ELG4139: DC to AC Converters Converts DC to AC power by switching the DC input voltage (or current) in a pre-determined sequence so as to generate AC voltage (or current) output. IDC + VDC Iac + Vac Square Wave Converter S1,S2 ON; S3,S4 OFF SQUARE-WAVE INVERTER for t1 < t < t2 vO T3 T1 D1 + VO - VDC S1 D3 VDC + vO IO T4 T2 D2 t1 S4 D4 VDC S3 S2 S3,S4 ON ; S1,S2 OFF for t2 < t < t3 EQUIVALENT CIRCUIT S1 vO S3 S1 VDC S4 t t2 S3 t2 + vO S2 S4 S2 -VDC t3 t Harmonics Filtering DC SUPPLY INVERTER (LOW PASS) FILTER LOAD L + vO 1 BEFORE FILTERING vO 1 + C vO 2 AFTER FILTERING vO 2 Output of the inverter is “chopped AC voltage with zero DC component”. It contain harmonics. An LC section low-pass filter is normally fitted at the inverter output to reduce the high frequency harmonics. In some applications such as UPS, “high purity” sine wave output is required. Good filtering is a must. In some applications such as AC motor drive, filtering may not required. Fourier Series for Harmonics Analysis Fourier Series ao an bn 1 1 Harmonics of Square Wave 2 f ( v ) d (" DC" term) 0 2 f (v) cosn d 0 1 Vdc (" cos" term) =t -Vdc 2 f (v) sinn d 2 (" sin" term) 0 Inverse Fourier ao 1 f (v) ao an cos n bn sin n 2 n 1 where t an 2 1 Vdc d Vdc d 0 0 2 Vdc cosn d cosn d 0 0 2 Vdc bn sin n d sin n d 0 Half-Bridge Inverter S1 ON Vdc S2 OFF + Vdc 2 S1 VC1 - V + o 0 G + VC2 - t RL S2 Vdc 2 S1 OFF S2 ON Also known as the Inverter Leg! Both capacitors have the same value. Thus the DC link is equally spilt into two. The top and bottom switch has to be complementary. Meaning, If the top switch is closed (ON), the bottom must be OFF, and vice-versa. Single Phase Full Bridge LEG R VRG Vdc 2 LEG R' 2 t 2 t 2 t + Vdc 2 + S1 - Vdc G R S3 Vo - R' VR 'G Vdc 2 Vdc 2 + Vdc 2 S4 S2 Vdc 2 Vo Vdc Vo V RG VR 'G G is " virtual groumd" Vdc Single phase full bridge is built from two half-bridge leg. The switching in the second leg is delayed by 180 degrees from the first leg. Three Phase Inverter +Vdc + Vdc/2 G S1 S3 S5 + Vdc/2 R Y iR iY S4 B iB S6 S2 ia ZR ib ZY N ZB Each leg is delayed by 120 degrees Pulse Width Modulation h( x) if ( k ( x) c ( x) 1 if ( k ( x) c ( x) 1 0) ) 1 t1 t2 Modulating Waveform 1 M1 Sinusoidal modulating waveform, vm(t) Carrier, vc(t) Carrier waveform 2 0 t 1 Regular sampling waveform, vs (t ) Vdc 2 0 t'1 t0 t1 t 2 t3 t 4 t 5 t'2 v pwm t Vdc 2 Regular sampling PWM Triangulation method (Natural sampling). Amplitudes of the triangular wave (carrier) and sine wave (modulating) are compared to obtain PWM waveform. Analogue comparator may be used. Basically an analogue method. Its digital version, known as REGULAR sampling is widely used in industry. Typical Configuration with 3-Wire DC Source Load current may not reverse at the same instants as does the load voltage. Current may lead or lag the output voltage due to the presence of capacitance and/or inductance in the load circuit. Diodes D1 and D2 in antiparallel with each transistors permit load current to flow if necessary. For positive voltage we should turn on the transistor connected to the positive half, and for negative voltage we should turn on the transistor connected to the negative half. In the leading current case, the output current reverses its direction at tx. Output voltage reverses its direction at T/2. Therefore, from tx to T/2 the output current will flow through D1. In the lagging current case, the output current reverses its direction at tY. Output voltage reverses its direction at T/2. Therefore, from T/2 to tY the output current will flow through D2. From the curves, it may be seen that the thyristors may start to conduct at different instants in the half cycle, depending on the nature of the load. To ensure that the thyristors will begin to conduct when required, each must be gated continuously throughout the half cycle. Single-Phase Half-Bridge Inverter (Rashid, Prentice Hall) 3-wire DC source • • • • Consists of 2 choppers, 3-wire DC source Transistors switched