Electronic Journal of Differential Equations, Vol. 2004(2004), No. 136, pp. 1–13. ISSN: 1072-6691. URL: http://ejde.math.txstate.edu or http://ejde.math.unt.edu ftp ejde.math.txstate.edu (login: ftp) APPROXIMATIONS OF SOLUTIONS TO RETARDED INTEGRODIFFERENTIAL EQUATIONS DHIRENDRA BAHUGUNA, MALIK MUSLIM Abstract. In this paper we consider a retarded integrodifferential equation and prove existence, uniqueness and convergence of approximate solutions. We also give some examples to illustrate the applications of the abstract results. 1. Introduction Consider the semilinear retarded differential equation with a nonlocal history condition in a separable Hilbert space H: Z 0 u0 (t) + Au(t) = Bu(t) + Cu(t − τ ) + a(θ)Lu(t + θ)dθ, 0 < t ≤ T < ∞, τ > 0, −τ u(t) = h(t), t ∈ [−τ, 0]. (1.1) Here u is a function defined from [−τ, ∞) to the space H, h : [−τ, 0] → H is a given function and the kernel a ∈ Lploc (−τ, 0). For each t ≥ 0, ut : [−τ, 0] → H is defined by ut (θ) = u(t + θ), θ ∈ [−τ, 0] and the operators A : D(A) ⊆ H → H, is a linear operator. The operators B : D(B) ⊆ H → H, C : D(C) ⊆ H → H, and L : D(L) ⊆ H → H are non-linear continuous operators. For t ∈ [0, T ], we shall use the notation Ct := C([−τ, t]; H) for the Banach space of all continuous functions from [−τ, t] into H endowed with the supremum norm kψkt := sup kψ(η)k. −τ ≤η≤t The existence, uniqueness and regularity of solutions of (1.1) under different conditions have been considered by Blasio [8] and Jeong [14] and some of the papers cited therein. For the initial work on the existence, uniqueness and stability of various types of solutions of differential and functional differential equations, we refer to Bahuguna [1, 2], Balachandran and Chandrasekaran [5], Lin and Liu [15]. The related results for the approximation of solutions may be found in Bahuguna, Srivastava and Singh [4] and Bahuguna and Shukla [3]. 2000 Mathematics Subject Classification. 34K30, 34G20, 47H06. Key words and phrases. Retarded differential equation; analytic semigroup; approximate solution; convergence of solutions; Faedo-Galerkin approximation. c 2004 Texas State University - San Marcos. Submitted October 21, 2002. Published November 23, 2004. 1 2 D. BAHUGUNA, M. MUSLIM EJDE-2004/136 Initial study concerning existence, uniqueness and finite-time blow-up of solutions for the following equation, u0 (t) + Au(t) = g(u(t)), t ≥ 0, u(0) = φ, (1.2) have been considered by Segal [19], Murakami [17], Heinz and von Wahl [13]. Bazley [6, 7] has considered the following semilinear wave equation u00 (t) + Au(t) = g(u(t)), u(0) = φ, t ≥ 0, 0 u (0) = ψ, (1.3) and has established the uniform