Physics 221 Spring 2006 Exam 2 PHYSICS 221 Spring 2006 EXAM 2: March 30 2006 8:00pm—10:00pm Name (printed): ____________________________________________ ID Number: ______________________________________________ Section Number: __________________________________________ INSTRUCTIONS: Each question is of equal weight, answer all questions. All questions are multiple choice. Choose the best answer to each question. Before turning over this page, put away all materials except for pens, pencils, erasers, rulers, your calculator and “aid sheet”. An “aid sheet” is one two sided 8½×11 page of notes prepared by the student. There is also a list of possibly useful equations at the end of the exam. "In general, any calculator, including calculators that perform graphing numerical analysis functions, is permitted. Electronic devices that can store large amounts of text, data or equations are NOT permitted." If you are unsure whether or not your calculator is allowed for the exam ask your TA. Examples of allowed calculators: Texas Instruments TI-30XII/83/83+/89, 92+ Casio FX115/250HCS/260/7400G/FX7400GPlus/FX9750 Sharp EL9900C. Examples of electronic devices that are not permitted: Any laptop, palmtop, pocket computer, PDA or e-book reader. In marking the multiple choice bubble sheet use a number 2 pencil. Do NOT use ink. If you did not bring a pencil, ask for one. Fill in your last name, middle initial, and first name. Your ID is the middle 9 digits on your ISU card. Special codes K to L are your recitation section, for the Honors section please encode your section number as follows: H1⇒02; H2⇒13 and H3⇒25. If you need to change any entry, you must completely erase your previous entry. Also, circle your answers on this exam. Before handing in your exam, be sure that your answers on your bubble sheet are what you intend them to be. It is strongly suggested that you circle your choices on the question sheet. You may also copy down your answers on a piece of paper to take with you and compare with the posted answers. You may use the table at the end of the exam for this. When you are finished with the exam, place all exam materials, including the bubble sheet, and the exam itself, in your folder and return the folder to your recitation instructor. No cell phone calls allowed. Either turn off your cell phone or leave it at home. Anyone answering a cell phone must hand in their work; their exam is over. Total number of questions is 28. Question 58 is “extra credit” Best of luck, David Atwood and Paula Herrera-Siklody Page 1 of 20 Formula sheet 2 –2006 Phys 2212 – Spring PhysicsExam 221 Spring Exam Vectors and math G G G 2 2 2 A ⋅ B = AB cos θ = Ax Bx + Ay By + Az Bz A = Ax + Ay + Az G G G G A × B = AB sin θ A × B = ( Ay Bz − Az By ) iˆ + ( Az Bx − Ax Bz ) ˆj + ( Ax By − Ay Bx ) kˆ ax 2 + bx + c = 0 2006 −b ± b 2 − 4ac 2a d d sin x = cos x cos x = − sin x dx dx ⇒ x= d n x = nx n −1 dx Geometry perimeter circle: 2π R area circle: π R 2 z area sphere: 4π R 2 4 volume sphere: π R 3 3 1 revolution = 2π radians = 360D Conversion factors (for barbaric units) k̂ iˆ ĵ y x 1 yard = 3 foot = 36 inches 1 inch = 2.54 cm 1 mile = 1.609 km 1 lb = 4.448 N 1 gallon = 3.788 liters Physical constants g = 9.81 m/s 2 G = 6.67 ×10−11 Nm 2 /kg 2 1 N m2 C2 −12 e = 1.60 ×10−19 C = 8.99 × 109 8.85 10 ε = × 0 2 2 4π ε0 C Nm General kinematics G G