Hindawi Publishing Corporation Abstract and Applied Analysis Volume 2011, Article ID 927690, 15 pages doi:10.1155/2011/927690 Research Article Oscillation of Second-Order Neutral Functional Differential Equations with Mixed Nonlinearities Shurong Sun,1, 2 Tongxing Li,1, 3 Zhenlai Han,1, 3 and Yibing Sun1 1 School of Science, University of Jinan, Jinan, Shandong 250022, China Department of Mathematics and Statistics, Missouri University of Science and Technology, Rolla, MO 65409-0020, USA 3 School of Control Science and Engineering, Shandong University, Jinan, Shandong 250061, China 2 Correspondence should be addressed to Shurong Sun, sshrong@163.com Received 2 September 2010; Revised 26 November 2010; Accepted 23 December 2010 Academic Editor: Miroslava Růžičková Copyright q 2011 Shurong Sun et al. This is an open access article distributed under the Creative Commons Attribution License, which permits unrestricted use, distribution, and reproduction in any medium, provided the original work is properly cited. We study the following second-order neutral functional differential equation with mixed α−1 nonlinearities rt|ut ptut − σ |α−1 ut ptut − σ q0 t|uτ ∞0 t|1/α uτ0 t β−1 γ−1 q1 t|uτ1 t| uτ1 t q2 t|uτ2 t| uτ2 t 0, where γ > α > β > 0, t0 1/r tdt < ∞. Oscillation results for the equation are established which improve the results obtained by Sun and Meng 2006, Xu and Meng 2006, Sun and Meng 2009, and Han et al. 2010. 1. Introduction This paper is concerned with the oscillatory behavior of the second-order neutral functional differential equation with mixed nonlinearities α−1 ut ptut − σ rt ut ptut − σ q0 t|uτ0 t|α−1 uτ0 t q1 t|uτ1 t|β−1 uτ1 t q2 t|uτ2 t|γ −1 uτ2 t 0, 1.1 t ≥ t0 , where γ > α > β > 0 are constants, r ∈ C1 t0 , ∞, 0, ∞, p ∈ Ct0 , ∞, 0, 1, qi ∈ Ct0 , ∞, Ê, i 0, 1, 2, are nonnegative, σ ≥ 0 is a constant. Here, we assume that there exists τ ∈ C1 t0 , ∞, Ê such that τt ≤ τi t, τt ≤ t, limt → ∞ τt ∞, and τ t > 0 for t ≥ t0 . 2 Abstract and Applied Analysis One of our motivations for studying 1.1 is the application of this type of equations in real word life problems. For instance, neutral delay equations appear in modeling of networks containing lossless transmission lines, in the study of vibrating masses attached to an elastic bar; see the Euler equation in some variational problems, in the theory of automatic control and in neuromechanical systems in which inertia plays an important role. We refer the reader to Hale 1 and Driver 2, and references cited therein. Recently, there has been much research activity concerning the oscillation of secondorder differential equations 3–8 and neutral delay differential equations 9–20. For the particular case when pt 0, 1.1 reduces to