convergence of approximations of solutions to (1.3) using the existence results of Heinz and von Wahl [13]. Goethel [12] has proved the convergence of approximations of solutions to (1.2) but assumed g to be defined on the whole of H. Based on the ideas of Bazley [6, 7], Miletta [16] has proved the convergence of approximations to solutions of (1.2). In the present work, we use the ideas of Miletta [16] and Bahuguna [3, 4] to establish the convergence of finite dimensional approximations of the solutions to (1.1). 2. Preliminaries and Assumptions Existence of a solution to (1.1) is closely associated with the existence of a function u ∈ CT̃ , 0 < T̃ ≤ T satisfying t ∈ [−τ, 0], h(t), R t u(t) = e−tA h(0) + e−(t−s)A [Bu(s) 0 R 0 +Cu(s − τ ) + −τ a(θ)Lu(s + θ)dθ]ds, t ∈ [0, T̃ ] and such a function u is called a mild solution of (1.1) on [−τ, T̃ ]. A function u ∈ CT̃ is called a classical solution of (1.1) on [−τ, T̃ ] if u ∈ C 1 ((0, T̃ ]; H) and u satisfies (1.1) on [−τ, T̃ ]. We assume in (1.1), that the linear operator A satisfies the following. (H1) A is a closed, positive definite, self-adjoint linear operator from the domain D(A) ⊂ H into H such that D(A) is dense in H, A has the pure point spectrum 0 < λ0 ≤ λ1 ≤ λ2 ≤ . . . and a corresponding complete orthonormal system of eigenfunctions {φi }, i.e., Aφi = λi φi and (φi , φj ) = δij , where δij = 1 if i = j and zero otherwise. If (H1) is satisfied then −A is the infinitesimal generator of an analytic semigroup {e−tA : t ≥ 0} in H (cf. Pazy [18, pp. 60-69]). It follows that the fractional powers Aα of A for 0 ≤ α ≤ 1 are well defined from D(Aα ) ⊆ H into H (cf. Pazy [18, pp. 69-75]). Hence for convenience, we suppose that ke−tA k ≤ M for all t ≥ 0 and 0 ∈ ρ(−A), where ρ(−A) is the resolvent set of −A. D(Aα ) is a Banach space endowed with the norm kxkα = kAα xk. EJDE-2004/136 APPROXIMATIONS OF SOLUTIONS 3 For t ∈ [0, T ], we denote by Ctα := C([−τ, t]; D(Aα )) endowed with the norm kψkt,α := sup kψ(ν)kα . −τ ≤ν≤t Further, we assume the following. (H2) h ∈ C0α and h is locally hölder continuous on [−τ, 0]. (H3) We shall assume that the map B : D(Aα ) → H satisfies the following Lipschitz condition on balls in D(Aα ): for each η > 0 and some 0 < α < 1 there exists a constant K1 (η) such that (i) kB(ψ)k ≤ K1 (η) for ψ ∈ D(Aα ) with kAα ψk ≤ η, (ii) kB(ψ1 ) − B(ψ2 )k ≤ K1 (η)kAα (ψ1 − ψ2 )k for ψ1 , ψ2 ∈ D(Aα ) with kAα ψi k ≤ η for i = 1, 2. (H4) The map C : D(Aα ) → H satisfies the following Lipschitz condition on balls in D(Aα ): For each η > 0 and some 0 < α < 1 there exists a constant K2 (η) such that (iii) kC(ψ)k ≤ K2 (η) for ψ ∈ D(Aα ) with kAα ψk ≤ η, (iv) kC(ψ1 ) − C(ψ2 )k ≤ K2 (η)kAα (ψ1 − ψ2 )k for ψ1 , ψ2 ∈ D(Aα ) with kAα ψi k ≤ η for i = 1, 2. (H5) The map L : D(Aα ) → H satisfies the following Lipschitz condition on balls in D(Aα ): For each η > 0 and some 0 < α < 1 there exists a constant K3 (η) such that (v) kL(ψ)k ≤ K3 (η) for ψ ∈ D(Aα ) with kAα ψk ≤ η, (vi) kL(ψ1 ) − L(ψ2 )k ≤ K3 (η)kAα (ψ1 − ψ2 )k for ψ1 , ψ2 ∈ D(Aα ) with kAα ψi k ≤ η for i = 1, 2. R0 (H6) a ∈ Lploc (−τ, 0) for some 1 < p < ∞ and aT = −τ |a(θ)| dθ. 3. Approximate Solutions and Convergence Let Hn denote the finite dimensional subspace of H spanned by {φ0 , φ1 , · · · , φn } and let P n : H −→ Hn be the corresponding projection operator for n = 0, 1, 2, · · · . Let 0 < T0 ≤ T be such that R (3.1) sup k(e−tA − I)Aα h(0)k ≤ , 2 0≤t≤T0 where R > 0 be a fixed quantity. Let us define ( h(t), if t ∈ [−τ, 0], h̄(t) = h(0), if t ∈ [0, T ]. We set R 1 1 1 T0 < min { (1 − α)(K(η0 )Cα )−1 } 1−α , { (1 − α)(K(η0 )Cα )−1 } 1−α , 2 2 where K(η0 ) = [K1 (η0 ) + K2 (η0 ) + K3 (η0 )aT ] α −tA and Cα is a positive constant such that kA e k ≤ Cα t Bn : H −→ H such that Bn x = BP n x, x ∈ H. Similarly Cn and Ln are given by Cn x = CP n x, x ∈ H, −α (3.2) (3.3) for t > 0. We define Ln x = LP n x, x ∈ H. 4 D. BAHUGUNA, M. MUSLIM EJDE-2004/136 Let Aα : Ctα → Ct be given by (Aα ψ)(s) = Aα (ψ(s)), s ∈ [−τ, t], t ∈ [0, T ]. We define a map Fn on BR (CTα0 , h̄) as follows t ∈ [−τ, 0], h(t), R t −(t−s)A −tA (Fn u)(t) = e [Bn u(s) h(0) + 0 e R0 +Cn u(s − τ ) + −τ a(θ)Ln u(s + θ)dθ]ds, t ∈ [0, T0 ], for u ∈ BR (CTα0 , h̄). Theorem 3.1. Suppose that the conditions (H1)-(H6) are satisfied and h(t) ∈ D(A) for all t ∈ [−τ, 0]. Then there exists a unique un ∈ BR (CTα0 , h̄) such that Fn un = un for each n = 0, 1, 2, · · · , i.e., un satisfies the approximate integral equation h(t), R un (t) = e−tA h(0) + t e−(t−s)A [Bn un (s) 0 R0 +Cn un (s − τ ) + −τ a(θ)Ln un (s + θ)dθ]ds, t ∈ [−τ, 0], (3.4) t ∈ [0, T0 ]. Proof. First we show that Fn : BR (CTα0 , h̄) → BR (CTα0 , h̄). For this first we need to show that the map t 7→ (Fn u)(t) is continuous from [−τ, T0 ] into D(Aα ) with respect to k · kα norm. Thus for any u ∈ BR (CTα0 , h̄), and t1 , t2 ∈ [−τ, 0], we have (Fn u)(t1 ) − (Fn u)(t2 ) = h(t1 ) − h(t2 ). (3.5) Now for t1 t2 ∈ (0, T0 ] with t1 < t2 we have k(Fn u)(t2 ) − (Fn u)(t1 )kα ≤ k(e−t2 A − e−t1 A )h(0)kα + Z t1 k(e−(t2 −s)A − e−(t1 −s)A )Aα k 0 × kBn u(s)k + kCn u(s − τ )k + Z 0 |a(θ)|kLn u(s + θ)kdθ ds −τ Z t2 + (3.6) k(e−(t2 −s)A )Aα k kBn u(s)k + kCn u(s − τ )k t1 0 Z + |a(θ)|kLn u(s + θ)kdθ ds. −τ Since part (d) of Theorem 6.13 in Pazy [18, p. 74] states that for 0 < β ≤ 1 and x ∈ D(Aβ ), k(e−tA − I)xk ≤ Cβ tβ kAβ xk. Hence if 0 < β < 1 is such that 0 < α + β < 1 then Aα y ∈ D(Aβ ). Therefore for t, s ∈ (0, T0 ], we have k(e−tA − I)Aα e−sA xk ≤ Cβ tβ kAα+β e−sA xk ≤ Cβ Cα+β tβ s−(α+β) kxk. (3.7) EJDE-2004/136 APPROXIMATIONS OF SOLUTIONS 5 We use the inequality (3.7) to obtain Z t1 k(e−(t2 −s)A − e−(t1 −s)A )Aα k[kBn u(s)k + kCn u(s − τ )k 0 0 Z |a(θ)|kLn u(s + θ)kdθ]ds + −τ t1 Z ≤ k(e−(t2 −t1 )A − I)e−(t1 −s)A Aα k[kBn u(s)k + kCn u(s − τ )k (3.8) 0 Z 0 |a(θ)|kLn u(s + θ)kdθ]ds + −τ ≤ Cα,β (t2 − t1 )β , where 1−(α+β) Cα,β = Cβ Cα+β K(η0 ) T0 , [1 − (α + β)] K(η0 ) is given by (3.3) and η0 = R + khk0,α . We calculate the second part of the integral (3.6) as follows. We have Z t2 Z 0 ke−(t2 −s)A Aα k[kBn u(s)k + kCn u(s − τ )k + |a(θ)|kLn u(s + θ)kdθ]ds −τ t1 (t2 − t1 )1−α ≤ Cα K(η0 ) . (1 − α) (3.9) Hence from (3.5), (3.8) and (3.9) the map t 7→ (Fn u)(t) is continuous from [−τ, T0 ] into D(Aα ) with respect to k · kα norm. Now, for t ∈ [−τ, 0], (Fn u)(t) − h̄(t) = 0. For t ∈ (0, T0 ], we have k(Fn u)(t) − h̄(t)kα ≤ k(e−tA − I)Aα h(0)k Z Z t + ke−(t−s)A Aα k kBn u(s)k + kCn u(s − τ )k + |a(θ)|kLn u(s + θ)kdθ ds −τ 0 ≤ 0 T01−α R + Cα K(η0 ) . 2 1−α Hence kFn u − h̄kT0 ,α ≤ R. Thus Fn : BR (CTα0 , h̄) → BR (CTα0 , h̄). Now, for any u, v ∈ BR (CTα0 , h̄) and t ∈ [−τ, 0] we have Fn u(t) − Fn v(t) = 0. For t ∈ (0, T0 ] and u, v ∈ BR (CTα0 , h̄) we have kFn u(t) − Fn v(t)kα Z t h ≤ ke−(t−s)A Aα k kBn u(s) − Bn v(s)k + kCn u(s − τ ) − Cn v(s − τ )k 0 Z 0 + i |a(θ)|kLn u(s + θ) − Ln v(s + θ)kdθ ds −τ Z ≤ 0 t Cα (t − s)−α [K1 (η0 )ku(s) − v(s)kα + K2 (η0 )ku(s − τ ) − v(s − τ )kα 6 D. BAHUGUNA, M. MUSLIM Z EJDE-2004/136 0 |a(θ)|K3 (η0 )ku(s + θ) − v(s + θ)kα dθ]ds + −τ Z ≤ t Cα (t − s)−α K(η0 )ku − vkT0 ,α ds 0 1 ku − vkT0 ,α . 2 Taking the supremum on t over [−τ, T0 ] we get ≤ 1 ku − vkT0 ,α . 2 Hence there exists a unique un ∈ BR (CTα0 , h̄) such that Fn un = un , which satisfies the approximate integral equation (3.4). This completes the proof of Theorem 3.1. kFn u − Fn vkT0 ,α ≤ Corollary 3.2. If all the hypotheses of the Theorem 3.1 are satisfied then un (t) ∈ D(Aβ ) for all t ∈ [−τ, T0 ] where 0 ≤ β < 1. Proof. From Theorem 3.1 there exists a unique un ∈ BR (CTα0 , h̄) satisfying (3.4). From [18, Theorem 1.2.4] we have that e−tA x ∈ D(A) for x ∈ D(A). Also from Part (a) of [18, Theorem 2.6.13] we have e−tA : H 7→ D(Aβ ) for t > 0 and 0 ≤ β < 1. Hölder continuity of un follows from the similar arguments as used in (3.8) and (3.9). From [18, Theorem 4.3.2], for 0 < t < T , we have Z t e−(t−s)A f (s)ds ∈ D(A). 