EECS 105 Fall 2003, Lecture 15 Lecture 15: Small Signal Modeling Prof. Niknejad Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Lecture Outline Department of EECS Review: Diffusion Revisited BJT Small-Signal Model Circuits!!! Small Signal Modeling Example: Simple MOS Amplifier University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Notation Review iC f (vBE , vCE ) Large signal IC iC f (VBE vBE ,VCE vCE ) Quiescent Point (bias) Q (VBE ,VCE ) IC ic f (VBE vbe ,VCE vce ) f ic vBE transconductance f vbe vCE Q vce small signal DC (bias) small signal (less messy!) Q Output conductance Since we’re introducing a new (confusing) subject, let’s adopt some consistent notation Please point out any mistakes (that I will surely make!) Once you get a feel for small-signal analysis, we can drop the notation and things will be clear by context (yeah right! … good excuse) Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Diffusion Revisited Why is minority current profile a linear function? Recall that the path through the Si crystal is a zig-zag series of acceleration and deceleration (due to collisions) Note that diffusion current density is controlled by width of region (base width for BJT): Half go left, half go right Density here fixed by potential (injection of carriers) Physical interpretation: How many electrons (holes) have enough energy to cross barrier? Boltzmann distribution give this number. Density fixed by metal contact Wp Decreasing width increases current! Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Diffusion Capacitance The total minority carrier charge for a one-sided junction is (area of triangle) qV D 1 1 Qn qA bh2 qA (W xdep , p )(n p 0e kT n p 0 ) 2 2 For a one-sided junction, the current is dominated by these minority carriers: qVD qADn ID (n p 0 e kT n p 0 ) W p xdep , p Dn ID 2 Qn W x p dep , p Department of EECS Constant! University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Diffusion Capacitance (cont) The proportionality constant has units of time Qn Wp xdep , p T ID Dn Temperature q Wp xdep , p T kT n 2 2 Distance across P-type base Diffusion Coefficient Mobility The physical interpretation is that this is the transit time for the minority carriers to cross the p-type region. Since the capacitance is related to charge: Qn T I D Department of EECS Qn I Cd T g d T V V University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad BJT Transconductance gm The transconductance is analogous to diode conductance Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Transconductance (cont) Forward-active large-signal current: iC I S e vBE / Vth (1 vCE VA ) • Differentiating and evaluating at Q = (VBE, VCE ) iC vBE Q q I S e qVBE / kT (1 VCE VA ) kT iC gm vBE Department of EECS Q qI C kT University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad BJT Base Currents Unlike MOSFET, there is a DC current into the base terminal of a bipolar transistor: I B IC F I S F eqVBE / kT (1 VCE VA ) To find the change in base current due to change in base-emitter voltage: ib iB vBE iB vbe vBE Q ib Department of EECS gm F Q iB iC iC Q vBE Q 1 F gm vbe University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Small Signal Current Gain 0 iC F iB iC 0 iB ic 0ib Since currents are linearly related, the derivative is a constant (small signal = large signal) Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Input Resistance rπ r 1 iB vBE Q 1 iC F vBE r Q gm F F gm In practice, the DC current gain F and the small-signal current gain o are both highly variable (+/- 25%) Typical bias point: DC collector current = 100 A r 100 25 mV 25 k .1mA Ri Department of EECS MOSFET University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Output Resistance ro Why does current increase slightly with increasing vCE? Collector (n) WB Base (p) Emitter (n+) Answer: Base width modulation (similar to CLM for MOS) Model: Math is a mess, so introduce the Early voltage iC I S e vBE / Vth (1 vCE V A ) Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Graphical Interpretation of ro slope~1/ro slope Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad BJT Small-Signal Model ib r vbe 1 ic g m vbe vce ro Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad BJT Capacitors Emitter-base is a forward biased junction depletion capacitance: C j , BE 1.4C j , BE 0 Collector-base is a reverse biased junction depletion capacitance Due to