on and off alternately Need to isolate the gate signal for Q1 (upper device) Each provides opposite polarity of Vs/2 across the load Q1 on, Q2 off, vo = Vs/2 Peak Reverse Voltage of Q2 = Vs Q1 off, Q2 on, vo = -Vs/2 Waveforms with Resistive Load Output Voltage rms value of the output voltage, Vo 2 Vo To 1 2 V Vs 0 4 dt 2 To 2 2 s Fourier Series of the Instantaneous Output Voltage ao vo an cos(nt ) bn sin(nt ) 2 n 1 ao , an 0 0 Vs 1 Vs bn sin(nt )d (t ) sin( nt ) d (t ) 2 2 0 2Vs bn n 1,3,5,... n 2Vs vo sin(nt ) n 1,3,5,.. n Load Current for a Highly Inductive Load Transistors are only switched on for a quarter-cycle, or 90 Performance Parameters • Harmonic factor of the nth harmonic (HFn) Von HFn Vo1 for n>1 Von = rms value of the nth harmonic component V01 = rms value of the fundamental component • Total Harmonic Distortion (THD): Measures the “closeness” in shape between a waveform and its fundamental component 1 1 THD ( Von2 ) 2 Vo1 n 2,3,... Performance Parameters • Distortion Factor (DF): Indicates the amount of HD that remains in a particular waveform after the harmonics have been subjected to second-order attenuation. 1 2 1 Von 2 DF 2 Vo1 n 2,3,... n DFn Von Vo1n 2 for n>1 • Lowest order harmonic (LOH): The harmonic component whose frequency is closest to the fundamental, and its amplitude is greater than or equal to 3% of the amplitude of the fundamental component. Single-Phase Full-Bridge Inverter • • • • Consists of 4 choppers and a 3-wire DC source Q1-Q2 and Q3-Q4 switched on and off alternately Need to isolate the gate signal for Q1 and Q3 (upper) Each pair provide opposite polarity of Vs across the load Q1-Q2 on, Q3-Q4 off, vo = Vs + Vs - Q3-Q4 on, Q1-Q2 off, vo = -Vs - Vs + When the Load is Highly Inductive Turn Q1-Q2 off – Q3-Q4 off Turn Q3-Q4 off – Q1-Q2 Off Load Current for a Highly Inductive Load Three-Phase Inverter Design Constraints of a Pure Sine wave Inverter Quantity Details Voltage Convert 12VDC to 120 VAC Power Provide 300 W continuous Efficiency > 90% efficiency Waveform Pure 60 Hz sinusoidal Total Harmonic Distortion < 5% THD Physical Dimensions 8” x 4.75” x 2.5” Cost $175.00 Required Components for Design 12 V DC Input from vehicle battery) PWM Control Circuit Half-bridge Converter Transformer Low-pass Filter Full-bridge Inverter Sinusoidal PWM Controller 120 VAC, 60 Hz, 300 W Output PWM Controller • Produces two complementary pulses to control half-bridge transistors. • Problem: – Voltage may drop when the input voltage is decreased. • Solution: – A feedback network may be added for voltage regulation. Half-Bridge Converter • Chops the 12 VDC to produce a 12 V, 100 kHz, square pulse • Problem: – IRF740A MOSFETs has an Rds(on) = 0.55Ω, resulting in high power losses. • Solution: – Choose IRF530 MOSFETs with an Rds(on) = 0.16 Ω Full-bridge Inverter • Converts 170 VDC to a 120 Vrms, 60 Hz, sine wave • IRF740A MOSFETs – Vdss = 400 V – Id = 10 A – Rds(on) = 0.55 Ω Software Flow Diagram (Dr. Yaroslav Koshka) Initialize all variables no Count0 = 300 (300 duty cycles) yes 300 duty cycle values? Output 1 = high, Output 2 = low duty cycle table (increment pointer) Output 1 = low, Output 2 = high Decrement Count0 by 1 Duty cycle and sampling period timer no no Has duty cycle been reached? yes One Sampling Period? ye s Low-pass Filter • 2nd order L-C filter – Filters to retain a 60 Hz fundamental frequency – Few components – Handle current – Wind inductor (fine tune) PCB Layout Case Study: Solar System Using Inverters Stand Alone; Simple Grid Tied; Grid Tie with Battery Solar Schoolhouse and San Mateo College Simple Grid-Connected System Utility Solar Array Inverter Distribution Panel Subpanel Solar AC in from Inverter Lightning surge arrestor Stand Alone Residential System Solar Array Charge Controller Battery DC to AC Inverter Distribution Panel AC Distribution Panel DC Small Stand Alone System (to power an office) Solar Array Charge Control Storage: Battery “Fuel Gauge” Inverter DC to AC