# 7

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ELET4223 Homework 7
(Some hints are given on page 2)
7-11.
For the specifications given in the figure below, design a Butterworth filter with the gain adjusted
to 0 dB at the midband frequency. Spread the gain adjustment equally over every stage.
Magnitude scale so that all capacitors in the filter are 1 µF.
7-9.
For the specifications given in the figure below, design a Butterworth filter with the gain adjusted
to 0 dB at the midband frequency. Spread the gain adjustment equally over every stage.
Magnitude scale so that all capacitors in the filter are 0.1 µF.
7-6.
The figure below shows a response that is maximally flat (Butterworth) in the passband. The
figure shows that α(500) = α(1000) = 1 dB. It is also given that the filter realization has two opamps. Determine the loss (attenuation) at a frequency of ω = 3000 rad/sec. [Note: that is all you
have to do; do not design a circuit!]
7-7.
The specification below is complete except that a value for π›Όπ‘šπ‘Žπ‘₯ is not given. Instead, we
require π›Όπ‘šπ‘Žπ‘₯ to be as small as possible. You are permitted to use only two op-amps for the filter
and you are also required to use only 0.1 µF capacitors. Design a filter to meet these
specifications and find the value of π›Όπ‘šπ‘Žπ‘₯ that your design achieves. To save work, you do not
need to adjust the gain to 0 dB at midband frequency.
Hints:
7-11 and 7-9 are straightforward bandpass Butterworth design problems. One of them has n=4 and
the other has n=3. Make sure you do all calculations to LOTS of decimal places, because filter design
generally (and the Geffe algorithm in particular) tends to be “numerically unstable”, which means that
small errors in input numbers can result in big differences in calculated results.
7-6 is just a calculation, no circuit design needed. It will be easiest to get your answer out of the
lowpass prototype rather than the bandpass circuit itself.
7-7 is almost a straightforward Butterworth bandpass design, except that you don’t get n from the
formula, it is “given” in the wording of the question. Instead, you can use the “n formula” to
calculate π›Όπ‘šπ‘Žπ‘₯ . Also, you are permitted to save some work by not doing the “gain adjustment”, i.e.
no need to do the voltage divider thing.
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