minority charge injection into base, we have to account for the diffusion capacitance as well Cb F gm Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad BJT Cross Section Core Transistor External Parasitic Core transistor is the vertical region under the emitter contact Everything else is “parasitic” or unwanted Lateral BJT structure is also possible Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Core BJT Model Reverse biased junction Base Collector g m v Reverse biased junction & Diffusion Capacitance Fictional Resistance (no noise) Emitter Given an ideal BJT structure, we can model most of the action with the above circuit For low frequencies, we can forget the capacitors Capacitors are non-linear! MOS gate & overlap caps are linear Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Complete Small-Signal Model “core” BJT Reverse biased junctions Real Resistance (has noise) External Parasitics Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Circuits! When the inventors of the bipolar transistor first got a working device, the first thing they did was to build an audio amplifier to prove that the transistor was actually working! Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Modern ICs Source: Intel Corporation Used without permission Source: Texas Instruments Used without permission First IC (TI, Jack Kilby, 1958): A couple of transistors Modern IC: Intel Pentium 4 (55 million transistors, 3 GHz) Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad A Simple Circuit: An MOS Amplifier Input signal RD VDD Supply “Rail” vo vs vGS VGS vs Department of EECS VGS I DS Output signal University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Selecting the Output Bias Point The bias voltage VGS is selected so that the output is mid-rail (between VDD and ground) For gain, the transistor is biased in saturation Constraint on the DC drain current: IR VDD Vo VDD VDS RD RD All the resistor current flows into transistor: I R I DS , sat Must ensure that this gives a self-consistent solution (transistor is biased in saturation) VDS VGS VT Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Finding the Input Bias Voltage Ignoring the output impedance I DS , sat W 1 nCox (VGS VTn ) 2 L 2 Typical numbers: W = 40 m, L = 2 m, RD = 25k, nCox = 100 A/V2, VTn = 1 V, VDD = 5 V I RD VDD W 1 I DS , sat nCox (VGS VTn ) 2 2 RD L 2 5V μA 1 100μA 20 100 2 (VGS 1) 2 50k V 2 .1 (VGS 1) 2 Department of EECS VGS 1.32 VGS VT .32 VDS 2.5 University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Applying the Small-Signal Voltage Approach 1. Just use vGS in the equation for the total drain current iD and find vo vGS VGS vs vs vˆs cos t vO VDD RD iDS W 1 VDD RD nCox (VGS vs VT ) 2 L 2 Note: Neglecting charge storage effects. Ignoring device output impedance. Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Solving for the Output Voltage vO vO VDD RD iDS vO VDD RD iDS W 1 VDD RD nCox (VGS vs VT ) 2 L 2 vs W 1 2 VDD RD nCox (VGS VT ) 1 L 2 V V GS T 2 I DS vs vO VDD RD I DS 1 V V GS T 2 VDD 2 Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Small-Signal Case Linearize the output voltage for the s.s. case Expand (1 + x)2 = 1 + 2x + x2 … last term can be dropped when x << 1 2 2 v 2v v s s s ------------------------------------------------1 + = 1 + + ------------------------- V GS – V Tn V GS – V Tn V – V GS Tn Neglect 2vs vO VDD RD I DS 1 VGS VT Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Linearized Output Voltage For this case, the total output voltage is: 2vs VDD vO VDD 1 2 VGS VT vsVDD VDD vO 2 VGS VT “DC” Small-signal output The small-signal output voltage: vo vsVDD Av vs VGS VT Voltage gain Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad Plot of Output Waveform (Gain!) Numbers: VDD / (VGS – VT) = 5/ 0.32 = 16 output input mV Department of EECS University of California, Berkeley EECS 105 Fall 2003, Lecture 15 Prof. A. Niknejad There is a Better Way! What’s missing: didn’t include device output impedance or charge storage effects (must solve non-linear differential equations…) Approach 2. Do problem in two steps. DC voltages and currents (ignore small signals sources): set bias point of the MOSFET ... we had to do this to pick VGS already Substitute the small-signal model of the MOSFET and the small-signal models of the other circuit elements … This constitutes small-signal analysis Department of EECS University of California, Berkeley