GEORGIAN MATHEMATICAL JOURNAL: Vol. 3, No. 4, 1996, 379-400 ESTIMATION OF THE INTEGRAL MODULUS OF SMOOTHNESS OF AN EVEN FUNCTION OF SEVERAL VARIABLES WITH QUASICONVEX FOURIER COEFFICIENTS T. TEVZADZE Abstract. The estimate of the modulus of smoothness of an even function of several variables with quasiconvex Fourier coefficients obtained in this paper extends one result of S. A. Telyakovski. 1. Let (ai,j )i,j≥0 be a double numerical sequence. Denote by ∆2 ai,j the expression ∆12 (∆12 ai,j ), where ∆12 ai,j = ∆1 (∆2 ai,j ) = ∆1 (ai,j − ai,j+1 ) = ai,j − ai+1,j − ai,j+1 + ai+1,j+1 . Definition 1. The double sequence (ai,j )i,j≥0 will be called quasiconvex if the series ∞ X ∞ X (i + 1)(j + 1)|∆2 ai,j | + (i + 1)|∆1 (∆12 aij )| + (j + 1)|∆2 (∆12 aij )| i=0 j=0 converges. As can be easily shown, if the sequence (ai,j )i,j≥0 is quasiconvex and lim ai,j = 0, i+j→∞ then the series ∞ X ∞ X λi,j ai,j cos ix cos jy, (∗) i=0 j=0 where λ0,0 = 14 , λ0,j = λi,0 = 12 , i, j = 1, 2, . . . , λi,j = 1 for i, j > 0, converges on (0, 2π)2 to some function f ∈ L(T 2 ) and is its Fourier series with T 2 = [0, 2π]2 . 1991 Mathematics Subject Classification. 42B05. Key words and phrases. Integral modulus of smoothness, quasiconvex Fourier coefficients. 379 c 1996 Plenum Publishing Corporation 1072-947X/96/0700-0379$09.50/0 380 T. TEVZADZE The expression ωm,n (δ, ρ; f )1 = Z X m X n m n f [x + (m − 2µ)h, y + (n − 2ν)η]dx dy = sup (−1)µ+ν ν µ |h|≤δ µ=0 ν=0 2 |η|≤ρT is usually called an integral modulus of smoothness of order (m, n) of a function f ∈ L(T 2 ). Here and in what follows it is assumed that δ ∈ [0, π], ρ ∈ [0, π]. Aljančič and Tomič [1], [2] considered an estimate of the integral modulus of continuity in terms of Fourier coefficients of the function f for some classes of sequences in the one-dimensional case. In 1963 M. and S. Izumi [3] proved that if the Fourier coefficients an → 0, n → ∞, form a quasiconvex sequence, then the estimate X X i2 |∆21 ai | + i|∆12 ai |1 ω(δ; f )1 ≤ cδ i≤ δ1 i> δ1 holds for the integral modulus of continuity ω(δ; f )1 . This result was later generalized by Telyakovski [4] who proved a theorem giving an estimate of an integral modulus of smoothness of order m, m ∈ N. In this paper an estimate is obtained for the integral modulus of smoothness for a function of several variables which is even with respect to each variable. 2. For a further discussion we need Lemma 1. Let 2mh ≤ t ≤ π. Then m X i m m (−1) Kp [t + (m − 2i)h] ≤ c(m)hm pm−1 t−2 , |Tp | = i i=0 |Tpm | ≤ c(m)hm pm+1 , where Kp (t) is the Fejer kernel, p ∈ N. Proof. It is easy to show that m X m Tpm = (−1)i Kp [t + (m − 2i)h] = i i=0 m−1 X m−1 = (−1)i Kp [t + (m−2i)h]−Kp [t+(m−2(i+1))h] = i i=0 1 Here and in what follows, c, c(m), c(m, n), . . . denote, generally speaking, various positive constants depending only on the parameters indicated in the brackets. ESTIMATION OF THE INTEGRAL MODULUS OF SMOOTHNESS 381 m−1 (−1) Kp0 [t + (m − 2(i + 1 − Q1 ))h] = · · · = = −2h i i=0 m−1 X i = (−1)m hm Kp(m) (t + c(m)h), where c(m) = m − 2(m − Q1 − · · · − Qm ), 0 < Qi < 1, i = 1, . . . , m. Since −m < c(m) < m, we have p Kp(m) (t 1 X (m) + c(m)h) = D (t + c(m)h) = p + 1 i=0 i ( p i 1 X X m cos j(t + c(m)h), =± j p + 1 i=0 j=1 sin j(t + c(m)h), 2|m, 2 - m, where Di (t) is the Dirichlet kernel. Let 2|m (the case 2 - m is considered similarly). Then applying twice the Abel transformation and taking into account the estimates c Kp (t) ≤ 2 , 0 < |t| ≤ π, pt Kp (t) ≤ p, |t| ≤ π, we find p i 1 X X m j − 2(j + 1)m + p + 1 i=0 j=1 + (j + 2)m jKj (t + c(m)h) + Kp(m) (t + c(m)h) = + + p 1 X (i − 1)m − im iKi (t + c(m)h) + p + 1 i=0 p 1 X m i − (i + 1)m iKi (t + c(m)h) + p + 1 i=0 1 · pm+1 Kp (t + c(m)h) ≤ p+1 ( c(m)pm−1 t−2 , 2mh ≤ t ≤ π, ≤ c(m)pm+1 , −π ≤ t ≤ π. + Therefore |Tpm | ≤ c(m)hm pm−1 t−2 , |Tpm | m m+1 ≤ c(m)h p , 2mh ≤ t ≤ π, −π ≤ t ≤ π. The two-dimensional analogue of Lemma 1 given below is proved similarly. 382 T. TEVZADZE Lemma 2. Let 2mh ≤ x ≤ π, 2nη ≤ y ≤ π. Then m,n |Tp,q | m X n X n µ+ν m (−1) Kp [x+(m−2µ)h]Kq [y+(n−2ν)η] ≤ = µ ν µ=0 ν=0 ≤ c(m, n) hm η n pm−1 q n−1 , (xy)2 m,n |Tp,q | ≤ c(m, n)hm η n pm+1 q n+1 , (x, y) ∈ T 2 . Lemma 3 ([5]). Let 2mh ≤ x ≤ π. Then m X m (−1)i Dp [x + (m − 2i)h] ≤ c(m)hm pm x−1 , i i=0 where Dp is the Dirichlet kernel, p ∈ N. Theorem 1. Let a double sequence (ai,j )i,j≥0 be quasiconvex and lim ai,j = 0. i+j→∞ Then for the sum f of the series (∗) we have 1 1 ] [ 2nη [ 2mh X] X m n ωm,n (h, η; f )1 ≤ c(m, n) h η im+1 j n+1 |∆2 ai,j | + i=1 1 ] [ 2mh X + hm ∞ X i=1 j=[ 1 ]+1 2nη +η ∞ X n ∞ X im+1 j|∆2 ai,j | + 1 [ 2nη ] X 1 ]+1 j=1 i=[ 2mh + ij n+1 |∆2 ai,j | + ∞ X 1 1 ]+1 j=[ 2nη ]+1 i=[ 2mh 4 X = s=1 j=1 ij|∆2 ai,j | = Ps (m, n, h, η). Proof. We write A(m, n, f ) = 4 Zπ Zπ 0 0 m,n |∆ 2mh Z Zπ Z Z2nη Zπ Z2nη 2mh + + f | dx dy = 4 + 0 0 2mh 0 0 2nη ESTIMATION OF THE INTEGRAL MODULUS OF SMOOTHNESS 383 Zπ Zπ 4 X + As (m, n, f ), |∆m,n f | dx dy ≡ s=1 2mh 2nη where ∆m,n f = m X n X (−1)µ+ν µ=0 ν=0 = m X n X µ+ν (−1) µ=0 ν=0 ∞ X + 1 ]+1 i=[ x ≡ 4 X s=1 ∞ X j=[ y1 ]+1 m n f [x + (m − 2µ)h, y + (n − 2ν)η] = µ ν 1 1 1 [ y1 ] X ] [y] [x ] [x ∞ ∞ X X X X X m n + + + µ ν 1 1 j=1 i=1 j=1 i=1 i=[ x ]+1 j=[ y ]+1 ai,j cos i[x + (m − 2µ)h] cos[y + (n − 2ν)η] ≡ Ts (m, n). It is easy to show that [1] 1 T1 ≡ T1 (m, n) = 2 Further, Zπ Zπ 2mh 2nη m+n [x] y X X i=1 j=1 ai,j sinm ih sinn jη × m+n (−1) 2 cos ix cos jy, (−1) m+n−1 2 sin ix cos jy, × m+n−1 2 (−1) cos ix sin jy, m+n−2 (−1) 2 sin ix sin jy, m n |T1 |dx dy ≤ c(m, n)h η m n ≤ c(m, n)h η (xy) ≤ c(m, n)hm η n 1 [ 2mh ] m n ≤ c(m, n)h η (rs)−2 s=1 j=1 im j n |ai,j |dx dy ≤ im j n |ai,j |dx dy ≤ s r X X i=1 j=1 1 ] [ 2nη X X i=1 [x] [y] X X 1 [ 2nη ] X X r=1 −2 i=1 j=1 1 1 ] [ 2mh 1 1 ] [y] [x Zπ Zπ X X 2mh 2nη i=1 j=1 2mh Z Z2nη 1 2|m, 2|n, 2 - m, 2|n, 2|m, 2 - n, 2 - |m, 2 - n. im j n |ai,j | ≤ 1 1 [ 2mh ] [ 2nη ] m n i j |ai,j | X X r=i s=j (rs)−2 ≤ 384 T. TEVZADZE 1 1 [ 2mh ] [ 2nη ] X X m n ≤ c(m, n)h η im−1 j n−1 |ai,j |. j=1 i=1 (2.1) 1 1 ], q = [ 2nη ], which