ME 475/675 Introduction to Combustion Lecture 20 Chapter 5 Some Important Chemical Mechanisms, π»2 − π2 , CO oxidation, Oxidation of Hydrocarbons, Global reaction rates Announcements • HW 7, Due Monday, 10/12/15 • College Distinguished Lecture • Tesla’s JB Straubel to speak about Nevada’s clean energy future • Sunday, October 11, 2015 • 5 pm posters; 6 pm Lecture • http://www.unr.edu/nevada-today/news/2015/jb-straubel-to-speak-at-university HW 7 hints • X2 • H2 / O2 reaction • Carefully apply steady state approximations • 4.16: • NO formation • you’ve already done part A π ππ • = 2π1π π ππ π2 ππ , so ππ = 2π1π π ππ π2 ππ‘ • Use equilibrium constant to find backward rate ππ π‘ • 4.18 • CO combustion • Find characteristic time (can assume one reactant is much more plentiful than other) • 4.19 • Use TPEQUIL to find equilibrium NO mole fraction for each conditions and compared to the amount calculated at 10 ms. Follow directions Chapter 5 Some Important Chemical Mechanisms • Can be very complex, and is a topic of current research, so changing with time • The π»2 − π2 system, • Page 149-140 lists 20 reactions (40 when reversed) • Initiating, Reactions 1 and 2 • Create π» and π»π2 radicals • Reactions involving O, H and OH: • Chain reactions: 3-6 (create ππ», π πππ π») • Chain terminating (ter-molecular) 7-10 • Reactions involving π»π2 (hydroperoxy) and π»2 π2 (hydrogen peroxide) • • • • High pressure Reactions 11-14 form π»π2 and then OH, O Reactions 15-16 form π»2 π2 and O Reactions 17-20 consume π»2 π2 , H and OH Explosive limit dependence on pressure and pressure Explosive No Explosion, 11 destroys H atoms Explosive Radicals not destroyed by walls (reactions 3-6) No Explosion, Walls Destroy Radicals CO oxidation • This is important since hydrocarbon (πΆπ₯ π»π¦ ) combustion has 2 main steps • πΆπ₯ π»π¦ + π2 → πΆπ + β― • πΆπ + π2 → πΆπ2 + β― • This second step is “slow” unless π»2 or π»2 π are present (these molecules help produce ππ») • If π»2 π is the primary π» containing species • • • • πΆπ + π2 → πΆπ2 + π π + π»2 π → ππ» + ππ» πΆπ + ππ» → πΆπ2 + π» π» + π2 → ππ» + π (slow but produces needed π, initiator of chain) (produces needed ππ») (key producer of πΆπ2 , needs ππ») (produces more ππ») • If π»2 is present • π + π»2 → ππ» + π» • ππ» + π»2 → π»2 π + π» (These lead to π»π2 formation, see π»2 − π2 system) • πΆπ + π»π2 → πΆπ2 + ππ» Oxidation of Hydrocarbons • Alkanes (or Paraffins) • Saturated, straight-chain or branching-chain, singlebonded hydrocarbons, πΆπ π»2π+2 • Discuss Higher Alkanes π ≥ 3 • Discuss π = 1 and 2 (methane πΆπ»4 , ethane πΆ2 π»6 ), later • Three step process • π πππ π» attach fuel (remove H from fuel) • Produces Alkenes (πΆπ π»2π , double carbon bonds) π» and water • Alkenes oxidize • Produces πΆπ πππ π»2 (all is converted to Water) • πΆπ burns (πΆπ + ππ» → πΆπ2 + π» ) • Nearly all the heat release occurs in this step Mole Fraction and Temperature versus Location (time) • Propane πΆ3 π»8 in air • πΆ3 π»8 mole fraction decreases with distance (time) • Alkenes (πΆ3 π»6 , πΆ2 π»4 ), π»2 and CO increase with distance, reach a maximum and