Journal of Inequalities in Pure and Applied Mathematics http://jipam.vu.edu.au/ Volume 4, Issue 5, Article 104, 2003 ON THE STABILITY OF A CLASS OF FUNCTIONAL EQUATIONS BELAID BOUIKHALENE D ÉPARTEMENT DE M ATHÉMATIQUES ET I NFORMATIQUE FACULTÉ DES S CIENCES BP 133, 14000 K ÉNITRA , M OROCCO . bbouikhalene@yahoo.fr Received 20 July, 2003; accepted 24 October, 2003 Communicated by K. Nikodem A BSTRACT. In this paper, we study the Baker’s superstability for the following functional equation XZ (E (K)) f (xkϕ(y)k −1 )dωK (k) = |Φ|f (x)f (y), x, y ∈ G ϕ∈Φ K where G is a locally compact group, K is a compact subgroup of G, ωK is the normalized Haar measure of K, Φ is a finite group of K-invariant morphisms of G and f is a continuous complex-valued function on G satisfying the Kannappan type condition, for all x, y, z ∈ G Z Z Z Z (*) f (zkxk −1 hyh−1 )dωK (k)dωK (h) = f (zkyk −1 hxh−1 )dωK (k)dωK (h). K K K K We treat examples and give some applications. Key words and phrases: Functional equation, Stability, Superstability, Central function, Gelfand pairs. 2000 Mathematics Subject Classification. 39B72. 1. I NTRODUCTION , N OTATIONS AND P RELIMINARIES Let G be a locally compact group. Let K be a compact subgroup of G. Let ωK be the normalized Haar measure of K. A mapping ϕ : G 7−→ G is a morphism of G if ϕ is a homeomorphism of G onto itself which is either a group-homorphism, i.e (ϕ(xy) = ϕ(x)ϕ(y), x, y ∈ G), or a group-antihomorphism, i.e (ϕ(xy) = ϕ(y)ϕ(x), x, y ∈ G). We denote by M or(G) the group of morphisms of G and Φ a finite subgroup of M or(G) of a K-invariant morphisms of G (i.e ϕ(K) ⊂ K). The number of elements of a finite group Φ will be designated by |Φ|. The Banach algebra of bounded measures on G with complex values is denoted by M (G) and the Banach space of all complex measurable and essentially bounded functions on G by L∞ (G). C(G) designates the Banach space of all continuous complex valued functions on G. We say that a ISSN (electronic): 1443-5756 c 2003 Victoria University. All rights reserved. The author would like to greatly thank the referee for his helpful comments and remarks. 098-03 2 B ELAID B OUIKHALENE function f is a K-central function on G if f (kx) = f (xk), x ∈ G, k ∈ K. (1.1) In the case where G = K, a function f is central if f (xy) = f (yx) x, y ∈ G. (1.2) See [2] for more information. In this note, we are going to generalize the results obtained by J.A. Baker in [8] and [9]. As applications, we discuss the following cases: a) K ⊂ Z(G), (Z(G) is the center of G). b) f (hxk) = f (x), h, k ∈ K, x ∈ G (i.e. f is bi-K-invariant (see [3] and [6])). c) f (hxk) = χ(k)f (x)χ(h), x ∈ G, k, h ∈ K (χ is a unitary character of K) (see [11]). d) (G, K) is a Gelfand pair (see [3], [6] and [11]). e) G = K (see [2]). In the next section, we note some results for later use. 2. G ENERAL P ROPERTIES In what follows, we study general properties. Let G, K and Φ be given as above. Proposition 2.1. For an arbitrary fixed τ ∈ Φ, the mapping Φ −→ Φ, ϕ −→ ϕ ◦ τ is a