Applying twice the Hardy transformation [6], p = [ 2mh is a two-dimensional analog of the Abel transformation, we find p X q X m−1 n−1 i j i=1 j=1 + q X n−1 |ai,q | s s=1 = q−1 X j + i=1 |ai,j | = ≤ n j=1 p X q−1 X X p−1 i=1 +pm+1 q−1 X +q n i=1 m−1 i i=1 s=1 |∆2 ai,j | + |∆2 ai,j | − |∆2 ai+1,j | p X p X i i=1 i X q |ai,q | = m−1 n rm−1 + r=1 r=1 i=1 im−1 ≤ j n |∆2 ap,j | + q n p−1 X q−1 X i=1 j=1 p−1 X i=1 im+1 j n+1 |∆2 ai,j | + q n+1 q−2 X j=1 p−2 X j n j=1 X p j X sn−1 + |ai,j | − |ai,j+1 | i=1 j=1 i=1 j=1 i X q−1 p−1 i X X m−1 |ai,q | − |ai+1,q | rm−1 + i |∆2 ap,j | + q n +pm ≤ m−1 i=1 j=1 +q n |ap,q | p−1 X q−1 X p X |∆12 ai,j |im j n + im |∆1 ai,q | + pm q n |ap,q | ≤ p−2 X i=1 im+1 |∆12 ai,q − ∆12 ai+1,q | + j n+1 |∆12 ap,j − ∆12 ap,j+1 | + pm+1 q n+1 |∆12 ap,q | + im+1 |∆1 (ai,q − ai+1,q )| + pm n m+1 +q p m n+1 |∆1 ap,q | + p q ≡ 9 X q−2 X j=1 j n+1 |∆2 (ap,j − ap,j+1 )| + |∆2 ap,q | + pm q n |ap,q | ≡ Iα (m, n, p, q). (2.2) α=1 For I2 we obtain I2 = q n p−2 X i=1 im+1 q|∆1 (∆12 ai,q )| = q n p−2 X i=1 ∞ X 2 im+1 q ∆ ai,j ≤ j=q ESTIMATION OF THE INTEGRAL MODULUS OF SMOOTHNESS ≤q n p−2 X im+1 i=1 ∞ X j=q j|∆2 ai,j |. 385 (2.3) Similarly, I3 ≤ pm q−2 ∞ X X i=p j=1 ij n+1 |∆2 ai,j |. (2.4) Let us now estimate I5 . We have I5 ≤ q n where p−2 X i=1 im+1 |∆21 ai,q |, ∆21 ai,q = ai,q − ai+1,q + ai+2,q . It is easy to show that ∆21 ai,q = ∞ X ∆2 (∆21 ai,s ) = s=q ∞ X ∆2 j=q ∞ X s=j ∞ ∞ X X ∆2 (∆2 ai,s ) = ∆2 ai,s . j=q s=j Therefore |∆21 ai,q | ≤ ∞ X ∞ X j=q s=j |∆2 ai,s | ≤ ∞ X s=q s|∆2 ai,s |. (2.5) Thus I5 ≤ q n p−2 X ∞ X i=1 s=q im+1 s|∆2 ai,s |. (2.6) Similarly, I6 ≤ pm q−2 ∞ X X i=p j=1 ij n+1 |∆2 ai,j |. (2.7) Next, Since I7 = pm q n · p|∆1 ap,q |. ∞ ∞ X X p|∆1 ap,q | = p i|∆21 ai,q |, ∆21 ai,q ≤ i=p i=p by repeating the arguments used for I5 we obtain I7 ≤ pm q n ∞ X ∞ X i=p j=q ij|∆2 ai,j |. (2.8) 386 T. TEVZADZE The same estimate holds for I8 . For I4 we have I4 ≤ pm q n ∞ X ∞ X i=p j=q ij|∆2 ai,j |. (2.9) In the same way, ∞ ∞ X ∞ ∞ X ∞ X ∞ X X X rs|∆2 ar,s |. (2.10) ∆2 ar,s ≤ pm q n I9 ≤ p m q n r=p s=q i=p j=q r=i s=j Using (2.2)–(2.10), we find Zπ Zπ |T1 | dx dy ≤ 2mh 2nη 4 X α=1 Pα (m, n, h, η). (2.11) If p = [ x1 ] + 1, q = [ y1 ] + 1, we again apply twice the Hardy transformation for T4 and obtain T4 = m X n X (−1)µ+ν µ=0 ν=0 n m n ap,q Dp [x+(m−2µ)h]Dq [y+(n−2ν)η]− µ ν − Dp [x + (m − 2µ)h]∆2 ap,q (q + 1)Kq [y + (n − 2ν)η] − − Dq [y + (n − 2ν)η]∆1 ap,q (p + 1)Kp [x + (m − 2µ)h] + + Dp [x + (m − 2µ)h] + Dq [y + (n − 2ν)η] + ∆212 ap,q (p ∞ X j=q ∞ X i=p ∆22 ap,j (j + 1)Kj [y + (n − 2ν)η] + ∆12 ai,q (i + 1)Ki [x + (m − 2µ)h] + + 1)(q + 1)Kp [x + (m − 2µ)h]Kq [y + (n − 2ν)η] − − (p + 1)Kp [x+(m − 2µ)h] − (q + 1)Kq [y+(n − 2ν)η] + ∞ X ∞ X i=p j=q = 9 X α=1 j=q ∞ X i=p ∆2 (∆12 ap,j )(j + 1)Kj [y+(n − 2ν)η] − ∆1 (∆12 ai,q )(i + 1)Ki [x+(m − 2µ)h] + ∆2 ai,j (i + 1)(j + 1)Ki [x+(m − 2µ)h]Kj [y+(n − 2ν)η] = (α) T4 ∞ X (m, n, p, q). (2.12) ESTIMATION OF THE INTEGRAL MODULUS OF SMOOTHNESS 387 By Lemma 2 (see (2.1)) we have Zπ Zπ 2mh 2nη 1 1 