₯ + π£π₯ ππ₯ + π£π₯π₯ ππ₯ ≤ πΆ π’2 ππ₯. (3.8) ππ‘ Ω π₯ Ω Ω Ω Similar procedure applied to the third equation of (1.4) leads to ∫ ∫ ∫ ∫ π 2 2 2 π€ ππ₯ + π€π₯ ππ₯ + π€π₯π₯ ππ₯ ≤ πΆ π’2 ππ₯. ππ‘ Ω π₯ Ω Ω Ω Combining (3.8) and (3.9) we have ∫ ∫ ∫ ∫ π 2 2 (π£π₯2 + π€π₯2 )ππ₯ + (π£π₯2 + π€π₯2 )ππ₯ + (π£π₯π₯ + π€π₯π₯ )ππ₯ ≤ πΆ π’2 ππ₯. ππ‘ Ω Ω Ω Ω (3.9) (3.10) Then integrating (3.10) with respect to π‘ yields that 2 ∫ β₯(π£π₯ , π€π₯ )β₯ + 0 π‘ 2 ∫ π‘ β₯(π£π₯ , π€π₯ )(π )β₯ ππ + β₯(π£π₯π₯ , π€π₯π₯ )(π )β₯2 ππ 0 ( ) ∫ π‘ ≤πΆ 1+ β₯π’(π )β₯2 ππ . (3.11) 0 Now we integrate (3.7) with respect to π‘ and obtain that 2 β₯π’(π‘)β₯ + ∫ 0 π‘ 2 β₯π’π₯ (π )β₯ ππ ≤ πΆ(1 + π‘) + πΆ ∫ π‘ 0 β₯(π£π₯π₯ , π€π₯π₯ (π )β₯2 ππ. (3.12) By using the Gronwall’s inequality (2.4) to (3.12), one has that β₯π’(π‘)β₯2 ≤ πΆ(1 + π‘)ππΆπ‘ . (3.13) Classical Solutions and Steady States of an Attraction-repulsion Chemotaxis Model Therefore substituting (3.13) back to (3.11) gives ∫ π‘ ∫ π‘ 2 2 β₯(π£π₯ , π€π₯ )β₯ + β₯(π£π₯ , π€π₯ )(π )β₯ ππ + β₯(π£π₯π₯ , π€π₯π₯ )(π )β₯2 ππ 0 πΆπ‘ ≤ πΆ(1 + π‘)π 0 πΆπ‘ 7 (3.14) ≤ πΆπ where we have used the fact that 0 < π‘ ≤ ππΆπ‘ for πΆ ≥ 1. Then the combination of (3.13) and (3.14) with (3.5) gives (3.6). With Lemma 3.4, we can derive the following estimates. Lemma 3.5. If (π£0 , π€0 ) ∈ [π» 2 (Ω)]2 . Let (π’, π£, π€) be a solution of the problem (1.4)-(1.6). Then for any π > 0, there is a positive constant πΆ such that for any 0 < π‘ < π it holds that ∫ π‘ ∫ π‘ 2 2 β₯(π£π₯π₯ , π€π₯π₯ )(π‘)β₯ + β₯(π£π₯π₯ , π€π₯π₯ )(π )β₯ ππ + β₯(π£π₯π₯π₯ , π€π₯π₯π₯ )(π )β₯2 ππ ≤ πΆ(1 + ππΆπ‘ ). 0 0 Proof. Diο¬erentiating the second question of (1.4) with respect to π₯ twice and then multiplying the result by π£π₯π₯ , we obtain ∫ ∫ ∫ ∫ ∫ 1 π 2 2 2 π£ ππ₯ + π½ π£π₯π₯ ππ₯ + π·π£ π£π₯π₯π₯ ππ₯ = π’π₯π₯ π£π₯π₯ ππ₯ = − π’π₯ π£π₯π₯π₯ ππ₯. 2 ππ‘ Ω π₯π₯ Ω Ω Ω Ω 2 By the Cauchy-Schwarz inequality, we have −π’π₯ π£π₯π₯π₯ ≤ π·2π£ π£π₯π₯π₯ + π·2π£ π’2π₯ , which is applied to the above identity yields ∫ π‘ ∫ π‘ ∫ π‘ 2 2 2 β₯π£π₯π₯ β₯ + β₯π£π₯π₯ (π )β₯ ππ + β₯π£π₯π₯π₯ (π )β₯ ππ ≤ πΆ β₯π’π₯ (π )β₯2 ππ. 0 0 0 Then the application of Lemma 3.4 to the above inequality gives the estimate for π£. By the same procedure, we can derive the similar estimates for π€ and complete the proof. Combining Lemma 3.5 and Lemma 3.4 and using the Sobolev embedding π» 1 ,→ πΏ∞ , we derive that β₯π£π₯ β₯πΏ∞ + β₯π€π₯ β₯πΏ∞ ≤ πΆ(1 + ππΆπ‘ ). (3.15) Then we can derive the π» 1 -estimates for π’. Lemma 3.6. Let π’0 ∈ π» 1 (Ω). Assume that (π’, π£, π€) is a solution of the problem (1.4)-(1.6). Then for any π > 0, there is a positive constant πΆ such that for any 0 < π‘ < π it has ∫ π‘ 2 β₯π’π₯ β₯ + β₯π’π₯π₯ (π )β₯2 ππ ≤ πΆ(1 + ππΆπ‘ ). 