Journal of Inequalities in Pure and Applied Mathematics BOUNDARY VALUE PROBLEM FOR SECOND-ORDER DIFFERENTIAL OPERATORS WITH MIXED NONLOCAL BOUNDARY CONDITIONS volume 5, issue 2, article 38, 2004. M. DENCHE AND A. KOURTA Laboratoire Equations Differentielles, Departement de Mathematiques, Faculte des Sciences, Universite Mentouri, 25000 Constantine, Algeria. EMail: denech@wissal.dz Received 15 October, 2003; accepted 16 April, 2004. Communicated by: A.G. Ramm Abstract Contents JJ J II I Home Page Go Back Close c 2000 Victoria University ISSN (electronic): 1443-5756 147-03 Quit Abstract In this paper, we study a second order differential operator with mixed nonlocal boundary conditions combined weighting integral boundary condition with another two point boundary condition. Under certain conditions on the weighting functions and on the coefficients in the boundary conditions, called non regular boundary conditions, we prove that the resolvent decreases with respect to the spectral parameter in Lp (0, 1), but there is no maximal decreasing at infinity for p ≥ 1. Furthermore, the studied operator generates in Lp (0, 1) an analytic semi group with singularities for p ≥ 1. The obtained results are then used to show the correct solvability of a mixed problem for a parabolic partial differential equation with non regular boundary conditions. Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta 2000 Mathematics Subject Classification: 47E05, 35K20. Key words: Green’s Function, Non Regular Boundary Conditions, Regular Boundary Conditions, Semi group with Singularities. Title Page Contents The authors are grateful to the editor and the referees for their valuable comments and helpful suggestions which have much improved the presentation of the paper. JJ J Contents 1 2 3 Introduction . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Green’s Function . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . Bounds on the Resolvent . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 3.1 Estimation of N (x, s; λ) . . . . . . . . . . . . . . . . . . . . . . . 3.2 Estimation of the Characteristic Determinant . . . . . . . 3.3 Application . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . References 3 5 10 10 17 26 II I Go Back Close Quit Page 2 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au 1. Introduction In the space Lp (0, 1) we consider the boundary value problem 00 L (u) = u = f (x) , 0 0 B1 (u) = a0 u (0) + b0 u (0) + c0 u (1) + d0 u (1) = 0, (1.1) R1 R1 0 B2 (u) = 0 R (t) u (t) dt + 0 S (t) u (t) dt = 0, where the functions R, S ∈ C([0, 1] , C). We associate to problem (1.1) in space Lp (0, 1) the operator: Lp (u) = u00 , with domain D(Lp ) = {u ∈ W 2,p (0, 1) : Bi (u) = 0, i = 1, 2} . Many papers and books give the full spectral theory of Birkhoff regular differential operators with two point linearly independent boundary conditions, in terms of coefficients of boundary conditions. The reader should refer to [7, 10, 20, 21, 22, 28, 31, 33] and references therein. Few works have been devoted to the study of a non regular situation. The case of separated non regular boundary conditions was studied by W. Eberhard, J.W. Hopkins, D. Jakson, M.V. Keldysh, A.P. Khromov, G. Seifert, M.H. Stone, L.E. Ward (see S. Yakubov and Y. Yakubov [33] for exact references). A situation of non regular non-separated boundary conditions was considered by H. E. Benzinger [2], M. Denche [4], W. Eberhard and G. Freiling [8], M.G. Gasumov and A.M. Magerramov [12, 13], A.P. Khromov [18], Yu. A. Mamedov [19], A.A. Shkalikov [24], Yu. T. Silchenko [26], C. Tretter [29], A.I. Vagabov [30], S. Yakubov [32] and Y. Yakubov [34]. Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close Quit Page 3 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au A mathematical model with integral boundary conditions was derived by [9, 23] in the context of optical physics. The importance of this kind of problem has been also pointed out by Samarskii [27]. In this paper, we study a problem for second order ordinary differential equations with mixed nonlocal boundary conditions combined with weighted integral boundary conditions and another two point boundary condition. Following the technique in [11, 20, 21, 22], we should bound the resolvent in the space Lp (0, 1) by means of a suitable formula for Green’s function. Under certain conditions on the weighting functions and on the coefficients in the boundary conditions, called non regular boundary conditions, we prove that the resolvent decreases with respect to the spectral parameter in Lp (0, 1), but there is no maximal decreasing at infinity for p ≥ 1. In contrast to the regular case this decreasing is maximal for p = 1 as shown in [11]. Furthermore, the studied operator generates in Lp (0, 1) an analytic semi group with singularities for p ≥ 1. The obtained results are then used to show the correct solvability of a mixed problem for a parabolic partial differential equation with non regular non local boundary conditions. Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close Quit Page 4 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au 2. Green’s Function Let λ ∈ C, u1 (x) = u1 (x, λ ) and u2 (x) = u2 (x, λ ) be a fundamental system of solutions to the equation L (u) − λu = 0. Following [20], the Green’s function of problem (1.1) is given by (2.1) G(x, s; λ) = N (x, s; λ) , ∆(λ) where ∆(λ) it the characteristic determinant of the considered problem defined by B1 (u1 ) B1 (u2 ) (2.2) ∆(λ) = B2 (u1 ) B2 (u2 ) u1 (x) u2 (x) g(x, s, λ) B1 (g)x N (x, s; λ) = B1 (u1 ) B1 (u2 ) B2 (u1 ) B2 (u2 ) B2 (g)x for x, s ∈ [0, 1].The function g(x, s, λ) is defined as follows (2.4) M. Denche and A. Kourta Title Page Contents and (2.3) Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions g(x, s; λ) = ± 1 u1 (x)u2 (s) − u1 (s)u2 (x) , 2 u01 (s)u2 (s) − u1 (s)u02 (s) where it takes the plus sign for x > s and the minus sign for x < s. JJ J II I Go Back Close Quit Page 5 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au Given an arbitrary δ ∈ π ,π 2 , we consider the sector Σδ = {λ ∈ C, |arg λ| ≤ δ, λ 6= 0} . P For λ ∈ δ , define ρ as the square root of λ with positive real part. For λ 6= 0, we can consider a fundamental system of solutions of the equation u00 = λu = ρ2 u given by u1 (t) = e−ρt and u2 (t) = eρt . In the following we are going to deduce an adequate formulae for ∆(λ) and G(x, s; λ). First of all, for j = 1, 2, we have (−1)j ρ j j Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions (−1)j ρ B1 (uj ) = a0 + (−1) b0 ρ + c0 e + (−1) d0 ρe , Z 1 Z 1 j j B2 (uj ) = R(t)e(−1) ρt dt + (−1)j ρ S(t)e(−1) ρt dt. 0 M. Denche and A. Kourta 0 so we obtain from (2.2) Title Page (2.5) ∆(λ) = a0 − b0 ρ + c0 e−ρ − d0 ρe−ρ ρ ρ 1 Z Z0 − (a0 + b0 ρ + c0 e + d0 ρe ) ρt (R(t) + ρS(t))e dt 1 (R(t) − ρS(t))e 0 dt , JJ J II I Go Back and g(x, s; λ) has the form g(x, s; λ) = −ρt Contents 1 ρ(x−s) (e − eρ(s−x) ) if x > s, 4ρ 1 ρ(s−x) (e − eρ(x−s) ) if x < s. 4ρ Close Quit Page 6 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au Thus we have B1 (g) = a0 − b0 ρ − c0 e−ρ + d0 ρe−ρ eρs 4ρ e−ρs + (−a0 − b0 ρ + c0 eρ + d0 ρeρ ) , 4ρ Z s Z 1 eρs −ρt −ρt B2 (g) = (R(t) − ρS(t))e dt + (−R(t) + ρS(t))e dt 4ρ 0 s Z s Z 1 e−ρs ρt ρt + − (R(t) + ρS(t))e dt + (R(t) + ρS(t))e dt . 