2nη 2mh Z Z (1) |T4 | dx dy ≤ c(m, n)hm η n 1 1 |a[x],[y] |xm−1 y n−1 dx dy ≤ 1 1 [ 2mh ] [ 2nη ] X X m n ≤ c(m, n)h η ≤ 4 X s=1 Ps (m, n, h, η). (2) Applying Lemmas 3 and 1 for T4 Zπ Zπ 2mh 2nη j=1 i=1 im−1 j n−1 |ai,j | dx dy ≤ we find 1 1 (2) |T4 | dx dy ≤ c(m, n)hm η n (2.13) 2nη 2mh Z Z 1 1 xm−1 y n |∆2 a[x]+1,[y]+1 | dx dy ≤ 1 1 [ 2mh ] [ 2nη ] ≤ c(m, n)hm η n X X i=1 j=1 im−1 j n |∆2 ai,j |. Using the Abel transformation leads to Zπ Zπ 2mh 2nη (2) |T4 | dx dy 1 ] [ 2nη m n ≤ c(m, n) h η X +h η X i m−1 i=1 j j=1 1 [ 2mh ] m −1 1 [ 2mh ] n+1 X i=1 im−1 |∆22 ai,j | + 1 |∆2 ai,[ 2nη ]| . Again applying twice the Abel transformation we obtain Zπ Zπ 2mh 2nη (2) |T4 | dx dy 1 [ 2nη ] +η n X j=1 1 [ 2nη ] +η n X j=1 1 1 ] [ 2nη [ 2mh X] X m n ≤ c(m, n) h η im+1 j n+1 |∆2 ai,j | + i=1 j=1 ∞ X ∆1 ∆1 (∆22 ai,j ) + j n+1 h−1 1 ] i=[ 2mh ∞ ∞ X X j n+1 ∆1 ∆1 (∆22 ai,j ) + 1 r=[ 2mh ] i=r 388 T. TEVZADZE 1 [ 2mh ] X m +h i=1 ∞ ∞ X 2 X 1 im+1 η −1 ∆2 ai,j + η −1 ∆2 a[ 2mh ],j ≤ j=q 1 ] j=[ 2nη 1 1 ] [ 2nη [ 2mh X] X m n im+1 j n+1 |∆2 ai,j | + ≤ c(m, n) h η i=1 1 ] [ 2nη +η n X j j=1 2 1 i=[ 2mh ]+1 1 [ 2mh ] +hm 1 [ 2nη ] ∞ X n+1 ∞ X X i=1 j=[ 1 ]+1 2nη j=1 i|∆ ai,j | + η im+1 j|∆2 ai,j | + ≤ 4 X s=1 n X ∞ X j n+1 j=1 1 i=[ 2mh ]+1 ∞ X ∞ X 1 1 i=[ 2mh ]+1 j=[ 2nη ]+1 i|∆2 ai,j | + ij|∆2 ai,j | ≤ Ps (m, n, h, η). (2.14) (3) One can estimate T4 quite similarly. (4) Let us now consider T4 . We have (4) T4 = m X (−1)µ µ=0 × 1 [X 2nη ] n X m n D[ x1 ] [x + (m − 2µ)h] (−1)ν × µ ν ν=0 + j=[ y1 ]+1 ∞ X 1 j=[ 2nη ]+1 (j + 1)∆22 a[ x1 ],j Kj [y + (n − 2ν)η] = (4) (4) = T4 (1) + T4 (2). (2.15) Since 1 [ 2nη ] (4) |T4 (1)| X m n −m−1 −2 ≤ c(m, n)h η x y j=[ y1 ]+1 j n |∆22 a[ x1 ],j |, we obtain Zπ Zπ 2mh 2nη (4) |T4 (1)| dx dy 1 1 ] [ 2nη ] [ 2nη 1 [ 2mh ] m n ≤ c(m, n)h η X m−1 i s=1 j=s+1 i=1 1 ] [ 2nη m n ≤ c(m, n)h η X j=1 X X j n |∆22 ai,j | ≤ 1 ] [ 2mh j n+1 X i=1 im−1 |∆22 ai,j |. ESTIMATION OF THE INTEGRAL MODULUS OF SMOOTHNESS 389 (2) Repeating the arguments used in estimating T4 , we find Zπ Zπ 2mh 2nη (4) |T4 (1)| dx dy ≤ P1 (m, n, h, η) + P3 (m, n, h, η). (2.16) Similarly, Zπ Zπ 2mh 2nη (4) |T4 (2)| dx dy 1 [ 2mh ] m −1 ≤ c(m, n)h η ≤ 4 X s=1 X m−1 i i=1 ∞ X 1 ]+1 j=[ 2nη |∆22 ai,j | ≤ Ps (m, n, h, η). (2.17) By (2.16) and (2.17) we conclude that Zπ Zπ 2mh 2nη (4) |T4 | dx dy ≤ 4 X Ps (m, n, h, η). (2.18) 4 X Ps (m, n, h, η). (2.19) s=1 Quite similarly we obtain Zπ Zπ 2mh 2nη (5) |T4 | dx dy ≤ s=1 By Lemma 1 and analysis of the arguments used in estimating I2 we have Zπ Zπ 2mh 2nη 1 (6) |T4 | dx dy 1 ] [ 2nη ] [ 2mh m n ≤ c(m, n)h η X X 1 ] [ 2mh m n ≤ c(m, n)h η i=1 X X i=1 j=1 im j n |∆12 ai,j | ≤ 1 ] [ 2nη j=1 im+1 j n+1 |∆2 ai,j | + 1 ] [ 2nη +h−m−1 X j=1 1 [ 2mh ] +η −n−1 X i=1 1 j n+1 |∆2 (∆12 a[ 2mh ],j )| + −m−1 −n−1 1 1 1 η im+1 |∆1 (∆12 ai,[ 2nη |∆12 a[ 2mh ]| + h ],[ 2nη ]| ≤ 1 1 ] [ 2nη [ 2mh X] X m n ≤ c(m, n) h η im+1 j n+1 |∆2 ai,j | + i=1 j=1 390 T. TEVZADZE ∞ X +hm η −1 1 ]+1 i=[ 2mh 1 im+1 |∆1 (∆12 ai,[ 2nη ] )| + 1 [ 2nη ] +h−1 η n X 1 j