Signal Circuit and Transistor Small-Signal Model Lecture notes: Sec. 5 Sedra & Smith (6th Ed): Sec. 5.5 & 6.7 Sedra & Smith (5th Ed): Sec. 4.6 & 5.6 F. Najmabadi, ECE65, Winter 2012 Transistor Amplifier Development Bias & Signal Bias Signal only = (Bias + Signal) - Bias + ? MOS : VGS ,VDS , I D , MOS : vgs , vds , id , vR = VR + vr RD : RD : iR = I R + ir ..... MOS : vGS , vDS , iD , (vGS = VGS + vgs ,...) RD : ..... F. Najmabadi, ECE65, Winter 2012 VR , I R ..... vr , ir Finding signal circuit elements -- Resistor Resistor Voltage Current iv Equation Bias + Signal: vR iR vR = R iR Bias: VR IR VR = R IR vr = vR − VR ir = iR − IR ?? Signal: vr = vR − VR = RiR − RI R = R (iR − I R ) vr = Rir A resistor remains as a resistor in the signal circuit. F. Najmabadi, ECE65, Winter 2012 Finding signal circuit elements -- Capacitor Capacitor Voltage Current iv Equation Bias + Signal: vC iC iC = C dvC /dt Bias: VC IC IC = C dVC /dt vc = vC − VC i c = i C − IC ?? Signal: ic = iC − I C = C dvC dV d (v − V ) −C C = C C C dt dt dt ic = C dvc dt A capacitor remains as a capacitor in the signal circuit. o Since VC = const., IC = 0 , i.e., A capacitor acts as an open circuit for bias circuit. F. Najmabadi, ECE65, Winter 2012 Finding signal circuit elements – IVS & ICS Independent voltage source Voltage Current iv Equation Bias + Signal: vIVS iIVS vIVS = VS = const Bias: VIVS IIVS VIVS = VS = const vivs = vIVS − VIVS iivs = iIVS − IIVS ?? Signal: vivs = vIVS − VIVS = VS − VS = 0 vivs = 0, iivs ≠ 0 An independent voltage source becomes a short circuit! Similarly: An independent current source becomes an open circuit! F. Najmabadi, ECE65, Winter 2012 Exercise: Show that dependent sources remain as dependent sources Summary of signal circuit elements Resistors& capacitors: The Same o Capacitor act as open circuit in the bias circuit. Independent voltage source (e.g., VDD) : Effectively grounded Independent current source: Effectively open circuit o Careful about current mirrors as they are NOT “ideal” current sources (early effect and/or channel width modulation was ignored!) Dependent sources: The Same Non-linear Elements: Different! o Diodes & transistors ? F. Najmabadi, ECE65, Winter 2012 Diode Signal Response v Bias + Signal : iD = I s exp D nVT Bias : Signal : VD I D = I s exp nVT vD iD VD ID V V + v id = iD − I D = I s exp D d − I s exp D nVT nVT VD vd − 1 × exp id = I s exp nV nV T T vd id = I D × exp nVT F. Najmabadi, ECE65, Winter 2012 − 1 id vd ? A different iv equation! iv equation is non-linear! Related to bias value, ID! Diode small-signal model: vd vd id = I D × exp nVT − 1 id v 1 v v Taylor Series Exapnsion : exp d = 1 + d + d nVT 2! nVT nVT v v vd << 1 : If exp d ≈ 1 + d nVT nVT nVT vd id ≈ I D × 1 + nVT vd = F. Najmabadi, ECE65, Winter 2012 ID − 1 = nVT nVT id = rd id ID 2 + .... vD ? Formal derivation of small signal model Signal + Bias for element A (iA, vA) : iA = f (vA) Bias for element A (IA, VA) : IA = f (VA) Signal for element A (ia, va) : ia = g (va) i A = f (v A ) f ( 2 ) (VA ) 2 = f (VA ) + f (VA ) ⋅ (v A − VA ) + ⋅ (v A − VA ) + ... 2! f ( 2 ) (VA ) 2 (1) = f (VA ) + f (VA ) ⋅ va + ⋅ va + ... 2! ≈ f (VA ) + f (1) (VA ) ⋅ va (1) i A = ia + I A = I A + f (1) (VA ) ⋅ va ia = g (va ) = f F. Najmabadi, ECE65, Winter 2012 (1) (VA ) ⋅ va (Taylor Series Expansion) Small signal means: f (1) f ( 2 ) (VA ) 2 ⋅ va (VA ) ⋅ va >> 2! f (1) (VA ) va << 2 ⋅ ( 2 ) f (VA ) Derivation of diode small signal model nVvD T i D = I S ⋅ e − 1 = f ( v D ) nVv T f (v) = I S e − 1 v 1 × I S e nVT f (1) (v) = nVT VD VD nV nV I D = f (VD ) = I S ⋅ e T − 1 = I S e T − I S v nVT I ⋅e id = f (1) (VD ) × vd = S nVT VD nV IS ⋅ e T × vd = nVT v =VD I I + I id = D S × vd ≈ D × vd nVT nVT id = vd rd rd ≈ F. Najmabadi, ECE65, Winter 2012 nVT ID ID + IS v × = d nV × vd T vD iD Diode can be replaced with a resistor in the signal circuit! vd id rd = nVT/ID Small signal model vs iv characteristics Small signal model is equivalent