Document 11692137

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Osmosis
Diffusion
Active
transport
Passive
transport
Endocytosis
Grab Bag
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500
List the forms of transport
that do not require energy.
(3)
A 100
Diffusion
Osmosis
Facilitated diffusion
A 100
AS a result of diffusion, the concentration os
substances will reach ____.
A 200
Equilibrium
A 200
What process is being
illustrated?
A 300
Diffusion
A 300
Red blood cells have a salt
concentration of 0.9%. If they
were placed in pure what, what
net movement of water will occur
due to osmosis?
A 400
Water moves
into the cell
A 400
A 500
Into the cell
through the
channel
A 500
The diffusion of water
into or out of the cell is
called ___.
B 100
osmosis
B 100
A cell will swell if it is
placed in a(n)_______
solution
B 200
hypotonic
B 200
Proteins that act like
selective passageways
in the cell membrane
are known as ____
B 300
Channel
proteins
B 300
Sugar molecules pass
through the cell membrane
via
B 400
Facilitated
diffusion
B 400
What kind of substances can
move through the cell membrane
unaided?
B 500
Small, nonpolar molecules
B 500
Unlike passive
transport, active
transport requires____.
C 100
Energy
C 100
A scientist places a cell in
a solution, and over time
the cell gains mass and
swells. What is most
likely the explanation for
the cell’s gain in mass?
C 200
The solution is
hypotonic to the
cell.
C 200
List two forms of active
transport.
C 300
1.) Endocytosis
(phagocytosis, carrier
mediated endocytosis,
pinocytosis)
2.) Exocytosis
3.) Sodium-potassium
pump
C 300
DAILY
Place A Wager
DOUBLE
C 400
The saline solution in an IV
bag is a ______ solution to
your blood cells. This way, the
net movement of water into or
out of the blood cells is zero
and they do not shrink or
swell.
C 400
Isotonic
C 400
Ridding the cells of materials
by discharging the materials
in vesicles is called _____.
C 500
Exocytosis
C 500
Molecules that are too
large to be moved
through the membrane
can be transported into
the cell by ____.
D 100
Endocytosis
D 100
What is the double
layer that makes up a
cell membrane called?
D 200
Phospholipid
bilayer
D 200
What is the difference
in concentration of a
substance across a
region?
D 300
Concentration
gradient
D 300
The cell membrane is ______ because it
allows for the passage of some substances but
not others.
D 400
Semi-permeable
D 400
A cell shrinks when it is in a(n)
_____
Solution.
D 500
hypertonic
D 500
___ is a form of passive
transport that involves
membrane channel
proteins that aid in the
movement of substances
down their concentration
gradient.
E 100
Facilitated
diffusion
E 100
Plant cells are
healthiest in a ____
solution
E 200
hypotonic
E 200
Paramecia live in a hypotonic
environment. How do they
overcome being constantly
flooded with water?
E 300
Contractile vacuole
E 300
What is occurring in the picture
above?
E 400
Carrier mediated
endocytosis
E 400
What process is occurring
in the illustration?
E 500
Exocytosis
E 500
The discharging of
molecules outside the sell
membrane is called:
F 100
exocytosis
F 100
The process of a cell
importing a material
that does not have to
be recognized is
called?
F 200
Phagocytosis
F 200
Why is osmoregulation
important to a cell?
F 300
To maintain the water balance in
the cell.
F 300
If something happened to a
paramecium that caused its
contractile vacuole to stop
contracting, one would expect it to
burst due to overwhelming flooding
of water. Would this result occur
more quickly if the paramecium was
in water with a high salt
concentration or in water with a low
salt concentration?
F 400
Water with a low salt
concentration
F 400
Salt
Very high
High
Medium
Low
Very low
Rate of contractile
vacuole
contractions/minute
2
8
15
22
30
How can you
explain the
observed
relationship
between salt
concentration
and rate of
contractile
vacuole
contraction?
F 500
As salt concentration increases,
there is less water flooding the
cell due to osmosis (the solution
is hypotonic to the cell, but
becomes less so as the
concentration of salt increases) ,
therefore the contractile vacuole
does not need to contract as often.
F 500
The Final Jeopardy Category is:
Diffusion
Please record your wager.
Click on screen to begin
A selectively permeable
membrane separates the solutions
in the arms of the U-tube shown
below. The membrane is
permeable to the water and to
solute A but not to solute B. Forty
grams of substance A and 20
grams of substance B have been
added to the water on side 1 of the
U – tube. Twenty grams of
substance A and forty grams of
substance B have been added to
the water on side 2 of the U-tube.
When the system
reaches
equilibrium, how
many grams of
substance A will
be on solution on
side 1 of the Utube?
Click on screen to continue
30 grams of solute A
will be in side 1 at the
end of the experiment
Click on screen to continue
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