n+1 |∆2 (∆12 a[ 2mh ],j )| + j=1 4 X 1 1 +(hη)−1 |∆12 a[ 2mh ], 2nη ] | ≤≤ (8) For T4 Zπ Zπ 2mh 2nη Ps (m, n, h, η). s=1 (2.20) we obtain 1 1 1 2nη 2mh Z [ 2mh Z X] (8) n m n im |∆1 (∆12 ai,[y] )|dxdy+ y |T4 | dx dy ≤ c(m, n)h η 1 1 2nη +c(m, n)η n Z y n 1 π+mh Z + ηn X 1 1 [ 2mh ] [ 2nη ] m n X X r=1 r=1 i=[ 1 ]+1 2mh j=1 1 ] [ 2mh j n X i=r+1 j=1 ∞ X X |∆1 (∆12 ai,[y] )|dxdy ≤ 1 ]+1 i=[ 2mh mh 1 [ mh ] jn ∞ X x−2 ≤ c(m, n) h η 1 [ 2nη ] i=[x]+1 1 im |∆1 (∆12 ai,j )| + |∆1 (∆12 ai,j )| ≤ 1 1 [ 2nη ] [ 2mh X] X m n n ≤ c(m, n) h η im+1 |∆1 (∆12 ai,j )| + j r=1 j=1 +η n ∞ X 1 [ 2nη ] X 1 ]+1 j=1 i=[ 2mh +η ∞ X 1 i=[ 2mh ]+1 ij |∆1 (∆12 ai,j )| X im+1 r=1 i j=1 X j=1 1 [ 2nη ] X = 1 [ 2nη ] 1 [ 2mh ] ≤ c(m, n) hm η n n n n j n |∆1 (∆12 ai,j )| + j |∆1 (∆12 ai,j )| . ESTIMATION OF THE INTEGRAL MODULUS OF SMOOTHNESS 391 Using the Abel transformation leads to 1 [ 2nη ] 1 ] [ 2nη X n j |∆1 (∆12 ai,j )| ≤ j=1 X 1 j n+1 |∆2 ai,j | + η −n−1 |∆1 (∆12 ai,[ 2nη ] )|. j=1 Hence (see (2.8)) it is easy to show that Zπ Zπ 2mh 2nη (8) |T4 | dx dy ≤ 4 X Pα (m, n, h, η). (2.21) 4 X Pα (m, n, h, η). (2.22) α=1 Similarly, Zπ Zπ 2mh 2nη (7) |T4 | dx dy ≤ α=1 Further, (9) T4 1 [ X 2mh ] n µ+ν m = (−1) ν µ 1 µ=0 ν=0 m X n X 1 [ 2mh ] + X 1 ]+1 i=[ x 1 [ 2nη ] X i=[ x ]+1 j=[ y1 ]+1 ∞ X 1 j=[ 2nη ]+1 ∞ X 1 i=[ 2mh ]+1 ∞ X + 1 [ 2nη ] X + 1 i=[ 2mh ]+1 j=[ y1 ] ∞ X (i + 1)(j + 1) × 1 j=[ 2nη ]+1 × Ki [x + (m − 2µ)h]Kj [y + (n − 2ν)η] = 4 X s=1 (9) T4 (s). (2.23) By Lemma 2 we have (9) |T4 (1)| 1 [ 2nη ] 1 [ 2mh ] m n ≤ c(m, n)h η X X 1 ]+1 j=[ y1 ]+1 i=[ x im j n (xy)−2 |∆2 ai,j |. Therefore Zπ Zπ 2mh 2nη 1 (9) |T4 (1)|dxdy 1 1 1 [ 2mh ] [ 2nη ] [ 2mh ] [ 2nη ] X X X X m n ≤ c(m, n)h η r=1 s=1 i=r j=s im j n |∆2 ai,j | ≤ 1 1 [ 2mh ] [ 2nη ] m n ≤ c(m, n)h η X X i=1 j=1 im+1 j n+1 |∆2 ai,j |. (2.24) 392 T. TEVZADZE The remaining terms of (2.22) are estimated by similar arguments. Thus we conclude that Zπ Zπ 2mh 2nη (9) |T4 | dx dy ≤ 4 X α=1 Pα (m, n, h, η). (2.25) Taking into account (2.13), (2.14), (2.18)–(2.22), and (2.25) we obtain Zπ Zπ 2mh 2nη |T4 | dx dy ≤ 4 X α=1 Pα (m, n, h, η). (2.26) For T2 we have [1] |T2 | ≤ c(n)η n y X j=1 X X ∞ m µ m (−1) j ai,j cos i[x + (m − 2µ)h]. µ n µ=0 1 i=[ x ]+1 Applying twice the Abel transformation, we find X ∞ m (−1) ai,j cos i[x + (m − 2µ)h] = µ 1 µ=0 m X µ i=[ x ]+1 X ∞ m (i + 1)∆21 ai,j Ki [x + (m − 2µ)h] − = (−1)µ µ 1 µ=0 m X −∆1 a[ x1 ],j h1i x i=[ x ]+1 K[ x1 ] [x + (m − 2µ)h] − a[ x1 ],j D[ x1 ] [x + (m − 2µ)h] . By virtue of Lemmas 3 and 1 we obtain m n |T2 | ≤ c(m, n)h η +x −m−2 + c(n)η j n j=1 1 [X 2mh ] 1 i=[ x ]+1 im |∆21 ai,j |x−2 + −m−1 |∆1 a[ x1 ],j | + |a[ x1 ],j |x [1] n [ y1 ] X y X j=1 j n X ∞ 1 i=[ 2mh ] i|∆12 ai,j | × m X m Ki [x + (m − 2µ)h]. × (−1)µ µ µ=0 + ESTIMATION OF THE INTEGRAL MODULUS OF SMOOTHNESS Hence σm,n ≡ Zπ Zπ 2mh 2nη |T2 | dx dy ≤ Zπ ≤ c(m, n)hm η n x−2 m n + c(m, n)h η −m−2 x Zπ + c(m, n)h η −m−1 x [ y1 ] + c(n)η n 1 i=[ x ]+1 Zπ Zπ X j n |∆1 a[ x1 ],j | dx dy + [ y1 ] Zπ X j n |a[ x1 ],j | dx dy + ∞ X jn 2mh 2nη j=1 im |∆21 ai,j | dx dy + [ y1 ] Zπ X 2nη j=1 2mh X jn 2nη j=1 2mh m n 1 [ 2mh ] 2nη j=1 2mh Zπ [ y1 ] Zπ X 1 i=[ 2mh ]+1 i|∆21 ai,j | × m X m × (−1)µ Ki [x + (m − 2µ)h] dx dy ≤ µ µ=0 1 1 m n ≤ c(m, n)h η Z 1 xm Z Z y −2 [y] X 1 2nη xm−1 1 Z y −2 [y] X 2nη 2mh Z Z 1 1 [ 2mh ] j j=1 n X i=[x]+1 im |∆21 ai,j | dx dy + j n |a[x],j | dx dy + 1 1 + c(m, n)η n [y] X j n |∆1 a[x],j | dx dy + j=1 1 y −2 1 j=1 1 1 2mh + 1 1 2nη 1 2mh + 2nη 2mh Z Z y −2 [y] X j=1 1 ∞ X jn 1 i=[ 2mh ]+1 |∆21 ai,j | dx dy. Next, as is easy to show, 1 1 [ 2mh ] [ 2nη ] m n σm,n ≤ c(m, n) h η X X r=1 s=1 −2 s s X j=1 1 ] [ 2mh j n X i=r+1 im |∆21 ai,j | + 393 394 T. TEVZADZE 1 ] [ 2nη 1 [ 2mh ] m n +h η r X rm−1 X s−2 m r=1 s X j=1 1 [ 2nη ] 1 [ 2mh ] X s−2 s=1 1 [ 2nη ] + η n h−1 s−2 s=1 r=1 + hm η n X X s=1 s X s X j=1 j n |ar,j | + ∞ X jn j=1 j n |∆1 ar,j | + 1 i=[ 2mh ]+1 |∆21 ai,j | . Therefore, after simple calculations, we find σm,n ≤ c(m, n)hm η n 1 [ 2nη ] 1 [ 2mh ] + X r X m r=1 1 [X 2mh ] 1 ] [ 2nη im+1 X j=1 i=1 j n−1 |∆12 ai,j | + 1 1 ] [ 2nη ] [ 2mh j n−1 j=1 +cm,n η n |∆1 ar,j | + ∞ X X X r=1 r m−1 n−1 j j=1 |ar,j | + 1 ] [ 2nη X i j=1 1 i=[ 2mh ]+1 j n−1 |∆21 ai,j |. The analysis of estimates (2.14) and (2.18) gives Zπ Zπ |T2 | dx dy ≤ Zπ Zπ |T3 | dx dy ≤ 2mh 2nη 4 X Pα (m, n, h, η). (2.27) 4 X Pα (m, n, h, η). (2.28) α=1 Similarly, 2mh 2nη α=1 Therefore by virtue of (2.11), (2.26), (2.27) and (2.28) we obtain A4 (m, n; f ) ≤ 4 X α=1 Pα (m, n, h, η). For A1 (m, n; f ) we have A1 (m, n; f ) = 2mh Z Z2nη 0 0 |∆m,n f | dx dy = (2.29) ESTIMATION OF THE INTEGRAL MODULUS OF SMOOTHNESS = 2mh Z Z2nη X s r X 0 0 ∞ X + + i=r+1 j=s+1 n m X X + i=r+1 j=1 i=1 j=1 ∞ X ∞ X s X r ∞ X X + i=1 j=s+1 (i + 1)(j + 1)∆2 ai,j × m n Ki [x + (m − 2µ)h] × µ ν µ=0 ν=0 4 X (α) ×Kj [y+(n−2ν)η]dx dy = A1 (m, n, h, η), × 395 (−1)µ+ν (2.30) α=1 1 1 ], s = [ 2nη ]. By Lemma 2 we obtain where r = [ 2mh (1) A1 2mh Z Z2nηX r X s m n ≤ c(m, n)h η i=1 j=1 0 0 1 [ 2mh ] 1 [ 2nη ] X X ≤ c(m, n)hm η n i=1 im+2 j n+2 |∆2 ai,j |dx dy ≤ j=1 im+1 j n+1 |∆2 ai,j |. (2.31) Further, (4) A1 = 2mh Z Z2nη 0 0 ∞ X ∞ X i=r+1 j=s+1 X X + (i + 1)(j + 1)∆2 ai,j m>2µ n>2ν X X n µ+ν m × (−1) + + + µ ν m>2µ n≤2ν m≤2µ n>2ν m≤2µ n≤2ν 4 X (4) × Ki [x + (m − 2µ)h]Kj [y + (n − 2ν)η] dx dy = A1 (α). X X X X α=1 (4) is sufficient to estimate A1 (4). For n µ ([ m 2 ] ≤ µ ≤ m) and ν ([ 2 ] ≤ ν ≤ n) the term of this sum Obviously, it (4) A1;µ,ν (4), where are fixed, a = 2µ−m, b = 2ν − n, we obtain, after passing to the variables t = x − ah, τ = y − bη, (4) Ai;µ,ν (4) ≤ c(m, n) where Fr,s = Z Z ur vs ∞ X ∞ X 1 1 i=[ 2mh ]+1 j=[ 2nη ]+1 |∆2 ai,j | 3 3 X X r=1 s=1 (i + 1)(j + 1)Ki (t)Kj (τ ) dt dτ, Fr,s , 396 T. TEVZADZE h 1 1i h1 h i 1i u1 = − ah, − , u2 = − , , u3 = , (2m − a)h , i i i i h 1 1i h1 h i 1i v1 = − bη, − , v2 = − , , v3 = , (2n − b)η , j j j j 3 [ ur × vs . [−ah, −(2m − a)h] × [−bη, (2n − b)η = r,s=1 Taking into account the properties of Fejer kernels in the respective intervals, we have Z Z Z dt dτ dτ 2 2 