# Final Exam Option 1 Answers Multiple Choice and Numerical Response Answers ```Final Exam Option 1 Answers
Multiple Choice and Numerical Response Answers
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C
68&deg;
C
A
B
D
A
D
B
B
C
D
B
C
165 ft2
B
C
B
1620 in.3
D
C
14.9&deg;
B
C
B
\$9.09
17.2 m
D
A
B
13.8 mm
C
C
B
B
A
24
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B
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3124
D
D
3
C
21
B
D
30
29.5&deg;
A
B
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0.5
A
________
1. a) 4 √302 + 202 = 144.222 204
The amount of cable needed is approximately 144 m.
30
b) tan θ = __
20
( )
θ = 56.309 932…
θ = 56.3
The angle is approximately 56.3&deg;.
-30
c) ____
= -1.5
20
d) y = -1.5x + 30; in general form:
5x = 2y – 60 = 0
2. a) V = π (302)(80)
V = 226 194.690 265…
The volume of the barrel is approximately
226 195 cm3.
b) V = π (32)(12)
V = 339.292 035…
The volume of the spigot is approximately 339 cm2.
This page may be reproduced for classroom use by the purchaser of this book without written permission of the publisher.
Name: ____________________________________________
V
c)
Date: _______________________________
3. a) Diagrams may vary. Example:
Rate of Water Flow
200 000
Volume (cm3)
150 000
b) 2x2 – 5x – 3
c) Answers will vary. Students may represent a linear
or a non-linear relation.
d) Answers will vary. Check that the graph passes the
vertical line test.
e) Answers will vary. Check that the graph does not
pass the vertical line test.
100 000
50 000
200
0
400
600
800
Time (min)
1000 1200
t
1
d) __4 (226 195) = 56 548.75;
56 549
_____
200
= 282.745
It would take approximately 283 s or 4.7 min before
the barrel was three quarters full. Alternatively,
students may use the graph in part c) to determine
the time.
e) Bryan is correct. The slope is decreasing (or
negative). As time passes, the level of the water in
the barrel decreases.
4
f) Vball = __3 π(6)3
Vball = 904.778 761 061 947…
The volume of the ball is approximately 905 cm3.
V
πr
905
h = _____
900π
h = ___2
905
h = ____________
2827.433 628…
h = 0.320 078…
The level of the water rose about 0.32 cm after the
ball sank.