the following equation: rt|ut|α−1 ut q0 t|uτ0 t|α−1 uτ0 t β−1 q1 t|uτ1 t| uτ1 t q2 t|uτ2 t| 1.2 γ −1 uτ2 t 0, t ≥ t0 . Sun and Meng 6 established some oscillation criteria for 1.2, under the condition ∞ t0 1 dt < ∞, r 1/α t 1.3 they only obtained the sufficient condition 6, Theorem 5, which guarantees that every solution u of 1.2 oscillates or tends to zero. Sun and Meng 7 considered the oscillation of second-order nonlinear delay differential equation α−1 rtu t u t q0 t|uτ0 t|α−1 uτ0 t 0, 1.4 t ≥ t0 and obtained some results for oscillation of 1.4, for example, under the case 1.3, they obtained some results which guarantee that every solution u of 1.4 oscillates or tends to zero, see 7, Theorem 2.2. Xu and Meng 10 discussed the oscillation of the second-order neutral delay differential equation α−1 rt ut ptut − τ qtfuσt 0, ut ptut − τ t ≥ t0 1.5 and established the sufficient condition 10, Theorem 2.3, which guarantees that every solution u of 1.5 oscillates or tends to zero. Han et al. 11 examined the oscillation of second-order neutral delay differential equation α−1 rtψut ut ptut − τ qtfuσt 0, ut ptut − τ t ≥ t0 1.6 Abstract and Applied Analysis 3 and established some sufficient conditions for oscillation of 1.6 under the conditions 1.3 and σt ≤ t − τ. 1.7 The condition 1.7 can be restrictive condition, since the results cannot be applied on the equation 1 1 λ e2t e2t2 ut − 1 0, e2t ut ut − 2 2 2 t ≥ t0 . 1.8 The aim of this paper is to derive some sufficient conditions for the oscillation of solutions of 1.1. The paper is organized as follows. In Section 2, we establish some oscillation criteria for 1.1 under the assumption 1.3. In Section 3, we will give three examples to illustrate the main results. In Section 4, we give some conclusions for this paper. 2. Main Results In this section, we give some new oscillation criteria for 1.1. Below, for the sake of convenience, we denote zt : ut ptut − σ, t ξt : r 1/α τt t1 t Rt : 1 rτs α Q0 t : 1 − pτ0 t q0 t, t0 1/α 1 r 1/α s ds, τ sds, β Q1 t : 1 − pτ1 t q1 t, γ Q2 t : 1 − pτ2 t q2 t, ζ0 t : q0 t 1 1 p ρt α , ζ2 t : q2 t h0 t : q0 t 1 1 pt α 1 1 p ρt ζ1 t : q1 t γ 1 1 p ρt , , h2 t : q2 t h1 t : q1 t 1 1 pt γ , 1 1 pt β , β , 4 Abstract and Applied Analysis δt : ∞ ρt 1 ds, 1/α r s ϕt : q0 t πt : δt 1 p ρt ∞ t α q1 t 1 r 1/α s k1 : ds, γ −β , γ −α β δt 1 p ρt q2 t k2 : δt 1 p ρt γ −β , α−β γ . 2.1 Theorem 2.1. Assume that 1.3 holds, p t ≥ 0, and there exists ρ ∈ C1 t0 , ∞, Ê, such that ρt ≥ t, ρ t > 0, τi t ≤ ρt − σ,i 0, 1, 2. If for all sufficiently large t1 , ∞ ατ tRα−1 τtr 1−1/α τt 1/k1 1/k2 dt ∞, R τt Q0 t k1 Q1 t − k2 Q2 t ξα t α 2.2 ∞ α ζ0 t k1 ζ1 t1/k1 k2 ζ2 t1/k2 δα t − α1 α1 ρ t dt ∞, δtr 1/α ρt 2.3 then 1.1 is oscillatory. Proof. Suppose to the contrary that u is a nonoscillatory solution of 1.1. Without loss of generality, we may assume that ut > 0 for all large t. The case of ut < 0 can be considered by the same method. From 1.1 and 1.3, we can easily obtain that there exists a t1 ≥ t0 such that zt > 0, z t > 0, α−1 rtz t z t ≤ 0, 2.4 α−1 rtz t z t ≤ 0. 2.5 or zt > 0, z t < 0, If 2.4 holds, we have α α rt z t ≤ rτt z τt , t ≥ t1 . 2.6 From the definition of z, we obtain ut zt − ptut − σ ≥ zt − ptzt − σ ≥ 1 − pt zt. 2.7 Define ωt Rα τt rtz tα , zτtα t ≥ t1 . 2.8 Abstract and Applied Analysis 5 Then, ωt > 0 for t ≥ t1 . Noting that z t > 0, we get zτi t ≥ zτt for i 0, 1, 2. Thus, from 1.1, 2.7, and 2.8, it follows that α ατ tRα−1 τt rtz tα α α − R τt 1 − pτ0 t q0 t 1/α r τt zτt ω t ≤ β γ − Rα τt 1 − pτ1 t q1 tzβ−α τt 1 − pτ2 t q2 tzγ −α τt − αRα τt rtz tα zτtα1 2.9 z τtτ t. By 2.4, 2.9, and τ t > 0, we get ω t ≤ α ατ tRα−1 τt rtz tα α α − R τt 1 − pτ0 t q0 t 1/α r τt zτt β γ − Rα τt 1 − pτ1 t q1 tzβ−α τt 1 − pτ2 t q2 tzγ −α τt . 2.10 In view of 2.4, 2.6, and 2.10, we have ω t ≤ α ατ tRα−1 τt rτtz τtα − Rα τt 1 − pτ0 t q0 t α 1/α r τt zτt β γ − Rα τt 1 − pτ1 t q1 tzβ−α τt 1 − pτ2 t q2 tzγ −α τt . 2.11 By 2.4, we obtain zτt zτt1 zτt1 t t1 z τsτ sds t t1 1 rτs ≥ r 1/α τtz τt t t1 1/α α 1/α rτs z τs τ sds 1 rτs 1/α 2.12 τ sds, that is, zτt ≥ ξtz τt. 2.13 Set 1/k1 , a : k1 Q1 tzβ−α τt 1/k2 b : k2 Q2 tzγ −α τt , p : k1 , q : k2 . 2.14 6 Abstract and Applied Analysis Using Young’s inequality |ab| ≤ 1 p 1 q |a| |b| , p q 1 1 1, p q a, b ∈ Ê, p > 1, q > 1, 2.15 we have Q1 tzβ−α τt Q2 tzγ −α τt ≥ k1 Q1 t1/k1 k2 Q2 t1/k2 . 2.16 Hence, by 2.11, 2.13, and 2.16, we obtain ω t ≤ ατ tRα−1 τtr 1−1/α τt 1/k1 1/k2 α Q . Q Q − R τt t k t k t 0 1 1 2 2 ξα t 2.17 Integrating 2.17 from t1 to t, we get 0 < ωt ≤ ωt1 , − t t1 2.18 ατ sRα−1 τsr 1−1/α τs 1/k1 1/k2 ds. R τs Q0 s k1 Q1 s − k2 Q2 s ξα s 2.19 α Letting t → ∞ in 2.19, we get a contradiction to 2.2. If 2.5 holds, we define the function υ by υt rt−z tα−1 z t , zα ρt t ≥ t1 . 2.20 Then, υt < 0 for t ≥ t1 . It follows from rt|z t|α−1 z t ≤ 0 that rt|z t|α−1 z t is nonincreasing. Thus, we have r 1/α sz s ≤ r 1/α tz t, s ≥ t. 2.21 Dividing 2.21 by r 1/α s and integrating it from ρt to l, we obtain zl ≤ z ρt r 1/α tz t l ρt ds r 1/α s , l ≥ ρt. 2.22 Letting l → ∞ in the above inequality, we obtain 0 ≤ z ρt r 1/α tz tδt, t ≥ t1 , 2.23 Abstract and Applied Analysis 7 that is, z t r 1/α tδt ≥ −1, z ρt t ≥ t1 . 2.24 Hence, by 2.20, we have −1 ≤ υtδα t ≤ 0, t ≥ t1 . 