drop off • The temperature rises significantly at locations where the CO is being consumed (heat release) and πΆπ2 is being produced • Minor species (some oxygenated) increase then decrease More detailed 8-step process (I. Glassman) 1. Break C-C bond (weaker than C-H bonds) 1. πΆ3 π»8 + π → πΆ2 π»5 + πΆπ»3 + π 2. Create alkenes (olifins?) by H-atom abstraction 1. πΆ2 π»5 + π → πΆ2 π»4 + π» + π 2. πΆπ»3 + π → πΆπ»2 + π» + π 3. π» atoms help produce pool of radicals 1. π» + π2 → ππ» + π 4. Radicals attack fuel 1. πΆ3 π»8 + ππ» → πΆ3 π»7 + π»2 π 2. πΆ3 π»8 + π» → πΆ3 π»7 + π»2 3. πΆ3 π»8 + π → πΆ3 π»7 + ππ» 5. New hydrocarbon radicals decay into alkenes via H-atom abstraction 1. πΆ3 π»7 + π → πΆ3 π»6 + π» + π 2. Follows b-session rule b-session rule • Radical site: • site of unpaired electron • Strengthens the adjacent bond(s) but weakens the next bond • The C-C or C-H bond that breaks will be one bond away from the radical site • Two possibilities (as seen in temporal evolution two slides back): • πΆ3 π»7 + π → πΆ3 π»6 + π» + π or • πΆ3 π»7 + π → πΆ2 π»4 + πΆπ»3 + π Continuation of 8-step process 6. O-atoms attach olefins from steps 2 and 5 1. πΆ3 π»6 + π → πΆ2 π»5 + π»πΆπ (formyl radical) 2. πΆ3 π»6 + π → πΆ2 π»4 + π»2 πΆπ (formaldehyde) 7. Methyl radicals (πΆπ»3 ), formaldehyde (π»2 πΆπ) and Methylene (πΆπ»3 ) oxidize 1. Produces πΆπ 8. πΆπ oxidizes to produce πΆπ2 Global and Quasi-global mechanisms rates • Empirical • πΆπ₯ π»π¦ + π₯ + π¦ 4 π2 ππΊ π¦ 2 π₯πΆπ2 + π»2 π • stoichiometric mixture with π2 , not air • π πΆπ₯ π»π¦ ππ‘ = −π΄ππ₯π πΈπ π π’ π πΆπ₯ π»π¦ π π2 π = πππππ ππ3 π • Page 157, Table 5.1: π΄, πΈπ π π’ , π πππ π for different fuels • These values are based on flame speed data fit (Ch 8) • In Table 5.1 units for π΄ = • However, we often want π΄ • 1 πππππ 1−π−π π ππ3 • π΄ 1 πππππ 1−π−π π π3 πππππ 1−π−π − π+π πππππ πππππ ππ3 = ππ3 π ππ3 π 1−π−π 1 πππππ in units of π π3 πππππ 1000 πππππ =π΄ 1−π−π 100 ππ 3 π 1 πππππ 1−π−π π ππ3 = 1 πππππ 1−π−π π ππ3 Usually Want These Units 1000 1−π−π = 1 πππππ 1−π−π π π3 10001−π−π = π΄ πππ₯π‘ππππ 10001−π−π Given in Table 5.1, p. 157 Other empirical models • Multistep models • Text pp. 157-8 • Fuel Surrogates • Text pp. 158-9 Methane Combustion, πΆπ»4 • 325 steps, 53 species • Text pp. 160-7 • Two pathways • High temperature • Low temp (< 1500 K) Oxides of Nitrogen Formation • Important contribution to air pollution • 4 mechanisms • • • • Thermal (Zeldovich): High temperature for a range of Φ Fenimore (or prompt): Fuel Rich Φ > 1 π2 π-intermediate (very lean Φ < 1 and low temperature) NNH: new • Thermal • • • • π + π2 → ππ + π π + π2 → ππ + π π + ππ» → ππ + H Coupled with fuel combustion through π2 , π πππ ππ». Chapter 6 Coupling Chemical and Thermal Analysis of Reacting systems • Four simple systems, p 184 • Constant pressure and fixed Mass Reactor • Constituents (reactants and products, π), π = 1,2, … π • P and m constant • Find as a function of time, t • π (energy) • π (species generation) π • π = , ππππ π (state, mixture) π • Assume we know ππ ππ‘ = ππ = ππ π • From chemical Kinetics • Energy π − π = ππ’ π ππ‘