4ρ 0 s After a long calculation, formula (2.3) can be written as Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta N (x, s; λ) = ϕ(x, s; λ) + ϕi (x, s; λ), (2.6) Title Page where Contents 1 2ρ Z 1 (a0 + ρb0 ) (R (t) + ρS (t)) eρt dt 0 Z s ρ ρt − e (c0 + ρd0 ) (R (t) + ρS (t)) e dt e−ρ(x+s) 0 Z 1 + (a0 − ρb0 ) (R (t) − ρS (t)) e−ρt dt s Z s ρ −ρt ρ(x+s) − e (c0 − ρd0 ) (R (t) − ρS (t)) e dt e (2.7) ϕ(x, s; λ) = JJ J II I Go Back Close Quit Page 7 of 36 0 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au and the function ϕi (x, s; λ) is given by ϕ1 (x, s; λ) if x > s, (2.8) ϕi (x, s; λ) = ϕ2 (x, s; λ) if x < s, with (2.9) ϕ1 (x, s; λ) Z s eρ(s−x) = (a0 + ρb0 + c0 eρ + ρeρ d0 ) (R (t) − ρS (t)) e−ρt dt 2ρ 0 Z 1 ρt − (a0 − ρb0 ) (R (t) + ρS (t)) e dt s Z s eρ(x−s) + a0 − ρb0 + c0 e−ρ − ρe−ρ d0 (R (t) + ρS (t)) eρt dt 2ρ 0 Z 1 −ρt − (a0 + ρb0 ) (R (t) − ρS (t)) e dt , 0 and Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back (2.10) ϕ2 (x, s; λ) Z 1 1 − (a0 + ρb0 + c0 eρ + ρeρ d0 ) (R (t) − ρS (t)) e−ρt dt = 2ρ s Z 1 −ρ ρt + (c0 − ρd0 ) e (R (t) + ρS (t)) e dt eρ(s−x) 0 Close Quit Page 8 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au Z − s 1 a0 − ρb0 + c0 e−ρ − ρe−ρ d0 (R (t) + ρS (t)) eρt dt Z 1 ρ −ρt ρ(x−s) − (c0 + ρd0 ) e (R (t) − ρS (t)) e dt e . 0 Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close Quit Page 9 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au 3. Bounds on the Resolvent Every λ ∈ C such that ∆(λ) 6= 0 belongs to ρ(Lp ), and the associated resolvent operator R(λ, Lp ) can be expressed as a Hilbert Schmidt operator Z 1 −1 (3.1) (λI − Lp ) f = R(λ, Lp )f = − G(·, s; λ)f (s)ds, f ∈ Lp (0, 1). 0 Then, for every f ∈ Lp (0, 1) we estimate (3.1) kR(λ; Lp )f kLp (0,1) ≤ Z sup 0≤s≤1 and so we need to bound p1 Z 1 p sup |G(x, s; λ)| dx = 0≤s≤1 3.1. 0 1 |G(x, s; λ)|p dx Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions p1 kf kLp (0,1) , 0 M. Denche and A. Kourta 1 |∆(λ)| Z p |N (x, s; λ)| dx sup 0≤s≤1 p1 1 . 0 Contents Estimation of N (x, s; λ) We will denote by k·k the supremum norm which is defined by kRk = sup |R (s)|. 0≤s≤1 Since ( N (x, s; λ) = ϕ (x, s; λ) + ϕ1 (x, s; λ) if x > s ϕ (x, s; λ) + ϕ2 (x, s; λ) if x < s ; then (3.2) Title Page JJ J II I Go Back Close Quit Page 10 of 36 kN (x, s; λ)kLp ≤ kϕ (x, s; λ)kLp + kϕi (x, s; λ)kLp , J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au from (2.8), we have (3.3) kϕi (x, s; λ)kLp (Z p1 Z s p 1/p ≤2 |ϕ2 (x, s; λ)| dx + 0 1 |ϕ1 (x, s; λ)|p dx p1 ) . s From (2.7) we have Z 1 e−(x+s) Re ρ |ϕ (x, s; λ)| ≤ (kRk + |ρ| kSk) (|a0 | + |ρ| |b0 |) et Re ρ dt 2 |ρ| s Z s Re ρ t Re ρ + (kRk + |ρ| kSk) (|c0 | + |ρ| |d0 |) e e dt 0 Z 1 e(x+s) Re ρ (kRk + |ρ| kSk) (|a0 | + |ρ| |b0 |) e−t Re ρ dt + 2 |ρ| Z ss − Re ρ −t Re ρ +e (kRk + |ρ| kSk) (|c0 | + |ρ| |d0 |) e dt 0 then e−(x+s) Re ρ (kRk + |ρ| kSk) (|a0 | + |ρ| |b0 |) eRe ρ − es Re ρ 2 |ρ| Re ρ + (kRk + |ρ| kSk) (|c0 | + |ρ| |d0 |) e(s+1) Re ρ − eRe ρ e(x+s) Re ρ (kRk + |ρ| kSk) (|a0 | + |ρ| |b0 |) e−s Re ρ − e− Re ρ + 2 |ρ| Re ρ + (kRk + |ρ| kSk) (|c0 | + |ρ| |d0 |) e− Re ρ − e−(s+1) Re ρ |ϕ (x, s; λ)| ≤ Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close Quit Page 11 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au and Z 1 |ϕ (x, s; λ)|p dx 0 R1 p 2p 0 e−px Re ρ dx h ≤ (kRk + |ρ| kSk)p (|a0 | + |ρ| |b0 |)p e(1−s) Re ρ − 1 p (|ρ| Re