bijection. Proof. Follows from the fact that Φ is a finite group. Proposition 2.2. Let ϕ ∈ Φ and f ∈ C(G), then we have: R R i) K f (xkϕ(hy)k −1 )dωK (k) = K f (xkϕ(yh)k −1 )dωK (k), x, y ∈ G, h ∈ K. ii) If f satisfy (*), the for all z, y, x ∈ G, we have Z Z Z Z −1 −1 f (zhϕ(ykxk )h )dωK (h)dωK (k) = f (zhϕ(xkyk −1 )h−1 )dωK (h)dωK (k). K Proof. K K K i) Let ϕ ∈ Φ and let x, y ∈ G, h ∈ K, then we have Case 1: If ϕ is a group-homomorphism, we obtain, by replacing k by kϕ(h)−1 Z Z −1 f (xkϕ(hy)k )dωK (k) = f (xkϕ(h)ϕ(y)k −1 )dωK (k) K K Z = f (xkϕ(y)ϕ(h)k −1 )dωK (k) K Z = f (xkϕ(yh)k −1 )dωK (k). K Case 2: if ϕ is a group-antihomomorphism, we have, by replacing k by kϕ(h) Z Z −1 f (xkϕ(hy)k )dωK (k) = f (xkϕ(y)ϕ(h)k −1 )dωK (k) K K Z = f (xkϕ(h)ϕ(y)k −1 )dωK (k) K Z = f (xkϕ(yh)k −1 )dωK (k). K J. Inequal. Pure and Appl. Math., 4(5) Art. 104, 2003 http://jipam.vu.edu.au/ O N THE S TABILITY OF A C LASS OF F UNCTIONAL E QUATIONS 3 ii) Follows by simple computation. Proposition 2.3. For each τ ∈ Φ and x, y ∈ G, we have XZ XZ −1 (2.1) f (xkϕ(τ (y))k )dωK (k) = f (xkψ(y)k −1 )dωK (k). ϕ∈Φ K ψ∈Φ K Proof. By applying Proposition 2.1, we get that when ϕ is iterated over Φ, the morphism of the form ϕ ◦ τ annihilates all the elements of Φ. 3. T HE M AIN R ESULTS Theorem 3.1. Let G be a locally compact group; let K be a compact subgroup of G with the normalized Haar measure ωK and let Φ given as above. Let δ > 0 and let f ∈ C(G) such that f satisfies the condition (*) and the functional inequality (3.1) X Z −1 f (xkϕ(y)k )dωK (k) − |Φ|f (x)f (y) ≤ δ, x, y ∈ G. K ϕ∈Φ Then one of the assertions is satisfied: (a) If f is bounded, then |f (x)| ≤ (3.2) |Φ| + p |Φ|2 + 4δ|Φ| . 2|Φ| (b) If f is unbounded, then i) f is K-central, ii) Rf ◦ τ = f , for all τ ∈ Φ, R iii) K f (xkyk −1 )dωK (k) = K f (ykxk −1 )dωK (k), x, y ∈ G. Proof. a) Let X = sup |f |, then we get for all x ∈ G |Φ||f (x)f (x)| ≤ |Φ|X + δ, from which we obtain that |Φ|X 2 − |Φ|X − δ ≤ 0, such that p |Φ|2 + 4δ|Φ| . 2|Φ| b) i) Let x, y ∈ G, h ∈ K, then by using Proposition 2.2, we find X≤ |Φ| + |Φ||f (x)||f (hy) − f (yh)| = ||Φ|f (x)f (hy) − |Φ|f (x)f (yh)| X Z ≤ f (xkϕ(hy)k −1 )dωK (k) − |Φ|f (x)f (hy) ϕ∈Φ K X Z −1 + f (xkϕ(yh)k )dωK (k) − |Φ|f (x)f (yh) K ϕ∈Φ ≤ 2δ. Since f is unbounded it follows that f (yh) = f (hy), for all h ∈ K, y ∈ G. J. Inequal. Pure and Appl. Math., 4(5) Art. 104, 2003 http://jipam.vu.edu.au/ 4 B ELAID B OUIKHALENE ii) Let τ ∈ Φ, by using Proposition 2.3, we get for all x, y ∈ G |Φ||f (x)||f ◦ τ (y) − f (y)| = ||Φ|f (x)f (τ (y)) − |Φ|f (x)f (y)| X Z −1 ≤ f (xkϕ(τ (y))k )dωK (k) − |Φ| f (x)f (τ (y)) ϕ∈Φ K X Z + f (xkψ(y)k −1 )dωK (k) − |Φ|f (x)f (y) K ψ∈Φ ≤ 2δ. Since f is unbounded it follows that f ◦ τ = f , for all τ ∈ Φ. iii) Let f be an unbounded solution of the functional inequality (3.1), such that f satisfies the condition (*), then, for all x, y ∈ G, we obtain, by using Part i) of Proposition 2.2: Z Z −1 −1 f (ykxk )dωK (k) |Φ||f (z)| f (xkyk )dωK (k) − K K Z f (z)f (xkyk −1 )dωK (k) = |Φ| K Z −1 f (z)f (ykxk )dωK (k) − |Φ| K Z Z f (zhϕ(xkyk −1 )h−1 )dωK (h)dωK (k) ≤ Σϕ∈Φ K K Z −1 f (z)f (xkyk )dωK (k) − |Φ| Z K Z + Σϕ∈Φ f (zhϕ(ykxk −1 )h−1 )dωK (h)dωK (k) K K Z −|Φ| f (z)f (ykxk −1 )dωK (k) K ≤ 2δ. Since f is unbounded we get Z Z −1 f (xkyk )dωK (k) = f (ykxk −1 )dωK (k), x, y ∈ G. K K The main result is the following theorem. Theorem 3.2. Let δ > 0 and let f ∈ C(G) such that f satisfies the condition (*) and the functional inequality X Z f (xkϕ(y)k −1 )dωK (k) − |Φ|f (x)f (y) ≤ δ, x, y ∈ G. (3.3) K ϕ∈Φ Then either (3.4) |f (x)| ≤ J. Inequal. Pure and Appl. Math., 4(5) Art. 104, 2003 |Φ| + p |Φ|2 + 4δ|Φ| , x ∈ G, 2|Φ| http://jipam.vu.edu.au/ O N THE S TABILITY OF A C LASS OF F UNCTIONAL E QUATIONS 5 or XZ (E (K)) f (xkϕ(y)k −1 )dωK (k) = |Φ|f (x)f (y), x, y ∈ G. K ϕ∈Φ Proof. The idea is inspired by the paper [1]. If f is bounded, by using Theorem 3.1, we obtain the first case of the theorem. Now let f be an unbounded solution of the functional inequality (3.3), then there exists a sequence (zn )n∈N in G such that f (zn ) 6= 0 and limn |f (zn )| = +∞. For the second case we will use the following lemma. Lemma 3.3. Let f be an unbounded solution of the functional inequality (3.3) satisfying the condition (*) and let (zn )n∈N be a sequence in G such that f (zn ) 6= 0 and limn |f (zn )| = +∞. It follows that the convergence of the sequences of functions: i) P x 7−→ (3.5) R ϕ∈Φ K f (zn kϕ(x)k −1 )dωK (k) , n ∈ N, f (zn ) to the function x 7−→ |Φ|f (x). ii) R P (3.6) x 7−→ ϕ∈Φ K f (zn hϕ(xkϕ(τ (y))k −1 )h−1 )dωK (h) , n ∈ N, τ ∈ Φ, k ∈ K, y ∈ G f (zn ) to the function x 7−→ |Φ|f (xkτ (y)k −1 ) τ ∈ Φ, k ∈ K, y ∈ G, is uniform. By inequality (3.1), we have P R −1 δ ϕ∈Φ K f (zn kϕ(y)k )dωK (k) − |Φ|f (y) ≤ , |f (zn )| f (zn ) then we have, by letting n 7−→ +∞, that R P −1 ϕ∈Φ K f (zn kϕ(y)k )dωK (k) lim = |Φ|f (y), n f (zn ) and f (zn hϕ (xkϕ (τ (y)) k −1 ) h−1 ) dωK (h) lim = |Φ|f (xkτ (y)k −1 ). n f (zn ) Since by Proposition 2.3, we have R P −1 −1 XZ ϕ∈Φ K f (zn hϕ(x)kϕ(τ (y))k h )dωK (h) dωK (k) f (zn ) τ ∈Φ K R P −1 −1 XZ ϕ∈Φ K f (zn hϕ(x)kψ(y)k h )dωK (h) = dωK (k), f (z n) K ψ∈Φ P ϕ∈Φ R K J. Inequal. Pure and Appl. Math., 4(5) Art. 104, 2003 http://jipam.vu.edu.au/ 6 B ELAID B OUIKHALENE combining this and the fact that f satisfies the condition (*), we obtain R −1 −1 X Z P ϕ∈Φ K f (zn hϕ(x)kϕ(τ (y))k h )dωK (h) dωK (k) f (zn ) τ ∈Φ K R P −1 f (z kψ(y)k )dω (k) δ n K ψ∈Φ K −|Φ|f (x) . ≤ |f (zn )| f (zn ) Since the convergence is uniform, we have XZ f (xkϕ(y)k −1 )dωK (k) − |Φ|2 f (x)f (y) ≤ 0, |Φ| K ϕ∈Φ thus (E (K)) holds and the proof is complete. 