Department of Materials Science and Engineering Massachusetts Institute of Technology

advertisement
Department of Materials Science and Engineering Massachusetts Institute of Technology 3.14 Physical Metallurgy – Fall 2008 Quiz I Friday, October 10, 2008 The Rules:
1) No calculators allowed
2) One hand written 3x5 index card may be prepared as a crutch
3) Complete 4 out of the 5 problems. If you do more than 4 problems, I will grade the first
4 that are not crossed out. 4) Make sure that you READ THE QUESTIONS CAREFULLY 5) Supplementary materials are attached to the end of the test (eqns., etc.) 6) WRITE YOUR NAME HERE:
Problem #1: Superdislocations!
In pure metals there is only one kind of atom, and the Burger’s vector is therefore always one
atomic spacing. What about in a chemically ordered, two-component solid (for example, NaCl,
SiC, CuAu)? Here is a 2-D picture of an ordered solid.
Part A: Draw a 2-D picture of a full edge dislocation in such an
ordered solid. (Reminder- a full edge dislocation leaves the crystal
undisturbed far away from the core)
Part B: Draw a Burger’s circuit around your full edge dislocation and
label the Burger’s vector.
Part C: Do you think that this full dislocation would like to
dissociate? Describe the forces/energetics involved in the choice of whether dissociation occurs
or not. If yes, explain why and draw a picture of it. If no, explain why not.
Problem #2: FCC or BCC?
Three different crystals, all of which are cubic (either FCC or BCC) are strained, and the
orientation of the crystal is tracked. Each of them is strained in compression.
In the stereographic projections below, the results of these tests are shown. Identify whether you
think the crystal is FCC or BCC, and explain briefly why in each case.
Problem #3: Unphysics
Each of these scenarios is unphysical. Explain what is wrong in each case, and correct it to make
it physically correct. In each drawing, the arrow denotes the Burger’s vector.
A) The small crystal at the left is stressed as shown. One dislocation moves to the right,
intersecting another dislocation and leaving the structure shown at the right.
B) A single crystal is loaded in tension, and slip happens on two planes as shown.
Dislocations run into each other and form a Lomer lock on the red line.
C) In the microscope, a dislocation loop is observed. The Burger’s vector is not known.
Over time, the loop expands spontaneously with no external load applied to the sample,
due to the repulsive forces exerted by different parts of the loop on one another.
D) A small crystal contains a bunch of parallel dislocations, and is strained in tension. The
dislocations move in the directions shown by the red arrows. The Burger’s vectors are
shown by the black arrows
┴
┴
┴
S~
Problem 4: Wherein the Student Demonstrates Knowledge of Both the Stereographic
Projection and Inter-Dislocation Forces
Here are two dislocations in a crystal. The coordinate system
is defined to lie on one of them, as shown. They lie in
different planes.
y
Now, notice that for the right dislocation, the Burger’s vector
is defined—it is a screw dislocation.
For the dislocation on the left, the Burger’s vector is
undefined. It can lie in any direction. In fact, it could lie
anywhere on the stereographic projection.
y
z
x
x
z
Part A:
Allow the Burger’s vector of the left dislocation to vary
over the stereographic projection at the left. On the
projection, indicate how the interactive forces between
the dislocations change with position in the projection.
More specifically, draw in regions where the
dislocations would be attracted to each other, repulsed
from one another, or non-interacting.
Part B:
y
z
x
Now add some more details to the projection: for
regions where the dislocations are attracted or repelled,
please mark regions of the diagram in which they will
actually move in response to the interaction, and
regions in which they will not move despite the forces
they feel. A second copy of the diagram is provided if
you need extra/clean space to work.
Problem 5: Frank-Read Redux
A dislocation segment is pinned at two pinning points, and is experiencing external stress that
encourages bowing. Its Burger’s vector is shown. This is the situation we covered in class that
led to the Frank-Read Source.
partials
Full Burger’s vector
Projection view
Top down view
Consider what happens if this is not a full dislocation, but rather is split into partials. For the full
dislocation, the bowing goes until a local annihilation event occurs. How does this annihilation
look for the dissociated dislocation? Draw some pictures and briefly walk though the sequence
of events.
Helpful (?) Bonus Information
Stress field around an edge dislocation:
σ xx = −
σ yy =
σ xy =
μb
y(3x 2 + y 2 )
2π (1−ν ) (x 2 + y 2 ) 2
μb
y(x 2 − y 2 )
2π (1 −ν ) ( x 2 + y 2 ) 2
μb
x(x 2 − y 2 )
2π (1−ν ) (x 2 + y 2 ) 2
σ zz = ν (σ xx + σ yy )
all other σ components are = 0.
Stress field around a screw dislocation:
σ rz =
μb
2πr
all other σ components are = 0, and note that r2 = x2+y2
Forces between dislocations:
Parallel edge:
μb 2 y(3x 2 + y 2 )
Fy =
2π (1 − ν ) (x 2 + y 2 ) 2
μb 2
x(x 2 − y 2 )
2π (1 − ν ) (x 2 + y 2 ) 2
Parallel screw:
μb 2
Fr =
2πr
Fx =
Inspirational Quote:
“The dislocation plays a commanding role in those grandest of all deformations on Earth: the
upheavals that have produced the mountain ranges and the continents themselves”
Johannes and Julia Weertman, pioneers in dislocation theory, 1964
9/21/2009
023
012
113
011
001
014
013
104
103
114
113
123
014
013
012
023
114
113 123
011
102
213 112
032
133
203
122
132
101 313
021
212
021
132
212
111
111
121
031
031
121
312 313 302 312
131
131
201
221
211
041
041
211
231
221
141
141
231
311 301
311
401
331 321
321 331
110 120 140
140 120 110
210 410 100 410 210
010
010
310 320
230 130
130 230
320 310
311 321 331
331
301
231
231
311
141
211
321
141
221
041
201
221
041
211
131
131
312 302 312
031
121
031
121
111 313 101 212
111
132
132
021
212
313
021
122
122
213 203
133
032
032
213 112
112
133
102
113
113 123
103
123
011
011
114 104 114
023
023
012
012
013
013 014
014
001
133
122
032
112
213
Figure by MIT OpenCourseWare.
112
123
213
011
023
132
331
221
121
113
114
012
013
104
014
123
203
103
101
102
001 114 113
313
213
312
212
211
112
311
113 114 104
014
411
103 114 013
141
111
123 111
213
231
321
012
212
102
113
221
023
221
122
313 203
112
331
133
331
312
123
213
011 132
101
321
313
121
211
133 032
231
212
302
122
201 312
110
111 132 021
110
311
131
320
031
301
121
411 401
211 221
131
041 141
230
310
311
141
410
120
140
411 321 331 231
210
130
310 320 110 120 140
100
010
410
141
411
231
321
230 130
210
131
411
141 041
411
321 331
401
231
311
311
131
031
301
121
211
221
211
121
021
201
131
112
312
302
101
312
212
313
213
111
114
132
221
113
112
032
132
331
011
123
Figure by MIT OpenCourseWare.
4
MIT OpenCourseWare
http://ocw.mit.edu
3.40J / 22.71J / 3.14 Physical Metallurgy
Fall 2009
For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.
Download