Electronic Journal of Differential Equations, Vol. 2015 (2015), No. 09, pp. 1–10. ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu ftp ejde.math.txstate.edu PARTICULAR SOLUTIONS OF GENERALIZED EULER-POISSON-DARBOUX EQUATION RAKHILA B. SEILKHANOVA, ANVAR H. HASANOV Abstract. In this article we consider the generalized Euler-Poisson-Darboux equation 2γ 2α 2β utt + ut = uxx + uyy + ux + uy , x > 0, y > 0, t > 0. t x y We construct particular solutions in an explicit form expressed by the Lauricella hypergeometric function of three variables. Properties of each constructed solutions have been investigated in sections of surfaces of the characteristic cone. Precisely, we prove that found solutions have singularity 1/r at r → 0, where r2 = (x − x0 )2 + (y − y0 )2 − (t − t0 )2 . 1. Introduction Many problems of modern mathematics and theoretical physics lead to the investigation of hypergeometric functions of many variables. In particular, problems of superstring theory [8], analytical continuations of Mellin-Barnes integrals [14] and algebraic geometry [13]. Systems of hypergeometric type differential equations have numerous applications as nontrivial model examples in realization of algorithms for symbolic calculations, which are used in modern systems of computer algebra [16]. Hypergeometric functions of many variables appear in quantum field theory as solutions of Knizhnik-Zamolodchikov equation [22]. These equations can be considered as generalized hypergeometric type equations and their solutions have integral representations, which generalize classic Euler integrals for hypergeometric functions of one variable. This approach allows us to link the special functions of hypergeometric type and challenges the theory of representations of Lie algebras and quantum groups [22]. Initially hypergeometric functions introduced by many authors with different methods, which are not related with each other. Their occurrence is determined, as a rule, by the need to solve problems, that led to a differential equation (or system of equations), insoluble in the class of elementary functions. Thus arose 2000 Mathematics Subject Classification. 35Q05, 35L80, 35C65. Key words and phrases. Generalized Euler-Poisson-Darboux equation; hyperbolic equation; Lauricelli hypergeometric functions. c 2015 Texas State University - San Marcos. Submitted October 21, 2014. Published January 5, 2015. 