1 Excerpts of TAL Agreement, Cancun • Subject to unspecified amendments, TAL interconnect and access cost models were stable enough to software application phase. • Revised methodologies will constitute Appendices 3& 4 of Recommendation D 400 R. • Deadline date for submission of contributions to revision of models prior to progress to software phase was August 31, 2003. • February 2004 initial date for completion of software. 2 Revision, TAL Interconnect Model Objectives To simplify basic interconnect services for software application in terms of: a) Unit costs of single transit interconnect traffic. b) Unit costs of Double transit interconnect traffic. 3 General Objective Regulator Service Provider Service Provider Investment Opportunity Fair Proxy Market price reflective of reasonably efficient cost Incumbent Service Provider Consumer 4 Traffic Definition According to Recommendation D 600 R : • 1.4.1. Incoming national, single transit: Traffic terminated on the network of an Operator in a country which originated on the network of another Operator in the same country and where the interconnection point between the two networks is located within the local tariff zone of the Operator which is terminating the traffic. Example: traffic between telephone G and A or telephone K and B at Diagram 1. • 5 Zone 1 Telephone "B" Telephone "D" Telephone "A" Zone 2 Telephone "C" 6 Distant Intertional IGW Distant International Satellite Telephone "E" IGW Telephone "F" Neighbouring country Telephone "C" h IGW Point of Interconnection Telephone "B" Neighbouring country Point of Interconnection Telephone "A" Telephone "D" National network operator XCloud Telephone "G" National Network Operator Y Telephone "H" Telephone "K" 7 Double Transit Traffic • Incoming national, double transit: Traffic terminated on the network of an Operator in a country which originated on the network of another Operator in the same country and where the interconnection point between the two networks is located outside the local tariff zone of the Operator which is terminating the traffic. Example: traffic between telephone G and B or telephone K and A at Diagram 1. 8 Network & Non-network Resources Used • Switching Components (including signaling network). • Transmission Components. • Other resources used to support network and general delivery of the services. • Unit Cost = ƒ(cost caused due to usage of network and other resources to deliver traffic in period n/Volume of traffic 9 delivered) in period n. Stages of cost-orientated Unit Costs •Cost of of network components components •Operation and maintenance costs costs •Service traffic •Amortization rules •Equipment price trends •Cost of capital •Cost of functional support •Identifiable direct and indirect costs costs •Other common costs •Routing table •Cost distribution distribution COSITU - The ITU tariff model •Unit endogenous cost of services 23 10 Two Basic Costing Principles • Causality: – The demonstration of a clear cause-and-effect relationship between service delivery, on the one hand, and the network elements and other resources used to provide it, on the other hand, taking account of relevant cost determinants (cost inducers/drivers). • Efficiency: – The provision of a forecast of cost reductions that result from a more efficient combination of resources. 11 Diagram 2 LRAEC 11/11/2003 Marginal Cost Cost Subtitle 11/11/2003 Efficient Cost C1 Quantity Q1 12 Parent Formula • • • • • • • • • General LREC formula: C = A(ß)/Mo Where: C= per minute cost of traffic A= total cost (direct, indirect and common) ß = Efficiency factor = x/y x = required capacity y = installed capacity 13 Mo = traffic throughput. throughput Cost Adjustment? • Historical costs: Based on the cost price of equipment and services, • Current costs: Take account of the changing environment: falling prices of telecommunication equipment, currency depreciation. The TAL Model utilizes current costs as confirmed on the relevant market. 