2.25 Differentiating 2.20, we get rt−z tα−1 z t zα ρt − αrt−z tα−1 z tzα−1 ρt z ρt ρ t , υ t z2α ρt 2.26 by the above equality and 1.1, we obtain υ t −q0 t uα τ0 t uβ τ1 t uγ τ2 t − q1 t α − q2 t α α z ρt z ρt z ρt 2.27 αrt−z tα−1 z tzα−1 ρt z ρt ρ t − . z2α ρt Noticing that p t ≥ 0, from 10, Theorem 2.3, we see that u t ≤ 0 for t ≥ t1 , so by τi t ≤ ρt − σ, i 0, 1, 2, we have uα τ0 t zα ρt uτ0 t u ρt p ρt u ρt − σ α 1 u ρt /uτ0 t p ρt uρt − σ/uτ0 t ≥ 1 1 p ρt uβ τ1 t zα ρt α α , uτ1 t u ρt p ρt u ρt − σ β zβ−α ρt 1 u ρt /uτ1 t p ρt u ρt − σ /uτ1 t ≥ 1 1 p ρt β zβ−α ρt , β zβ−α ρt 8 Abstract and Applied Analysis u τ2 t/z ρt α γ γ uτ2 t u ρt p ρt u ρt − σ zγ −α ρt 1 u ρt /uτ2 t p ρt u ρt − σ /uτ2 t ≥ 1 1 p ρt γ γ zγ −α ρt zγ −α ρt . 2.28 On the other hand, from rt−z tα−1 z t ≤ 0, ρt ≥ t, we obtain z ρt ≤ r 1/α t z t. r 1/α ρt 2.29 Thus, by 2.20 and 2.27, we get υ t ≤ − ζ0 t ζ1 tzβ−α ρt ζ2 tzγ −α ρt − αρ t −υtα1/α . r 1/α ρt 2.30 Set 1/k1 a : k1 ζ1 tzβ−α ρt , 1/k2 b : k2 ζ2 tzγ −α ρt , p : k1 , q : k2 . 2.31 Using Young’s inequality 2.15, we obtain ζ1 tzβ−α ρt ζ2 tzγ −α ρt ≥ k1 ζ1 t1/k1 k2 ζ2 t1/k2 . 2.32 Hence, from 2.30, we have υ t ≤ − ζ0 t k1 ζ1 t1/k1 k2 ζ2 t1/k2 − αρ t −υtα1/α , r 1/α ρt 2.33 that is, υ t ζ0 t k1 ζ1 t1/k1 k2 ζ2 t1/k2 αρ t −υtα1/α ≤ 0, r 1/α ρt t ≥ t1 . 2.34 Abstract and Applied Analysis 9 Multiplying 2.34 by δα t and integrating it from t1 to t implies that δα tυt − δα t1 υt1 α t t1 α t t1 r −1/α ρs ρ sδα−1 sυsds ζ0 s k1 ζ1 s1/k1 k2 ζ2 s1/k2 δα sds t t1 2.35 δα sρ s −υsα1/α ds ≤ 0. r 1/α ρs Set p : α 1/α, q : α 1, and a : α 1α/α1 δα 2 /α1 tυt, b : α α/α1 α 1 δ−1/α1 t. 2.36 1 . δt 2.37 Using Young’s inequality 2.15, we get −αδα−1 tυt ≤ αδα t−υtα1/α α α1 α1 Thus, − α αρ tδα−1 tυt δα t−υtα1/α ≤ αρ ρ t t α1 r 1/α ρt r 1/α ρt α1 1 δtr 1/α . ρt 2.38 Therefore, 2.35 yields δα tυt ≤ δα t1 υt1 , − t t1 α ζ0 s k1 ζ1 s1/k1 k2 ζ2 s1/k2 δα s − α1 α1 ρ s ds. δsr 1/α ρs 2.39 Letting t → ∞ in the above inequality, by 2.3, we get a contradiction with 2.25. This completes the proof of Theorem 2.1. From Theorem 2.1, when ρt t, we have the following result. Corollary 2.2. Assume that 1.3 holds, p t ≥ 0, and τi t ≤ t − σ, i 0, 1, 2. If for all sufficiently large t1 such that 2.2 holds and ∞ α h0 t k1 h1 t1/k1 k2 h2 t1/k2 π α t − α1 then 1.1 is oscillatory. α1 1 dt ∞, πtr 1/α t 2.40 10 Abstract and Applied Analysis Theorem 2.3. Assume that 1.3 holds, p t ≥ 0, and there exists ρ ∈ C1 t0 , ∞, Ê, such that ρt ≥ t, ρ t > 0, τi t ≤ ρt − σ, i 0, 1, 2. If for all sufficiently large t1 such that 2.2 holds and ∞ ζ0 t k1 ζ1 t1/k1 k2 ζ2 t1/k2 δα1 tdt ∞, 2.41 then 1.1 is oscillatory. Proof. Suppose to the contrary that u is a nonoscillatory solution of 1.1. Without loss of generality, we may assume that ut > 0 for all large t. The case of ut < 0 can be considered by the same method. From 1.1 and 1.3, we can easily obtain that there exists a t1 ≥ t0 such that 2.4 or 2.5 holds. If 2.4 holds, proceeding as in the