ρ) i p p Re ρ (1−s) Re ρ p + (kRk + |ρ| kSk) × (|c0 | + |ρ| |d0 |) e −e R 1 p 2p 0 epx Re ρ dx + [(kRk + |ρ| kSk)p (|a0 | + |ρ| |b0 |)p 1 − e(s−1) Re ρ p (|ρ| Re ρ) p i + (kRk + |ρ| kSk)p (|c0 | + |ρ| |d0 |)p e(s−1) Re ρ − e−1 Re ρ , Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta after calculation we obtain Title Page Z 1 |ϕ (x, s; λ)|p dx p1 Contents 0 1+ p2 Re ρ ≤ 2 e 1 |ρ| (Re ρ)1+ p p1/p (kRk + |ρ| kSk) (|a0 | + |ρ| |b0 |) e−s Re ρ − e− Re ρ × 1 − e−p Re ρ p1 p1 i 1 − e(s−1) Re ρ +(kRk + |ρ| kSk) h 1 × (|c0 | + |ρ| |d0 |) 1 − e−p Re ρ p 1 − e−s Re ρ 1 ii + 1 − e−p Re ρ p e(s−1) Re ρ − e− Re ρ + 1 − e−p Re ρ JJ J II I Go Back Close Quit Page 12 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au as Re ρ > 0 so Z (3.4) p p1 |ϕ (x, s; λ)| dx sup 0≤s≤1 1 0 2 ≤ 21+ p eRe ρ (kRk + |ρ| kSk) [(|a0 | + |c0 |) + |ρ| (|b0 | + |d0 |)] 1 |ρ| (Re ρ)1+ p p1/p From (2.9) we have e(s−x) Re ρ |ϕ1 (x, s; λ)| ≤ (|a0 | + |ρ| |b0 |) + eRe ρ (|c0 | + |ρ| |d0 |) 2 |ρ| Z s × (kRk + |ρ| kSk) e−t Re ρ dt 0 Z 1 t Re ρ + (|a0 | + |ρ| |b0 |) (kRk + |ρ| kSk) e dt 0 e(x−s) Re ρ + (kRk + |ρ| kSk) [(|a0 | + |ρ| |b0 |) 2 |ρ| Z s Re ρ +e (|c0 | + |ρ| |d0 |)] et Re ρ dt 0 Z 1 −t Re ρ + (|a0 | + |ρ| |b0 |) (kRk + |ρ| kSk) e dt 0 . Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close Quit Page 13 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au then e(s−x) Re ρ |ϕ1 (x, s; λ)| ≤ (|a0 | + |ρ| |b0 |) (kRk + |ρ| kSk) eRe ρ − e−s Re ρ 2 |ρ| Re ρ + (|c0 | + |ρ| |d0 |) (kRk + |ρ| kSk) eRe ρ − e(1−s) Re ρ e(x−s) Re ρ (kRk + |ρ| kSk) (|a0 | + |ρ| |b0 |) es Re ρ − e− Re ρ + 2 |ρ| Re ρ + (|c0 | + |ρ| |d0 |) (kRk + |ρ| kSk) e(s−1) Re ρ − e− Re ρ and Z 1 |ϕ1 (x, s; λ)|p dx s R1 p 2p s e−px Re ρ dx h ≤ (|a0 | + |ρ| |b0 |)p (kRk + |ρ| kSk)p e(1+s) Re ρ − 1 p p |ρ| (Re ρ) p i + (|c0 | + |ρ| |d0 |)p (kRk + |ρ| kSk)p e(1+s) Re ρ − eRe ρ R1 p 2p s epx Re ρ dx h (|a0 | + |ρ| |b0 |)p (kRk + |ρ| kSk)p 1 − e−(1+s) Re ρ + p p |ρ| (Re ρ) p + (|c0 | + |ρ| |d0 |)p (kRk + |ρ| kSk)p e− Re ρ − e−(1+s) Re ρ , this yields Z 1 |ϕ1 (x, s; λ)|p dx ≤ s Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close 2p+1 ep Re ρ p p p p+1 [(|a0 | + |ρ| |b0 |) (kRk + |ρ| kSk) |ρ| (Re ρ) p × 1 − e−(1+s) Re ρ 1 − ep(s−1) Re ρ Quit Page 14 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au + (|c0 | + |ρ| |d0 |)p (kRk + |ρ| kSk)p 1 − e−s Re ρ p 1 − ep(s−1) Re ρ as Re ρ > 0 we obtain Z (3.5) p p1 |ϕ1 (x, s; λ)| dx sup 0≤s≤1 1 s 2 ≤ 21+ p eRe ρ (kRk + |ρ| kSk) [(|a0 | + |c0 |) + |ρ| (|b0 | + |d0 |)] 1 |ρ| (Re ρ)1+ p p1/p . Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions From (2.10) we have |ϕ2 (x, s; λ)| Z 1 e(x−s) Re ρ ≤ (kRk + |ρ| kSk) (|c0 | + |ρ| |d0 |) e(1−t) Re ρ dt 2 |ρ| 0 Z 1 t Re ρ − Re ρ + (kRk + |ρ| kSk) (|a0 | + |ρ| |b0 |) + e (|c0 | + |ρ| |d0 |) e dt 0 Z 1 e(s−x) Re ρ + [(|c0 | + |ρ| |d0 |) (kRk + |ρ| kSk) e(t−1) Re ρ dt 2 |ρ| 0 Z 1 Re ρ −t Re ρ + (|a0 | + |ρ| |b0 |) + e (|c0 | + |ρ| |d0 |) (kRk + |ρ| kSk) e dt M. Denche and A. Kourta Title Page Contents JJ J II I Go Back s then ex Re ρ (kRk + |ρ| kSk) (|c0 | + |ρ| |d0 |) e(1−s) Re ρ − e− Re ρ |ϕ2 (x, s; λ)| ≤ 2 |ρ| Re ρ + (|a0 | + |ρ| |b0 |) (kRk + |ρ| kSk) e(1−s) Re ρ − 1 Close Quit Page 15 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au + So Z e−x Re ρ (kRk + |ρ| kSk) (|c0 | + |ρ| |d0 |) eRe ρ − e(s−1) Re ρ 2 |ρ| Re ρ + (|a0 | + |ρ| |b0 |) (kRk + |ρ| kSk) 1 − e(s−1) Re ρ . s |ϕ2 (x, s; λ)|p dx 0 p 2p+1 ep Re ρ h p p 1 − e(s−2) Re ρ p p+1 (kRk + |ρ| kSk) (|c0 | + |ρ| |d0 |) p |ρ| (Re ρ) × 1 − e−ps Re ρ + (|a0 | + |ρ| |b0 |)p i p −ps Re ρ (s−1) Re ρ p × (kRk + |ρ| kSk) 1 − e 1−e ≤ as Re ρ > 0 we obtain Z sup (3.6) 0≤s≤1 s |ϕ2 (x, s; λ)|p dx 1+ p2 Re ρ 2 Contents e (kRk + |ρ| kSk) [(|a0 | + |c0 |) + |ρ| (|b0 | + |d0 |)] 1 |ρ| (Re ρ)1+ p p1/p . ≤ II I Close kR (λ, Lp )k 2 JJ J Go Back From (3.4), (3.5) and (3.6), we obtain 1+ p2 M. Denche and A. Kourta Title Page p1 0 ≤ Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions Quit eRe ρ (kRk + |ρ| kSk) [(|a0 | + |c0 |) + |ρ| (|b0 | + |d0 |)] 1+ p1 |4 (λ)| |ρ| (Re ρ) 1+ p2 2 +1 , Page 16 of 36 p1/p J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au for ρ ∈ Σ δ = ρ ∈ C : |arg ρ| ≤ 2δ , ρ 6= 0 , we have (Re ρ)−1 < 2 1 , |ρ| cos( 2δ ) then kR (λ, Lp )k 1+ p2 1+ p2 2 2 + 1 eRe ρ (kRk + |ρ| kSk) [(|a0 | + |c0 |) + |ρ| (|b0 | + |d0 |)] . ≤ 1+ p1 1 |4 (λ)| |ρ| |ρ|1+ p cos 2δ p1/p Finally, we obtain for λ = ρ2 ∈ Σδ (3.7) kR (λ, Lp )kLp ≤ c eRe ρ 1+ p1 |4 (λ)| |ρ| kRk + kSk [(|a0 | + |c0 |) + |ρ| (|b0 | + |d0 |)] , |ρ| M. Denche and A. Kourta Title Page where 1+ p2 2 c= p1/p 3.2. Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions 2 +1 1+ p1 . cos 2δ 1+ p2 Estimation of the Characteristic Determinant The next step is to determine the cases for which |∆(λ)| remains bounded below. It will then be necessary to bound |∆(λ)| appropriately. However, formula (2.5) is not useful for this purpose. It will be then necessary to make some additional regularity hypotheses on the functions R and S, and so we assume that the functions R and S are in C 2 ([0, 1] , C). Contents JJ J II I Go Back Close Quit Page 17 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au Integrating twice by parts in (2.5), we obtain h 0 0 (3.8) ∆(λ) = eρ ρ(d0 S(0) − b0 S(1)) + (d0 S (0) + b0 S (1) + a0 S (1) 1 0 −b0 R (1) − d0 R (0) + c0 S (0)) + (a0 R (1) − c0 R (0) + b0 R (1) ρ 1 0 0 0 0 0 −a0 S (1) − d0 R (0) + c0 S (0)) + 2 (−a0 R (1) − c0 R (0)) + Φ(ρ) , ρ where Z 1 R00 (t) S 00 (t) ρt −ρ −2ρ (3.9) Φ(ρ) = (a0 − ρb0 )e + (c0 − ρd0 )e − e dt ρ2 ρ 0 Z 1 R00 (t) S 00 (t) −ρt −ρ + (a0 + ρb0 )e + (c0 + ρd0 ) − e dt ρ2 ρ 0 0 −ρ 1 +e −b0 R0 (0) + d0 R0 (1) − c0 S 0 (1) + a0 S (0) + c0 R(1) − a0 R(0) ρ + ρ(b0 S(0) − d0 S(1))] + 2e−2ρ [(a0 + ρb0 )(R(1) − ρS(1)) 1 0 0 − (c0 − ρd0 )(R(0) + ρS(0)) + 2 (a0 + ρb0 )(R (1) − ρS (1)) ρ 1 0 0 + 2 (c0 − ρd0 )(R (0) + ρS (0)) . ρ After a straightforward calculation, we obtain the following inequality valid for Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close Quit Page 18 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au ρ ∈ Σ δ ,with |ρ| sufficiently large, 2 |Φ(ρ)| ≤ (|a0 | + |ρ| |b0 |) e− Re ρ + (|c0 | + |ρ| |d0 |) e−2 Re ρ 00 Re ρ kR k kS 00 k e −1 × + |ρ| Re ρ |ρ|2 − Re ρ + (|a0 | + |ρ| |b0 |) e + (|c0 | + |ρ| |d0 |) 00 kR k kS 00 k 1 − e− Re ρ + × |ρ| Re ρ |ρ|2 1 0 0 0 0 −b R (0) + d R (1) − c S (1) + a S (0) + c R(1) − a R(0) + 2e− Re ρ 0 0 0 0 0 0 |ρ| 1 + |ρ| |b0 S(0) − d0 S(1)|] + e−2 Re ρ (|a0 | + |ρ| |b0 |) (kRk + |ρ| kSk) |ρ| 0 ! R + |ρ| S 0 1 + (|c0 | + |ρ| |d0 |) (kRk + |ρ| kSk) + (|a0 | + |ρ| |b0 |) |ρ| |ρ|2 0 !# R + |ρ| S 0 + (|c0 | + |ρ| |d0 |) . |ρ|2 Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close Then Quit |Φ(ρ)| ≤ 2 (|a0 | + |c0 |) + (|b0 | + |d0 |) δ |ρ| |ρ| cos 2 00 kR k + kS 00 k |ρ| Page 19 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au 1 1 0 0 0 + 2 −b0 R (0) + d0 R (1) − c0 S (1) δ |ρ| cos 2 |ρ| i 0 + +a0 S (0) + c0 R(1) − a0 R(0) |b0 S(0) − d0 S(1)| 1 |a0 | kRk + + |b0 | + kSk |ρ| |ρ| |ρ| (cos 2δ )2 kRk |c0 | + + |d0 | + kSk |ρ| |ρ| 0! 0 S R |a0 | + + |b0 | 2 + |ρ| |ρ| |ρ| 0 !