0 Proof. Multiplying the ο¬rst equation of (1.4) by (−π’π₯π₯ ) and integrating the result yields ∫ ∫ ∫ ∫ 1π 2 2 π’ ππ₯ + π’π₯π₯ ππ₯ = π’π₯π₯ (π’π£π₯ )π₯ ππ₯ − π’π₯π₯ (π’π€π₯ )π₯ ππ₯ (3.16) 2 ππ‘ Ω π₯ Ω Ω Ω Next we estimates the terms on the right hand side terms of (3.16). To this end, we ο¬rst diο¬erentiate the second equation of (1.4) thrice and then multiply the resulting equation by π£π₯π₯π₯ . After integrating the result with respect to π₯ and π‘, we have ∫ π‘ ∫ π‘ ∫ π‘ β₯π£π₯π₯π₯ β₯2 + β₯π£π₯π₯π₯ (π )β₯2 ππ + β₯π£π₯π₯π₯π₯ (π )β₯2 ππ ≤ πΆ0 β₯π’π₯π₯ (π )β₯2 ππ (3.17) 0 0 0 Classical Solutions and Steady States of an Attraction-repulsion Chemotaxis Model 8 where we have used the Cauchy-Schwarz inequality and πΆ0 is a constant. In virtue of the integration by parts, we deduce that ∫ ∫ ∫ 1 2 π’π₯π₯ (π’π£π₯ )π₯ ππ₯ = π’ π£π₯π₯π₯π₯ ππ₯ + 3 π£π₯ π’π₯ π’π₯π₯ ππ₯ 2 Ω Ω Ω ∫ 2 ≤ β₯π’β₯πΏ4 β₯π£π₯π₯π₯π₯ β₯ + 3β₯π£π₯ β₯πΏ∞ β£π’π₯ π’π₯π₯ β£ππ₯ Ω where the HoΜlder inequality has been used. Then by the Cauchy-Schwarz inequality and using (3.17), (3.6), (2.2) and (3.15), one has ∫ π‘∫ ∫ π‘ ∫ π‘ 1 π’π₯π₯ (π’π£π₯ )π₯ ππ₯ ≤ πΆ (β₯π’(π )β₯2πΏ4 )2 ππ + β₯π£π₯π₯π₯π₯ (π )β₯2 ππ 8πΆ 0 0 0 Ω 0 ∫ π‘ ∫ ∫ ∫ 1 π‘ πΆπ 2 π’2π₯π₯ ππ₯ππ +πΆ (1 + π ) π’π₯ ππ₯ππ + 8 0 Ω 0 Ω ∫ π‘ ∫ π‘ (3.18) ≤πΆ (1 + β₯π’π₯ (π )β₯)2 ππ + πΆ(1 + ππΆπ‘ ) β₯π’π₯ (π )β₯2 ππ 0 0 ∫ 1 π‘ + β₯π’π₯π₯ (π )β₯2 ππ 4 0 ∫ 1 π‘ πΆπ‘ β₯π’π₯π₯ β₯2 ππ. ≤ πΆ(1 + π ) + 4 0 The same argument as above applied to π€ also gives rise to ∫ π‘∫ ∫ 1 π‘ πΆπ‘ π’π₯π₯ (π’π€π₯ )π₯ ππ₯ ≤ πΆ(1 + π ) + β₯π’π₯π₯ β₯2 ππ. 4 0 0 Ω (3.19) Then integrating (3.16) with respect to π‘ and applying the inequalities (3.18) and (3.19), we complete the proof. 3.3 Proof of Theorem 3.1 By Lemma 3.4 and Lemma 3.6 as well as Sobolev embedding π» 1 ,→ πΏ∞ , we have sup 0<π‘<π0 ∩π β₯(π’, π£, π€)(π‘)β₯πΏ∞ ≤ πΆ(1 + ππΆπ‘ ) for any π > 0. That is for any ο¬nite time π‘ with 0 < π‘ < π0 ∩ π , β₯(π’, π£, π€)(π‘)β₯πΏ∞ is bounded. By the statement (ii) of Theorem 3.2, the maximal existence time constant π0 of the classical solution obtained in Theorem 3.2 must be inο¬nite. The non-negativity of the solution follows from (ii) of Theorem 3.2 directly. Then the proof of theorem 3.1 is ο¬nished. 