4. A PPLICATIONS If K ⊂ Z(G), we obtain the following corollary. Corollary 4.1. Let δ > 0 and let f be a complex-valued function on G satisfying the Kannappan condition (see [10]) f (zxy) = f (zyx), x, y ∈ G, (*) and the functional inequality X f (xϕ(y)) − |Φ|f (x)f (y) ≤ δ, x, y ∈ G. (4.1) ϕ∈Φ Then either |f (x)| ≤ (4.2) |Φ| + p |Φ|2 + 4δ|Φ| , x ∈ G, 2|Φ| or X (4.3) f (xϕ(y)) = |Φ|f (x)f (y), x, y ∈ G. ϕ∈Φ If G is abelian, then the condition (*) holds and we have the following: If Φ = {i} (resp. Φ = {i, σ}), where i(x) = x and σ(x) = −x, we find the Baker’s stability see [8] (resp. [9]). If f (kxh) = χ(k)f (x)χ(h), k, h ∈ K and x ∈ G, where χ is a character of K (see [11]), then we have the following corollary. Corollary 4.2. Let δ > 0 and let f ∈ C(G) such that f (kxh) = χ(k)f (x)χ(h), k, h ∈ K, x ∈ G, Z Z Z Z f (zkyhx)χ(k)χ(h)dωK (k)dωK (h) (*) f (zkxhy)χ(k)χ(h)dωK (k)dωK (h) = K K K K and (4.4) X Z f (xkϕ(y))χ(k)dωK (k) − |Φ|f (x)f (y) ≤ δ, x, y ∈ G. K ϕ∈Φ J. Inequal. Pure and Appl. Math., 4(5) Art. 104, 2003 http://jipam.vu.edu.au/ O N THE S TABILITY OF A C LASS OF F UNCTIONAL E QUATIONS 7 Then either |f (x)| ≤ (4.5) |Φ| + p |Φ|2 + 4δ|Φ| , x ∈ G, 2|Φ| or XZ (4.6) ϕ∈Φ f (xkϕ(y))χ(k)dωK (k) = |Φ|f (x)f (y), x, y ∈ G. K Proposition 4.3. If the algebra χωK ?M (G)?χωK is commutative then the condition (*) holds. Proof. Since f (kxh) = χ(k)f (x)χ(h), k, h ∈ K, x ∈ G, then we have χωK ? f ? χωK = f . Suppose that the algebra χωK ? M (G) ? χωK is commutative, then we get: Z Z Z Z −1 −1 f (xkyk hzh )dωK (k)dωK (h) = f (xkyhzh−1 k −1 )dωK (k)dωK (h) K K K K = hδz ? χωK ? δy ? χωK ? δx , f i = hδz ? χωK ? δy ? χωK ? δx , χωK ? f ? χωK i = hχωK ? δz ? χωK ? δy ? χωK ? δx ? χωK , f i = hχωK ? δz ? χωK ? δx ? χωK ? δy ? χωK , f i Z Z = f (ykxk −1 hzh−1 )dωK (k)dωK (h). K K Let f be bi-K-invariant (i.e f (hxk) = f (x), h, k ∈ K, x ∈ G), then we have: Corollary 4.4. Let δ > 0 and let f ∈ C(G) be bi-K-invariant such that for all x, y, z ∈ G, Z Z Z Z (*) f (zkxhy)dωK (k)dωK (h) = f (zkyhx)dωK (k)dωK (h), K K K K and (4.7) X Z f (xkϕ(y))dωK (k) − |Φ|f (x)f (y) ≤ δ, x, y ∈ G. K ϕ∈Φ Then either |f (x)| ≤ (4.8) |Φ| + p |Φ|2 + 4δ|Φ| , x ∈ G, 2|Φ| or (4.9) XZ ϕ∈Φ f (xkϕ(y))dωK (k) = |Φ|f (x)f (y), x, y ∈ G. K Proposition 4.5. If the pair (G, K) is a Gelfand pair (i.e ωK ? M (G) ? ωK is commutative), then the condition (*) holds. Proof. We take χ = 1 (unit character of K) in Proposition 4.3 (see [3] and [6]). In the next corollary, we assume that G = K is a compact group. Lemma 4.6. If f is central, then f satisfies the condition (*). Consequently, we have Z Z −1 (4.10) f (xtyt )dt = f (ytxt−1 )dt, x, y ∈ G. G J. Inequal. Pure and Appl. Math., 4(5) Art. 104, 2003 G http://jipam.vu.edu.au/ 8 B ELAID B OUIKHALENE Corollary 4.7. Let δ > 0 and let f be a complex measurable and essentially bounded function on G such that X Z f (xtϕ(y)t−1 )dt − |Φ|f (x)f (y) ≤ δ, x, y ∈ G. (4.11) G ϕ∈Φ Then |f (x)| ≤ (4.12) |Φ| + p |Φ|2 + 4δ|Φ| , x ∈ G. 2|Φ| Proof. Let f ∈ L∞ (G) be a solution of the inequality (4.11), then f is bounded, if not, then f satisfies the second case of Theorem 3.2 which implies that f is central (i.e the condition (*) holds) and f is a solution of the following functional equation XZ (4.13) f (xtϕ(y)t−1 )dt = |Φ|f (x)f (y), x, y ∈ G. ϕ∈Φ G In view of the proposition in [5], we have that f is continuous. Since G is compact, then the proof is accomplished. R EFERENCES [1] R. 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