G G G G dr ∆r ∆v G dv G v average = v= aaverage = a= ∆t dt ∆t dt Constant acceleration v 02 G G 1G2 G G G G G G 2 2 R = sin 2θ v − v = 2 ⋅ ∆ a r r = r0 + v 0t + at v = v 0 + at 0 g 2 2 1 v x = v 0 x + axt v x − v 02x = 2ax ∆x x = x0 + v 0 x t + ax t 2 2 ke = dθ dω s = Rθ v = Rω atan = Rα α= dt dt G G G G dv v2 2 Circular motion a = arad + atan atan = arad = = Rω dt R 1 2π 2π R T= = = v f ω 1 ω = ω0 + α t Constant α: θ = θ 0 + ω 0t + α t 2 ω 2 − ω 02 = 2α∆θ 2 ω= Relative motion G G G G G G rA relative to C = rA relative to B + rB relative to C v A relative to C = v A relative to B + v B relative to C G G G aA relative to C = aA relative to B + aB relative to C Page 2 of 20 10−15 10−12 10−9 10−6 10−3 103 106 109 1012 femto- (f) pico- (p) nano- (n) micro- (ì) milli- (m) kilo- (k) mega- (M) giga- (G) tera- (T) Physics 221 Spring 2006 Exam 2 Forces G G ∑ F = ma G G G Fg (≡ W ) = mg fs ≤ µs N fk = µk N Work and energy G G 1 2 p2 Wnet = ∆KE W = ∫ F ⋅ dl KE = mv = 2 2m G G r G G G U (r ) − U (r0 ) = − ∫G F ⋅ dl Wconservative = −∆U 1 2 kx + C 2 Pinst = U = mgy + C ( When only conservative forces do work: ∆E = 0 ) ∆E = Wnon-conservative E = KE + U Momentum, impulse. Systems of particles. G G G G G J = ∆p = ∫ Fdt p = mv G G mi ri miv i ∑ ∑ G G G rCM = i v CM = i aCM = ∑ mi ∑ mi i i mA − mB v0x mA + mB v Bx = G G G ∆p J Fave = = ∆t ∆t G ∑m a ∑m i i KElab = KECM + KErelative to CM i G G dptotal G = mtotal aCM Fnet = dt G G ptotal = mtotalv CM v Ax = dW G G = F ⋅v dt ∂U ( Fx = − , etc) ∂x W ∆t G G F = −∇U Pave = r0 U= FHooke = − k ∆x i i G ( When F net 2mA v0x mA + mB G G = 0, ptotal,i = ptotal,f ) v A,i,x − v B,i,x = −(v A,f,x − v B,f,x ) Rigid-body motion KEtranslation = KEtotal = KEtranslation + KErotation I = ∑ mi ri 2 G I = I CM + md 2 i G τ net G dL = dt G G KErotation = G τ net = Iα τ = r×F 1 I CMω 2 2 G G G L=r×p G G L = Iω G G (When τ net = 0, Ltotal,i = Ltotal,f ) 2 2 mr 5 2 I hollow sphere = mr 2 3 I solid sphere = I solid cylinder = I rod = L G 1 2 mv CM 2 1 mL2 12 1 2 mr 2 b a Page 3 of 20 I hollow cylinder = mr 2 with thin walls I rectangle = 1 m ( a 2 + b2 ) 12 Physics 221 Spring 2006 Exam 2 Simple harmonic motion d 2x +ω2x = 0 2 dt T= 1 2π = f ω G G Fdamping = −bv A= x = A cos(ω t + ϕ ) ω= k m x = A(t ) cos(ω ′t + ϕ ) v = − Aω sin(ωt + ϕ ) ω= κ ω= I A(t ) = Ae − b t 2m Fmax m bω (ω − ω ) + d m 2 0 2 2 2 d Page 4 of 20 a = − Aω 2 cos(ωt + ϕ ) g l ω= mgd I b ω′ = ω − 2m 2 0 2 Physics 221 Spring 2006 Exam 2 Please be sure you mark the answers in spaces 31-58 on the bubble sheet [31] A 2kg block is attached to a spring with force constant k=100N/m. The block is initially moving at a speed of 3m/s and the spring is compressed 0.3m from its relaxed length. What is the total mechanical energy of this system taking the potential energy of the spring to be 0 when the spring is relaxed? (A) 4.5J (B) 9.0J (C) 13.5J (D) 18.0J (E) 22.5J [32] Particles P, Q, R and S are moving in the +x direction. The momenta and kinetic energies of these particles are given in the table below. Which is the correct ranking of the speeds of these particles? Particle P Q R S Kinetic Energy K0 2K0 K0 2K0 Momentum p0 p0 2p0 2p0 (A) vR > vP > vS > vQ (B) vR > vS > vP > vQ (C) vQ > vP = vS > vR (D) vQ > vS > vP > vR (E) None of the above [33] If a collision between two particles is elastic, which of the following statements is false? (A) The