0 β Since D(A) ⊆ D(A ) for 0 ≤ β ≤ 1, the result of Corollary 3.2 thus follows. Corollary 3.3. If h(0) ∈ D(Aα ), where 0 < α < 1 and t0 ∈ (0, T0 ] then there exists a constant Mt0 , independent of n, such that kAβ un (t)k ≤ Mt0 for all t0 ≤ t ≤ T0 and 0 ≤ β < 1. Furthermore if h(t) ∈ D(A) for all t ∈ [−τ, 0] then there exist a constant M0 , independent on n, such that kAβ un (t)k ≤ M0 for all −τ ≤ t ≤ T0 and 0 ≤ β < 1. Proof. For any t0 ∈ (0, T0 ], we have, kun (t)kβ ≤ Cβ t−β 0 kh(0)k + Cβ K(η0 ) T01−β ≤ Mt0 . 1−β Now as h(t) ∈ D(A) for all t ∈ [−τ, 0] hence h(t) ∈ D(Aβ ) for all t ∈ [−τ, 0] so for any t ∈ [−τ, 0], we have kun (t)kβ = kAβ h(t)k ≤ khk0,β for all t ∈ [−τ, 0]. Now again for any t ∈ (0, T0 ] we have kun (t)kβ ≤ M khk0,β + Cβ K(η0 ) This completes the proof of the Corollary 3.3. T01−β . 1−β (3.10) EJDE-2004/136 APPROXIMATIONS OF SOLUTIONS 7 Theorem 3.4. Suppose that the conditions (H1)-(H6) are satisfied and h(t) ∈ D(A) for all t ∈ [−τ, 0]. Then the sequence {un } ⊂ CTα0 is a Cauchy sequence and therefore converges to a function u ∈ CTα0 . Proof. For n ≥ m ≥ n0 , where n0 is large enough, n, m, n0 ∈ N, t ∈ [−τ, 0] we have kun (t) − um (t)kα = kh(t) − h(t)kα = 0. For t ∈ (0, T0 ] and n, m and n0 as above we have Z t kun (t) − um (t)kα ≤ ke−(t−s)A Aα k[kBn un (s) − Bm um (s)k (3.11) 0 + kCn un (s − τ ) − Cm um (s − τ )k Z 0 + |a(θ)|kLn un (s + θ) − Lm um (s + θ)kdθ]ds. −τ For 0 < t00 < t0 , we have Z kun (t) − um (t)kα ≤ ( t00 Z t )ke−(t−s)A Aα k[kBn un (s) − Bm um (s)k + t00 0 + kCn un (s − τ ) − Cm um (s − τ )k Z 0 + |a(θ)|kLn un (s + θ) − Lm um (s + θ)kdθ]ds. (3.12) −τ Now for 0 < α < β < 1, we have k[Bn (un (s)) − Bm (um (s))]k ≤ kBn (un (s)) − Bn (um (s))k + kBn (um (s)) − Bm (um (s))k ≤ K1 (η0 )kAα [un (s) − um (s)]k + K1 (η0 )kAα−β (P n − P m )Aβ um (s)k ≤ K1 (η0 )kAα [un (s) − um (s)]k + K1 (η0 ) λβ−α m (3.13) kAβ um (s)k. Similarly k[Cn (un (s − τ )) − Cm (um (s − τ ))]k ≤ kCn (un (s − τ )) − Cn (um (s − τ ))k + kCn (um (s − τ )) − Cm (um (s))k ≤ K2 (η0 )kAα [un (s − τ ) − um (s − τ )]k (3.14) + K2 (η0 )kAα−β (P n − P m )Aβ um (s − τ )k ≤ K2 (η0 )kAα [un (s − τ ) − um (s − τ )]k + K2 (η0 ) λβ−α m kAβ um (s − τ )k and k[Ln (un (s + θ)) − Lm (um (s + θ))]k ≤ kLn (un (s + θ)) − Ln (um (s + θ))k + kLn (um (s + θ)) − Lm (um (s + θ))k ≤ K3 (η0 )kAα [un (s + θ) − um (s + θ)]k α−β + K3 (η0 )kA n m (3.15) β (P − P )A um (s + θ)k ≤ K3 (η0 )kAα [un (s + θ) − um (s + θ)]k + K3 (η0 ) λβ−α m kAβ um (s + θ)k. 8 D. BAHUGUNA, M. MUSLIM EJDE-2004/136 From inequalities (3.13), (3.14) and (3.15), inequality (3.12) becomes kun (t) − um (t)kα Z t00 Z t ≤( + )ke−(t−s)A Aα k[K1 (η0 )kAα [un (s) − um (s)]k t00 0 + + + K1 (η0 ) kAβ um (s)k + K2 (η0 )kAα [un (s − τ ) − um (s − τ )]k β−α λm K2 (η0 ) kAβ um (s − τ )k + β−α λm K3 (η0 ) 0 Z |a(θ)|K3 (η0 )kAα [un (s + θ) − um (s + θ)]k −τ kAβ um (s + θ)kdθ]ds. β−α λm (3.16) ¿From Corollaries 3.2 and 3.3, inequality (3.16) becomes Z t C2 0 kun (t) − um (t)kα ≤ C1 .t0 + β−α + Cα K(η0 ) (t − s)−α kun − um ks,α ds, (3.17) λm t00 0 )Cα T where C1 = 2Cα (t0 − t00 )−α CK(η0 ) and C2 = 2K(η(1−α) 0 t + θ in inequality (3.17) where θ ∈ [t0 − t, 0], we get 1−α . Now we replace t by kun (t + θ) − um (t + θ)kα ≤ C1 .t00 + Z C2 λβ−α m t+θ + Cα K(η0 ) (t + θ − s)−α kun − um ks,α ds. (3.18) t00 We put s − θ = γ in (3.18) to get kun (t + θ) − um (t + θ)kα ≤ C1 .t00 + ≤ C1 .t00 + t Z C2 λβ−α m C2 λβ−α m (t − γ)−α kun − um kγ,α ds + Cα K(η0 ) t00 −θ Z t (t − γ)−α kun − um kγ,α ds. + Cα K(η0 ) t00 Now sup t00 −t≤θ≤0 ≤ C1 .t00 kun (t + θ) − um (t + θ)kα + C2 β−α λm Z t (t − γ)−α kun − um kγ,α ds. + Cα K(η0 ) (3.19) t00 We have sup kun (t + θ) − um (t + θ)kα −τ −t≤θ≤0 ≤ sup 0≤θ+t≤t00 kun (t + θ) − um (t + θ)kα + sup t00 −t≤θ≤0 kun (t + θ) − um (t + θ)kα . Using inequalities (3.19) and (3.16) in the above inequality, we get sup kun (t + θ) − um (t + θ)kα −τ ≤t+θ≤t ≤ (C1 + C3 )t00 + (C2 + C4 ) λβ−α m Z t + Cα K(η0 ) t00 (t − γ)−α kun − um kγ,α ds, EJDE-2004/136 APPROXIMATIONS OF SOLUTIONS 9 where C3 and C4 are constants. An application of Gronwall’s inequality to the above inequality gives the required result. This completes the proof of the Theorem 3.4. With the help of Theorems 3.1 and 3.4, we may state the following existence, uniqueness and convergence result. Theorem 3.5. Suppose that the conditions (H1)-(H6) are satisfied and h(t) ∈ D(A) for all t ∈ [−τ, 0] hold. Then there exist a function un ∈ C([−τ, T0 ]; H) and u ∈ C([−τ, T0 ]; H) satisfying t ∈ [−τ, 0], h(t), R t (3.20) un (t) = e−tA h(0) + e−(t−s)A [Bn un (s) 0 R0 +Cn un (s − τ ) + −τ a(θ)Ln un (s + θ)dθ]ds, t ∈ [0, T0 ] and h(t), R u(t) = e−tA h(0) + t e−(t−s)A [Bu(s) 0 R 0 +Cu(s − τ ) + −τ a(θ)Lu(s + θ)dθ]ds, t ∈ [−τ, 0], (3.21) t ∈ [0, T̃ ] such that un → u in C([−τ, T0 ]; H) as n → ∞, where Bn , Cn and Ln are as defined earlier. 4. Faedo-Galerkin Approximations We know from the previous sections that for any −τ ≤ T0 ≤ T , we have a unique u ∈ CTα0 satisfying the integral equation t ∈ [−τ, 0], h(t), R t −(t−s)A −tA u(t) = e (4.1) h(0) + 0 e [Bu(s) R0 +Cu(s − τ ) + −τ a(θ)Lu(s + θ)dθ]ds, t ∈ [0, T̃ ]. Also, there is a unique solution u ∈ CTα0 of the approximate integral equation t ∈ [−τ, 0], h(t), R t −(t−s)A −tA un (t) = e (4.2) h(0) + 0 e [Bn un (s) R0 +Cn un (s − τ ) + −τ a(θ)Ln un (s + θ)dθ]ds, t ∈ [0, T0 ]. Faedo-Galerkin approximation ūn = P n un is given by n t ∈ [−τ, 0], P h(t), R t ūn (t) = e−tA P n h(0) + e−(t−s)A P n [Bn un (s) 0R 0 +Cn un (s − τ ) + −τ a(θ)Ln un (s + θ)dθ]ds, t ∈ [0, T0 ], (4.3) where Bn , Cn and Ln are as defined earlier. If the solution u(t) to (4.1) exists on −τ ≤ t ≤ T0 then it has the representation u(t) = ∞ X i=0 αi (t)φi , (4.4) 10 D. BAHUGUNA, M. MUSLIM EJDE-2004/136 where αi (t) = (u(t), φi ) for i = 0, 1, 2, 3, · · · and ūn (t) = n X αin (t)φi , (4.5) i=0 where αin (t) = (ūn (t), φi ) for i = 0, 1, 2, 3, · · · . As a consequence of Theorem 3.1 and Theorem 3.4, we have the following result. Theorem 4.1. Suppose that the conditions (H1)-(H6) are satisfied and h(t) ∈ D(A) for all t ∈ [−τ, 0]. Then there exist unique functions ūn ∈ C([−τ, T0 ]; Hn ) and u ∈ C([−τ, T0 ]; H) satisfying n t ∈ [−τ, 0], P h(t), R t −(t−s)A n −tA n ūn (t) = e P h(0) + 0 e P [Bn un (s) R0 +Cn un (s − τ ) + −τ a(θ)Ln un (s + θ)dθ]ds, t ∈ [0, T0 ] and h(t), R u(t) = e−tA h(0) + t e−(t−s)A [Bu(s) 0 R 0 +Cu(s − τ ) + −τ a(θ)Lu(s + θ)dθ]ds, t ∈ [−τ, 0], t ∈ [0, T̃ ], such that ūn → u in C([−τ, T0 ]; H) as n → ∞, where Bn , Cn and Ln are as defined earlier. Theorem 4.2. Let (H1)-(H6) hold. If h(t) ∈ D(A) for all t ∈ [−τ, 0] then for any −τ ≤ t ≤ T0 ≤ T , n X n 2 λ2α = 0. lim sup i {αi (t) − αi (t)} n→∞ −τ ≤t≤T0 Proof. Let αin (t) i=0 = 0 for i > n. We have Aα [u(t) − ūn (t)] = Aα ∞ X ∞ X n {αi (t) − αin (t)}φi = λα i {αi (t) − αi (t)}φi . i=0 i=0 Thus we have kAα [u(t) − ūn (t)k2 ≥ n X n 2 λ2α i |αi (t) − αi (t)| . (4.6) i=0 Hence as a consequence of Theorem 3.5 we have the required result. 5. Example Consider the following partial differential equation with delay, wt (t, x) = wxx (t, x) + b(w(t, x))wx (t, x) + c(w(t − τ, x))wx (t − τ, x) Z 0 + a(s)l(w(t + s, x))wx (t + s, x)ds, t ≥ 0, x ∈ (0, 1), −τ w(t, x) = h̃(t, x), (5.1) t ∈ [−τ, 0], x ∈ (0, 1), w(t, 0) = w(t, 1) = 0, t ≥ 0, where the kernel a ∈ Lploc (−τ, 0), b, c, l are smooth functions from R into R, h̃ is a given continuous function and τ > 0 is a given number. EJDE-2004/136 APPROXIMATIONS OF SOLUTIONS 11 We define an operator A, as follows, Au = −u00 with u ∈ D(A) = H01 (0, 1) ∩ H 2 (0, 1). (5.2) Here clearly the operator A satisfies the hypothesis (H1) and is the infinitesimal generator of an analytic semigroup {e−tA : t ≥ 0}. For 0 ≤ α < 1, and t ∈ [0, T ], we denote Ctα := C([−τ, t]; D(Aα )), which is the Banach space endowed with the sup norm kψkt,α := sup kψ(η)kα . −τ ≤η≤t We observe some properties of the operators A and Aα defined by (5.2) (cf. [3] for more details). For φ ∈ D(A) and λ ∈ R, with Aφ = −φ00 = λu, we have hAφ, φi = hλφ, φi; that is, h−φ00 , φi = |u0 |2L2 = λ|φ|2L2 , so λ > 0. A solution φ of Aφ = λφ is of the form √ √ φ(x) = C cos( λx) + D sin( λx) and the conditions