1 2 R. B. SEILKHANOVA, A. H. HASANOV EJDE-2015/09 Bessel functions, Hermite functions, Gauss hypergeometric function. Hypergeometric functions occupy an important place among the special functions of mathematical physics. Many problems of gas dynamics are reduced to boundary value problems for degenerate equations of mixed type. It is known that the degenerate equation of mixed type in the hyperbolic part of the domain is reduced to the generalized equation of Euler-Poisson-Darboux utt + 2α 2β 2γ ut = uxx + uyy + ux + uy , t x y x > 0, y > 0, t > 0, (1.1) where α > 0, β > 0 and γ > 0 are constants. We note that Euler-Poisson-Darboux equation uξη − β α uξ + uη = 0, ξ−η ξ−η α > 0, β > 0, α + β < 1, (1.2) was considered in [21], where the Cauchy problem for (1.2) was solved. In [17, 18, 19], non-local boundary problems for (1.2) were investigated in characteristic triangles. In [11], two confluent hypergeometric functions of three variables were introduced. Further, for introduced hypergeometric functions authors prove formulas of analytical continuation. Using the introduced confluent hypergeometric functions, they constructed the Riemann function for the generalized Euler -Poisson-Darboux equation α β α β uξη + [ + ]uξ + [ − ]uη + γu = 0. (1.3) η+ξ η−ξ η+ξ η−ξ Further, by the Riemann-function method the Cauchy problem for (1.3) was solved in characteristic triangle. Solution is written in an explicit form. Note that Euler Poisson-Darboux equations (1.2) and (1.3) are written in characteristic coordinates. In [20], the unique solvability of the Darboux problem with deviation for the Euler -Poisson-Darboux equation was proved outside of characteristic cone. Other type of the Euler -Poisson-Darboux equations were investigated in works [5, 7, 6, 23, 10, 15, 2, 3, 4]. 2. Reduction of the Euler-Poisson-Darboux equation to a system of Lauricella hypergeometric functions Solution of the Euler-Poisson-Darboux equation (1.1) is searched in the form u = P ω(ξ, η, ζ), (2.1) where ω(ξ, η, ζ) is unknown function and −α−β−γ− 12 P = (r2 ) 2 r12 2 r22 , (2.2) 2 r32 r − r − r − , η= , ζ= , r2 r2 r2 2 2 2 2 2 2 r2 = (x − x0 ) + (y − y0 ) − (t − t0 ) , r12 = (x + x0 ) + (y − y0 ) − (t − t0 ) , ξ= 2 2 2 r22 = (x − x0 ) + (y + y0 ) − (t − t0 ) , 2 2 2 r32 = (x − x0 ) + (y − y0 ) − (t + t0 ) . Calculating necessary derivatives from (2.1) and substituting them into (1.1), we obtain A1 ωξξ + A2 ωηη + A3 ωζζ + B1 ωξη + B2 ωξζ + B3 ωηζ (2.3) + C1 ωξ + C2 ωη + C3 ωζ + Dω = 0, EJDE-2015/09 GENERALIZED EULER-POISSON-DARBOUX EQUATION 3 where A1 = P ξx2 + P ξy2 − P ξt2 , A2 = P ηx2 + P ηy2 − P ηt2 , B1 = 2P ξx ηx + 2P ξy ηy − 2P ξt ηt , A3 = P ζx2 + P ζy2 − P ζt2 , B2 = 2P ξx ζx + 2P ξy ζy − 2P ξt ζt , B3 = 2P ηx ζx + 2P ηy ζy − 2P ηt ζt , 2α 2β 2γ C1 = P (ξxx + ξyy − ξtt ) + 2(Px ξx + Py ξy − Pt ξt ) + P ξx + ξy − ξt , x y t 2α 2β 2γ C2 = P (ηxx + ηyy − ηtt ) + 2(Px ηx + Py ηy − Pt ηt ) + P ηx + ηy − ηt , x y t 2α 2β 2γ C3 = P (ζxx + ζyy − ζtt ) + 2(Px ζx + Py ζy − Pt ζt ) + P ζx + ζy − ζt , x y t 2α 2β 2γ D = Pxx + Pyy − Ptt + Px + Py − Pt . x y t Now we consider A1 . Since 2 2 ξx2 = 2 2 4(x + x0 ) (r2 ) − 8(x + x0 )(x − x0 )r2 r12 + 4(x − x0 ) (r12 ) 4 (r2 ) 2 2 2 2 4(y − y0 ) (r2 ) − 8(y − y0 ) r2 r12 + 4(y − y0 ) (r12 ) ξy2 = 2 , 4 (r2 ) 2 ξt2 = 2 2 , 2 2 4(t − t0 ) (r2 ) − 8(t − t0 ) r2 r12 + 4(t − t0 ) (r12 ) 4 (r2 ) , we obtain −3 A1 = 4P r12 (r2 ) −3 or A1 = 4P r12 (r2 ) 2 2 [(r2 ) + (r12 ) − 2(x + x0 )(x − x0 ) − 2(y − y0 ) + 2(t − t0 ) ], 4x20 . By the equality 4x0 = −x−1 r2 ξ, we obtain −1 A1 = −4P x−1 x0 (r2 ) ξ(1 − ξ). (2.4) η(1 − η), (2.5) ζ(1 − ζ). (2.6) Similarly we have −1 A2 = −4P y −1 y0 (r2 ) 2 −1 A3 = −4P t−1 t0 (r ) Further, we calculate representation of B1 . Finding necessary derivatives from the arguments and substituting them we obtain n 2(x + x )r2 − 2(x − x )r2 2(x − x )r2 − 2(x − x )r2 0 0 1 0 0 2 B1 = 2P 2 2 2 2 (r ) (r ) 2(y − y0 )r2 − 2(y − y0 )r12 2(y + y0 )r2 − 2(y − y0 )r22 + 2 2 (r2 ) (r2 ) 2(t − t0 )r2 − 2(t − t0 )r12 2(t − t0 )r2 − 2(t − t0 )r22 o − , 2 2 (r2 ) (r2 ) or n −4 B1 = 8P (r2 ) [(x + x0 )r2 − (x − x0 )r12 ][(x − x0 )r2 − (x − x0 )r22 ] + [(y − y0 )r2 − (y − y0 )r12 ][(y + y0 )r2 − (y − y0 )r22 ] o − [(t − t0 )r2 − (t − t0 )r12 ][(t − t0 )r2 − (t − t0 )r22 ] . 4 R. B. SEILKHANOVA, A. H. HASANOV EJDE-2015/09 After some evaluations, we deduce B1 = 4P y −1 y0 (r2 ) −1 ξη + 4P x−1 x0 (r2 ) −1 ξη. (2.7) ξζ, (2.8) ηζ. (2.9) Similarly one obtains B2 = 4P t−1 t0 (r2 ) −1 −1 ξζ + 4P x−1 x0 (r2 ) 2 −1 B3 = 4P t−1 t0 (r ) 2 −1 ηζ + 4P y −1 y0 (r ) Further, considering the following expressions −1 (2x−1 x0 ξ − ξ), 1 α + β + γ + (x−1 x0 ξ + ξ), 2 ξxx + ξyy − ξtt = 2(r2 ) −1 Px ξx + Py ξy − Pt ξt = 2P (r2 ) 2β 2γ 2α −1 ξx + ξy − ξt = −4(r2 ) αx−1 x0 + αξ + αx−1 x0 (1 − ξ) − βy −1 y0 x y t + βξ + βy −1 y0 (1 − ξ) − γt−1 t0 + γξ + γt−1 t0 (1 − ξ) , we define 1 + 1)ξ] 2 −1 −1 + 4P (r2 ) y −1 y0 βξ + 4P (r2 ) t−1 t0 γξ. −1 −1 C1 = −4P (r2 ) x x0 [2α − (2α + β + γ + (2.10) Similarly, we define 1 + 1)η] 2 −1 −1 + 4P (r2 ) x−1 x0 αη + 4P (r2 ) t−1 t0 γη, 1 −1 C3 = −4P (r2 ) t−1 t0 [2γ − (α + β + 2γ + + 1)ζ] 2 2 −1 −1 2 −1 −1 + 4P (r ) x x0 γζ + 4P (r ) y y0 βζ. −1 −1 C2 = −4P (r2 ) y y0 [2β − (α + 2β + γ + (2.11) (2.12) After simple calculations we obtain 1 1 −1 −1 D = 4(α + β + γ + )P (r2 ) αx−1 x0 + 4(α + β + γ + )P (r2 ) βy −1 y0 2 2 (2.13) 1 2 −1 −1 + 4(α + β + γ + )P (r ) γt t0 . 2 Substituting (2.4)-(2.13) in (2.3), we obtain 4P x0 n − ξ(1 − ξ)ωξξ − ξηωξη − ξζωξζ − αηωη − γζωζ xr2 o 1 1 + [2α − (α + β + γ + + α + 1)ξ]ωξ − (α + β + γ + )αω 2 2 4P y0 n − η(1 − η)ωηη − ξηωξη − ηζωηζ − βξωξ − βζωζ yr2 (2.14) o 1 1 + [2β − (α + β + γ + + β + 1)η]ωη − (α + β + γ + )βω 2 2 4P t0 n − ζ(1 − ζ)ωζζ − ξζωξζ − ηζωηζ − γξωξ − γηωη tr2 o 1 1 + [2γ − (α + β + γ + + γ + 1)ζ]ωζ − (α + β + γ + )γω = 0. 