Physics I Class 19 Coulomb’s Law Rev. 26-Mar-03 GB 19-1 Forces Known to Physics (Review) There are four fundamental forces known to physics: Gravitational Force (“yesterday’s news”) Electromagnetic Force (start today) Weak Nuclear Force Strong Nuclear Force (All forces we observe are comprised of these fundamental forces. Most forces observable in everyday experience are electromagnetic on a microscopic level.) 19-2 A New Property of Matter Charge Charge comes in two types: positive and negative. NET charge can neither be created nor destroyed. (Principle of Conservation of Charge) However, positive and negative charges can be separated or combined. Neutral H proton electron 0 charge +e charge -e charge Charge is quantized – the smallest unit of charge (magnitude) in normal experience is the charge of the electron or proton, “e”. (All charges are integer multiples of this unit.) By arbitrary historical convention, the charge of an electron is negative and the charge of a proton is positive. 19-3 Conservation of Charge Charge is even conserved in nuclear reactions. Here is what happens to a free neutron (outside a nucleus) in about 12 minutes: neutron proton electron anti-neutrino 0 charge +e charge -e charge 0 charge This is an example of the weak nuclear force (beta decay). 19-4 Coulomb - A Man, A Unit, A Law Charles Coulomb, 1736-1806 Coulomb invented a delicate torsion balance with which he was able to measure the forces between charged and magnetic objects with sufficient accuracy to verify a previous conjecture that the mathematical formula for electromagnetic force should resemble the formula for gravity. The unit of charge is named after Coulomb, abbreviated C. 1.0 C = 6.24150975 × 10+18 e 1.0 e = 1.60217646 × 10–19 C One Coulomb is a lot of protons! 19-5 Coulomb’s Law of Electrostatic Force F 1 q1 q 2 ( r̂ ) (Prof. B’s version – more later.) 2 4 0 r The meaning of each term: F: Electrostatic force on charge 1 from charge 2. 1 2 2 : Electrostatic force constant = 8.98755 × 10+9 N m /C 4 0 q1 : Value of charge 1, positive or negative. q 2 : Value of charge 2, positive or negative. r 2 : Center distance from point charge 1 to point charge 2. r̂ : Unit vector from charge 1 to charge 2. 19-6 Direction of Electrostatic Force “Opposites Attract” 19-7 Properties of Electrostatic Force Similarities with Gravity Every object with charge is attracted or repelled by every other object with charge. (Opposites attract, same repel.) Electric force is a force at a distance (through occupied or empty space). Electric force is a “central” force (center-to-center for point charges). Electric force varies as the inverse square of the center distance. Electric force varies as the product of the charges. 19-8 Properties of Electrostatic Force Differences with Gravity Electrostatic force is both attractive and repulsive, depending on the signs of charge. Gravity is always attractive. There is only one sign of mass and no way to “cancel out” positive mass with negative mass. A charged object can attract an object with no net charge by causing polarization (a Physics 2 topic). The electric force between a proton and an electron is far larger than the gravitational force. (Next slide.) 19-9 Comparison of Gravity and Electrostatic Force r = distance between proton and electron (doesn’t matter) M = mass of a proton = 1.67252 × 10–27 kg. m = mass of an electron = 9.1091 × 10–31 kg. 2 2 G = gravitation constant = 6.673 × 10–11 N m /kg e = charge of proton (+) or electron (–) = 1.60217646 × 10 –19 C 1 2 2 = electrostatic constant = 8.98755 × 10+9 N m /C 4 0 Considering only the ratio of the magnitudes: Felec Fgrav 1 e2 4 0 r 2 e2 M m 4 0 G M m G 2 r 2.269 × 10+39 That number is dimensionless – the same everywhere in the universe (as far as we know). A deep mystery: Why is it so large? 19-10 Superposition of Electrostatic Forces +5.0 C +1.0 C Y 1 X resultant -3.0 C N 1 q1 q i Fon 1 ( r̂i ) (find and add X and Y components) 2 i 2 4 0 ri 19-11 Two Ways of Calculating the Electric Force Vector Book Method: Find the magnitude of the force vector using the absolute values of the charges. Use trigonometry and “opposite attract, like repel” to find the direction. Convert to X, Y components. Prof. B’s Method (Used in Computational Electromagnetics) A systematic method that will give you the X and Y components without resorting to trigonometry or intuition. Use whichever method works best for you. 19-12 How to Calculate a Unit Direction Vector From blue (x0,y0) to red (x,y): 1. Find the displacement in X,Y components. d ( x x 0 ) î ( y y 0 ) ĵ 8 î 6 ĵ 2. Find the length of this vector. 3. Divide by the length to get a unit vector. r | d | ( x x 0 ) 2 ( y y 0 ) 2 82 6 2 10 r̂ d r 8î 6 ĵ 10 0.8î 0.6 ĵ Y 6 0 X 0 8 19-13 How to Calculate the Electric Force Vector (Prof. B’s Method) Force on blue charge (x0,y0) from red charge (x,y): 1. Find the value of the scalar part of the formula: 1 q1 q 2 F 4 0 r 2 2. 3. (could be + or –) Find the unit vector from blue to red. This will be in X and Y components. Change the sign on both components. (Takes into account like charges repel.) Multiply F from step 1 times each component to get final X and Y components of force. Make sure you account for all – signs! Y 6 0 X 0 8 19-14 Class #19 Take-Away Concepts 1. Charges come in positive and negative. 2. Opposites charges attract, like charges repel. 3. Coulomb’s Law of Electrostatic Force F 1 q1 q 2 (r̂ ) 2 4 0 r 4. Similarities and differences with gravity. 5. The principle of superposition. N 1 q1 q i Fon 1 (r̂i ) 2 i 2 4 0 ri 19-15 Class #19 Problems of the Day ___1. The nucleus of an atom consists of a number of protons and neutrons, depending on the particular element/isotope. Considering only the gravitational and electrical forces we have studied (ignoring quantum mechanical effects), which statement below makes the most physical sense? A. The electrical and gravitational forces both act to hold the nucleus together. B. The electrical force acts to push the nucleus apart, but gravity overcomes the electrical force and keeps the nucleus together. C. The electrical force acts to push the nucleus apart and gravity is too weak to overcome the electrical repulsion. D. None of the above statements (A-C) make physical sense. 19-16 Answer to Problem 1 for Class #19 The answer is C. This is a bit of a trick question. When the atomic theory of matter was first considered, the known electrical repulsion of the protons was an objection. Only a hitherto unknown, short-range attractive force could oppose the electrical repulsion of the protons to make a stable nucleus. This is the “strong nuclear force” that is one of the four fundamental forces. 19-17 Class #19 Problems of the Day 2. Calculate the value in Coulombs of the total charge in Avogadro’s Number of protons. What would be the attractive force (magnitude) in Newtons on that much positive charge from an equal amount of negative charge one meter distant? 19-18 Answer to Problem 2 for Class #19 The charge is Avogadro’s Number times the charge of one proton: Q N A e (6.02 10 23 )(1.60 10 19 ) 96320 C The magnitude of the force is 1 Q2 9 2 2 19 F ( 8 . 99 10 )( 96320 ) / 1 8 . 34 10 N 2 4 0 r That’s a big force! 19-19 Activity #19 Coulomb’s Law (Another Pencil and Paper Activity) Objective of the Activity: 1. 2. 3. Think about Coulomb’s Law. Consider the implications of the Coulomb’s Law formula. Practice calculating electrostatic forces using superposition. 19-20