Estimation of the Moment Axis of a Cell and the... The orientation of any object in an image is simply... ). The perpendicular distance of

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APPENDIX B

Estimation of the Moment Axis of a Cell and the Equivalent Ellipse [29]

The orientation of any object in an image is simply reduced to defining the slope m of the moment axis through the center of area ( x

0

, y

0

). The perpendicular distance of any point ( x i

, y i

) within the perimeter from this imagined moment axis is: p = Equation

1 + m 2

0 B . 1

The sum of the inertial contribution from each point, or the rotational moment of inertia of the areal projection of the object is therefore:

I =

p 2 =

[( y i

− y

0

) −

1 + m ( x i m 2

− x

0

)] 2

Equation B . 2

The moment axis is the line that would result in the least moment of inertia of the object area. Minimizing Equation 3 we get:

∂ I

∂ m

=

∂ m

[( y i

− y

0

) −

1 + m ( x i m 2

− x

0

)] 2

= 0 Equation B . 3

m

2

( y i

− y

0

)( x i

− x

0

) − m [( y i

− y

0

) 2 − ( x i

− x

0

) 2 ] − ( y i

− y

0

)( x i

− x

0

) = 0

m 2 ( ∑ y i x i

∑ y i

N

∑ x i ) − m



[ ∑ y i

2 −

( )

2

N

] − [ ∑ x i

2 −

( )

2

N

]



− ( ∑ y i x i

∑ y i

N

∑ x i ) = 0

Equation B . 4

The summations may be easily estimated from the image matrix and expressed in terms of the individual moments:

µ yx

= ( ∑ y i x i

∑ y i

N

∑ x i ); µ yy

= [ ∑ y 2 i

( )

2

N

]; µ xx

= [ ∑ x 2 i

( )

2

N

] .

The quadratic equation may be solved to yield the orientation from the x-axis: m = tan( θ ) =

( µ yy

− µ xx

) ± ( µ yy

2 µ yx

− µ xx

) 2 + 4 µ 2 yx Equation B . 5

Once the orientation axis has been determined, the co-ordinates ( x i

, y i

) in the mask image of each particle (cell) may be clockwise rotated to new co-ordinates ( X i

, Y i

) by the transformation:



X

Y i i



=



− cos θ sin θ sin θ cos θ



 x y i i

 Equation B . 6

The major axis is now parallel to the x-axis and the modified moment of rotation about the major axis is estimated to be:

I a

= yy

= ∑ Y 2 −

(

N

)

2

µ ' Equation B . 7 i

∑ Y i

The moment of inertia of an equivalent elliptical slab about the major axis (major axis a , minor axis b , and thickness h, and mass M ) may be equated:

I a

=

1

6

M ( 3 b 2 + 4 h ) =

N

2 b 2

B . 8 assuming h = 0, and the mass to be equivalent to the area of the ellipse M= A = N = π ab .

The above treatment allows rigorous estimation of the major and minor axis of the equivalent ellipse to the particle and its orientation to the x-axis.

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