φ(0) = φ(1) = 0 imply that C = 0 and λ = λn = n2 π 2 , n ∈ N. Thus, for each n ∈ N, the corresponding solution is p φn (x) = D sin( λn x). √ We have hφn , φm i = 0, for n 6= m and hφn , φn i = 1 and hence D = 2. For u ∈ D(A), there exists a sequence of real numbers {αn } such that X X X u(x) = αn φn (x), (αn )2 < +∞ and (λn )2 (αn )2 < +∞. n∈N n∈N n∈N We have A1/2 u(x) = Xp λn αn φn (x) n∈N P with u ∈ D(A1/2 ) = H01 (0, 1); that is, n∈N λn (αn )2 < +∞. Then equation(5.1) can be reformulated as the following abstract equation in a separable Hilbert space H = L2 (0, 1): Z 0 u0 (t) + Au(t) = Bu(t) + Cu(t − τ ) + a(θ)Lu(t + θ)dθ, 0 < t ≤ T < ∞, τ > 0, −τ u(t) = h(t), t ∈ [−τ, 0], where u(t) = w(t, .) that is u(t)(x) = w(t, x), ut (θ)(x) = w(t + θ, x), t ∈ [0, T ], θ ∈ [−τ, 0], x ∈ (0, 1), the operator A is as define in equation (5.2) and h(θ)(x) = h̃(θ, x) for all θ ∈ [−τ, 0] and x ∈ (0, 1). The operators B, C and L are given by as follows: B : D(A1/2 ) 7→ H, where Bu(t)(x) = b(w(t, x))wx (t, x), C : D(A1/2 ) 7→ H, where Cu(t − τ )(x) = c(w(t − τ, x))wx (t − τ, x), and L : D(A1/2 ) 7→ H, where Lu(t + s)(x) = l(w(t + s, x))wx (t + s, x), where s ∈ [−τ, 0] and x ∈ (0, 1). Let α be such that 3/4 < α < 1. For u, v ∈ D(Aα ) with kAα uk ≤ η and kAα vk ≤ η, we have |b(u(x))ux (x) − b(v(x))vx (x)| ≤ |b(u(x)) − b(v(x))||ux (x)| + |b(v(x))||ux (x) − vx (x)| 12 D. BAHUGUNA, M. MUSLIM EJDE-2004/136 ≤ Lb |u(x) − v(x)||ux (x)| + b1 |ux (x) − vx (x)|, where Lb is the Lipschitz constant for b and b1 = Lb η 1/2 λ0 + |b(0)|. For u, v ∈ D(Aα ) ⊂ D(A1/2 ), we have Z 1 2 kB(u) − B(v)k ≤ |[Lb |u(x) − v(x)||ux (x)| + b1 |ux (x) − vx (x)|]|2 dx. 0 Thus, from [18, Lemma 8.3.3], we get kB(u) − B(v)k2 Z 1 Z 2 2 2 2 ≤ 2Lb |u(x) − v(x)| |ux (x)| dx + 2b1 0 2 ≤ 2Lb ku − 1 |ux (x) − vx (x)||2 dx 0 vk2∞ Z 1 2 |ux (x)| dx + 2b1 2 Z 0 1 |ux (x) − vx (x)|2 dx 0 ≤ 2Lb 2 ku − vk2∞ kA1/2 uk2 + 2b1 2 kA1/2 (u − v)k2 ≤ 2Lb 2 c2 η 2 kAα (u − v)k2 + 2b1 2 kAα (u − v)k2 2 ≤ Mb (η) kAα (u − v)k2 , √ where 3/4 < α < 1, kAα uk ≤ η, kAα vk ≤ η, Mb (η) = 2[Lb cη + b1 ], kuk∞ = sup0≤x≤1 |u(x)| and kuk∞ ≤ ckAα uk for any u ∈ D(Aα ). Hence the operator B restricted to D(Aα ) satisfies the hypothesis (H3) for K1 (η) = Mb (η). Similarly we can show that the operators C and L satisfies the hypothesis (H4) and (H5) respectively. 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Math., 78 (1963), 339-364. Dhirendra Bahuguna Department of Mathematics, Indian Institute of Technology, Kanpur - 208 016, India E-mail address: d bahuguna@yahoo.com Malik Muslim Department of Mathematics, Indian Institute of Technology, Kanpur - 208 016, India E-mail address: malik iitk@yahoo.com