Physics 105A Analytical Mechanics The Euler-Lagrange Equations The Principle of Stationary Action 28 June 2016 Manuel Calderón de la Barca Sánchez Particle’s Motion: Free fall Drop a ball starting from rest. Analyze the motion between t1=0 sec, t2=1 sec Endpoints: y(t=0) = 0 meters y(t=1) = -4.9 meters y(t) 1 0 Infinitely many curves connecting endpoints Each one will yield a different Action, S. 28 June 2016 MCBS -4.9 t Hamilton’s Principle of “Least” Action Ok, it should really be of Stationary Action… The “Action” thingy in Mechanics is another functional: Take the Lagrangian, L = T – V, and integrate it over time: S is a functional, i.e. a function of a function. Classical Mechanics: – It is typically a minimum, but not necessarily. 28 June 2016 MCBS Fundamental Lemma of Calculus of Variations x=x0(t)+ a b(t) x=x0(t) t2 t1 The first order variation in the action given by a small change in x0(t), parameterized as a b(t), will vanish iff x0(t) satisfies the Euler-Lagrange equations. 28 June 2016 MCBS S:Stationary Point → E-L Equations The first order variation on the action S vanishes... S= t2 ò L(x, x,t) dt t1 æ ¶L ¶x ¶L ¶x ö ¶S = òç + ÷ dt = 0 ¶a t1 è ¶x ¶a ¶x ¶a ø t2 …if and only if the E-L equations are satisfied. 28 June 2016 d æ ¶L ö ¶L ç ÷- = 0 dt è ¶x ø ¶x MCBS 6.2 Two Falling Sticks ** Two massless sticks of length 2r, each with a mass m fixed at its middle, are hinged at an end. One stands on top of the other. The bottom end of the lower stick is hinged on the ground. They are held such that the lower stick is vertical and the upper stick is tilted at a small angle e with respect to the vertical. They are then released. Find the Lagrangian of the system For small angles, find the equations of motion and determine the angular acceleration of the sticks at the instant they are released. 28 June 2016 MCBS e r m r r m r Principle of Least Action in QM Particle takes ALL possible paths. Sum amplitude for each path: Feynman Path Integral Quantum Mechanical amplitude for each path: Stationary action: phases add constructively. 28 June 2016 MCBS Adding complex amplitudes… Illustration of a “path integral”. Each path has a phase (angle of the arrow) Paths with similar phase add constructively. Similar phase: change in path causes little change in phase 28 June 2016 MCBS QED Lagrangian y, y : electrons, positrons Dirac (bi)spinor, for spin ½ particles (fermions). † 0 :Dirac adjoint Dm = ¶m + ieAm +ieBm Bm : External EM field. Fmn = ¶m An -¶n Am e: coupling constant, electric charge of bispinor field Am : Covariant four-vector potential of EM field generated by the electron itself. 28 June 2016 E = ¶A / ¶t - Ñf B = Ñ´ A y =y g gauge covariant derivative Am = (f / c, A) MCBS EM Field tensor