14 Fully Distributed or Incremental Costing Accounting Methods Cost Methods Historical Costing Actual Cost incurred (includes inefficiencies) Current Costing Hybrid Costing (Adjustment toward Current costs) Current Costs of Providing Service (Reduction of over pricing) Actual Costs adjusted for market changes and efficiency Fully Distributed Costing Incremental Costing Total Cost is allocated to Services Long Run Incremental Costs are allocated to Incremental services 15 Clarity re consistency with Fundamental Costing Principles • • • • • • Parent TAL formula: C = A(ß)/Mo Interconnect Model Formulae: LEC = (A/Mo ) *(∑∝) IEC = (? A/? Mo ) *(∑∝) The efficiency factor ∝, is estimated in terms of adjustment in OPEX and or adjustment for avoidable excess network capacity. 16 LEC & IEC ü EEC = Aå/M1 ü Aå = total cost adjusted for unavoidable diseconomies of scale (inefficiency). ü M1= total traffic (current + expected) ü IEC= A@/M-1 ü A@ = cost of additional components to deliver interconnect traffic, subject to adjustment for inefficiency ü M-1= interconnect 17 traffic Current Cost Adjustment Effect of Exchange rate adjustment on cost may be estimated by: CAD = DA[(1+ τ)DP/2 /(1-ε)DP/2 –1] Where: CAD = Adjustment to current cost; DA = Depreciation allowance; τ = Average annual variation in equipment price; • 18 DP = Depreciation period; ε = Average per annum rate in currency movement. 19 Cost of Capital Combined effect of debt and equity (i) Creditors demand interest (ii) Owners demand dividends Firms normally raise capital through: q Long term & short term debt q Sale of Preferred stock q Sale of common stock q Retained earnings These cost are basic determinants of the cost of capital. 20 Cost of Debt Cost of debt is determined by: • Interest rate on debt; subject to: • Adjustment for taxes where interest payment on debt are deductible for income tax purposes. • After tax cost of debt can be expressed as: (interest rate) * (1- tax rate) • E.g. If interest rate is 9% and tax rare of 25% • The after tax cost of debt = (0.09)*(1- 0.25) = 0.0675 21 Marginal Cost of Debt Cost of debt should be calculated at marginal cost: • Current interest rates on the market • Taking into account interest rates on similar enterprise on the international market 22 Cost of Equity • Required rate of return (s ) on the common stock of the firm • Firms use Expected rate of return. • The Expected Rate of return on a stock is a risky variable. • s = risk-free rate of return σ(RF) + Risk Premium (RP). • RF is normally reflective of interest on government security. • RP is the difference between the required rate & risk free rate of return 23 • • • RF = ƒ(rate on government securities ) RP = ƒ(different methodology of estimation) Interest on firms long term bonds (iC ) + a percentage-points addition based on historical returns per year on the financial market (iA). Let RF,iC & iA be 6%, 9% and 5% respectively: • iC + iA = (0.09 + 0.05) = 0.14 • RP = 0.14 – 0.06 = 0.08 • s = 0.14 24 Jeorgenson Method qThe cost of capital d is calculated using the formula: formula • d = D i* (i-t) + E s D+E D+E Where: D = amount of medium and long term debt; σ = before tax return on capital; E = equity; and i = average interest rate. t = rate of corporation tax. 25 Operating and maintenance costs q Cost of inputs ü Purchases and variations in stock ; ü Transport; ü Outside services q Personnel costs q Taxes and levies (corporation Tax not included q Other charges q Other Financial and similar charges q Operating provisions 26 Total Network Costs Cost of Network Elements Operating Costs Depreciation Expenses Capital Cost Operating & Maintenance costs (OPEX) Text Network TextAsset Valuation Technology Text (Adjusted) Cost relationship Text Text Cost Drivers Depreciation Profile (time, method etc) Text Text Other Operating Costs Contribution to Interest rate: Text Text Service TextText equity & debt prooduction Routing: :Component Usage Production Efficiency Text Disaggregated Component Costs Interconnect Service Costs 27 Total Product/Service Efficiency i, Mi, Ler, Ai, Ws,Ti, µi) Oz ƒ ( S e • Total Service Efficiency (Tse) could Where: Si = Relative Salaries and wage be expressed as: levels; • Tse = OZe + Ne Mi = Managerial competences; Where: Ler = Line/employee ratio; OZe = Organization and Ai = Employees work ethic; Operational Ws = Skill of Average Worker; Ti = Availability state-of-theefficiency. art technology at work place; Ne = Network efficiency. µi = Other factors. 