proof of Theorem 2.1, we obtain a contradiction with 2.2. If 2.5 holds, we proceed as in the proof of Theorem 2.1, then we get 2.25 and 2.34. Multiplying 2.34 by δα1 t and integrating it from t1 to t implies that δα1 tυt − δα1 t1 υt1 α 1 α t t1 t t1 r −1/α ρs ρ sδα sυsds ζ0 s k1 ζ1 s1/k1 k2 ζ2 s1/k2 δα1 sds t t1 2.42 δα1 sρ s −υsα1/α ds ≤ 0. r 1/α ρs In view of 2.25, we have −υtδα1 t ≤ δt < ∞, t → ∞. From 1.3, we get t t1 −r −1/α ρs ρ sδα sυsds ≤ t t1 t t1 δα1 sρ s −υsα1/α ds ≤ r 1/α ρs r −1/α ρs ρ sds ρt ρt1 r −1/α udu < ∞, ρt ρt1 r −1/α udu < ∞, t −→ ∞, t −→ ∞. 2.43 Letting t → ∞ in 2.42 and using the last inequalities, we obtain ∞ ζ0 t k1 ζ1 t1/k1 k2 ζ2 t1/k2 δα1 tdt < ∞, which contradicts 2.41. This completes the proof of Theorem 2.3. From Theorem 2.3, when ρt t, we have the following result. 2.44 Abstract and Applied Analysis 11 Corollary 2.4. Assume that 1.3 holds, p t ≥ 0, τi t ≤ t − σ, i 0, 1, 2. If for all sufficiently large t1 such that 2.2 holds and ∞ h0 t k1 h1 t1/k1 k2 h2 t1/k2 π α1 tdt ∞, 2.45 then 1.1 is oscillatory. Theorem 2.5. Assume that 1.3 holds, p t ≥ 0, and there exists ρ ∈ C1 t0 , ∞, Ê, such that ρt ≥ t, ρ t > 0, τi t ≤ ρt − σ, i 0, 1, 2. If for all sufficiently large t1 such that 2.2 holds and ∞ t1 r −1/α v v t1 1/α ϕudu dv ∞, 2.46 then 1.1 is oscillatory. Proof. Suppose to the contrary that u is a nonoscillatory solution of 1.1. Without loss of generality, we may assume that ut > 0 for all large t. The case of ut < 0 can be considered by the same method. From 1.1 and 1.3, we can easily obtain that there exists a t1 ≥ t0 such that 2.4 or 2.5 holds. If 2.4 holds, proceeding as in the proof of Theorem 2.1, we obtain a contradiction with 2.2. If 2.5 holds, we proceed as in the proof of Theorem 2.1, and we get 2.21. Dividing 2.21 by r 1/α s and integrating it from ρt to l, letting l → ∞, yields z ρt ≥ −r 1/α tz t ∞ ρt r −1/α sds −r 1/α tz tδt ≥ −r 1/α t1 z t1 δt : aδt. 2.47 By 1.1, we have α q0 tuα τ0 t q1 tuβ τ1 t q2 tuγ τ2 t. rt −z t 2.48 Noticing that p t ≥ 0, from 10, Theorem 2.3, we see that u t ≤ 0 for t ≥ t1 , so by τi t ≤ ρt − σ, i 0, 1, 2, we get uτi t uτi t z ρt u ρt p ρt u ρt − σ 2.49 1 1 . ≥ u ρt /uτi t p ρt u ρt − σ /uτi t 1 p ρt Hence, we obtain α ≥ bϕt, rt −z t 2.50 12 Abstract and Applied Analysis where b min{aα , aβ , aγ }. Integrating the above inequality from t1 to t, we have t α α rt −z t ≥ rt1 −z t1 b ϕudu ≥ b t1 t t1 ϕudu. 2.51 Integrating the above inequality from t1 to t, we obtain zt1 − zt ≥ b 1/α t t1 r −1/α v v t1 1/α ϕudu dv, 2.52 which contradicts 2.46. This completes the proof of Theorem 2.5. 