(1)

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PHYSICS 140B : STATISTICAL PHYSICS

HW ASSIGNMENT #2 SOLUTIONS

(1) For each of the cluster diagrams in Fig. 1, find the symmetry factor s

γ expression for the cluster integral b

γ

.

and write an

(a) (b) (c) (d)

Figure 1: Cluster diagrams for problem 1.

Solution : Choose labels as in Fig. 2, and set x n

γ definition of b

γ

.

≡ 0 to cancel out the volume factor in the

2 2 3 3

1 5 1 5

1 1

4 5 4 5

2 6 2 6

3 3

4 4

(a) (b) (c) (d)

Figure 2: Labeled cluster diagrams.

(a) The symmetry factor is s

γ

= 2 , so b

γ

=

1

2

Z d d x

1

Z d d x

2

Z d d x

3

Z d d x

4 f ( r

12

) f ( r

13

) f ( r

24

) f ( r

34

) f ( r

4

) .

(b) Sites 1, 2, and 3 may be permuted in any way, so the symmetry factor is s

γ then have b

γ

=

1

6

Z d d x

1

Z d d x

2

Z d d x

3

Z d d x

4 f ( r

12

) f ( r

13

) f ( r

24

) f ( r

34

) f ( r

14

) f ( r

23

) f ( r

4

= 6

) .

. We

(c) The diagram is symmetric under reflections in two axes, hence s

γ

= 4 . We then have b

γ

=

1

Z

4 d d x

1

Z d d x

2

Z d d x

3

Z d d x

4

Z d d x

5 f ( r

12

) f ( r

13

) f ( r

24

) f ( r

34

) f ( r

35

) f ( r

4

) f ( r

5

) .

(d) The diagram is symmetric with respect to the permutations (12) , (34) , (56) , and (15)(26) .

Thus, s

γ

= 2 4 = 16 . We then have b

γ

=

1

16

Z d d x

1

Z d d x

2

Z d d x

3

Z d d x

4

Z d d x

5 f ( r

12

) f ( r

13

) f ( r

14

) f ( r

23

) f ( r

24

) f ( r

34

) f ( r

35

) f ( r

45

) f ( r

3

) f ( r

4

) f ( r

5

) .

1

(2) Compute the partition function for the one-dimensional Tonks gas of hard rods of length a on a ring of circumference L . This is slightly tricky, so here are some hints. Once again, assume a particular ordering so that x

1

< x

2

< · · · < x

N

. Due to translational invariance, we can define the positions of particles { 2 , . . . , N } relative to that of particle 1 , which we initially place at one then has x

1

= 0 . Then periodicity means that x

N

≤ L − a , and in general x j

− 1

+ a ≤ x j

≤ L − ( N − j + 1) a .

Now integrate over { x

2

, . . . , x

N

} subject to these constraints. Finally, one does the x

1 integral, which is over the entire ring, but which must be corrected to eliminate overcounting from cyclic permutations. How many cyclic permutations are there?

Solution :

There are N cyclic permutations, hence

Z ( T, L, N ) = λ −

N

T

L

N

Z

Y

2 dx

2

Z

Y

3 dx

3 a x

2

+ a

· · ·

Y

N

Z dx

N

=

L ( L − N a ) N − 1 λ − N

T

N !

x

N

1

+ a

.

(3) Consider a three-dimensional gas of point particles interacting according to the potential u ( r ) =

+∆

0

− ∆

1

 0 if r ≤ a if a < r ≤ b if b < r , where ∆

0 , 1 are both positive. Compute the second virial coefficient B

2

( T tion which determines the inversion temperature in a throttling process.

) and find a rela-

Solution :

The Mayer function is f ( r ) =

 e −

0 e ∆

1

/k

B

T

/k

B

T

− 1 if r ≤ 0

− 1 if a < r ≤ b

 0 if b < r .

The second virial coefficient is

B

2

( T ) = −

1

2

Z d

3 r f ( r )

=

2 πa 3

3

· 1 − e − ∆

0

/k

B

T

+ ( s

3

− 1) 1 − e

1

/k

B

T

,

2

where s = b/a . The inversion temperature is a solution of the equation B

2

( T ) = T B ′

2

( T ) , which gives s

3

− 1 =

1 +

1 +

0 k

B

T

1 k

B

T

− 1 e − ∆

0

/k

B

T

+ 1 e

1

/k

B

T

.

3

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