total kinetic energy is conserved. (B) The total momentum is conserved. (C) The velocity of the center of mass of the system does not change. (D) The total kinetic energy is reduced by the collision. (E) The total angular momentum of the system is conserved. Page 5 of 20 Physics 221 Spring 2006 Exam 2 This graph applies to questions 34, 35 and 36 t=−4s t=−2s t=0s t=2s t=4s t=6s t=8s t=10s t=12s x=2m x=0m x=−2m [34] The graph above is a sketch of the position versus time graph for a mass attached to a spring undergoing simple harmonic motion. What is the period of this motion? (A) 6s (B) 11s (C) 12s (D) 24s (E) 0s [35] In the graph above, what is the phase angle φ if we write the solution in the form x(t ) = A cos(ω t + φ ) ? (A) − π 2 (B) − π 3 (C) 0 (D) + π 3 (E) + π 2 [36] In the graph above, if the spring constant is k=10N/m, what is the mechanical energy of the system? (A) 10J (B) 20J (C) 40J (D) 80J (E) The mechanical energy changes with time. Page 6 of 20 Physics 221 Spring 2006 Exam 2 [37] A car with mass 1000kg is driving along a road. It collides with a stationary truck with mass 2000kg. The two vehicles fuse together and the moment after the collision, the fused wreckage of the two vehicles is moving at a speed of 10m/s. What was the initial speed of the car? (A) 10m/s (B) 15 m/s (E) None of the above. (C) 17 m/s (D) 25 m/s [38] A particle with mass m=5kg resting on a frictionless horizontal surface is connected to an ideal spring with force constant k=100N/m. At t=0s, the mass is at the equilibrium position and has a kinetic energy of 10J. What is the amplitude of the subsequent oscillation? k=100 N/m 5kg (A) 45cm (B) 89cm Kinitial=10J (C) 63cm Page 7 of 20 (D) 32cm (E) 98cm Physics 221 Spring 2006 Exam 2 [39] A 3m long plank of weight 60N and uniform density rests on two scales which measure force in Newtons. Scale #1 supports the left hand end of the plank while scale #2 supports a point 1m from the right end of the plank. What are the readings of the two scales? 3m 1m 2m Plank weight=60N Scale 1 Scale 2 (A) Scale 1 reads 45N; Scale 2 reads 15N (B) Scale 1 reads 40N; Scale 2 reads 20N (C) Scale 1 reads 30N; Scale 2 reads 30N (D) Scale 1 reads 20N; Scale 2 reads 40N (E) Scale 1 reads 15N; Scale 2 reads 45N [40] A rock of mass 200kg is traveling through space at a speed of 10m/s in the +x direction. It collides with a stationary rock of mass 400kg. The 200kg rocks bounces off at an angle of 10º with respect to the x-axis. What is the velocity of the center of mass of the two rock system after the collision? (A) (10m/s) iˆ (B) (3.3m/s) iˆ (C) (20m/s) iˆ (E) Cannot be determined from the information given. Page 8 of 20 (D) (30m/s) iˆ Physics 221 Spring 2006 Exam 2 [41] Consider the configuration of two thin rods shown below. Each rod has a mass of 5kg uniformly distributed over a length of 2m. If it rotates at an angular velocity of ω=3rad/s about the axis shown, what is the rotational kinetic energy of the system? (A) 120J (D) 40J (B) 240J (E) 135J Axis 2m; 5kg (C) 27J G 2m; 5kg [42] If a particle has momentum p = (−i − ˆj + kˆ)Ns and radius G G vector R = (3i + 2 ˆj + kˆ)m , what is the angular momentum vector L of the particle about the origin? G (A) L = (−3,+4,+1) Js G (D) L = (+3,+4,−1) Js G (B) L = (+3,−4,−1) Js G (E) L = (−3,−6,+1) Js Page 9 of 20 G (C) L = (−3,−4,+1) Js Physics 221 