4 Steady States In this section, we study the non-trivial steady states of (1.4) with homogeneous boundary conditions (1.6). Steady states of (1.4) satisο¬es the system π’π₯π₯ − (π’π£π₯ )π₯ + (π’π€π₯ )π₯ = 0, π·π£ π£π₯π₯ + π’ − π½π£ = 0, π·π€ π€π₯π₯ + πΎπ’ − πΏπ€ = 0. (4.1) Classical Solutions and Steady States of an Attraction-repulsion Chemotaxis Model 9 The non-trivial steady state of (1.4) is deο¬ned as the solution of (4.1) where none of π’, π£ and π€ is a constant. In this paper, we only consider the simple case π·π½π£ = π·πΏπ€ = π which indicates that both the chemoattractant and chemo-repellent have the same death rate relative to their diο¬usions, respectively. The result of the non-trivial steady state for the general system (4.1) still remains open. By deο¬ning π = π£ − π€, the system (4.1) can be transformed as π’π₯π₯ − (π’ππ₯ )π₯ = 0 ππ₯π₯ + ππ’ − ππ = 0 (4.2) where π = π·1π£ − π·πΎπ€ . Then integrating the ο¬rst equation of (4.2) and using the homogeneous boundary conditions (1.6), we have π’ = πππ where π is a positive constant. We substitute the expression for π’ into the second equation of (4.2) and obtain an elliptic equation for the steady states: ππ₯π₯ = ππ − ππππ . (4.3) This equation of steady states has been extensively investigated when π ≥ 0 and π > 0. e.g., see [13, 8]. However in our model both the variable π and the constant π can be non-positive. We write (4.3) as a ο¬rst order Hamiltonian system ππ₯ = π¦, π¦π₯ = ππ − ππππ . (4.4) Without loss of generality we assume Ω = (0, πΏ) with πΏ > 0. Then the Neumann boundary conditions (1.6) becomes π¦(0) = π¦(πΏ) = 0. (4.5) Let (π∗ , π¦ ∗ ) be an equilibrium point of (4.4). Then the coeο¬cient matrix of the linearized system of (4.4) about (π∗ , π¦ ∗ ) is [ ] 0 1 π= . ∗ π − ππππ 0 It is straightforward to see that the equilibria of (4.4) satisο¬es π¦ = 0 and ππ = ππππ . (4.6) Then there are two cases to consider: (1) When π ≤ 0, namely π·π€ ≤ πΎπ·π£ , the equation (4.6) always has a unique solution ∗ π < 0. The equilibrium (π∗ , 0) is a saddle point for the linearized system due to det π = ∗ −π + ππππ < 0. It is also a saddle for the full nonlinear system (4.4) by Hartman-Grobman 2 theorem. Since the nonlinear system has the Hamiltonian functional π»(π, π¦) = π¦2 − π2 π2 + ππππ , there are no non-trivial steady state solutions satisfying the boundary condition (4.5) by simple phase plane analysis. (2) When π > 0, namely π·π€ > πΎπ·π£ , the equation (4.6) can have zero, one or two solutions depending on the parameters. It is straightforward to check that only the case of two solutions yields the non-trivial steady states. The equation (4.6) has two solutions 0 < π∗1 < π∗2 if and ∗ ∗ only if π > πππ, where π∗1 satisο¬es π > ππππ1 and π∗2 satisο¬es π < ππππ2 . It is