Unit 4: Interpolation and Extrapolation Binomial Expansion The steps are as follows: 1. Find the number of known values (n) of dependent variable Y. 2. For the two missing values, first take βπ0 = 0 π‘βππ‘ ππ (π¦ − 1) π = 0 And β1π = 0 is written by increasing the suffix value by one in βπ0 = 0 3. The left hand side of the equation is expanded using the binomial expansion. Suppose 4 values of Y are known, 4th order (leading) difference will be zero. β40 = 0 (π¦ − 1) 4 = π¦4 − 4π¦3 + 6π¦2 − 4π¦2 + π¦0 = 0 We get one missing value within the range of the data. 4. To get the other missing value, the same binomial expansion as in case of β40 = 0 Is written with suffixes of each ‘raised by 1. π¦5 − 4π¦4 + 6π¦3 − 4π¦2 + π¦1 = 0 The successive numerical co-efficient of ‘y’ can be obtained using binomial coefficients table or y the formula πβπ πΆπππππππππ‘ ππ ππππ£πππ’π π¦ × π π’ππππ₯ ππ ππππ£πππ’π π¦ ππππ’πππ‘πππ πππππ ππ ππππ£πππ’π π‘πππ The numerical coefficient of the first term will be always 1. Newton’s Advancing Difference Method π¦π₯ = π¦0 + π₯β10 + π₯= π₯(π₯ − 1) 2! 2 0 + π₯(π₯ − 1)(π₯ − 2) 3! 3 0+ π₯(π₯ − 1)(π₯ − 2)(π₯ − 3) 4! π‘βπ π£πππ’π ππ π π‘π ππ πππ‘πππππππ‘ππ − π£πππ’π ππ π ππ‘ ππππππ π·ππππππππ πππ‘π€πππ π‘π€π πππππππππ π£πππ’ππ ππ π π₯= π‘βπ π¦πππ ππ πππ‘πππππππ‘πππ − π‘βπ π¦πππ ππ ππππππ π·πππππππππ πππ‘π€πππ π‘π€π πππππππππ π¦ππππ