# 0 R S |c0 | + + |d0 | + . |ρ| |ρ| |ρ|2 (3.10) Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Where we have used that Re(ρ) ≥ e− Re ρ ≤ |ρ| cos( 2δ ), − Re ρ (1 − e ) < 1, 2 1 ande−2 Re ρ ≤ , e− Re ρ < 1. 2 δ 2 |ρ| (cos 2 ) 2 |ρ| (cos 2δ )2 2 There are several cases to analyze depending on the functions R and S. Contents JJ J II I Go Back Close • Case 1. Quit Suppose that S 6= 0, d0 6= 0, b0 6= 0, d0 S (0) − b0 S (1) = 0 and 0 Page 20 of 36 0 k1 = d0 S (0) + b0 S (1) + a0 S (1) − b0 R (1) − d0 R (0) + c0 S (0) 6= 0. J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au From (3.8), we have for |ρ| sufficiently large |4 (λ)| h 0 0 ≥e d0 S (0) + b0 S (1) + a0 S (1) − b0 R (1) − d0 R (0) + c0 S (0) 1 0 0 0 0 − a0 R (1) − c0 R (0) + b0 R (1) − a0 S (1) − d0 R (0) + c0 S (0) |ρ| 1 0 0 − 2 a0 R (1) + c0 R (0) − |Φ(ρ)| . |ρ| Re ρ From (3.10) we deduce for ρ ∈ Σ δ , |ρ| ≥ r0 > 0. Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions 2 M. Denche and A. Kourta c(r0 ) |Φ(ρ)| ≤ . |ρ| Then, we have |4 (λ)| h 0 0 Re ρ ≥e d0 S (0) + b0 S (1) + a0 S (1) − b0 R (1) − d0 R (0) + c0 S (0) 1 0 0 0 0 − a R (1) − c R (0) + b R (1) − a S (1) − d R (0) + c S (0) 0 0 0 0 0 0 |ρ| c(r ) 1 0 0 0 . − 2 a0 R (1) + c0 R (0) − |ρ| |ρ| Title Page Contents JJ J II I Go Back Close Quit Page 21 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au we can now choose r0 > 0, such that 1 0 0 0 0 a0 R (1) − c0 R (0) + b0 R (1) − a0 S (1) − d0 R (0) + c0 S (0) r0 c(r ) 1 0 0 0 + 2 a0 R (1) + c0 R (0) + r0 |ρ| 1 0 0 ≤ d0 S (0) + b0 S (1) + a0 S (1) − b0 R (1) − d0 R (0) + c0 S (0) , 2 then, for ρ ∈ Σ δ , |ρ| ≥ r0 > 0, we get 2 |4 (λ)| ≥ eRe ρ |k1 | . 2 From (3.7), we deduce the following bound, valid for every |arg ρ| ≤ 2δ , ρ 6= 0 2c |a0 | + |c0 | kRk kR (λ, Lp )k ≤ + (|b0 | + |d0 |) + kSk , 1 |ρ| |ρ| |ρ| p |k1 | then kR (λ, Lp )k ≤ c1 1 , |λ| 2p as |λ| −→ +∞, where M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close c1 = • Case 2. Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions 2c kSk (|b0 | + |d0 |) . |k1 | Quit Page 22 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au If b0 = d0 = 0, S 6= 0 and a0 S (1) + c0 S (0) = 0, with 0 0 k2 = a0 R (1) − c0 R (0) − a0 S (1) + c0 S (0) 6= 0, we have the following bound, valid for λ ∈ Σδ and |λ| big enough, 2c (|a0 | + |c0 |) kRk kR (λ, Lp )k ≤ + kSk , 1 |ρ| |ρ| p |k2 | then kR (λ, Lp )k ≤ c1 1 Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions , |λ| 2p as |λ| −→ +∞, where M. Denche and A. Kourta c1 = 2c (|a0 | + |c0 |) kSk . |k2 | Title Page Contents • Case 3. If S = 0, b0 6= 0, d0 6= 0 and b0 R(1) + d0 R (0) = 0, with 0 0 k3 = a0 R (1) − c0 R (0) + b0 R (1) − d0 R (0) 6= 0. JJ J II I Go Back Close Similarly, we get Quit kR (λ, Lp )k ≤ 2c kRk 1+ p1 |ρ| |k3 | (|a0 | + |c0 |) + (|b0 | + |d0 |) , |ρ| Page 23 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au then, we have kR (λ, Lp )k ≤ c1 1 , |λ| 2p as |λ| −→ +∞, where c1 = 2c kRk (|b0 | + |d0 |) . |k3 | • Case 4. If b0 = d0 = 0, S = 0 and a0 R (1) − c0 R (0) = 0 with 0 Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions 0 k4 = a0 R (1) − c0 R (0) 6= 0. M. Denche and A. Kourta Again in this case, we have Title Page kR (λ, Lp )k ≤ 2c (|a0 | + |c0 |) kRk 1 p |ρ| |k4 | then kR (λ, Lp )k ≤ c1 1 , |λ| 2p , Contents JJ J II I Go Back Close as |λ| −→ +∞, where c kRk (|a0 | + |c0 |) c1 = . |k4 | Quit Page 24 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au Definition 3.1. The boundary value conditions in (1.1) are called non regular if the functions R, S ∈ C 2 ([0, 1] , C) and if and only if one of the following conditions holds 1-d0 S (0) − b0 (1) = 0, b0 