2 , F2,1 ≤ i j , F1,1 ≤ ij ij(tτ )2 i jτ 2 v1 u1 v1 Z Z Z dt dt dτ 2 , F ≤ ij , F3,1 ≤ ij 1,2 2 ij(tτ ) j it2 u1 u 3 v1 Z 4 2 dt F2,2 ≤ i2 j 2 , F3,2 ≤ ij 2 , ij j it2 u3 Z Z Z dτ dt dτ 2 2 F1,3 ≤ ij , F , ≤ i j 2,3 ij(tτ )2 i jτ 2 u1 v 3 v3 Z Z dt dτ F3,3 ≤ ij . ij(tτ )2 u3 v 3 Therefore ∞ X (4) A1 (4) ≤ c(m, n) (2) 1 i=[ 2mh ]+1 ∞ X 1 j=[ 2nη ]+1 ij|∆2 ai,j |. (2.32) (3) A1 and A1 are estimated by the same scheme as used in deriving (2.31) and (2.32). Therefore for A1 we have A1 ≤ 4 X s=1 Ps (m, n, h, η). (2.33) It remains to consider A2 (m, n; f ) (A3 is estimated similarly). We have 1 [ 1 ] ] 2nη [x Zπ Z2nη Zπ Z2nη X ∞ X X m,n A2 = |∆ f | dx dy = + 2mh 0 1 ] [x + X i=0 j=0 2mh 0 ∞ X i=0 j=[ 1 ]+1 2nη + ∞ X ∞ X 1 1 ]+1 j=[ 2nη i=[ x ]+1 1 [ 2nη ] X i=[ r1 ]+1 j=0 (i + 1)(j + 1)∆2 ai,j × + ESTIMATION OF THE INTEGRAL MODULUS OF SMOOTHNESS m n Ki [x + (m − 2µ)h] × µ ν µ=0 ν=0 4 X (α) × Kj [y + (n − 2ν)η] dx dy = A2 (m, n, h, η). × m X n X 397 (−1)µ+ν (2.34) α=1 Again, by Lemma 2 we obtain (1) A2 ≤ c(m, n)hm η n 1 [ 1 ] ] 2nη [x Zπ Z2nηX X 2mh 0 i=1 j=1 1 2mh ≤ c(m, n)hm η n Z x−2 (2) For A2 (2) A2 X im+2 1 ] [ 2nη X X i=1 j=1 j n+1 |∆2 ai,j |dx ≤ j=1 im+1 j n+1 |∆2 ai,j |. (2.35) we have 1 Zπ Z2nη [ X 2mh ] + = 2mh 0 n m X X Further, 1 ] [ 2nη i=1 1 1 ] [ 2mh ≤ c(m, n)hm η n [x] X im+2 j n+2 |∆2 ai,j |dx dy ≤ ∞ X 1 i=[ 2mh ]+1 1 ]+1 i=[ x 1 [X 2nη ] (i + 1)(j + 1)|∆2 ai,j | × j=0 m n (−1)µ+ν × Ki [x + (m − 2µ)h] × µ ν µ=0 ν=0 (2) (2) × Kj [y + (n − 2ν)η] dx dy = A2 (1) + A2 (2). 1 1 [ 2nη ] (2) A2 (1) ≤ c(m, n)hm η n m n ≤ c(m, n)h η j=1 2mh Z 1 [ 2nη ] 1 ] [ 2mh X X j n+1 j 1 ] [ 2nη X X i=1 X r=1 j=1 1 [ 2mh ] ≤ c(m, n)hm η n 1 [ 2mh ] x−2 j=1 X i=[x]+1 1 n+1 (2.36) im+2 |∆2 ai,j |dx dy ≤ 1 ] [ 2mh r −2 X i=r+1 im+2 |∆2 ai,j |dx ≤ im+1 j n+1 |∆2 ai,j |. (2.37) 398 T. TEVZADZE Similarly (see (2.32)) we find ∞ X (2) A2 (2) ≤ c(m, n)η n 1 ]+1 i=[ 2mh 1 [ 2nη ] X j=1 ij n+1 |∆2 ai,j |. (2.38) By (2.35)–(2.37) we obtain (2) A2 ≤ P1 (m, n, h, η) + P3 (m, n, h, η). (2.39) It is likewise easy to show that (3) A2 ≤ P2 (m, n, h, η) + P4 (m, n, h, η), (4) A2 ≤ P4 (m, n, h, η). (2.40) Keeping in mind (2.33), (2.34), (2.38)–(2.40), we find A2 ≤ 4 X s=1 Ps (m, n, h, η). (2.41) With regard to (2.29), (2.33), and (2.41) we conclude that A≤ 4 X s=1 Ps (m, n, h, η). 3. Let now Rk be a k-dimensional Euclidean space of points x = (x1 ,. . . ,xk ) with ordinary linear operations and the Euclidean norm kxk. The product of two vectors x, y ∈ Rk is understood componentwise and so are the inequalities x < y, x ≤ y. It is assumed that T k = [0, 2π]k . If n = (n1 , . . . , nk ) is a multi-index with non-negative integral components, 0 = (0, . . . , 0), 1 = (1, . . . , 1), and (an )n≥0 is a k-multiple numerical sequence, then ∆i an = an − an+(δi1 ,...,δik ) , where δij is the Kronecker symbol, i, j ∈ M = {1, . . . , k}. We introduce the notation ∆M an ≡ ∆1···k an = ∆1 (∆2 (· · · (∆k an ) · · · )), for each B, ∅ 6= B ⊂ M , ∆B an is defined similarly, and assume that λ(n) is the