to approximating the non-liner iv characteristics curve by a line tangent to the iv curve at the bias point id = f (1) (VD ) × vd rd = 1 nVT ≈ f (1) (VD ) I D F. Najmabadi, ECE65, Winter 2012 Derivation of MOS small signal model (1) MOS iv equations: iD = f (vGS, vDS) iG = 0 Signal + Bias for MOS (iD, vGS , vDS) : iD = f (vGS, vDS), iG = 0 Bias for MOS (ID, VGS , VDS) : ID = f (VGS, VDS), IG = 0 Signal for MOS (id, vgs , vds) : id = g (vgs , vds), (Taylor Series Expansion in 2 variables) I D + id = iD = f (vGS , vDS ) = f (VGS , VDS ) + ≈ ID + ∂f ∂vGS ∂f ∂vGS ⋅ (vGS − VGS ) + VGS ,VDS × v gs + VGS ,VDS ∂f ∂vDS id ≈ F. Najmabadi, ECE65, Winter 2012 ig = 0 ∂f ∂vDS ⋅ (vDS − VDS ) + ... VGS ,VDS × vds VGS ,VDS ∂f ∂vGS × v gs + VGS ,VDS ∂f ∂vDS × vds VGS ,VDS Derivation of MOS small signal model (2) iD = 0.5µ nCox id = ∂f ∂vGS ∂f ∂vGS W (vGS − Vt ) 2 (1 + λvDS ) = f (vGS , vDS ) L ⋅ v gs + VGS ,VDS VGS ,VDS 0.5µ nCox =λ× 0.5µ nCox VGS ,VDS VGS ,VDS W (VGS − Vt ) 2 (1 + λVDS ) 2I L = D ≡ gm (VGS − Vt ) VOV = λ × 0.5µ nCox VGS ,VDS ⋅ vds W (vGS − Vt )(1 + λvDS ) L = 2 × 0.5µ nCox = 2× ∂f ∂vDS ∂f ∂vDS W (vGS − Vt ) 2 L VGS ,VDS W (VGS − Vt ) 2 (1 + λVDS ) 1 λI D L = ≈ λI D ≡ (1 + λVDS ) (1 + λVDS ) ro id = g m ⋅ v gs + F. Najmabadi, ECE65, Winter 2012 vds ro ig = 0 MOS small signal “circuit” model ig = 0 and id = g m ⋅ v gs + vds ro Statement of KCL Two elements in parallel Input open circuit gm = 2⋅ ID VOV F. Najmabadi, ECE65, Winter 2012 ro ≈ 1 λ ⋅ ID g m ro = 2 2V = A >> 1 λVOV VOV PMOS “circuit” small signal model is identical to NMOS PMOS* NMOS = PMOS small-signal circuit model is identical to NMOS o We will use NMOS circuit model for both! o For both NMOS and PMOS, while iD ≥ 0 and ID ≥ 0, signal quantities: id, vgs, and vds , can be negative! F. Najmabadi, ECE65, Winter 2012 Exercise: Derive PMOS small signal model (follow derivation of NMOS small-signal model) Derivation of BJT small signal model (1) iB = ( I s / β ) e BJT iv equations: iB = f1 (vBE) iC = f2 (vBE, vCE) iC = I s e v BE VT v BE VT vCE 1 + VA Signal + Bias for BJT (iB, iC, vBE , vCE) : iB = f1 (vBE), iC = f2 (vBE, vCE) Bias for BJT (IB, IC, VBE , VCE) : IB = f1 (VBE), IC = f2 (VBE, VCE) Signal for BJT (ib, ic, vbe , vce) : ib = g1 (vbe), ic = g2 (vbe, vce) We need to perform Taylor Series Expansion in 2 variables for both iB and iC. iB ≈ df1 dvBE × vbe VBE ,VCE F. Najmabadi, ECE65, Winter 2012 iC ≈ ∂f 2 ∂vBE × vbe + VBE ,VCE ∂f 2 ∂vDCE × vce VBE ,VCE Derivation of BJT small signal model (2) iB = ( I s / β ) e v BE VT I B = (I s / β ) e df1 dvBE iC = I s e = f1 (vBE ) VBE VT IC = I s e v BE VBE ,VCE df iB ≈ 1 dvBE v BE VT 1 ( I s / β ) e VT = VT × vbe VBE ,VCE VBE 1 I = B ≡ VT rπ df 2 dvCE 1 = × vbe rπ ib = F. Najmabadi, ECE65, Winter 2012 df 2 dvBE vbe rπ VBE VT vCE 1 + VA VCE 1 + VA BE V +V VT = I s e × A CE VA v BE VBE ,VCE I = s e VT VT VBE ,VCE I = s e VT VA V vCE 1 + VA CE v BE ic = g m vbe + I = C ≡ gm VT VBE ,V vce ro = VBE ,VCE IC 1 ≡ VA + VCE ro BJT small signal “circuit” model vbe ib = rπ A resistor, rπ , between B & E vce ic = g m vbe + ro Statement of KCL Two elements in parallel IC gm = VT VT rπ = IB We follow S&S: vbe is denoted as vπ ro = Similar to NMOS/PMOS, the small circuit model for a PNP BJT is the same as that of a NPN. F. Najmabadi, ECE65, Winter 2012 VA + VCE VA ≈ IC IC Alternative BJT small signal “circuit” model gm Model gm = IC IC I B β = × = VT I B VT rπ g m vπ = β ib Model F. Najmabadi, ECE65, Winter 2012 β rπ × vπ = β iπ Summary of transistor small signal models NMOS/PMOS gm = 2⋅ ID VOV ro ≈ NPN/PNP BJT 1 λ ⋅ ID rπ = VT IB gm = IC β = VT rπ ro ≈ VA IC Comparison of MOS and BJT small-signal circuit models: 1. MOS has an infinite resistor in the input (vgs) while BJT has a finite resistor, rπ (typically several kΩ). 2. BJT gm is substantially larger than that of a MOS (BJT has a much higher gain). 3. ro values are typically similar (10s of kΩ). gm ro >> 1 for both. F. Najmabadi, ECE65, Winter 2012