You must be able to measure and calculate
AREA:
 Rectangle
 Triangle
 Circle
w = 175 ft
h = 65 ft
175 X 65 = 11,375
11 375 sq.
sq ft
ft.
b = 25 ft
h = 18 ft
Area = ½ X 25 X 18 = 225 sq.
sq ft
ft.
r = radius (1/2 the diameter)
r2 (r
( squared)
d) = r x r
pi = 3.14
r = 24 ft.
area = 3.14
3 14 X 24 X 24
3 14 X 576
3.14
= 1,808.64
1 808 64 sq.
sq ft
ft.
Calculations
How many pounds of AI are there in a 10 pound bag of a
50WP?
Calculations
How many pounds of AI are there in a 10 pound bag of a
50WP?
10 x 0.50
0 50 = X
Calculations
How many pounds of AI are there in a 10 pound bag of a
50WP?
10 x 0.50
0 50 = X
X=5
Calculations
How many pounds of AI are there in a 10 pound bag of a
50WP?
10 x 0.50
0 50 = X
X=5
5# A.I.
A I in
i a 10# bag
b off 50WP
C l l i
Calculations
How many pounds of a 75WP are needed to supply
15 pounds of AI?
C l l i
Calculations
How many pounds of a 75WP are needed to supply
15 pounds of AI?
X x 0.75
0 75 = 15
C l l i
Calculations
How many pounds of a 75WP are needed to supply
15 pounds of AI?
X x 0.75
0 75 = 15
0.75 0.75
C l l i
Calculations
How many pounds of a 75WP are needed to supply
15 pounds of AI?
X x 0.75
0 75 = 15
0.75 0.75
X = 20
20# of 75%WP needed to provide 15# AI.
C l l i
Calculations
How many pounds of AI are there in a 5 gallon
container of Atrazine 4L?
C l l i
Calculations
How many pounds of AI are there in a 5 gallon
container of Atrazine 4L?
Liquid!
C l l i
Calculations
How many pounds of AI are there in a 5 gallon
container of Atrazine 4L?
Liquid!
4 lbs/gallon!
C l l i
Calculations
How many pounds of AI are there in a 5 gallon
container of Atrazine 4L?
5 gallons X 4# A.I./gallon =
C l l i
Calculations
How many pounds of AI are there in a 5 gallon
container of Atrazine 4L?
5 gallons X 4# A.I./gallon = 20# AI
C l l i
Calculations
The label on a granular pesticide calls for an application rate of 4 pounds
of product per 1,000 square feet. How many pounds of product
would you need to treat an area that measures 125 feet long by 90 feet
wide?
125’
90’
C l l i
Calculations
The label on a granular pesticide calls for an application rate of 4 pounds
of product per 1,000 square feet. How many pounds of product
would you need to treat an area that measures 125 feet long by 90 feet
wide?
125 feet X 90 feet = 11,250
,
square
q
feet
C l l i
Calculations
The label on a granular pesticide calls for an application rate of 4 pounds
of product per 1,000 square feet. How many pounds of product
would you need to treat an area that measures 125 feet long by 90 feet
wide?
125 feet X 90 feet = 11,250
,
square
q
feet
You know y
you need 4 p
pounds to treat 1,000 square
q
feet.
C l l i
Calculations
The label on a granular pesticide calls for an application rate of 4 pounds
of product per 1,000 square feet. How many pounds of product
would you need to treat an area that measures 125 feet long by 90 feet
wide?
4 pounds product
1,000 square feet
=
X pounds product
11,250 square feet
C l l i
Calculations
The label on a granular pesticide calls for an application rate of 4 pounds
of product per 1,000 square feet. How many pounds of product
would you need to treat an area that measures 125 feet long by 90 feet
wide?
4 pounds product
1,000 square feet
=
X pounds product
11,250 square feet
(4) (11,250) = (X) (1,000)
C l l i
Calculations
The label on a granular pesticide calls for an application rate of 4 pounds
of product per 1,000 square feet. How many pounds of product
would you need to treat an area that measures 125 feet long by 90 feet
wide?
(4) (11,250) = (X) (1,000)
C l l i
Calculations
The label on a granular pesticide calls for an application rate of 4 pounds
of product per 1,000 square feet. How many pounds of product
would you need to treat an area that measures 125 feet long by 90 feet
wide?
(4) (11,250) = (X) (1,000)
1,000
1000
C l l i
Calculations
The label on a granular pesticide calls for an application rate of 4 pounds
of product per 1,000 square feet. How many pounds of product
would you need to treat an area that measures 125 feet long by 90 feet
wide?
(4) (11,250) = (X) (1,000)
1,000
1000
45 = X
You need 45 lbs. of product to treat 11,250 sq. ft.
C l l i
Calculations
With a full tank, a sprayer holds 5 gallons which will cover 2500 square
feet, and your product label says to apply 6 oz. of product per 1000
square feet, how many oz. of this product will you need to add to a full
tank?
C l l i
Calculations
With a full tank, a sprayer holds 5 gallons which will cover 2500 square
feet, and your product label says to apply 6 oz. of product per 1000
square feet, how many oz. of this product will you need to add to a full
tank?
Decide what information you need…
C l l i
Calculations
With a full tank, a sprayer holds 5 gallons which will cover 2500 square
feet, and your product label says to apply 6 oz. of product per 1000
square feet, how many oz. of this product will you need to add to a full
tank?
Decide what information you need…
C l l i
Calculations
With a full tank, a sprayer holds 5 gallons which will cover 2500 square
feet, and your product label says to apply 6 oz. of product per 1000
square feet, how many oz. of this product will you need to add to a full
tank?
Decide what information you need…
We are looking for OZ.
C l l i
Calculations
With a full tank, a sprayer holds 5 gallons which will cover 2500 square
feet, and your product label says to apply 6 oz. of product per 1000
square feet, how many oz. of this product will you need to add to a full
tank?
6 oz = X oz
1000
2500
C l l i
Calculations
With a full tank, a sprayer holds 5 gallons which will cover 2500 square
feet, and your product label says to apply 6 oz. of product per 1000
square feet, how many oz. of this product will you need to add to a full
tank?
6 oz = X oz
1000
2500
Cross Multiply!
C l l i
Calculations
With a full tank, a sprayer holds 5 gallons which will cover 2500 square
feet, and your product label says to apply 6 oz. of product per 1000
square feet, how many oz. of this product will you need to add to a full
tank?
6 oz = X oz
1000
2500
(6) (2500) = (1000) X
C l l i
Calculations
With a full tank, a sprayer holds 5 gallons which will cover 2500 square
f
feet,
andd your product
d llabel
b l says to apply
l 6 oz. off product
d per 1000
square feet, how many oz. of this product will you need to add to a full
tank?
6 oz = X oz
1000
2500
(6) (2500) = (1000) X
(1000)
(1000)
C l l i
Calculations
With a full tank, a sprayer holds 5 gallons which will cover 2500 square
f
feet,
andd your product
d llabel
b l says to apply
l 6 oz. off product
d per 1000
square feet, how many oz. of this product will you need to add to a full
tank?
6 oz = X oz
1000
2500
(6) (2500) = (1000) X
(1000)
(1000)
15 = X
C l l i
Calculations
Any questions on calculations?