3. Examples In this section, three examples are worked out to illustrate the main results. Example 3.1. Consider the second-order neutral delay differential equation 1.8, where λ > 0 is a constant. Let rt e2t , pt 1/2, σ 2, q0 t λ2e2t e2t2 /2, α 1, τ0 t t − 1, q1 t q2 t 0, and τt τ0 t, then Rt ξt r 1/α τt t t0 t t1 −2t e 0 − e−2t 1 , ds 2 r 1/α s 1 rτs q0 t λ 2e2t e2t2 Q0 t , 2 4 1/α 2t−t 1 −1 e , τ sds 2 3.1 2q0 t λ 2e2t e2t2 ζ0 t . 3 3 Setting ρt t 1, we have τ0 t t − 1 ≤ ρt − σ, δt e−2t−2 /2. Therefore, for all sufficiently large t1 , ∞ ∞ ατ tRα−1 τtr 1−1/α τt 1/k1 1/k2 R τt Q0 t k1 Q1 t − dt ∞, k2 Q2 t ξα t α α ζ0 t k1 ζ1 t1/k1 k2 ζ2 t1/k2 δα t − α1 ∞ α1 ρ t dt δtr 1/α ρt λ 2e−2 1 − 3 dt ∞ 6 if λ > 3/2e−2 1. Hence, by Theorem 2.1, 1.8 is oscillatory when λ > 3/2e−2 1. 3.2 Abstract and Applied Analysis 13 Note that 11, Theorem 2.1 and 11, Theorem 2.2 cannot be applied in 1.8, since τ0 t > t − 2. On the other hand, applying 11, Theorem 3.2 to that 1.8, we obtain that 1.8 is oscillatory if λ > 3/e−2 2e−4 . So our results improve the results in 11. Example 3.2. Consider the second-order neutral delay differential equation √ √ π 65 1 1 et ut u t − 12 65et u t − arcsin 2 4 8 65 0, t ≥ t0 . 3.3 √ Let rt √et , pt 1/2, σ π/4, q0 t 12 65et , q1 t q2 t 0, α 1, τ0 t t − arcsin 65/65/8, ρt t π/4, and τt t − π/4, then t Rt t0 1 ds e−t0 − e−t , r 1/α s Q0 t √ q0 t 6 65et , 2 t 1 rτs ξt r 1/α ζ0 t √ 2q0 t 8 65et , 3 τt t1 1/α τ sds et−t1 − 1, δt e−t−π/4 . 3.4 Therefore, for all sufficiently large t1 , ∞ ∞ ατ tRα−1 τtr 1−1/α τt 1/k1 1/k2 R τt Q0 t k1 Q1 t − dt ∞, k2 Q2 t ξα t α α ζ0 t k1 ζ1 t1/k1 k2 ζ2 t1/k2 δα t − α1 ∞ α1 ρ t dt δtr 1/α ρt √ −π/4 1 dt ∞. 8 65e − 4 3.5 Hence, by Theorem 2.1, 3.3 oscillates. For example, ut sin 8t is a solution of 3.3. Example 3.3. Consider the second-order neutral differential equation t e z t e2λ∗ t uλ0 t q1 tu1/3 λ1 t q2 tu5/3 λ2 t 0, t ≥ t0 , 3.6 where zt ut ut − 1/2, λi > 0 for i 0, 1, 2, are constants, q1 t > 0, q2 t > 0 for t ≥ t0 . Let rt et , σ 1, q0 t e2λ∗ t , λ∗ max{λ0 , λ1 , λ2 }, τi t λi t, τt λt, 0 < λ < min{λ0 , λ1 , λ2 , 1}, ρt λ∗ t 1, α 1, β 1/3, and γ 5/3, then k1 k2 2, Rt ξt r 1/α τt t t1 t t0 1 rτs 1 r 1/α s 1/α ds e−t0 − e−t , 3.7 λt−t1 τ sds e − 1, δt e −λ∗ t−1 . 14 Abstract and Applied Analysis It is easy to see that 2.2 and 2.41 hold for all sufficiently large t1 . Hence, by Theorem 2.3, 3.6 is oscillatory. 4. Conclusions In this paper, we consider the oscillatory behavior of second-order neutral functional differential equation 1.1. Our results can be applied to the case when τi t > t, i 0, 1, 2; these results improve the results given in 6, 7, 10, 11. Acknowledgments The authors sincerely thank the reviewers for their valuable suggestions and useful comments that have led to the present improved version of the original paper. 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