2 2 EJDE-2015/09 GENERALIZED EULER-POISSON-DARBOUX EQUATION 5 Hence, the following equality is valid ξ(1 − ξ)ωξξ − ξηωξη − ξζωξζ + [2α − (α + β + γ + 1 + α + 1)ξ]ωξ 2 1 − αηωη − γζωζ − (α + β + γ + )αω = 0, 2 η(1 − η)ωηη − ξηωξη − ηζωηζ + [2β − (α + β + γ + 1 + β + 1)η]ωη 2 (2.15) 1 − βξωξ − βζωζ − (α + β + γ + )βω = 0, 2 ζ(1 − ζ)ωζζ − ξζωξζ − ηζωηζ + [2γ − (α + β + γ + 1 + γ + 1)ζ]ωζ 2 1 − γξωξ − γηωη − (α + β + γ + )γω = 0. 2 Thus, the Euler-Poisson-Darboux equation (1.1) equivalently reduced to the system (2.15). 3. Particular solutions of the Euler-Poisson-Darboux equation In [1], system (2.15) was considered for the n-dimensional case (n) xj (1 − xj ) − bj ∂ 2 FA ∂x2j n X k=1, k6=j xk − xj n X (n) xk k=1, k6=j (n) ∂FA ∂xk (n) (n) ∂F ∂ 2 FA + [cj − (a + bj + 1)xj ] A ∂xk ∂xj ∂xj − abj FA = 0, j = 1, 2, . . . , n. There were found 2n particular solutions of this system. All of them are expressed (n) by Lauricella hypergeometric functions FA . In particular case, system of hypergeometric functions (2.15) has the following solutions [1] 1 (3) ω1 = FA α + β + γ + ; α, β, γ; 2α, 2β, 2γ; ξ, η, ζ , (3.1) 2 3 (3) ω2 = ξ 1−2α FA − α + β + γ + ; 1 − α, β, γ; 2 − 2α, 2β, 2γ; ξ, η, ζ , (3.2) 2 3 (3) (3.3) ω3 = η 1−2β FA α − β + γ + ; α, 1 − β, γ; 2α, 2 − 2β, 2γ; ξ, η, ζ , 2 3 (3) (3.4) ω4 = ζ 1−2γ FA α + β − γ + ; α, β, 1 − γ; 2α, 2β, 2 − 2γ; ξ, η, ζ , 2 5 (3) ω5 = ξ 1−2α η 1−2β FA − α − β + γ + ; 1 − α, 1 − β, γ; 2 (3.5) 2 − 2α, 2 − 2β, 2γ; ξ, η, ζ , 5 (3) ω6 = ξ 1−2α ζ 1−2γ FA − α + β − γ + ; 1 − α, β, 1 − γ; 2 − 2α, 2β, 2 (3.6) 2 − 2γ; ξ, η, ζ , 5 (3) ω7 = η 1−2β ζ 1−2γ FA α − β − γ + ; α, 1 − β, 1 − γ; 2α, 2 − 2β, 2 (3.7) 2 − 2γ; ξ, η, ζ , 6 R. B. SEILKHANOVA, A. H. HASANOV EJDE-2015/09 7 − α − β − γ + ; 1 − α, 1 − β, 1 − γ; 2 2 − 2α, 2 − 2β, 2 − 2γ; ξ, η, ζ , (3) ω8 = ξ 1−2α η 1−2β ζ 1−2γ FA (3.8) where the Lauricella hypergeometric function is defined as ∞ X (a)m+n+p (b1 )m (b2 )n (b3 )p m,n,p=0 (c1 )m (c2 )n (c3 )p m!n!p! (3) FA (a; b1 , b2 , b3 ; c1 , c2 , c3 ; x, y, z) = xm y n z p . Further, substituting (3.1) - (3.8) in (2.1), we obtain q1 (x, y, t; x0 , y0 , t0 ) −α−β−γ− 21 = k1 (r2 ) 1 FA α + β + γ + ; α, β, γ; 2α, 2β, 2γ; ξ, η, ζ , 2 (3.9) q2 (x, y, t; x0 , y0 , t0 ) α−β−γ− 32 = k2 (r2 ) 3 − α + β + γ + ; 1 − α, β, γ; 2 (3.10) 3 α − β + γ + ; α, 1 − β, γ; 2α, 2 (3.11) 3 α + β − γ + ; α, β, 1 − γ; 2α, 2β, 2 (3.12) 5 − α − β + γ + ; 1 − α, 2 (3.13) 5 − α + β − γ + ; 1 − α, β, 2 (3.14) 5 α − β − γ + ; α, 1 − β, 2 (3.15) (3) 1−2α FA 1−2β FA (xx0 ) 2 − 2α, 2β, 2γ; ξ, η, ζ , q3 (x, y, t; x0 , y0 , t0 ) −α+β−γ− 32 = k3 (r2 ) (yy0 ) 2 − 2β, 2γ; ξ, η, ζ , (3) q4 (x, y, t; x0 , y0 , t0 ) −α−β+γ− 23 = k4 (r2 ) (tt0 ) 1−2γ (3) FA 2 − 2γ; ξ, η, ζ , q5 (x, y, t; x0 , y0 , t0 ) α+β−γ− 52 = k5 (r2 ) 1−2α (xx0 ) 1−2β (yy0 ) (3) FA 1 − β, γ; 2 − 2α, 2 − 2β, 2γ; ξ, η, ζ , q6 (x, y, t; x0 , y0 , t0 ) α−β+γ− 52 = k6 (r2 ) (xx0 ) 1−2α 1−2γ (tt0 ) 1 − γ; 2 − 2α, 2β, 2 − 2γ; ξ, η, ζ , (3) FA q7 (x, y, t; x0 , y0 , t0 ) = k7 (r2 ) −α+β+γ− 52 (yy0 ) 1−2β 1−2γ (tt0 ) 1 − γ; 2α, 2 − 2β, 2 − 2γ; ξ, η, ζ , (3) FA q8 (x, y, t; x0 , y0 , t0 ) 7 (3) FA − α − β − γ + ; 2 1 − α, 1 − β, 1 − γ; 2 − 2α, 2 − 2β, 2 − 2γ; ξ, η, ζ 1−2α = k8 (xx0 ) 1−2β (yy0 ) (tt0 ) 1−2γ α+β+γ− 27 (r2 ) (3.16) EJDE-2015/09 GENERALIZED EULER-POISSON-DARBOUX EQUATION 7 where ki , i = 1, 8 are constants. 4. Some properties of particular solutions Theorem 4.1. If α, β, γ > 0, then particular solutions (3.9)–(3.16) tends to infinity of the order 1/r at r → 0. Proof. By the expansion for the Lauricella hypergeometric function [12] (3) FA (a; b1 , b2 , b3 ; c1 , c2 , c3 ; x, y, z) ∞ X (a)i+j+k (b1 )i+j (b2 )i+k (b3 )j+k = i,j,k=0 (c1 )i+j (c2 )i+k (c3 )j+k i!j!k! xi+j y i+k z j+k × F (a + i + j, b1 + i + j; c1 + i + j; x)F (a + i + j + k, b2 + i + k; c2 + i + k; y) × F (a + i + j + k, b3 + j + k; c3 + j + k; z), (4.1) the particular solution (3.9) is rewritten as follows −α−β−γ− 12 q1 (x, y, t; x0 , y0 , t0 ) = k1 (r2 ) × ∞ X (α + β + γ + 21 )i+j+k (α)i+j (β)i+k (γ)j+k (2α)i+j (2β)i+k (2γ)j+k i!j!k! i,j,k=0 i+j i+k j+k r2 − r12 r2 − r22 r2 − r32 r2 r2 r2 1 r2 − r12 × F α + β + γ + + i + j, α + i + j; 2α + i + j; 2 r2 1 r2 − r22 × F α + β + γ + + i + j + k, β + i + k; 2β + i + k; 2 r2 2 r − r32 1 . × F α + β + γ + + i + j + k, γ + j + k; 2γ + j + k; 2 r2 × −b Using the formula F (a, b; c; x) = (1 − x) obtain q1 (x, y, t; x0 , y0 , t0 ) = k1 (r2 ) − 21 −α (r12 ) (4.2) F (c − a, b; c; x/(x − 1)) [9], from (4.2) we (r22 ) −β −γ ∗ q1 (x, y, t; x0 , y0 , t0 ), (r32 ) (4.3) where q1∗ (x, y, t; x0 , y0 , t0 ) = ∞ X (α + β + γ + 21 )i+j+k (α)i+j (β)i+k (γ)j+k i,j,k=0 (2α)i+j (2β)i+k (2γ)j+k i!j!k! i+j i+k j+k r12 − r2 r22 − r2 r32 − r2 r12 r22 r32 1 r2 − r2 (4.4) × F α − β − γ − , α + i + j; 2α + i + j; 1 2 2 r1 1 r2 − r2 × F β − α − γ − − j, β + i + k; 2β + i + k; 2 2 2 r2 2 1 r − r2 × F γ − α − β − − i, γ + j + k; 2γ + j + k; 3 2 . 2 r3 × 8 R. B. SEILKHANOVA, A. H. HASANOV EJDE-2015/09 Now we show that q1∗ (x, y, t; x0 , y0 , t0 ) is bounded aa r → 0. Since r12 − r2 r22 − r2 r32 − r2 = lim = lim = 1, r→0 r→0 r→0 r12 r22 r32 lim hence, one can find 1 F α − β − γ − , α + i + j; 2α + i + j; 1 2 Γ(2α)Γ(β + γ + 21 )(2α)i+j = , Γ(α)Γ(α + β + γ + 12 )(α + β + γ + 12 )i+j 1 F β − α − γ − − j, β + i + k; 2β + i + k; 1 2 Γ(2β)Γ(α + γ + 21 )(2β)i+k (α + γ + 12 )2j , = Γ(β)Γ(α + β + γ + 21 )(α + β + γ + 21 )i+j+k 1 F γ − α − β − − i, γ + j + k; 2γ + j + k; 1 2 Γ(2γ)(2γ)j+k Γ(α + β + 21 )(α + β + 21 )i . = Γ(γ)Γ(α + β + γ + 21 )(α + β + γ + 21 )i+j+k (4.5) (4.6) (4.7) Due to (4.5)–(4.7) at r → 0 from (4.4) we obtain lim q1∗ (x, y, t; x0 , y0 , t0 ) r→0 = Γ(2α)Γ(2β)Γ(2γ)Γ(α + β + 12 )Γ(α + γ + 21 )Γ(β + γ + 21 ) Γ(α)Γ(β)Γ(γ)Γ3 (α + β + γ + 21 ) × (4.8) (α + β + 21 )i (α + γ + 21 )j (α)i+j (β)i+k (γ)j+k . (α + β + γ + 21 )i+j (α + β + γ + 12 )i+j+k i!j!k! i,j,k=0 ∞ X It is easy to show that ∞ X (α + β + 12 )i (α + γ + 12 )j (α)i+j (β)i+k (γ)j+k i,j,k=0 (α + β + γ + 12 )i+j (α + β + γ + 12 )i+j+k i!j!k! Γ( 12 )Γ2 (α + β + γ + 21 ) = . Γ(α + β + 12 )Γ(α + γ + 12 )Γ(β + γ + 21 ) Thus, from (4.4) we deduce lim r→0 q1∗ (x, y, t; x0 , y0 , t0 ) (4.9) √ = πΓ(2α)Γ(2β)Γ(2γ) . Γ(α)Γ(β)Γ(γ)Γ(α + β + γ + 21 ) (4.10) From here considering (4.10), from (4.3) at r → 0 we have the estimate c0 |q1 (x, y, t; x0 , y0 , t0 )| ≤ , (4.11) r where k1 22α+2β+2γ−1 Γ(α + β + γ)Γ(2α)Γ(2β)Γ(2γ) c0 = . α β γ Γ(α)Γ(β)Γ(γ)Γ(2α + 2β + 2γ)(r12 ) (r22 ) (r32 ) Estimate (4.11) states that function q1 (x, y, t; x0 , y0 , t0 ) at r → 0 tends to infinity of the order 1/r. Similarly one can prove that every function qi (x, y, t; x0 , y0 , t0 ), i = 2, 3, . . . , 8 has singularity 1/r as r → 0. EJDE-2015/09 GENERALIZED EULER-POISSON-DARBOUX EQUATION 9 Theorem 4.2. If α, β, γ > 0, then the found particular solutions have the following properties ∂ ∂ ∂ q1 = 0, y 2β q1 = 0, = 0, t2γ q1 ∂x x=0 ∂y y=0 ∂t t=0 ∂ ∂ q2 x=0 = 0, y 2β q2 = 0, t2γ q2 = 0, ∂y y=0 ∂t t=0 ∂ ∂ x2α q3 = 0, q3 y=0 = 0, t2γ q3 = 0, ∂x x=0 ∂t t=0 ∂ ∂ = 0, y 2β q4 = 0, q4 t=0 = 0, x2α q4 ∂x x=0 ∂y y=0 ∂ q5 x=0 = 0, q5 y=0 = 0, t2γ q5 = 0, ∂t t=0 ∂ = 0, q6 t=0 = 0, q6 x=0 = 0, y 2β q6 ∂y y=0 ∂ x2α q7 = 0, q7 y=0 = 0, q7 t=0 = 0, ∂x x=0 q8 x=0 = 0, q8 y=0 = 0, q8 t=0 = 0. x2α Proofs of the above equalities are based on elementary calculations. These properties could be used in studying various boundary problems for the equation (1.1). Acknowledgements. We are grateful to the Professor H. M. Srivastava for his suggestion to consider this problem. References [1] P. Appell, Kampe de Feriet J; Fonctions Hypergeometriques et Hyperspheriques; Polynomes d’Hermite, Gauthier - Villars. Paris, 1926, p. 440. [2] J. Barros-Neto, I. M. 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[22] A. Varchenko; Multidimensional Hypergeometric Functions and Representation Theory of Lie Algebras and Quantum Groups, Advanced Series in Mathematical Physics 21. World Scientific. 1995. [23] K. Yagdjian; A note on the fundamental solution for the Tricomi-type equation in the hyperbolic domain, J. Differential Equations 206 (2004) pp. 227–252. Rakhila B. Seilkhanova S. Baishev University Aktobe, Department for Information Systems and Applied Mathematics, 030000 Aktobe, Zhubanov str. 302, Kazakhstan E-mail address: srahila@inbox.ru Anvar H. Hasanov S. Baishev University Aktobe, Department for Information Systems and Applied Mathematics, 030000 Aktobe, Zhubanov str. 302, Kazakhstan E-mail address: anvarhasanov@yahoo.com