Spring 2006 Exam 2 [43] A physics book (2 kg) is dropped from the top of ISU Campanile (about 94 m high). What is the magnitude of the average force it exerts on the ground if it is in contact with the ground for 0.1s before coming to a complete stop? Neglect air resistance. (A) 86N (B) 196N (C) 860N (D) 980N (E) 1960N [44] Sarah throws a 50g snowball at John who is in a tree. Sarah releases the snowball at an angle of 60º to the horizontal at a speed of 20m/s from a point 1.5m above the ground. The snowball strikes John who is 8m above the ground. How fast is the snowball traveling when it strikes John? Neglect air resistance. (A) 16.5m/s (B) 15.6m/s (C) 18.3m/s (D) 13.1m/s (E) The snowball cannot reach John given the information in the problem. [45] A rocket engine operates by ejecting exhaust gasses at a speed of 300m/s. If it produces exhaust at a rate of 3kg/s, what is the magnitude of force that the rocket engine generates? (A) 300N (B) 600N (C) 900N Page 10 of 20 (D) 1350N (E) 45000N Physics 221 Spring 2006 Exam 2 This figure applies to questions 46 and 47 y-axis Axis 4m 1kg 2m 1kg 2m 1kg 2kg 1kg x-axis 1kg 4m 2m [46] Consider the system of point masses shown above. What is the x-coordinate of the center of mass of this system? (A) 1.7m (B) 2.0m (C) 0.0m (D) 4.0m (E) 2.3m [47] Consider the system of point masses shown above. What is the moment of inertia of this system of masses about the indicated axis that passes through the origin at an angle of 45° to the x-axis? (A) 5 kg m² (B) 10 kg m² (C) 12 kg m² Page 11 of 20 (D) 20 kg m² (E) 24 kg m² Physics 221 Spring 2006 Exam 2 [48] The angular position of a wheel with moment of inertia I=2kg m² is given as a function of time by θ = Ae − Bt where A=4 radians and B=3s−1. At t=0s, what is the magnitude of the angular momentum of the wheel? (A) 72 Js (B) 18 Js (C) 24 Js (D) 144 Js (E) 54Js [49] A 2kg block is sliding to the right along a frictionless horizontal surface. Initially the kinetic energy of the block is 16J. It encounters an incline that slopes upwards at an angle of 30º. The coefficient of kinetic friction between the block and the incline is µ k = 0.58 . What is the maximum distance, d, which the block slides up the ramp before coming to a stop? 2kg µ k = 0.58 d=? K.E.=16J 2kg 30º Frictionless (A) 41cm (B) 82cm (C) 163cm Page 12 of 20 (D) 71cm (E) 52cm Physics 221 Spring 2006 Exam 2 [50] A small 0.5-kg ball is pressed against a vertical spring of negligible mass as shown below. The spring is compressed x= 7.0 cm from its relaxed position. When the system is released from rest, the ball is shot up in the air and reaches a maximum height of h = 1.1 m above its initial position. Determine the force constant k of the spring. Neglect air resistance. h x (A) 500 N/m (B) 1100 N/m (E) The ball can never reach that height. (C) 1500 N/m Page 13 of 20 (D) 2200 N/m Physics 221 Spring 2006 Exam 2 [51] In the figure at right, a horizontal rod of uniform density with weight 40N and length 2m is attached to a wall with a frictionless ideal hinge. An ideal massless string connects the end of the rod to the wall at a point 2m above the hinge. A box with weight 20N is hung from the end of the rod with an ideal massless string. If the system is in equilibrium, what is the tension, T0, in the string connecting the end of the rod to the wall? 2m T0 40N 2m Hinge 20N