252onesex 9/10/99
MINITAB EXAMPLE
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Hypothesis Test for Mean of One Sample with Unknown Variance
Explanation: The data set x has already been prepared and stored as 2b.mtb. It
is retrieved and a 95% confidence interval is taken. Then the hypothesis test
 H 0 :   20000
is done. The intention here was to do a test with a significance

 H1 :   20000
level of 5%. Since the p-value was 16% (above 5%), we do not reject the null
hypothesis.
Minitab Output:
Worksheet size: 100000 cells
MTB > Retrieve 'C:\MINITAB\2B.MTW'.
Retrieving worksheet from file: C:\MINITAB\2B.MTW
Worksheet was saved on 9/10/1999
MTB > print 'x'
Data Display
x
21600.7
21632.5
17681.6
20698.0
22062.0
20893.8
20158.2
18283.7
19239.5
22797.4
21192.6
17492.7
21207.4
19583.5
19505.5
23181.6
19500.2
17459.4
16739.8
23308.3
19274.1
17918.9
22850.6
20699.6
19042.8
20001.0
19101.5
19322.1
19524.5
19406.7
19254.7
22663.6
20375.1
18117.0
18189.4
21869.6
20280.6
18819.2
18284.8
19875.8
18986.3
18200.6
19122.4
19061.2
16098.3
19441.1
20992.1
20375.9
20695.9
17350.3
21222.1
20476.2
17722.9
20010.4
20566.7
21815.2
20515.5
19953.3
20956.3
19732.8
19374.0
19002.4
18422.6
18028.2
MTB > tinterval 'x'
Confidence Intervals
Variable
x
N
64
Mean
19800
StDev
1600
SE Mean
200
(
95.0 % C.I.
19400,
20200)
MTB > ttest mu=20000 'x';
SUBC> alt= -1.
T-Test of the Mean
Test of mu = 20000 vs mu < 20000
Variable
x
N
64
© 2002 R. E. Bove
Mean
19800
StDev
1600
SE Mean
200
T
-1.00
P-Value
0.16