3.7 Complex Zeros 2011 October 17, 2011 3.7 ­ Complex Zeros 0 0 0 0 0 0 0 0 0 0 Objectives: Use the conjugate pairs theorem. Find a polynomial when the zeros are given. Find zeros when some are already given. 1 3.7 Complex Zeros 2011 October 17, 2011 Warm-up: 1. Find k such that f(x) = x3 ­ kx2 + kx + 2 has the factor x ­ 2. 2. What is the remainder when f(x) = 2x20 ­ 8x10 + x ­ 2 is divided by x ­ 1? 2 3.7 Complex Zeros 2011 October 17, 2011 Review: Find the real zeros of the polynomial function and write the function in factored form. f(x) = 2x3 + 3x2 + 2x + 3 3 3.7 Complex Zeros 2011 0 0 0 0 0 0 0 0 0 October 17, 2011 Polynomial Function Degree Zeros 1 1 2 2 3 3 . . . . n n *Note: Multiple zeros are counted more than once AND complex zeros are counted. Complex Zero: A number consisting of a real part and an imaginary part, written: a + bi . 0 4 3.7 Complex Zeros 2011 October 17, 2011 0 Conjugate Pairs Theorem 0 Complex zeros of polynomial 0 functions occur in conjugate pairs. 0 If a + bi is a zero of f, 0then the complex conjugate a ­ bi is also a real zero of f. 0 0 0 0 Example: If 3 ­ i is a zero, then 3 + i must also be a zero. 0 5 3.7 Complex Zeros 2011 0 0 0 0 0 0 0 0 0 October 17, 2011 Example #1: Using the given information, find the remaining zeros of f. Degree 4; zeros: 3, 4, 4 ­ i 4 + i Degree 4; zeros: i, 1 + i ­i, 1 ­ i Degree 5; zeros: 1, ­i, 2 + i i, 2 ­ i 0 6 3.7 Complex Zeros 2011 0 0 0 0 0 0 0 0 0 October 17, 2011 Example #2: Form a polynomial f(x) with real coefficients having the given degree and zeros. Degree 4; zeros: 3, 4, 4 ­ i f(x) = (x ­ 3)(x ­ 4)(x ­(4 ­ i))(x ­ (4 + i)) f(x) = x4 ­ 15x3 + 85x2 ­ 215x + 204 0 7 3.7 Complex Zeros 2011 0 0 0 0 0 0 0 0 0 October 17, 2011 Example #3: Form a polynomial f(x) with real coefficients having the given degree and zeros. Degree 4; zeros: i, 1 + i f(x) = (x ­ i)(x + i)(x ­ (1 + i))(x ­ (1 ­ i)) f(x) = x4 ­ 2x3 + 3x2 ­ 2x + 2 0 8 3.7 Complex Zeros 2011 0 0 0 0 0 0 0 0 0 October 17, 2011 Example #4: Form a polynomial f(x) with real coefficients having the given degree and zeros. Degree 5; zeros: 1, ­i, 2 + i f(x) = x5 ­ 5x4 + 10x3 ­ 10x2 + 9x ­ 5 0 9 3.7 Complex Zeros 2011 0 0 0 0 0 0 0 0 0 October 17, 2011 Example #5 Use the given zero to find the remaining zeros. f(x) = x4 ­ 7x3 + 13x2 ­ 7x + 12 zero: ­i Step 1: Determine the number of zeros. 4 Step 2: Find the complex conjugate of the given zero. ­i, i Step 3: Write the zeros as factors and expand. (x ­ i)(x + i) x2 + ix ­ ix ­ i2 x2 ­ (­1) x2 + 1 0 10 3.7 Complex Zeros 2011 0 0 0 0 0 0 October 17, 2011 Example #5 Use the given zero to find the remaining zeros. f(x) = x4 ­ 7x3 + 13x2 ­ 7x + 12 zero: ­i Step 4: Use long division to find the remaining zeros. 2 x + 1 4 2 3 x ­ 7x + 13x ­ 7x + 12 0 0 0 0 11 3.7 Complex Zeros 2011 0 0 0 0 0 0 0 0 0 October 17, 2011 Example #5 Use the given zero to find the remaining zeros. f(x) = x4 ­ 7x3 + 13x2 ­ 7x + 12 zero: ­i Step 5: Factor if necessary to find remaining zeros. zeros: ­ i, i, 3, 4 0 12 3.7 Complex Zeros 2011 0 0 0 0 0 0 0 0 0 October 17, 2011 Example #6 Use the given zero to find the remaining zeros. f(x) = x4 ­ 7x3 + 19x2 ­ 23x + 10 zero: 2 ­ i zeros: 2 ­ i, 2 + i, 1, 2 0 13 3.7 Complex Zeros 2011 0 0 0 0 0 0 0 0 0 0 October 17, 2011 0 0 0 Homework 0 page 237 0 (3 ­ 28) skip #20 0 0 0 0 0 14