28 Network Efficiency (Ne) • Ne = tc + tc+1 -? = 0 Where: Ø tc is Current traffic; Ø ti is Expected traffic where i = 1 to n; Ø ? is Network capacity. capacity • 29 Evaluating Total Efficiency Factor • Let the network efficiency be expressed as Q1(used capacity +backup capacity ) /Q2(installed capacity) =ß Total Service Efficiency, (T ( se) is: Tse = (ß + Si+ Mi + Ler+ Ai+ Ws + Ti+ µi) = (ß + OZe) 30 Issue /Decision a) Except for the element: employee line ratio, the other elements that comprise OZe are extremely difficult to model. b) The fundamental question: do the elements that comprise OZe satisfy the SG3 practicability criterion for inclusion in any cost model??????. c) ß is measurable, with some degree of difficulty. 31 Practicability 1. Sg3 documents the need for a model to be practicable. 2. Two fundamentals of Practicability are a) Availability of data; and b) Simplicity of methodology for quantitative estimation. estimation 32 Evaluating Network Efficiency Assumptions: qEfficiency requires network dimensioning to accommodate full-capacity busy hour traffic (including factor for traffic growth and breakdown). qIf not, the network is inefficient either in terms of excess or under capacity. qAn important concern, in terms of cost, of the regulator is excess capacity. 33 Estimating Network factor, ϖ – TBHEj = ß j (1+ g + ? ) = Required capacity • • • • • Where: ß j is current busy hour traffic in erlangs. g is the growth factor for busy hour traffic; ? = network backup factor j = 1 to n. So: ϖ = ß j (1+ g + ? ) • ____________ • IC (installed capacity) 34 • Likely Outcome ϖ ϖ ϖ =1 < 1 >1 OPTIMA % Excess capacity % Under capacity 35 Avoidable/Unavoidable Excess Capacity Key efficiency questions: 1. Is excess network capacity avoidable? 2. Example when not and when: i. If computed required capacity for consistent busy hour traffic demand at a particular switch is Q, but closest manufacturing specification for that switch is of capacity Q1where Q1 > Q, the excess capacity Q1- Q is unavoidable. 36 ii. However, if the operator elects to install a switch with capacity Q2, where Q2 > Q1, there is a gap Q2 - Q1 iii. If pQ2 > pQ1, the efficiency gap is negative and avoidable and requires an efficiency adjustment factor: ϖu = (Q1/ Q2) So the LEC unit cost of interconnect traffic is: (Total induced cost of Traffic)*(ϖu) • Volume of traffic 37 Possible Cost Model Architecture for (PSTN) Fixed Network Sources of Data Extract following data from the Plant Accounts Determine network cost of services (4) (5) (6) Technology Cost Pool Cost Driver Services Element / Functionality Local Loop Underground Conduit Cable Poles etc. Determine weighted average cost of capital Apply cost drivers and routing factors (3) Annualized Capital Cost Switch Group Elements into Cost Pools Loop distance # lines in service Line miles in service sensitive costs Line termination Signalling Signalling and Setup & Setup/ Minutes of Use No. of call attempts Routing Factors Identify network support costs from general ledger Unbundle Technology Groups to Technology Elements (2) Engineering Studies • (1) • Opening & Closing Net Book Values • Depreciation Charge for the period • Date of Commissioning of Assets Determine capital works in progress by asset class Reclassify to Technology Groups Classify plant account records into following technology groups and determine annualized capital cost Services Trunk Termination Minutes of Use Conveyance Transmission Electronics Satellite Equipment Direct Microwave Equipment Fibre Optic Equipment 38 National Network 39 Unit Service Cost Interconnect formula per individual service becomes: (Total induced cost of Traffic)*(ϖ u) Rij • Volume of traffic of Service, j • Rij is the factor which represents the intensity and frequency of use of the network in the delivery of service, j where j = 1 to n 40 COSITU REVISION • Old Efficiency factor COSITU = Used capacity/Installed capacity. • Efficiency Factor TAL = Used capacity + backup capacity / unavoidable installed capacity. This adjustment was effected in COSITU. 41 42