12.510 Introduction to Seismology

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12.510 Introduction to Seismology
Spring 2008
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12.510
April, 8, 2008
Continents: Quick review. Surface waves
Ground roll-acoustic 𝑝 = 𝑉. ∇.
Love waves – SH 𝑒𝑦 = πœ‡. ∇.
1
p
1
𝑝
∇𝑝 . where p is the pressure
∇uy
Rayleigh waves P-SV
Quick review (refer to April, 4, 2008 for details)
Surface wave
S
P
Ground roll
T
x
ω – k domain
ω
c2=ω/k1 cfix
c1=ω/k2
kfix
3rd higher mode
2nd higher mode
1st higher mode
ω2
ω1
ω0
ωfi
Fundamental mode
k2 k1
x
k0
k
1
12.510
April, 8, 2008
Ground roll dispersion relationship
𝟏
Pre-cretical 𝐩 < 𝐜
𝟐
R
T
πœ‚2 =
1
− 𝑝2 ∈ ℝ
𝑐2 2
(1)
𝟏
Post-critical 𝐩 > 𝐜
𝟐
Head wave
πœ‚2 = i 𝑝2 −
1
= iπœ‚2 ∈ β„‚
𝑐2 2
2
(2)
12.510
April, 8, 2008
\
𝑃
i
j
/
𝑆
\
𝑆
𝑠𝑖𝑛(𝑗) 𝑠𝑖𝑛(𝑖)
=
=p
𝛽
𝛼
(3)
if β < α, there can be critical reflection and horizontal propagating p-wave. If j > jc then there
will be evanescence in the p-wave ( p > 1/ α).
‘P
S
P
S’
Both p-wave and s-wave horizontal propagation if p ο€Ύ
1
ο€Ύ
1
ο€½
1
. If a wave comes in with a
c
 
1/c that is larger than local 1/α and 1/β, the above will occur. This will also happen if the source
emits a horizontal energy (rare).
𝑃: ∅ = 𝐴𝑒π‘₯𝑝 −πœ”πœ‚π›Ό 𝑧 𝑒π‘₯𝑝 π‘–πœ”(𝑝π‘₯ − 𝑑 ), πœ‚π›Ό =
𝑖
1 2
𝑐
−
1 2
𝛼
1
𝛼2
1
− 𝑝2 = 𝑖 𝑝2 − 𝛼 2 = π‘–πœ‚π›Ό =
1
𝛼
𝑝>
1
; where 𝑐 = 𝑐𝑅 = 𝑝 (𝑐𝑅 : phase velocity for Rayleigh waves)
𝑆: πœ“ = 𝛽𝑒π‘₯𝑝 −πœ”πœ‚π›½ 𝑧 𝑒π‘₯𝑝 π‘–πœ”(𝑝π‘₯ − 𝑑 ), πœ‚π›½ =
1
1
− 𝑝2 = 𝑖 𝑝2 − 2 = π‘–πœ‚π›½
2
𝛽
𝛽
1
𝑝>
𝛽
=𝑖
1
𝑐
2
1
−
𝛽
2
3
(4)
(5)
12.510
April, 8, 2008
We follow the same “Recipe” we used before:
1. Potentials
2. Boundary Conditions (Kinematic and dynamic)
3. Zoeppritz equatios.
Boundary conditions
𝑒 π‘₯, 𝑑 = 𝛻∅ + 𝛻 × πœ“
(6)
In this case
𝑅/ \ , 𝑅/ \ , 𝑅 / \ , 𝑅 /
𝑠 𝑠
𝑠 𝑝
𝑝 𝑠
\
𝑝 𝑝
(7)
After some work we get:
𝐴 πœ† + 2πœ‡ πœ‚π›Ό2 + πœ†π‘2 + 2πœ‡π‘πœ‚π›½ = 0
𝐴 2π‘πœ‚π›Ό + 𝐡 𝑝2 − πœ‚π›½2 = 0
(9)
Zoepprtiz
πœ† + 2πœ‡ πœ‚π›Ό2 + πœ†π‘2
2πœ‡π‘πœ‚π›½
2π‘πœ‚π›Ό
𝑝2 − πœ‚π›½2
0
𝐴
=
0
𝐡
(10)
Trivial solution is
𝑨=𝑩=𝟎
Non-trivial solution leads to:
πœ† + 2πœ‡ πœ‚π›Ό2 + πœ†π‘2 𝑝2 − πœ‚π›½2 − 2π‘πœ‚π›Ό (2πœ‡π‘πœ‚π›½ ) = 0
(11)
This expression; Rayleigh wave denominator (Rayleigh, 1887), can be written looking at
wave speeds, but usually done numerically assuming a Poisson’s medium (λ=μ) and
 ο€½ 3 . This scaling will help to simplify the above equation.