Wall (A) 57N (B) 85N (C) 40N (D) 60N (E) 42N [52] In the figure at right, a horizontal rod of uniform density with weight 40N and length 2m is attached to a wall with a frictionless ideal hinge. If the rod is released at rest, what is the angular acceleration of the rod about the hinge just after it is released? (A) 4.90 rad/s² (B) 7.35 rad/s² (C) 8.40 rad/s² (D) 9.80 rad/s² (E) 14.70 rad/s² 40N 2m Hinge Wall Page 14 of 20 Physics 221 Spring 2006 Exam 2 [53] A disk of uniform density with mass 2kg and radius 1m can rotate without friction about a vertical axle. It is initially rotating with a period of 4s. A sticky ball of mass 1kg (which can be treated as a point mass) is dropped vertically downwards. The ball sticks to the rim of the disk. After the ball sticks, what is the period of rotation of the disk? Disk radius = 1m mass=2kg Vertical axle Ball Mass=1kg (edge view) (A) 2s (B) 4s (C) 6s (D) 8s (E) 12s [54] A 1.5 kg rock initially at rest undergoes an explosion into three fragments of mass 0.5kg each. Fragment #1 has a kinetic energy of 25J; Fragment #2 has a kinetic energy of 16J and fragment #3 has a kinetic energy of 100J. What is the angle between the velocity vectors of fragment #1 and fragment #2? (A) 49° (B) 42° (D) There is not enough information given to determine this angle (E) The scenario described is not physically possible. Page 15 of 20 (C) 90° Physics 221 Spring 2006 Exam 2 [55] Consider the graphs of potential energy of a 4kg particle versus position shown below. If the particle is released at rest from the position x=6m, what is the maximum kinetic energy that the particle assumes thereafter? Potential (J) 6 4 2 0 2 4 6 8 −2 −4 (A) 0J (B) 1J (C) 2J (D) 3J Page 16 of 20 (E) 4J Position (m) Physics 221 Spring 2006 Exam 2 [56] In the three systems below, the inclines have the same angle with the horizontal and the objects are released from the same height h. 1. Block of mass M on a frictionless incline. h θ 2. Solid cylinder of mass M and radius R rolling down without slipping. h θ 3. Solid cylinder of mass M and radius 2R rolling down without slipping. h θ How do their speeds at the bottom of the incline compare? A. B. C. D. E. v1 < v2 = v3 v1 < v2 < v3 v1 > v2 > v3 v1 > v3 > v2 v1 > v2 = v3 Page 17 of 20 Physics 221 Spring 2006 Exam 2 [57] A 250-g particle attached to a spring with k = 150 N/m is also subject to a damping force F = − bv, where v is the velocity of the particle and b = 1.5 kg/s. Which of the graphs shown below best represents the kinetic energy of the particle as a function of time? Page 18 of 20 Physics 221 Spring 2006 Exam 2 [58] (Note: Extra Credit Problem) The figure below depicts a position dependent non-conservative force acting on a particle. To the right of the dashed line the force is constant while to the left it varies as shown. P, Q, R and S are closed path direction indicated. Note that R is a “figure eight” path that crosses itself. In which case is the work done by the field on a particle moving around the closed path not zero. (A) All of the paths (B) Paths P and R (C) Paths Q and S (D) Paths P and Q (E) Path P only Page 19 of 20 Physics 221 Spring 2006 Exam 2 You may record your answers here and take this page with you to compare with the posted answers. 31 41 51 32 42 52 33 43 53 34 44 54 35 45 55 36 46 56 37 47 57 38 48 58 39 49 40 50 Page 20 of 20