6= 0, d0 6= 0, S 6= 0 and 0 0 d0 S (0) + b0 S (1) + a0 S (1) − b0 R (1) − d0 R (0) + c0 S (0) 6= 0 2- b0 = d0 = 0, kSk = 6 0, a0 S (1) + c0 S (0) = 0 with 0 0 a0 R (1) − c0 R (0) − a0 S (1) + c0 S (0) 6= 0 3-S = 0, b0 6= 0, d0 6= 0, b0 R(1) +0 R (0) 6= 0 with 0 0 a0 R (1) − c0 R (0) + b0 R (1) − d0 R (0) 6= 0 4-b0 = d0 = 0, S = 0, a0 R (1) − c0 R (0) = 0 with 0 0 a0 R (1) − c0 R (0) 6= 0. This proves the following theorem Theorem 3.1. If the boundary value conditions in (1.1) are non regular, then Σδ ⊂ ρ(Lp ) for sufficiently large |λ| and there exists c > 0 such that kR (λ, Lp )k ≤ M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close c |λ| Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions 1 2p . Remark 3.1. From Theorem 3.1 it follows that the operator Lp , for p 6= ∞, generates an analytic semigroup with singularities [25] of type A (2p − 1, 4p − 1). Quit Page 25 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au 3.3. Application In the following, we apply the above obtained results to the study of a class of a mixed problem for a parabolic equation with an weighted integral boundary condition combined with another two point boundary condition of the form ∂ 2 u(t, x) ∂u(t, x) − a = f (t, x) ∂t ∂x2 L (u) = a u (0, t) + b u0 (0, t) + c u (1, t) + d u0 (1, t) = 0, 1 0 0 0 0 (3.11) R R 0 1 1 L2 (u) = 0 R(ξ) u(t, ξ) dξ + 0 S(ξ) u (t, ξ) dξ = 0, u(0, x) = u0 (x), where (t, ξ) ∈ [0, T ] × [0, 1]. Boundary value problems for parabolic equations with integral boundary conditions are studied by [1, 3, 5, 6, 14, 15, 16, 17, 35] using various methods. For instance, the potential method in [3] and [17], Fourier method in [1, 14, 15, 16] and the energy inequalities method has been used in [5, 6, 35]. In our case, we apply the method of operator differential equation. The study of the problem is then reduced to a cauchy problem for a parabolic abstract differential equation, where the operator coefficients has been previously studied. For this purpose, let E, E1 , and E2 be Banach spaces. Introduce two Banach spaces Cµ ((0, T ] , E) ( = Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close Quit ) f /f ∈ C ((0, T ] , E) , kf k = sup ktµ f (t)k < ∞ , µ ≥ 0, Page 26 of 36 t∈(0,T ] J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au ( Cµγ ((0, T ] , E) = f /f ∈ C ((0, T ] , E) , kf k = sup ktµ f (t)k t∈(0,T ] + sup −γ µ kf (t + h) − f (t)k h t < ∞ , 0<t<t+h≤T µ ≥ 0, γ ∈ (0, 1] , and a linear space C 1 ((0, T ] , E1 , E2 ) = f /f ∈ C ((0, T ] , E1 ) ∩ C 1 ((0, T ] , E2 ) , E1 ⊂ E2 , where C ((0, T ] , E) and C 1 ((0, T ] , E) are spaces of continuous and continuously differentiable, respectively, vector-function from (0, T ] into E. We denote, for a linear operator A in a Banach space E, by n 1 o E(A) = u/u ∈ D(A), kukE(A) = kAuk2 + kuk2 2 , and n o 0 C 1 ((0, T ] , E(A), E) = f /f ∈ C ((0, T ] , E(A)) , f ∈ C ((0, T ] , E)) . Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Let us derive a theorem which was proved by various methods in [25] and [31, 33]. Consider, in a Banach space E, the Cauchy problem ( 0 u (t) = Au(t) + f (t), t ∈ [0, T ] , (3.12) u(0) = u0 , Close Quit Page 27 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au where A is, generally speaking, unbounded linear operator in E, u0 is a given element of E, f (t) is a given vector-function and u(t) is an unknown vectorfunction in E. Theorem 3.2. Let the following conditions be satisfied: 1. A is a closed linear operator in a Banach space E and for some β ∈ (0, 1] , α>0 π kR (λ, A)k ≤ C |λ|−β , |arg λ| ≤ + α, |λ| → ∞; 2 2. f ∈ Cµγ ((0, T ] , E) for some γ ∈ (1 − β, 1] , µ ∈ [0, β) ; Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta 3. u0 ∈ D(A). Then the Cauchy problem (3.12) has a unique solution Title Page Contents u ∈ C ([0, T ] , E) ∩ C 1 ((0, T ] , E(A), E) and for the solution u the following estimates hold ku(t)k ≤ C kAu0 k + ku0 k + kf kCµ ((0,t],E) , t ∈ (0, T ] , JJ J II I Go Back Close 0 u (t) + kAu(t)k ≤ C tβ−1 (kAu0 k + ku0 k) + tβ−µ−1 kf kCµγ ((0,t],E) , t ∈ (0, T ] . Quit Page 28 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au As a result of this we get the following theorem Theorem 3.3. Let the following conditions be satisfied 1. a 6= 0, |arg a| < π , 2 2. the functions R(t), S(t) ∈ C 2 ([0, 1] , C) and one of the following conditions is satisfied d0 S (0) − b0 S (1) = 0, b0 6= 0, d0 6= 0, and S 6= 0 0 0 d0 S (0) + b0 S (1) + a0 S (1) − b0 R (1) − d0 R (0) + c0 S (0) 6= 0, or b0 = 0, d0 = 0, S 6= 0 , a0 S (1) + c0 S (0) = 0 with 0 Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta 0 a0 R (1) − c0 R (0) − a0 S (1) + c0 S (0) 6= 0, Title Page or b0 6= 0, d0 6= 0, S = 0, b0 R(1) + d0 R (0) = 0 with 0 0 a0 R (1) − c0 R (0) + b0 R (1) − d0 R (0) 6= 0, or b0 = d0 = 0, S = 0, a0 R (1) − c0 R (0) = 0 with 0 0 a0 R (1) − c0 R (0) 6= 0. Contents JJ J II I Go Back Close i h 1 1 3. f ∈ Cµγ ((0, T ] , Lq (0, 1)) for some γ ∈ 1 − 2q , 1 and some µ ∈ 0, 2q , 4. u0 ∈ Wq2 (0, 1) , Li u = 0, i = 1, 2 . Quit Page 29 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au Then the problem (3.11) has a unique solution u ∈ C ((0, T ] , Lq (0, 1)) ∩ C 1 (0, T ] , Wq2 (0, 1), Lq (0, 1) and for this solution we have the estimates: (3.13) ku(t, ·)kLq (0,1) ≤ c ku0 kWq2 (0,1) + kf kCµ ((0,t],Lq (0,1)) , t ∈ (0, T ] , (3.14) ku00 (t, ·)kLq (0,1) + ku0 (t, ·)kLq (0,1) 1 1 ≤ c t 2q −1 ku0 kWq2 (0,1) + t 2q −1−µ kf kCµγ ((0,t],Lq (0,1)) , t ∈ (0, T ] . Proof. We consider in the space Lq (0, 1) 1 ≤ q < ∞, the operator A defined by A(u) = au00 (x), D(A) = u ∈ Wq2 (0, 1), Li (u) = 0, i = 1, 2 . Then problem (3.11) can be written as ( 0 u (t) = Au(t) + f (t), u(0) = u0 , where u(t) = u(t, ·), f (t) = f (t, ·), and u0 = u0 (·) are functions with values in the Banach space Lq (0, 1). From Theorem 3.1 we conclude that kR(λ, A)k ≤ 1 π c |λ|− 2q , for |arg λ| ≤ + α, as |λ| → ∞. 2 Then, from Theorem 3.2 the problem (3.11) has a unique solution u ∈ C ((0, T ] , Lq (0, 1)) ∩ C 1 (0, T ] , Wq2 (0, 1), Lq (0, 1) Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close Quit Page 30 of 36 J. Ineq. Pure and Appl. Math. 5(2) Art. 38, 2004 http://jipam.vu.edu.au and we have the following estimates (3.15) ku(t, .)kLq (0,1) ≤ c kAu0 kLq (0,1) + ku0 kLq (0,1) + kf kCµ ((0,t],Lq (0,1)) , 0 (3.16) u (t) + kAu(t, ·)kLq (0,1) Lq (0,1) 1 1 ≤ c t 2q −1 kAu0 kLq (0,1) + ku0 kLq (0,1) + t 2q −1−µ kf kCµγ ((0,t],Lq (0,1)) , where t ∈ [0, T ], from (3.15) we get ku(t, ·)kLq (0,1) ≤ c ku000 kLq (0,1) + ku0 kLq (0,1) + kf kCµ ((0,t],Lq (0,1)) ≤ c ku0 kWq2 (0,1) + kf kCµ ((0,t],Lq (0,1)) , t ∈ [0, T ] . and from (3.16) we get 0 + ku00 (t, ·)kLq (0,1) u (t) q L (0,1) 1 1 −1 −1−µ 2q 2q ≤c t kAu0 kLq (0,1) + ku0 kLq (0,1) + t kf kCµγ ((0,t],Lq (0,1)) 1 1 ≤ c t 2q −1 ku0 kWq2 (0,1) + t 2q −1−µ kf kCµγ ((0,t],Lq (0,1)) , t ∈ [0, T ] . Boundary Value Problem for Second-Order Differential Operators with Mixed Nonlocal Boundary Conditions M. Denche and A. Kourta Title Page Contents JJ J II I Go Back Close Quit which gives the desired result. Page 31 of 36 J. Ineq. Pure and Appl. 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