number of zero coordinates of the vector n (see [7]). We will also use the notation B 0 = M \ B, where B ⊂ M . Definition 2. A sequence (an )n≥0 will be called quasiconvex if the series X X Y (ni + 1)|∆B (∆M an )| n≥0 B⊂M, B6=∅ i∈B converges. ESTIMATION OF THE INTEGRAL MODULUS OF SMOOTHNESS 399 If the sequence (an )n≥0 is quasiconvex and lim an = 0, knk→∞ then the series X 2−λ(n) an k Y cos ni xi (∗∗) i=1 n≥0 converges on (0, 2π)k to some function f : Rk → R summable on T k and is its Fourier series. Let m, i, δ, h ∈ Rk , where m and i have non-negative integral components, while δ has positive components. Consider Z X Pk k Y mj ij j=1 ωm (δ; f )1 = sup (−1) f [x + (m − 2i)h] dx ij −δ≤h≤δ j=1 0≤i≤m Tk as an integral modulus of smoothness of order m of the function f ∈ L(T k ). The validity of the following analogue of Lemmas 1 and 2 is obvious. Lemma 4. Let p ∈ Rk have natural components, h > 0 and 2mh ≤ x ≤ π1. Then X Pk k h i Y mj i Kpj [xj + (mj − 2ij )hj ] ≤ |Tpm | = (−1) j=1 j ij j=1 0≤i≤m ≤ c(m) k Y m mj −1 j x−2 j hj Pj , j=1 |Tpm | ≤ c(m) k Y m mj +1 hj j Pj . j=1 We have Theorem 2. Let a sequence (an )n≥0 be quasiconvex and Then for the sum f of the series (∗∗) we have X X (m) ω1 (δ; f ) ≤ c(m) B:B⊂M × Y ν∈B where Nν = [ δ1ν ], ν ∈ M . X 1≤nν ≤Nν Nµ +1≤nµ ≤∞ ν∈B µ∈B 0 ν +1 Nν−mν im ν Y µ∈B 0 lim an = 0. knk→∞ × iµ |∆B (∆M an )| 400 T. TEVZADZE (As usual, the empty product is assumed to be zero.) To prove the theorem note that the Hardy transformation is defined in Rk for k > 2 too and its structure becomes more complicated as the dimension increases. Nevertheless, the estimates from the proof of Theorem 1 can hold for the case k > 2 as well. References 1. S. Aljanĉiĉ and M. Tomiĉ, Sur le module de continuite integral des séries de Fourier a coefficients convexes. C. R. Acad. Sci. Paris 259(1964), No. 9, 1609–1611. 2. S. Aljanĉiĉ and M. Tomiĉ, Über den Stetigkeitsmodul von FourierReihen mit monotonen Koeffizienten. Math. Z. 88(1965), No. 3, 274–284. 3. M. and S. Izumi, Modulus of continuity of functions defined by trigonometric series. J. Math. Anal. and Appl. 24(1968), 564–581. 4. S. A. Telyakovski, The integrability of trigonometric series. Estimation of the integral modulus of continuity. (Russian) Mat. Sbornik 91(133)(1973), No. 4(8), 537–553. 5. T. Sh. Tevzadze, Some classes of functions and trigonometric Fourier series. (Russian) Some questions of function theory (Russian), v. II, 31–92, Tbilisi University Press, 1981. 6. E. H. Hardy, On double Fourier series and especially those which represent the double zeta-function with real and incommensurable parameters. Quart. J. Math. 37(1906), 53–79. 7. L. V. Zhizhiashvili, Some questions of the theory of trigonometric Fourier series and their conjugates. (Russian) Tbilisi University Press, 1993. (Received 29.12.1993; revised version 15.06.1995) Author’s address: Faculty of Mechanics and Mathematics I. Javakhishvili Tbilisi State University 2, University St., Tbilisi 380043 Republic of Georgia