𝟏
𝟏
−
𝟐
𝜢
𝒄
𝟐
𝜼𝜢 =
𝟏
− π’‘πŸ =
𝜢𝟐
𝟏
𝟏
−
𝜷𝟐
𝒄
𝟐
𝜼𝜷 =
𝟏
− π’‘πŸ =
𝜷𝟐
4
(12)
12.510
𝜢=
April, 8, 2008
𝝀 + 𝟐𝝁
𝝆
οƒ° π†πœΆπŸ = 𝝀 + 𝟐𝝁
𝜷=
𝝁
𝝆
οƒ° π†πœ·πŸ = 𝝁
𝜢𝟐
𝜼𝟐𝜢
+ 𝟏 − 𝟐𝜷𝟐
π†πŸ
𝟏−
𝜼𝟐𝜷
π†πŸ
οƒ°
−
πŸ’πœ·πŸ 𝜼𝜢 𝜼𝜷
π†πŸ
𝜷
𝜢
Assumptions
Poisson medium:𝝀 = 𝝁
𝝀
Poisson ratio: 𝑽 = 𝟐(𝝀+𝝁) = 𝟎. πŸπŸ“
𝜢 = πŸ‘πœ·
π’„πŸπ‘Ή
𝜷𝟐
πŸ‘
π’„πŸπ‘Ή
−πŸ– 𝟐
𝜷
𝟐
+
πŸ“πŸ” π’„πŸπ‘Ή
πŸ‘ 𝜷𝟐
−
πŸ‘πŸ
=𝟎
πŸ‘
Three solutions
1.
𝒄 𝟐
𝜷
𝟏
𝟏
𝟏
= πŸ’  𝒄 = 𝟐𝜷, 𝒄 > 𝜷, 𝒑 = 𝒄 < 𝒑, 𝒑 < 𝜢
j
\
𝑃
i
/
𝑆
\
𝑆
5
=𝟎
12.510
2.
April, 8, 2008
𝒄 𝟐
𝜷
𝟐
𝟏
𝟏
𝟐
= 𝟐 + πŸ‘ πŸ‘, 𝜢 < 𝒑 < 𝜷, π’„πŸ = (𝟐 + πŸ‘ πŸ‘)𝜷𝟐
\
𝑃
/
𝑆
3.
𝒄 𝟐
𝜷
= (𝟐 −
𝟐
πŸ‘
πŸ‘),
𝟏
𝜢
\
𝑆
𝟏
<𝒑< ,𝒄=
𝜷
𝟐+
𝟐
πŸ‘
𝟏
𝟏
𝒄
𝜷
πŸ‘, 𝒄 < 𝜷, 𝒑 = >
𝟏
> , (𝜼𝜢 = π’ŠπœΌπœΆ , 𝜼𝜷 = π’ŠπœΌπœ· )
𝜢
\
𝑃
\
𝑆
/
𝑆
Note: cR ~ 0.92β which makes it about 10% slower than the shear wave velocity. This explains
why the Rayleigh wave is slower than the love wave. The Love wave, at low frequency οƒ  c2
and at high frequencies Love wave (at it’s slowest) is c1…Rayleigh wave is about 90% of the
Love wave at the most.
exponential decay with depth
∅ = 𝐴𝑒π‘₯𝑝 −πœ”πœ‚π›Ό 𝑧 𝑒π‘₯𝑝 π‘–πœ”(𝑝π‘₯ − 𝑑 )
πœ“ = 𝛽𝑒π‘₯𝑝 −πœ”πœ‚π›½ 𝑧 𝑒π‘₯𝑝 π‘–πœ”(𝑝π‘₯ − 𝑑 )
(13)
𝑒 = 𝛻∅ + 𝛻 × πœ“
ux =
∂∅
∂x
∂ψ
− ∂z ; uz =
∂∅
∂z
∂ψ
− ∂x
(14)
ux ~A sin kx − ωt …
𝝅
𝒖𝒙 , 𝒖𝒛 are 𝟐 out of phase
uz ~A cos kx − ωt …
Updated by: Sami Alsaadan
Sources: April 13, 2008 by Patricia Gregg. April 8, 2008 lecture.
“An Introduction to Seismology, Earthquakes, And Earth Structure” by Stein &Wysession
(2007).
6
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