Linear Algebra 2270 Ivlidterm 3 Group A 08/06/2015 Solve 4 out of 6 problems: 1. Find the LU factorization the following matrix —1 1 2 A= 0 1 —2 1 1 1 Usiiig the factorization, find the determinant of A and its rank. 2. Find the rank and the inverse of the following matrix: 0 A= 1 2 1 1 —2 1 1 2 3. Find the determinant aiid the rank of the following matrix: 2 2 A— 2 2 — 2 4 —1 —1 3 —3 1 0 1 1 0 1 4. What is the definitioii of (a) rank of a matrix (b) orthonormal vectors 5. Prove that the set of 6. Matrix A E symmetric matrices is a subspace IR is called symmetric positive of definite (SPD) if (a) A is symmetric (b) for any x e R, if x * then Prove that if A is SPD tlieii , xTAx > 0 (x,y) is an inner prodnct. = yTAx — 0 0-0 I’ —o — ‘I — 1 I,, I I, I 0 - -7 S I 0 0 - 0 — — w I —öo — — iJ N— ) __:_____z c . N 0 __ ‘p (I cc: I, 0 — rJ — L) S -t I -4i L “ L. — -, r 0 ck ‘ S. — n c’ -, fc- 4., cc,, ‘ - - p , -X v,, cJ v - 0 r— ‘— ‘S H -r 4- * -1-. I, i0 r £\ 4 — ‘- ç L\3 gr’ i’ II 3 -c: Li. it (, — —4- C 0 X 1’ -‘ - < 0 — (—I :5-, - -‘ >( F—’ - 3: - > H U - 0 i — ci : H N A _1.- _.-_.___1 U - U — -z. - - c -i .) Linear Algebra 2270 Midterm 3 Group B 08/06/2015 Solve 4 out of 6 problems: 1. Find the LU factorization the following matrix —1 1 3 A= 0 1 —2 1 1 1 Using the factorization, find the determinant of A and its rank. 2. Find the rank and the inverse of the following matrix: 011 —1 —1 2 —2 2 A= —1 3. Find the determinant and the rank of the following matrix: A = 2 2 2 2 3 —3 1 0 2 4 —1 —1 1 1 0 1 4. What is the definition of (a) linearly independent vectors (b) inverse of a matrix 5. Prove that the set of symmetric matrices is a subspace of R>< 6. Consider a linear system Ax = b with infinitely niany 0 Ax = solutions. Let xo be a solution of this system: b Prove that the solution set of this linear system may be written as { x + x : Ax = 1 —d--- 0 IL —0 c3 I I - c 00 C. o - - - Ii L Lc c 4 -- J - U, N — — —Hi LI _ — ‘4 L — I, F sJ 0 C Il ‘I -i -1 I, -4- 1- L. 0 I, -1 —1 ;z. —I 1 ‘) — - c— • cD H Vs— -.f 1 -, it I — -- Th 0 — -1 -h 0 ‘I’ _•% ‘.- 3 N — r— , L çJ 2. z -1- e S. C C ‘I U o c cr L V O 0 4-. .4- 0 >c. x k c—c z Cr ,s I) 0 - -c- -I .- 0 I., —- ri’e -f ‘.— ‘I , c t ‘) ‘F., * 1 ç7: ‘. —. p c-I I, 7:) Lñ I, cm’ -?- \j Lf’ .:: i ‘\.z - —. c • r D rv