trivial to check Classical Solutions and Steady States of an Attraction-repulsion Chemotaxis Model 10 that the equilibrium (π∗1 , 0) is a saddle and the equilibrium (π∗2 , 0) is a center. Since the interval [0, πΏ] is bounded and the system (4.4) is Hamiltonian, by the standard phase plane analysis, we can readily show that for each πΏ, there is a non-trivial solution of (4.4)-(4.5) which is a closed orbit. The non-trivial steady states are nested around the center (π∗2 , 0). y=µφ φ y=ληe 0 φ* 1 1 φ φ* 2 Figure 1: An illustration of the two solutions of the equation (4.6). Therefore when π·π€ > πΎπ·π£ , there is a non-trivial smooth solution to the equation (4.3) which satisο¬es the Neumann boundary condition ∂π ∂π = 0 at π₯ = 0, πΏ. Hence the steady state π solution π’ = ππ exists. Substituting it into the second equation of (4.1) yields with (1.6) π π(π₯) π , 0<π₯<πΏ −π£π₯π₯ + ππ£ = π·π£ (4.7) ∂π£ = 0, π₯ = 0 or πΏ ∂π which is a linear elliptic equation with Neumann boundary condition. Since the non-homogeneous term ππ is smooth for π₯ ∈ (0, πΏ), the smooth solution of (4.7) exists (e.g. see [2]). By the same argument, the solution π€ of the third equation of (4.1) with Neumann boundary condition can be obtained. In summary, we have the following theorem about the steady states of system (1.4) subject to the boundary condition (1.6). Theorem 4.1. Let Ω = (0, πΏ). Assume π·π½π£ = π·πΏπ€ . If π·π€ ≤ πΎπ·π£ , the system (1.4) with Neumann boundary conditions (1.6) has no non-trivial steady states. If π·π€ > πΎπ·π£ , then a non-trivial steady state of the system (1.4) subject to (1.6) exists for each πΏ > 0. From the above analysis and results, we see that the existence of non-trivial steady states of (1.4) depends on the sign of parameter π which relates the diο¬usion coeο¬cients π·π£ and π·π€ . Hence if other parameters are ο¬xed, the relative diο¬usivity of the chemo-attractant to chemo-repellent play a prominent role in determining the nature of the steady states. 5 Summary In this paper, we establish the existence of global classical solutions and steady states to an attraction-repulsion chemotaxis model in one dimension. Our result does not exclude the Classical Solutions and Steady States of an Attraction-repulsion Chemotaxis Model 11 possibility that the solution may blow up at inο¬nity time. From the analysis of steady state, we ο¬nd that the existence of non-trivial steady states depends on the ratio of the chemoattractant diο¬usion to the chemo-repellent diο¬usion. 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